# Chapter Seven

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Atlanteans
ARAM ¢ MATH & NUHMBERS

155

ELLEIPSIS & KONOS

"MOVING-POINT" WITH-STRING.

I

Above

= R-(;ONST,L",T

Dimencion units.

The ELLEIPSIS(

"ellipse"

is the LINE-PATH inscribed by a "POIKT"
"POI~T"

that moves to inscribe that line and such 2 FOCUS-POIKTS as are "FIXED",

is restrained by

therefore v i a use of a "FIXED-LENGTH"

string the MOVING-POINT will inscribe the ELLEIPSIS and the Radius at any given-point of ELLEIPSIS will be proportional to the 2 AR!'-lS of "FIXED-LENGTH" line extending off the FOCII other-points. ie: ) we r-e on- c en t er the "MO\'ING­ with a In the event the FOCII ( 2 f o cus-po in t s

POINT"( 3rd point) would inscribe a perfect-circle 360 0

constant "radius" 100% ADIMENCIONAL. Thus to draw an ELLEIPSIS you spread the FOCII( 2 points ) away from the "circle-center" and the wider-apart the FOCII, OBLIQ"lJE( the narrower-the-elleipsis, while the "FIXED­ "cone" ) off the perpendic­ LENGTH" line shows proportional TRIANGLES during its MOCION. The "slanted" ) CUT of the KONOS( ular plane of base reference yields the ELLEIPSIS surface as shown on the right-hand drawing above. A "CIRCLE" is an ELLEIPSIS when such "CIRCLE" is viewed from any degree-of-angle off its centerline-axis "POINT" --- see the AXIS between APEX and baseline "CIRCLE" of the KONOS above wherein the AXIS line runs through the CENTER-POINT of the 360 0 "CIRCLE".

156

ELLEIPSIS

=

"SPHERE" WITH SECTION-REMOVED

--8­

()­

"WE :MUST PERCEIVE VIA REASON OF THE MIND TRJ\.T KHICH WE CANNOT WITNESS VIA SIGHT ALONE FROM A GIVE", VIEW" Only wi th such COMPLETENESS-OF-INSIGHT can w-e construct via our MIND and "SENSES" the form of an object and its relative MOCIO.t\ ( "motion"

=

"time" ) via the "IMAGINATION" 100% MENTAL in "TUNE"

with our "SIGHT-SENSORY" inputs which are also given to our "MIKD" as gives us the "SIGHT-IMAGE" via our optic-system. ELLEIPSIS APPARENT is also the view looking 100% TOWARD the surface of a "SPHERE" NUCLEUS-PLANET form with such theoretical-wedge removed to show the ELLEIPSIS as shown above, ::: 2 180 0 "CIRCLE-HALVES" though this ELLEIPSIS

=

2 distinct-planes of .5 "CIRCLE" which

being angled to our sense-of-view appear as the ELLEIPSIS form. ELLEIPSIS is therefore an illusion of the 100% GRETCIRCLE.

157

ELLEIPSIS -

"HEMISPHERE-CIRCLE" ROTATED

t

"CIRCLE"

25

+ ________t
+
35%
<,

_
,
\
\

-,
\
\
\

--8­
J

I-­

\I~
I
I

I
I

<r:
90° = 2Si­

"

/
/

L
,/

"SHORT APPARENT.

r"

-I
\
\

,
\
\

,
I
J

/
I

/

~-o-

....

-

158

Of the preceding "HEMISPHERE-CIRCLE", until the .5 PLANET Illumin­ ated face is turned more than 90° it will not reveal its Short-r ( 'radius-apparent perpendicular to R-Constant 100% ADIMENCIONAL' ) and thus the R-Constant is the Long-R & r-Variable is the Short-r. ELLEIPSIS SURFACE "EQUATION" S S R

= Rr
2

/

r2

=
=

Surface apparent "SQUARE"(

) "dimension" of the ELLEIPSIS.

Radius Constant 100% ADIMENCIONAL 3.96 as illustrated.

r = Short-r as compared to the above Long-R of 3.96 constant.
r2

=

.3168 ratio

fOT

loC'~/( DI.A!'rr'T'TRIA(

"diameter" ) as the constant

wherein 31.689-'~ 100% PERIPHERE of 25 = 7.92 10010 ADIHENCIONAL. Therefore, for the preceding ELLEIPSIS forms having ADIMENCIONAL
100% 3.96( R 'Long-R' following prevails:
3.96( R ) x 2.75( r
8: 3.96( R

) and either 2.5 or 2.75 'Short-r'

the

)

) x 2.5( r )

= =

10.89 which 9.9 which

/ /

.3 168( r2 ratio ) .3 168( r2 ratio )

= =

3 4.375( S ) 3 1 .25 ( S )

.

