Algebra practice
Name
Directions: Show all work on a separate piece of paper. Place your final answer on this sheet. 1. Given g ( x)
3 x 1 a. Evaluate and simplify completely
i) g (2) = ii) g (0) = iii) g (1) = iv) g (4) = v)
g ( x 3) =
b. Solve algebraically for exact x iii) g ( x) 2 4 x= f x h f x 2. Simply the difference quotient for the following functions [different quotient ] h f x h f x a) f x x 2 2 x 3 = h b) f x x3 5 c) f x i) g ( x) 5 x= ii) g ( x 2) 4 x=
f x h f x = h f x h f x = h
4 x
3. Simplify the following completely with a common denominator. Your final answer will not contain any negative exponents. b 2x = 4 x 5x 2 a) = b) x 1 2x b 24 x2 1 x2 1 x 2 x 1 2t 2 x c) d) = 2 t 3= 2 t 3 x2 1
1
2 3 e) = x5 x5
g)
4z 2 2 2 z z 2 f) z2
h) e x e1 x =
1
2
=
a n 3n 1 = 3n a n 1
i)
x
3
1 6 x3 x3 1
3
x
2
1
4
=
j)
5 1 z
2
3 1 z2 =
k)
2x x 5
2
1
2
x x 5 x2 5
2 2
1
2
2x
=
l)
x h
1
2
1 x2
h
=
m)
1 x 1 x2
1 y = 1 y2
n)
3 3 1 x 1
=
4. Solve algebraically for the exact solution(s). Solve for the indicated variable. Assume all other variables are constants. 1 ax 4b x __________ e5 x e5 x 1 x __________ x2
x __________ y _________ p _________
log( x) log( x 21) 2
x __________
a b 1 x 2x
6 y 2 y 0
t __________ 10te3t 2t 2e3t 0
p 1 p 2 11 0 p 2 p 3
t __________ 3t 12(.8)t
x __________
x __________ ln(t 2) ln(t ) ln 7 y _________
x 1 10 2
3
x 2 y x3 22 y 3
x __________ 3 x 13 x __________ 9 xe ax 3x2eax 0 x __________ ln(ln( x)) 1 x __________ A(.83) x B(b) x x __________ x 4x 2 7 x __________ 4 xe x 3e x 0 y _________
x __________ 3(ax 1) 2 x 4(a ax) x __________ x 1x 3 15 x __________ x __________
log( x) log( x 1) 1
3x 2 1 5 x 5
x __________ logx 4 2 logx 1 x __________ 4x 1 5 0
2
5y 2 0 y2 1 4y 20 1 2y
z __________ 0 4 z 3 6 z 2 24 z 36
t __________ t 2 t 6 14
y _________
t __________ 2t (3t 4) 5(t 2)
y _________
x2
2y y3 x
y __________ Ax By C 0
t __________ ln(t 2) ln(t ) ln( )
t __________ t 3 16t 1 0
3 p2 p 2 0 p _________ p7
R _________
1 1 1 R a b
5. Determine if each statement is Correct or Incorrect. Circle the correct answer. C I
x 2 121 x 11
w 1 2 1 for w 1 w 1 2
ln( M ) ln( B)
C I
4 2
C I
x3 3 x3 3 9
C I
C I ln e xe y x y
C I eln(x ) 5 xe5 C I 2x y 2x 2 y
C I ln( M ) ln( B)
C I ln a
1 ln a 2
C I log abt t logab C I
C I ln e x e y x y C I
C I
3
r 3 64 r 4
2
x 1 2 2 2 x x
3 3
x 2 3x 1 3x 1 x2
C I e3 e9
C I 82t 1 4t 2
C I
e
x 2
e2 x
C I
1 1 x4 4 x
C I
x 12 2x 1 x 1x 3
1
3
C I
1 4 3t 4 3t 1 ab 1 a b ab
1
C I ln(1) e
C I
z 8
2
z 8
2
3
C I
C I 2t t ln(2)
C I
1 1 1 x2 x 2
log( x) ln( x) C I log( t ) ln(t )
C I e4 ln(x ) 4 x
C I
Ax 2 B Ax B x
C I log( x y) log( x) log( y) C I If f ( x) 5x , then f x 4 5x 4
C I
1 y 3 1 y3