# 3A-1_ Write the percentage as a fraction or decimal. Write 13.5

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```					Study Guide Solutions – Exam 1
   Exam #1 on Chapters 1-4 is now through
March 6th in ETS testing lab
1A-1) The argument given or described involves some kind
of fallacy. Identify the fallacy
You should brush your teeth every day because brushing

Since this only restates the proposition this is

Circular Reasoning
1B-1) Determine whether the statement is a proposition.
0. 2 = .0 2
Do you like this color?

The equation 0.2=.02 is always false so it
is a proposition

“Do you like this color?” makes no statement (it
is a question) so it is
not a proposition
1B-2) Write the negation of the proposition.
Susie lives in a green house.
Everyone is asleep.

Susie does not live in a green house.

There is somebody who is not asleep.
1B-3) Make a truth table for the given statement. The letters
p, q, r, s represent propositions.
q∧~r∧s

q   r   ~r s     q ~ r q ~ r  s
T   T   F T        F        F
T   T   F    F     F         F
T   F   T    T     T         T
T F     T    F     T         F
F T     F    T     F         F
F T     F    F     F         F
F   F   T    T     F         F
F   F   T    F     F         F
1B-4) Write the converse, inverse, ad contrapositive of the
proposition.
If you received a refund of over \$1000, then you cannot make
a claim.

If you received a refund of over \$1000, then you cannot make a
claim.

Converse: If you cannot make a claim, then you received a refund
of over \$1000.

Inverse: If you did not receive a refund of over \$1000, then you can
make a claim.

Contrapositive: If you can make a claim, then you did not receive a
refund of over \$1000.
1B-5) Two statements are listed in which p, q, and r
represent propositions. Are the two statements logically
equivalent?
~(p∧q); ~ p∨q

p q       p  q ~  p  q ~ p ~ p  q
T T        T        F       F    T
T   F       F            T          F          F
F T         F            T          T          T
F F         F            T          T          T
1C-1) Solve the problem using Venn Diagrams.
The following Venn diagram describes the types of cookies
in a bakery. Use it to determine how many chocolate chip cookies do
not also have walnuts.

13
1D-1) Decide whether the argument is inductive or deductive.

All U.S. Presidents have come from the contiguous 48
states. No person from Alaska can be President.

This is inductive (based on selected observations)

For any positive number p, |-p| = p. Therefore, |-23| = 23

This is deductive (a specific case of know properties)
1D-2) Evaluate the validity of the chain of conditionals.

Premise: If the moon is made of cheese, then what goes
up must come down.
Premise: If what goes up must come down, then most
Americans like apple pie.
Conclusion: If the moon is made of cheese, then most
Americans like apple pie.

This is valid (p implies r AND r implies q,
THEREFORE p implies q)
2A-1) Carry out the indicated unit conversion. Round your

Convert a distance of 42 feet into yards.
1yd
42 ft        14yd
3 ft
Convert a weight of 13 pounds into ounces; there are 16 ounces in a
pound.
      
         16oz
13lb        208oz
1lb
A container holds 6 gallons of water. How many fluid ounces is
that?
        128oz
 6gal            768oz
1gal
2B-1) Convert the measurement to the units specified. Round

31 liters to gallons (1gal = 3.785 L)
1gal
31l           8.19gal  8.2gal
3.785l

     35 pounds to grams (1 pound = 453 grams)

          453g
35lb         15855g  15.8kg
1lb

           

2B-2) Convert the temperature, as indicated. Round your

60°F, into Celsius (C=5(F-32)/9)

C = 5(60-32)/9 = 15.6°C

20°C, into Fahrenheit (F=9C/5+32)

F = 9(20)/5+32 = 68°F
2C-1) Solve the problem.

A traffic counter consists of a thin black tube stretched across a
street or highway and connected to a "brain box" at the side of
the road. The device registers one "count" each time a set of
wheels (that is, wheels on a single axle) rolls over the tube. A
normal automobile (two axles) registers two counts, and a light
truck (three axles) registers three counts. Suppose that, during a
one-hour period, a particular counter registers 38 counts on a
residential street on which only two-axle vehicles (cars) and
three-axle vehicles (light trucks) are allowed. How many cars
and light trucks passed over the traffic counter? Find all the
possible solutions to the problem.
2C-1) Solve the problem.