3.96 x 2.75 x 2¢( 3.96 x 2.5 x 2¢(

3. 1..2..§. ratio )

J. 1..2..2. rat,io )
S

= =

34.375 Surface of ELLEIPSIS and

J 1 .25

SurInCP 01 ELLEIPSIS, via:

=

Rr x 2¢
EIP~IS

Realize that

th~

preceding ELI

illustrations first use the
NUCLLL~-PLANET

VERTICAL-AXIS to roll-about while OUR-EARTH with the
10o~

uses

N-S AXIS to roll-about, hence the C'!lestii:..ll-Vertical provides us ADIMENCIONAL 3.96 Radius-constant and 25 PERIPHERE 100% for our 100% STANDARDS used in the examples arithmetic above. GRETCIRCLE 100% S Radius 3.96 when "squared"(

= R2 =
=

/

r2 .3 168

222 2 ) = 3.96 = R hence 3.96 /

( r2 ratio of DIAMETTRIA 100% ) be the ELLEIPSIS according to S

49.5 Surface of 100% GRETCIRCLE
Rr / r2 showTI preceding.

100% STANDARDS arithmetic. Anything less than 49.5 Surface would

159

3. 12 §' Short-r

3.96 Long-R radius-constant = 79.0123456789~~ via .83.2. 'differential' which / 3.96 R constant: 20.9876543210% and

/

3.96( R ) x 3. 12§.( r 3.96( R ) x 3.96( R ) 39.1 /
sho~n

)

/ /

.3 168( r2 ratio .3 168( r2 ratio

) )

= 39 • .2. ELLEIPSIS Surface = 49.5 "CIRCLE-Surface"

49.5

=
=

79.01234567 89% for the ELLEIPSIS SURFACE and 20.9876543210% for the 'differential-surface'

10.3§./ 49.5

between 100% GRETCIRCLE and the ELLEIPSIS.

"RHIND PAPYRUS" s ho w s us that the reduction of the R Constant 3.52 Short-r radius-of­ 2 / .3168 = circle and a "CIRCLE" having 3.52 Radius has 3.52 39 •.2. SL~FACE which 49.5 SURFACE ~hich of 3.96 100% ADIME~CIO~AL by 1 / 9

=

=
=

79.0123456789% the 100% STANDARDS of 20.9876543210% 'differential' caused by

.44 radius-differential.
In the above examples we could term them ELLEIPSIS ELLEIPSIS of 39 . .2. SURFACE. Note that of the Short-r for this ELLEIPSIS of 3.12§. that
wh e n
QGADR~TCRE

since we have converted the "CIRCLE" of 39 . .2. SURFACE to an

x l . 125

=

3.52 Short-r for the "RHIND PAPYRUS CIRCLE"

and note that the 100% ASQUARRE has a "diagonal" of 11.25 100% ADIMENCIONAL which "diagonal" or "hypotenuse" x 70.49c will FIND its "SIDE" of 1+1 radius-units of J.96 constant per each for the "SIDE" of that 100% ASQGARRE. In ALL cases we must first find
UNDERST~~DING

of

~hat

the

~ATLRE

of the object under our scrutiny is and then

~e

can reason via

100% MENTAL perception what the arithmetic relationships are that attend that form which via "SIGHT-SENSE" alone may not appear as a "SOLID" --- ie: ELLEIPSIS & "CIRCLE" are considered planar, yet in one direction and then the ELLEIPSIS and "CIRCLE" are shown to also be relative-portions of the "SPHERE". Turn a "CIRCLE" 180 0 180 0 in a direction 90 0 to the first turn and you will have thus

described a "SPHERE" when you have rendered all those LINES and such "SPHERE" would be dark from so many lines of definition.

160

ERATOSTHENES

HEMISPHERIu~

"SUN_DIAL"
.02112 TORRID-ZONE 2 x 1584 STATUTE-MILE SURFACE PARALLEL WIDE.

3960 RaDEUS
of

PLANET

=
3960

.1584 Ratio.

3168

~

The above drawing s ho w s the Illuminated "side" of our-earth planet wherein its NIGHT-SHAD01\' SIDE" would be u pwa r d of the N-S Axis. 1\-e "SEE" only 2556 of the KUCLEDS-PLAKET as

= 50r6

of its Illuminated­ via the 3168

face in the above view. Our TORRID-ZONE is

sho"~

MILE STATUTE parallel-lines off Celestial-Vertical Axis ECQUATOR

100510 and thus each zone
in this drawing
sho,,~

=

1584 Mile Statute "width" --- both are

"TINTED" and it is in this zone that our

maximum "SUKLIGHT" reaches the surface via "SUNLIGHT-AXIS" of .25 0 radius-triangulation giving us the "CONE" of such maximal-light vibration.

ALL-SALT

SEA-LEVEL

Let the above be 25% "SPHERE" of PLANET dishing-out a LEVEL-STONE with .5 0 included-triangulation angle being the "INDICE" of the HEMISPHERIUM-SUNDIAL of ERATOSTHENES for purpose of such explan­ ation of this work you now read.

161

THEREFORE: With the LEVEL-STONE 'carved-out'

the HEMISPHERIUM Apex

of that zone ARC inline with SUNLIGHT-AXIS up-coming and the .25 0 radius-triangulation of maximal-light intensity being show'll as a 180 0 reversed-cone GNOMON having its Apex at ARC Apex and its 2.2 replaces the planet-earth though maintaining MILLION-INCH CONE-DIAMETTRIA circled now at Planet-Nucleus POINT wherein such
Su~DIAL

its rotation will when GNOMON and SUNLIGHT Axes are in-line "CAST NO SHADOW" until via planet-rotation the SUNDIAL HEMISPHERIUM GNOMON Axis is not aligned with SUNLIGHT Axis when a SHADOW will be "CAST". Such a SHADOW during THE MEAN Earth-Orbi twill h a v e relat­ ively inscribed THE FULL 1 0
/

.02112 = 47.348 0 TORRID-ZONE show'll in

TINT on the normal-planet viewing of its "illuminated-face" base. H+E+M+I+S+P+H+E+R+I+C+M = 144 & 1+4+4 = 3x3 = marks the
~
\$

