Quadrature Amplitude Modulation _QAM_ Receiver

Description

QAM (Quadrature Amplitude Modulation) digital modulator for DVB system, front-end device, receiving data from the encoder, multiplexer, DVB gateway, video server and other equipment of the TS stream, the RS coding, convolution coding and QAM modulation, RF signals can be output directly in the cable TV transmission over the Internet, but also can be selected IF output. With its flexible configuration and superior performance, widely used in the field of digital cable TV transmission and digital MMDS system.

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5/25/2011
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							EE345S Real-Time Digital Signal Processing Lab Spring 2006


Quadrature Amplitude Modulation
        (QAM) Receiver


                 Prof. Brian L. Evans
    Dept. of Electrical and Computer Engineering
          The University of Texas at Austin

                          Lecture 16
                                   Introduction
• Channel has linear distortion, additive noise, and
  nonlinear distortion
• Adaptive digital FIR filter used to equalize linear
  distortion (magnitude/phase distortion in channel)
   Channel equalizer coefficients adapted during modem startup
   At startup, transmitter sends known PN training sequence
                                   AGC                 Carrier Detect
                                                                              I(nT)
 r0(t)              r1(t)   r(t)          r(nT)                    X    LPF
         Receiver
                                    A/D
          Filter
                                                                              Q(nT)
                                                                    X   LPF
                                             Symbol
                                              Clock        90o
                                            Recovery                            16 - 2
                  QAM Receiver
• Automatic gain control
  – Scales analog input voltage to appropriate level for A/D
  – Increase gain when received signal level is low
• Carrier detection
  – Determines whether or not a QAM signal is present
• Symbol clock recovery
  – Track clock frequency
• In-phase/quadrature (I/Q) demodulation
  – Recover baseband in-phase/quadrature signal

                                                          16 - 3
                 Carrier Detection
• If receiver is not currently receiving a signal, then
  it listens for known training sequence
• Detect energy of received signal
   p[n] = c p[n − 1] + (1 − c) r 2 [n]       Transfer function?
   – c is a constant where 0 < c < 1
   – r[n] is received signal
• Check if received energy is larger than threshold
• If receiver is currently receiving signal, then it
  detects when transmission has stopped
   – Detect energy of received signal
   – Check whether it is smaller than a smaller threshold
                                                            16 - 4
           Symbol Clock Recovery
• Two single-pole bandpass filters in parallel
  – One tuned to upper Nyquist frequency ωu = ωc + 0.5 ωsym
  – Other tuned to lower Nyquist frequency ωl = ωc – 0.5 ωsym
  – Bandwidth is B/2 (100 Hz for 2400 baud modem)          Pole
• A recovery method                                     locations?
  – Multiply upper bandpass filter output with conjugate of lower
    bandpass filter output and take the imaginary value
  – Sample at symbol rate to estimate timing error τ See Reader
    v[n] = sin(ω sym τ ) ≈ ω sym τ when ω sym τ << 1 handout M
  – Smooth timing error estimate to compute phase advancement
     p[n] = β p[n − 1] + α v[n]        Lowpass
                                       IIR filter          16 - 5
 In-Phase/Quadrature Demodulation
• QAM transmit signal x(t ) = a(t ) cos(ω c t ) + b(t ) sin(ω c t )
• QAM demodulation by modulation then filtering
    – Construct in-phase i(t) and quadrature q(t) signals
    – Lowpass filter them to obtain baseband signals a(t) and b(t)
 i (t ) = 2 x(t ) cos(ω ct ) = 2a (t ) cos 2 (ω ct ) + 2b(t ) sin(ω ct ) cos(ω ct )
      = a(t ) + a(t ) cos(2ω c t ) + b(t ) sin(2ω c t )
        baseband       high frequency component centered at 2 ωc

q (t ) = 2 x(t ) sin(ω ct ) = 2a (t ) cos(ω ct ) sin(ω ct ) + 2b(t ) sin 2 (ω ct )
      = b(t ) + a (t ) sin( 2ω c t ) − b(t ) cos(2ω c t )
        baseband       high frequency component centered at 2 ωc
             1                                                     1
    cos 2 θ = (1 + cos 2θ )     2 cosθ sinθ = sin 2θ      sin 2 θ = (1 − cos 2θ )   16 - 6
             2                                                     2

						
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