This amounts to solving the equation 2x+3y=38 with nonegative
integers x and y.

Starting with x=19 and y=0, we can use the slope of this line (m=-
2/3 or m=2/(-3)) and generate the other points
x=16, y=2
x=13, y=4
x=10, y=6
x=7, y=8
x=4, y=10
x=1, y=12 There are seven in all.
3A-1) Write the percentage as a fraction or decimal.
Write 13.5% as a decimal.

To write a percent as a decimal
we divide by 100

13.5
 0.135
100
3A-2) Write as a percent.
Write 0.829 as a percent

To write a decimal as a percent
we multiply by 100

0.829x100
= 82.9%
3A-3) Find Percentage
\$973 is    % of \$1676

To find percent of, we use the formula
Part
P
Whole
1676 is the whole
973 is the part
973
P       0.58  58%
1676
3A-4) Find percentage part.
An outlet store had monthly sales of \$119,400 and spent 4%
of it on health insurance. How much was spent on health
insurance?

To find percent part, we use the formula
Part  Whole  Percent

119400 is the whole
4% = 0.04 is the percent
Part  119400  0.04  \$4776
3A-5) Find percentage mark-up/down.
A store manager paid \$57 for an item and set the selling price
at \$82.65. What was the percent markup?

To find percent mark-up, we use the formula
New  Old
Percent 
Old

82.65 is the new
57 is the old
82.65  57
Percent              0.45  45%
57
3A-6) Find mark-up/down value.
The regular selling price of an item is \$ 182. For a special
year-end sale the price is at a markdown of 20%. Find the
discount sale price.

To find marked-down price, we use the formula
New  Old  Old  Percent

20%=0.20 is the percent
182 is the old

New  182 182  0.20  \$145.60
3B-1) Write the number in standard notation.
a) 5.8x106
b) 7. 83 x 10-4

If the exponent is positive, we move the decimal point
to the right. So in 5.8x106 we move the decimal
point in 5.8, 6 places to the right.
5.800000 becomes 5,800,000

If the exponent is negative, we move the decimal point
to the left. So in 7.83x10-4 we move the decimal
point in 7.83, 4 places to the left.
00007.83 becomes 0.000783
3B-2) Write the number in scientific notation.
a) 3,400,000

b) 0.0000561

To get a mantissa between 1 and 10, we have to move the
decimal point to immediately after the first non-zero number.
If we move to the left, the exponent is positive, if we move to
the right, the exponent is negative.

3400000.0 becomes 3.4 after moving the decimal point 6 places
to the left so 3400000= 3.4 106

0.0000561 becomes 5.61 after moving the decimal point 5
places to the right so 0.0000561= 5.61105
3B-3) Use scientific notation to perform the following

a) (4x103)( 9x104)

When multiplying numbers in scientific notation, the resulting mantissa is the
product of the factors’ mantissas. The exponent is the sum of the factors’
exponents.

(4  10 3 )( 9  10 4 ) =(4  9)  10 3+4   =36 10 7

If the resulting mantissa is greater than 10, we must divide it by 10 and add 1
to the exponent.

36 10 7 =3.6 108
3B-3) Use scientific notation to perform the following
2.8  10 8
b)    7.0  10 1

When dividing numbers in scientific notation, we divide the mantissas. The
exponent is the difference of the factors’ exponents.
2.8  10 8    2.8
      10 8(1)  0.4 109
7.0  10 1   7.0

If the resulting mantissa is less than 1, we must multiply it by 10 and subtract
1 from the exponent.

0.4 109      4.0 108
4A-1) Use the compound interest formula for compounding more than
once a year to determine the accumulated balance after the stated period.
a) \$ 900 deposit at an APR of 12% with quarterly compounding for 5 years

The value of an investment into which P dollars is invested for t units of time
at an interest rate of r per unit time and compounded n times per unit time is
nt
    r
A  P  1    P 1  r / n   (n  t)
    n
P=900,      r=12%=0.12,            n=4,     and     t=5
45
     0.12 
A  900  1                   900 1  0.12 / 4   (4  5)
      4 

=1625.50
4A-1) Use the compound interest formula for compounding more than
once a year to determine the accumulated balance after the stated period.
b) \$ 5500 deposit at an APR of 5.5% with monthly compounding for 8 years

The value of an investment into which P dollars is invested for t units of time
at an interest rate of r per unit time and compounded n times per unit time is
nt
    r
A  P  1    P 1  r / n   (n  t)
    n
P=5500,       r=5.5%=0.055,          n=12,       and     t=8
128
    0.055 
A  5500  1                     5500 1 0.055 /12   (12  8)
     12 

= 8531.31
4A-2) Find the annual percentage yield (APY).