"circled-cross" as

ACENTERUM "density-center-point" within a "electron" ) and its NUCLEUS-PLA"t\ET. 144 ) = 720 noting that 360 0
/

100% ELEKTRON(

-

E( 5 ) x R+A+T+O+S+T+H+E+N+E+S( = .5 0

720

'included-angle' 01 SOLAR-DISC "triangulation" off NUCLEl'S­ 3+3= 6 ) x ALTAIRE(.66 ) = 3.96

POINT of our-earth 100% ELEKTRO~ within its Nucleus-Planet 3960 Mile Statute below-surface of THE( Thousand MILE STATUTE "high-place" lor Celestial-Vertical STANDARDS 100%. When 1 time every 66 at 10
/

26

orbi ts 01 26136 "YEARS" the SlJNLIGHT-A.XIS is or 500 MILE STATUTE Iurther as its 100% ) + L+E+X+A+N+D+R+I+ of "ERATOSTHEXES"

.04224 = 23.6742 0 TROPIC-ZONE "SUMMER SOLSTICE" at SIENE

( 52 = 25 ) precisely 7.2 0

Celestial-vertical Radius-ol-surface = A( A+N( 100% ) = 1+1 site wherein 2 x 7.2
0

= 14.4 0

wherein a vertical GNOMON Obelus upward-aI-planet surface would "CAST" a 7.2 0 SHADOW"

OUR-EARTH ELEVATION-VIEW

o
'4.4.

ERATOSTHENES

-.../1 \.. . ­
162

PLAN-VIEW
( Looking UPWAI1D

ERATOSTHENES 14,4 0 EARTH SEGMENT DATA ENLARGED ERATOSTHENES 14,4 0 EARTH-SEGMENT

..

EARTH~

OUR-

a

o

~~R1lIT-~
PLANE

a

PLANET­

EARTH SURFACE
@

The drawing-above is OUR-EARTH'S

ILLD~lINATED-FACE

portion as 14.4 0
MILLION INCH R2

EARTH-CIRCLE and the small-circle at-center

= 2.2

of' "SUNLIGHT-COXE of maximum-strength via the .25° radius-of­
Solar-Disc "triangulation" --- its CHORD-LI!\E of such "SEGl'IENT"
A-A is the "dimension" of the ARC Surface / 62 099 136 INCH which c ARC and CHORD PERIPHERE = .19602 INCH "hich CHORD as 396 3 INCH 1.0203040506070809, ie:

=

=

/ /

.9801 .9801

= =

63.36 b INCH
c .2 IKCH

PERIPHERE of "T'L at t ened- arc" of 63 360 000 INCH.
b ARC	 R2 "FLATTENED" would exhibit a SURFACE of 31.68 INCH Radius & d 2 3168 INCH wh i ch is 3.940 389 86% greater than the ac tual ARC SURFACE.

163

when the SUNLIGHT-AXIS is on 100% ECQUATOR at Mount 100% Rl~E~ TSORI ( 8+1 JxJ

=
\$

JxJ

=

\$

)

on Celestial-Vertical due SOUTH of the RED( 2+7

=

100% MIKERINU

=

S(

1+9

=

1+0

=

100% ) PYRAMID ( 8+2

= = 1+0 =

100% ) and THE(

J+J ) x LUNAR(

.66 )

=

J.96 100% ELEKTRON Nucleus

at the J+J & J+J "HOUR" of "NOON"

casts a relative 2.2 MILLION

INCH 100% DIAMETTRIA "CONE-CIRCLE" "SHADOW-OF-NIGHT" on MIKERINU'S' it would surely be a "DAY" to CELEBRATE since it wo u l d clearly mark the end of A( NINISTRY( 1+2+J 1 + JJ + JJ + ) THIRTY( 9+6

=

1+5

=

J+J ) IEAR(

JJ 1+0

= =

"year" )

= J+J ) JJ = 100%

wherein:

"A THIRTY YEAR Mlt-."ISTRY" would

=

as 1 + 6 + 6 + 6

=

1+9

=

100%.

To have thus brought a perfect "MIKISTRY" to an end and to thus have heralded the "BEGINNING" of yet another is surely "hy at the site 01 CHEOPS GRETPYRAMID such JxJ pyramids and SPHINX were constructed to thus ceremonially commemorate that "DAY". AMOS 8: 9. "And it shall come to pass in that day, that I darken the earth in a clear day."
L l:KE

saith the Lord, God, and I will

will cause the sun to go do"n at noon,

2 J : Lj 5 • the t empl e wa s

"And the sun was darkened, and the vei 1 0 f rent in the midst."
T+H+E( JJ ) + TEMPL( 66 ) WASREN( 9+9 1+0+1

=

99 & 9+9

= =

18 ( Ra ) wh i c h x . E (

.5

=

JxJ /

=

1+8

=

JxJ ) x T( 2+0

=

1+ 1 )

=

1+ 1 and

INTHEMIDS(

) / T( 2+0

=

1+ 1 )

100% "THE 'VEIL OF THE

TEMPLE wAS RENT IN THE MIDST." DAWN of the FIRST-DAYLIGHT PERIOD of the above would first show SUNLIGHT on the south-faces 01 CHEOPS & KEPHREN pyramids and for 100% MIKERINU'S' pyramid that SUNLIGHT at DAWN would only grace the western 50% of its south-face --- and at NOON it would go TOTALLY DARK due to the "TOTAL SOLAR ECLIPSE" --- and after full illumination again it would find before NIGHT-TIME that its south­ face would only find its eastern 50% illuminated.

