Laws Order
Description
Laws Order document sample
Document Sample


Slide 1 Section 12.2
Rate Laws & Reaction Order
For this reaction:
aA + bB Products
• A and B are chemical formulas for the
reactants
• a and b are the coefficients in the balanced
equation
Rate Law expression= k[A]m [B]n
How to determine
Slide 2 m and n
• For simple reactions (the ones found in this
class) an exponent of 1 means that the rate
depends linearly on the concentration of the
corresponding reactant.
• For example if m=1 and the [A] is doubled, the
rate doubles.
• If m = 2 and the [A] is doubled, [A]2 quadruples
and the rate increases by a factor of 4.
• If m=0, the rate is independent of the [A]
Slide 3
The m and n that you put as exponents are
the rate orders for the reactants.
For the given reaction:
Rate = k [ A]2 [B]
It is read as:
The reaction is in the 2nd order for A, first
order for B and third order for the whole
reaction
Slide 5
Section 12.3
Experimental Determination
Of Rate Law
Slide 6
Let’s look at the following reaction:
2NO(g) + O2(g) 2NO2(g)
And the following experimental data
Experiment Initial [NO] Initial [O2] Initial Rate
M/s
1 0.015 0.015 0.024
2 0.030 0.015 0.096
3 0.015 0.030 0.048
4 0.030 0.030 0.192
Slide 7
Analyzing the data you see that when the
[NO] is doubled (comparing experiment 1 to
2) and the [O2] stays the same, the rate
increases by a factor of 4, telling you that
[NO] is in the second order.
And when the [O2] is doubled (comparing
experiment 1 to 3) the rate doubled, from
the initial rate, telling you that [O2] is in the
first order.
Slide 4
Units for the reaction:
Rate Law Overall Rate Units for k
Order
Rate = k[B] First order 1/s
Rate = k [A]2 Second order 1/M(s)
Rate = k[A]2[B] Third order 1/M2(s)
Get documents about "