A bank offers an APR of 3.6% compounded monthly.

The annual percentage yield of an account with an annual interest rate of r
and compounded n times per year is
n
   r
APY   1   1  (1 r / n)  n  1
   n

r=3.6%=0.036        and       n=12
12
    0.036 
APY   1         1  (1 0.036 /12)  12  1
     12 

= 0.0366 = 3.66%
4B-1) Calculate the balance under the given assumptions.
Find the savings plan balance after 27 months with an APR
of 11% and monthly payments of \$306.
If PMT dollars are added to an investment account, n times per year, the
annual interest rate is r and the payments are made for t years, the value of
the account would be
   r
nt

 1   1 
 n
A  PMT              PMT ((1 r / n)  (n  t)  1) / (r / n)
     r     
     n     
           
A=306,       r=11%=0.11,                n=12,        and      t=2.25
  0.11   12 2.25

  1                1
    12 
A  306                           306((1 0.11 /12)  (12  2.25)  1) / (0.11 /12)
       0.11             
        12              
                        

=9326.08
4B-2) Calculate the payment for the given situation.
You intend to create a college fund for your baby. If you can get an
APR of 7.0% and want the fund to have a value of \$154,826 after 18
years, how much should you deposit monthly?

The payment required for a savings plan to have A dollars if it is deposited
n times per year for t years at an annual interest rate of r is
         r         
                   
PMT  A             n          =A  r/n/((1+r/n)^(n  t)-1)
nt
       r         
  1 n   1 
                 
A=154826,        r=7%=0.07,                n=12,        and    t=18
         0.07             
                          
PMT  154826            12               =154826  0.07/12/((1+0.07/12)^(12  18)-1)
1218
  0.07                  
  1                 1
      12                
=359.46
4B-3) Compute the total and annual returns on the described
investment.
Five years after buying 200 shares of XYZ stock for \$ 30
per share, you sell the stock for \$10,000.
The total return formula is

TR = (10000 - 6000) / 6000 = .6667 = 66.67%

The annual return formula is
AR  TR+1 1
1/t

TR=.667                   t=5

AR  .667+1 1  .1076  10.76%
1/5
4B-4) Calculate current yield of a bond.
Calculate the current yield for a \$1000 Treasury bond with
a coupon rate of 2.9% that has a market value of \$750.
The interest that any bond pays is given by the formula
Interest = FaceValue x CouponRate

FaceValue=1000               CouponRate=0.029

Interest = 1000 x 0.029 = \$29

Interest
The Current Yield is given by the formula    CurrentYield 
MarketValue

MarketValue=750
29
CurrentYield         0.0387  3.87%
750
4C-1) Find loan payment
Calculate the monthly payment for a student loan of \$
67,519 at a fixed APR of 8% for 17 years.
A loan payment is given by the formula
 r
P 
 n
PMT                nt  P  r / n / (1- (1 r / n)  (-n  t))
    r
1  1 
 n

P=67519         r=0.08             n=12               t=17

PMT  67519  0.08 /12 / (1- (1 0.08 /12)  (-12 17))  \$606.49
4C-2) Compute the monthly payment for 30 vs. 15-year mortgage.
Assume that the loans are fixed rate and that closing costs are the
same in both cases. You need a \$ 104,473 loan.
Option 1: a 30 year-loan at an APR of 8%
Option 2: a 15-year loan at 7%

A loan payment is given by the formula
 r
P 
 n
PMT                     nt    P  r / n / (1- (1 r / n)  (-n  t))
   r
1  1 
 n
P=104473       r=0.08             n=12           t=30
PMT  104473 0.08 /12 / (1- (1 0.08 /12)  (-12  30))  \$766.59

P=104473       r=0.07            n=12           t=15
PMT  104473 0.07 /12 / (1- (1 0.07 /12)  (-12 15))  \$939.03

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