164

1

2

DAWN #1 DAWN #2 DAWN ttJ

"First-L ight" splits

MIKERI~TLfS'

S outh-Face vertically. So uth-Fac e in s h a d o w ,

"Fi rs t-Li ght" s ho w s MIKERI!\Li I S I

"First-L ight" splits CHEOPS South-F ace vertically.

Each Vernal & Au tumnal EQUINOX the same "SPL IT-PYRA.J"'lID" s h a do w & light phenomenon occurs --­ though the
DAw~

& EVENING exposures

are "different" each ORBIT until that-day wh e n the SUKLIGHT-AXIS precession-cycle about our 100% ECQUATOR is again precisely total and thus again at Mount 100% RUWEK TSORI
NOO~.
\$

at 3+3 & 3+3 hours of site

This event with TOTAL SOLAR EKLEIPSIS at MIKERINurs,

with no KORONA evident -and thus 100% PAENUMBRAI( "penumbra" 26 occurs every 66 Earth-Orbits as equals 65.34 x the 400 orbit­ cycle now given for nearly total solar "eclipse" as such site and 2 100% MIRRORED the product of 6.6 = 65.34 since 43.56 = 6.6 2 In the event the MIKERINU'S' site,
SL~LIGHT-AXIS

at Mount

R~~ENTSORI

at NOON during

5940 B.C. provided a TOTAL SOLAR EKLEIPSIS with UMBRA-AXIS at the then such totality would occur again during 18213 A.D. although 'partial Solar Ekleipsis' being nearly-total would occur at that same-site every 400 Earth-Orbit periods at other than noon periods of "DAYLIGHT" due to the obvious factors of THE LUNAR and the EARTH precession rates about their respective host system nucleus-points. See 100% INTELLECT book of Author.

165

ARCHIMEDES

SPHERE

~1-·_--12.5 --~----1.25

-------4

5~~~~T

11--­ .
S+P+E+R+E( 6xJ = 666 ) and S+P+H+E+R( 66 ) x .~( / K+Y+L+I+:t\+D+R+O+S( P+Y+R+A+M+I+D+O+C(
25

A+R+C+H+I+M+E+D+E( 66 & 6+6 = 1+2 = J ) x ~( ( 9 x .99 )

lx9 )

= 999 = INVERTED
"numbers" ).

=

.1122JJ445566778899 &

.5 ) = JJ = ¢ = 100~~, N1JHMBERS(

12J & 1+2+J = J+J ) "cylinder" 100% = 1 ) .5 ) = JJ = ¢ "pyramidos"/"pyramid" "sphere"

S+P+H+E+R( 66 ) x .E(

G+R+E+A+T( 5+1 = J+J = ¢ ) 100% = P+U+R+A+M+I+D+O+C G+R+E+T( 50%

&

x 100%( PURA:'1IDOC ) = .5 "great pyramid"

2x66 MILLION FOOT 100% GRETCIRCLE / A+R+C( 22 ) = J+J MILLION b FOOT anj JJ MILLION FOOT = 2x66 FOOT / 2+2 and JJb FOOT is the .5 illuminated-face of Our-Earth Nucleus-Planet ECQLATOR 100% with THE( J+J ) x .~ITTRIA( .66 ) = J.96 Thousand MILE SPHER( 66 ) x .E( .5 ) STATUTE Radius-vertical for such

=

JJ.

Start "TEST PROOFS" via the above rectangle form using GRETCIRCLE 100% RO(

=

25 and Radi us- cons t ant = J. 96 as s ho wn above wherein your

JJ ) LL( 2+4= JJ ) of that flat-form into a J.96 constant-Ra

KYLINDROS of 25 100% PERIPHERE as shown on the following-page and 6§.% the "CUBE-VOLUME" of 196.02 for this KYLINDROS

=

lJo.68 for

the "CUBE-VOLUME" of' thi s SPHER x • E --- and then no t e tha t such 100% STANDARDS for such "SPHERE" shows that JJ x J.96 Radius-const­ ant = 1 Jo. 68 "CUBE-VOLUME". A+R+E+A = 25 of the "ARCHIMEDES SPHERE" and "ARCHIMEDES KILINDROS" 100% P+E+R+I+P+H+E+R+E( "periphery" ) --- thus ARCHIMEDES is an arithmetic statement not at all depicting a person.

166

~PHER

x .E ARC-SURFACE x r8

=

99 KrLINDROS

ARC-Sl~FACE

"SPHERE"

=

Any round-body having

OI'>L~I-DIRECTIONAL

equal-radius o f f

100% ACENTERlJM point. It is a BALL or GLOBE defined in "geom,,,try" as	 a solid bounded by a surface having CONSTANT-RADIUS "dimension" off its CENTER-POINT as when an ARC of 180 0 about its R2( CIRCLE AREA( plane-section taken through the CENTER-POIKT is made to rotate reveals a CONSTANT­ "diameter" ) generating a "Sphere" form wherein any 25 ) while that plane-line defines its 2-radius height

or length as is proportional to its circle-length. Kote: J.96

=

15.84% 25 and 2xJ.96

=

J1.68% 25

J.96 x 6.~

= 25

and 2xJ.96 x J.l2£

= 25

Supposed "sphere-surface" is assumed proportional to the "squares" of its 2 radius-units wherein a radius J.96 has 1.989974874 "square­ root"	 which x 5+5 PiR 2 x 4

=

198.9974874 statement 0: "surface" analog. 2 x 4

=

J.14159265J+ .. x J.96

=

197.0607974 "sphere-surface"

as is not 198.9974874 Sh~~l preceding, and neither is 197.0607974 4 x the surface of 2xJ.96 "circled" since 4 x 49.5

=

198 hence

both these "equations" of E,resent-daY textbooks are imprecise. Your present-day textbooks further state that ARCHIMEDES( 287 b c,
i

212

) made 100% ADISCOVERE(

"discovery" ) concerning the LEVER & 'root' data pertinent the "cylinder"

GRAVITAS(

"gravity" ) principles and that ARCHIMEDES is also thus

credited to have found the 5

and "sphere" via the following to ARCHIMEDES credit: "The AREA( 25 ) of a sphere-surface equals the AREA( 25 ) circumscribed by a cylinder-arc while the sphere-volume 2 /

=

J the cylinder-vo 1 ume as = 6£r~". Not e that the PERIPHERE

=

25 for both as have 3.96 Radius constant.

167

Above

=

"RIGHT" KYLINDROS and "RIGHT" SPHER x .E showing that both

have 25( AREA )of 100% PERIPHERE and 3.96 Radius-constant for the ARCHIMEDES SPHERE.

r"25 -j-1.25 -j-1.25 -j-1.25 --j
T

6.25

I­

25

Above shown are 20 EQUAL-TRIANGLES of 1.25 base-width x 6.25 "height" from base-to-apex noting that 6.25 via "equation" BH.5 ( ~ase x !:!eight x.5

=

25% "circle" 25 and

) each such TRIANGLE

=

3.90625 SURFACE portion wh i c h x 20 TRIANGLES = 78.125 SPHER x .E 2 Surfase wherein the full BALL would have 12.5 or 156.25 Surface. The erroneous 198 "BALL SURFACE" sho"TI on the preceding page actually

=

a "CYLINDER-ARC-SG"RFACE" of 7.92 x 25

=

198 value.

Via the simple accurate arithmetic shown above the SPHER x .E drawing illustration of 20
equal-tria~gles

which when

having its 20 APEX points brought-together and the 25 line of the 20 BASELINES brought-into-a-circle will find the SPHER( 66 ) x .E( .5 )

=

33 uni t-volume ratio wh i c h x

APEX-POLAR to ECQUATOR Constant-Radius 3.96

=

130.68

"CUBIC-VOLUME" 100% STANDARDS of ARCHU1EDES and the 100% GRETCIRCLE shown via such "SECTION" = 49.5 Surface 2 2 / .3168 statement. which = 3.12Q x 3.96 or = 3.96

168

ARCHIMEDES SPHERE will find its AREA( ( r2 ratio)

25 )

100% PERIPHERE x .J168

=

2xJ.96 100~ DIAMETTRIA of such "SPHERE".

ARCHIMEDES

PYRA~IDOC

above shown uses also J.96 Radius-constant as
J6~(,

the "RIGHT-PYRAMID" as has a "CUBIC-VOLUT\I.E" equal to 6J. ShO,,'Tl next to the ARCHIMEDES FYRAMIDOC form,

the

lJo.68 shown for the "RIGHT-SPHERE" of ARCHIMEDES SPHER x .E unit thus this "pyramid" as 82.798848 / r2 has 82. 798848 "Cubi c- Vo 1 ume" wh i ch x 2¢ ra tio 0 l' J. 12.§. w l Ll find 261 • J6 "cubi c-vo 1 ume" of the "RIGHT-BALL" jus t ratio of' .J168 will find 261.J6 "c ub e d-i vo Lum o " of "RIGHT-SPHERE". RJ / .75

=

"PYRAMID'S Volume-Cubic"

, ie:

J. 96 J /

.75 = 82.798848

"cubed~'

0 f' ARCHIMEDES 100% = PYRAMIDOC. magnitude of

ARCHIMEDES SPHER x .E at OUR-EARTH

~CCLECS-PLA~ET

J.96 Thousand MILE STATUTE constant-Radius when computed for its volume-content in terms of the H 0 Constant 18 atomic-weight at 7.2 0 2 Hydrograde THER'1E constant for such arithmetic-model would c<Jntain h J3 INCH J and this = JJ BILLION x BILLION x MILLION I~CHJ cont~nt c as also = lJo.68 MILE-STATUTE J volume-content of' Mass/!\latter( Space ). "PYRAMID VOLUME" 2R J / 6

=

Volume

The above "equations" are t ho s e of' t.o d a y s c-c o n v e n t.Lo n for the form of a "pyramid" , ie: when using J.96 2 2xJ.96 = 7.92 & 7.92 x J.96 & 7.92 J = 496.79J088 which / 6

= R-constant,

then: J

= =

248.J96544 which /

=

82.798848

82.7988·'-1-8 "pyramid-volume".

169

ADIMENCIOKAL 3.96 = R & r = .1584 RATIO CONSTANT

4 = R2 R

=

190.08%

3.96
=

2

x

4

x

3.96

=

248.396 544 "cubic"

3.96 3 /
=

( .1584

x

2 )

=

196.02 "cubic"

=

R~r3 = 100%
63.36%

=

3.9 6 3 / ( .1584 x 3 ) 130.68 "cubic"

=

=

3.96 3 / • ~ = (5 82.798 848 "cubic"

=

65.J4 "cubic"

+
+
R~r2
37.8%

=

62.7264 "plane"

'I

=

=

=

3.96"- / 49.5

( • 1584
"plane"

x

2

=

170

ADI~ffiNCIONAL

3.96

=

R &
r

=
.1584
RATIO
A

CONSTANT

A

L
A

J

31.68
PERIPHERE

I

A-A
30.42 PERIPHERE

A

L

+

.~

25 PERIPHERE

A-A
23.76 PERIPHERE

I

20.42 PERIPHERE

A

L

B

x

J

A

3 1.68
PERIPHERE 25 PERIPHERE

B

1,---­
A

+

~

31 .68
19.17 PERIPHERE

PERIPHERE

L
25 PERIPHERE 19.17 PERIPHERE

171

ADIMENCIONAL J.96

=

R & r -

.1584 RATIO CONSTANT for both the PYRAMIDOC and

25(

100% PERIPHERE ) = SECTION

A·A

SPHER x .E as shown on the preceding-page and both have3.96 for 100% ADIMENCIONAL Radius-constant representing r ratio-of-radius of 100% DIAMETTRIA R2 or r2 constant. This attends: A+L+L( 25 ) x N+A+T+U+R( 7+4 = 1+1 = 2 ) / ALL NATURE = 100% = ACOSMOLOG JJ .E( .5 ) = 10010

=

ACOSMOLOGE(

1+0+5

=

J+J )

( "A Cos mol 0 gy " )

R/r
3.96

= 100% GRETCIRCLE 25

J.96/ .1584

=

25

100% PERIPHERE 100% GRETCIRCLE ,

The 7 f o rrn s shown in the preceding 2-pages h a v e 100% STA:':DARDS w i, t. h
=

R

constant 1 005~

ADIME~CIONAL

and hi t h

.1584 =

r

c on s t a n t ,

Of the R-4R form preceding its minus( A-A.
) 6.66

?

'section' A-A

=

30.42 PERIPHERE

10o~c

=

23.76 PERIPHERE 100% of the R J/r2
form 'section'

66.6°H 66x6 =

HYDROGRADE( H symbol ) = HEALTHY-I-IL"!vIA.l'\ Therme value CHEOPS ( 66 ) x GRETPYRAMID( GREATPYRAMID 1+ 3+2 = 6 ) 1 & 33 )

*

= =

100% + 33% and thus:

CHEOPS ( 66 ) + GREATPYRAMID(

=

1 000~

66)(6= 396 =

THE ( 3+3

6 ) x METRIA ( 66 ) = "the meter"

*

H 0 = 18 Atomic-Weight which x 10 = 180 0H of its "BOIL-FREEZE" 2 Range of such calibration which x 37%( 37° = Centigrade = Celsius, Anders 1701-1744 A.D. Astronomer - Inventor of Sverige ) will find 66.6 0H which + 32°F( Gabriel Daniel Fahrenheit 1686-1736 A.D. ­ German physicist) will find 98.6°F as = 37°C as = 66.6 0H shown for ALL Healthy-humans "temperature"

172

ALL

FORH

Via ADIMENCIOXAL 3.96 ALL the
follo~ing,

=R

& r

=

.1584 RATIO COKSTAXT you can compute
fe~

~hich

are some

of ALL, 1+1 )

~ith

fe~-digit

form of

E+Q+U+A+C( 4+7 ALETTERS "angle"
ANKLYOS AREA ARK ASQl'ARRE ARK BALL "circle" "cone" "cube" "cylinder" CURVE DEGREE DEXSITY DEPTH DIMENCIOK ELEKTRON ENERGIA

=

1+1 ) / I+O+X( 3+8 FORCE FORM GEOID GLOBE GRAVITAS HEIGHT INERTIA
KI~E~lA

=

=

100% ADIMEXCIOXAL: RADIes
RANGE RATE RATIO ROUXD RYylE SCOPE SECOND SEGl'IL\T SPACE SPHERE "square" SURFACE THIE TRIANGLE VELOCITY UNIT VOLUME WEIGHT

"measures" MESGHES "meter" NETRIA METRO:" :vII Nl'TE ivl0CIO:,\ "motion" Xl"HMBERS OPTICS "physics" PHI SIKES PLANE POIXT PORTIOK POWER QUANTA QUAXTl'-'}·l

KIRKOS KONOS KYBOS KYLINDROS
LAS GUAGE

LENGTH LEVEL LIGHT LINE MASS MATTER 1.5782 ratio

0r

= "FIRE" = ¢(

and ¢r

=

x .15 8 4( r ratio) = .25 = ALL certainly applies to 100% = A+T+I+M+E+P+L+A+N+E+D.

.all

173

Trieplane = 100%

1

2

3
DRAWI~G

4
til

rotated 180 0 about vertical axis

= =

DRAWING rr2

DRAWlKG f2 rotated

90 0 about horizontal axis

= DRAWING
DRAWING #~

#1

DRAWING #3 rotated 180 0 about vertical axis

CONSTRUCT A TRIPOD

w i,

th LEG-LEKGTH of 3.96 1 001~ ADITvIENCIOt\AL from

APEX of its 3 Leg-Joint to APEX of each LEG-FOOT and place each 2 LEG-POINTS at 2 x 2.8125 100% ADIMENCIONAL distance-apart as equals 3x3 x 5+5 0 RIGHT-ANGLE for each pair off the 3 Leg-Joint APEX. In this mode your tripod describes 3--EQ~AL RIGHT-TRIANGLES totalling
2 c 2.8125 x 11.88 units Surface noting that 11.88 INCH / SECOND =
The Mean "LIGHT-VIBRATION RATE" of 1 4.4 a tomi c-i\'eight AIR Standards.
ROTATE your TRIPOD 120 0 about its vertical AXIS and its Leg-Points

2

will circumscribe a 360 0 ARC that contains precisely 33 "square" ( Surface-units 100 ADIHENCIONAL and such "circle" will reveal a
Radius of the following SISE( "size" ):

)

~33 x .3168 = 3.233 326 46 Radius-value

174

100%

= T+R+I+E+P+L+A+N+E =

the form when you place your TRIPOD on

the Surface-ARC of a 3.96 Radius-constant RIGHT-SPHERE wherein the ARC 100% ADIMENCIONAL between your 2 LEG-POINTS now equals 6.25 as

=

25% 25 100% PERIPHERE of that RIGHT-SPHERE although these 3 LEG­

POINTS will circumscribe the Radius of ~33 x .3168 which via 2 2 the R / r2 'equation' format will find the 33 Surface units of such PLANE-CIRCLE taken from the RIGHT-SPHERE, ie: ( 433 x .3168 )2 / .3168

=

33 "Chord-Surface of Sphere-Seg­ ment" so described.

2

X

( ~ 133 ~

x

.3168 )2 /

r8

=

33 since r 8 = 1.2 6 72 as = .3168 100% 2 hence 2R /
DIA~ITTTRIA

I 4

x

ratio

"circle­ 2 surface" equal to R / r2

r8

=

While these 3

"PLANE-S~"'RFACES"

of the 100% TRIEPLANE are found in remaining­

the 100% ASQUARRE display with 100% GRETCIRCLE removed --- see the 100% ASQUARRE illustration again to see these 3 + 1 and having 6.25 ARC connecting its 2 LEG-POINTS. Nonetheless, this 100% TRIEPLANE describes via its 120 0 rotation a Surface-units having 3.96 100% ADIMENCIOKAL "sides" at 90 0 A..1\,JGLE

RIGHT-SPHERE segment of' the following 100% ADIMENCIONAL values: 2 x 33

.ii....I 33

x

.3 168

= 100% DIA..4ETTRIA of its "Chord" = "SlJRFACE of' chord-circle"

= AXIS
=
20.412 414 52 Therefore
ri

of "sphere segment" sphere-center point.

SURFACE-ARC via its 109 0 ANGLE off 100% PERIPHERE of its "chord" ) for the

=

o w see 100% = K+A+L+C+U+L+U+S ( "calculus"

"EI-CONVEX" form comprised of 2 "RIGHT-SPHERE" segments placed together at their "SURFACE of CHORD CIRCLES" wherein we will n o w use KALCULUS to determine the "cubic-content" of that "EI-CONVEX" form starting out with the 100% ASQUARRE concept of the 3.96 Radius-constant 100% ADIMENCIONAL.

175

3+3 x

100% ASQGARRE

+

3+3 x 100% ASQFARRE "FACE" units placed 90° to each other's edges contact will find that such 3+3 FACES bring ALL their 24 EDGES into con tac t f o rms a "CUBE" ( 7.92 3 ) w i, th 8 "CORr\ERS". Then 0 f tha t f o rm "CUBE" remove the 7.92 100% DIAHETTRIA portions of the SPHER( 66 ) x .E(

.5 ) pair and the above

"RE~1AINDER" are

the portions Elevation­ 4

Vi ew of the "PLANE-StTRFACES" ( 4 ) showing of the 100% TRIEPL.A..l\E of that "SIDE-of-CUBE" wi th "SPHERE" remoyed wh i c h appears as the 100% ASQUARRE Surface-unit. Any 3 of the 100% ASQUARRE corner-planes, wh e n 100% GRETCIRCLE is removed leaving these corner-planes, wh e n placed-together along their 3+3 edges from their Corner-APEX to LEG-APEX forms the TRIEPLful\E 100% when that form is stood upon the surface of the RIGHT-SPHERE having 100% GRETCIRCLE of 25 100% PERIPHERE of its 3.96 Radius-constant 100% ADIMENCIONAL. We now will describe a SPHERE SEGHENT having "chord" R2 of 2 x 2.8125 as is somewhat uses a KYLINDROS( 'different' than the "chord" R2 s ho wn for the 100% TRIEPLANE indiced SPHERE SEGHENT. To do this our model "cylinder" ) with 100% GRETCIRCLE via the 3.96 Radius-constant and 25 100% PERIPHERE and place within it a "square" of 7.92 "diagonal" and 5.625 "sides" 100% ADIHENCIONAL as shown on the following-page.

176

>~I

The above "EI-CONVEX" f'orm is the product of' 2 RIGHT-SPHERE SEG­ MENTS taken f'rom the 1.1475 AXIS-of'-segment and 2.8125 Radius-of'­ segment having 17.75568182 or 1 / .05632 100% PERIPHERE and 6.25 Surf'ace ARC f'or such 5.625 "chord" opposite. See f'irst the below s ho wn 100% GRETCIRCLE with "minor-square" of' 7.92 "diagonal" and showing its 4 corners tangent with the ARC of' the "circled" 3.96 Radius-constant.

.. --1
2. S 12 5

r-­

B.HABE

The above is PLAN-VIEW

¥

= 1. 14 7 5

LEFT

= ELLEIPSIS-VIEW

177

Note	 that in the KrLINDROS view we show the ELLEIPSIS view with a

5.625

2

end-rectangle 7.92 long and the 7.92 100% DIAMETTRIA form of
"PLAc~-VIEW"

RIGHT-SPHERE overlain within such KYLINDROS form wherein the above "MINOR-SQUARE" wi thin the "CIRCLE" is in reali ty the our KYLINDROS end-face. 5.625 x 7.92 = 250.59375 "volume-cubic" of this RECTAcT\JGLE form and 3 x 1.408= 250.59375 "volume-cubic" of such RECTA-T\JGLE form as 5.625 2 of

has 4 lines of 7.92 length TAXGENT with the KYLINDROS vertical­ circled-wall and such RECTAKGLE is with 3+3 "POINT" Tangent contact with the RIGHT-SPHERE of that composite-drawing ie: each END of the RECTANGLE has its Center-point tangent with the RIGHT-SPHERE ARC while at the length-midpoint each Corner-Edge of the RECTANGLE is Tangent with the ARC of the RIGHT-SPHERE as a "POINT" contact and 4 such "POINTS" of the RECTA.:\JGLES-CORKER-EDGES and 2 of its MINOR-SQUARE ENDS = 3+3 such interface-points. 2+2 SPHERE-SEGMENTS thus project past the PLANE-SIDES of the form RECTANGLE so superimposed within the KYLINDROS Volume = 392.04
KrLI~DROS,

and: = of
392.0~

KnI~DROS

Volume

-RECTANGLE Volume of 250.59375 = "DIFFERENTIAL" 141.44625
= 130.68

1~1.44625

-

SPHERE Volume

261.36 130.68

= "DIFFERENTIAL"

10.76625 =	 Volume of 2+2 SPHERE-SEGMENTS representing
SPHFRE-VOLL~E

261.36 /

24.275 862 07, hence

2 SPHERE-SEGMENTS times 48.551 724 14 equals SPHERE-VOLUME. 100% ALOWING your SPHERE-SEGMENT "chord" to "grow" from 2 x 2.8125 to 2 x 2.821 460 312 will increase the former SPHERE-SEGMENT "cube" volume to 2.7225 from the prior 2.6915625 hence 2 x 2.7225 = 5.445 "EI-CONVEX" form volwne which x 48 = 261.36 SPHERE-VOLUME via such 48-to-1 ratio. Therefore via such "growth" to "chord" value of 5.642 920 624	 instead of the former 5.625 value such 'growth" of

178

"CHORD" reveals that "CHORD" R2 100% ADIMENCIONAL when "CUBED"( } will find such 2R} = 179.685 which / volume which }} = 5.445 "BI-CONVEX" form

=

1 /

48th RIGHT-SPHERE Volume-Cubic of 261.}6 and
2R} / }}

=

Volume

CHORD} /

}} = Volume

Thus for the "BI-CONVEX" 100% KALClJLUS without changing the }.96 Radius-constant of the 100% GRETCIRCLE of RIGHT-SPHERE we have readily determined via simple mathematic 100% PROCEDUR / E = 2+0
1+1

=

steps-arithmetic we first determined that the KILINDROS has

} x the HE~ISPHERIUM Volume of 1}0.68 units} and then by 'steps' reduced the data to a "DIFFERENTIAL" shown for the 4 SPHERE-SEGMENTS portions protruding past the RECTANGLES "SIDE-PLANES of 5.625 x 7.92 2 value of 44.55 units per "side" and via the "growth-extrapolation" used .1 x 44.55 to find 4.455 to which we add( + ) .99 to find the 5.445 "cubic-value" of the 2 "grown-segments" via having increased its "chord" by a small-value-precisely. ie: 5.}9} 288 }52 EMPIRICALLY = 5.625} 5.445 5.}8} 125 PRECISELY 100% TREOW

/ /

}} = "Chord"}/}}

= 5.642920624}= "Chord"}/}} = 5.625} 3}.062}0407
1009~

Now it is very simple to convert the 5.445

ADIMENCIONAL "cube"

value of the "BI-CONVEX" form into whatever magnitude you might require --- ie: 5.445 x 1728( "inch}" per foot} ) = 9408.96 Inch} or perhaps: 5.445 "cubic-yards" as = 27( "foot J " per Yard J ) = 147.015 Foot 3 which x 1728 = 254041,92 Inch} per 5.445 "cubic-yards". When your "BI-CONVEX·" form .be related to DISPLACEMENT-VOLUlvm of a specific Mass/Matter( Space) unit-order of Atomic-Weight such as H 0 at 18aw you can as readily determine that when your BI-CONVEX 2 form represents 5.445 "cubic-foot" then 5.445 x 62.5 POUNDS AVOIR­ DUPOIS would find its 340.3125 "POUND" di s p L c ern eri t-weight of H 0 2 and when your BI-CONVEX form weighs less than }40.}125 it would LEVITATE in H 0 until part of it projected into AIR( 14.4aw ) and 2 the balance in H 0 ( 18aw ) to such ARITHMETIC-DEGREE of Volume. 2

179

ATLANTIS = PLANET

The above view is when "LOOKING UP" 100% TOWARD "O"lJR-EARTH" Planet directly inline with "SLNLIGHT-AXIS" intersection o:f ECQUATOR
100;:~

at QUITO, ECUADOR o:f South America. In this view you see NO-SHADOW since the "NIGHT-TERMINATOR" LINE is the "CIRCLE o:f the DRAWING" and the N-S AXIS 1 00% DIA~1ETTRIA Celestial-Vertical 100%
1007~ STANDARDS

= 7893.6 I'-Iil e S ta tu t e wh LI e the
7920 Mile Statute Khich :for this

ST~\DARDS=

view gives the PLAXET 7906.8 MEAN R2. The celesTial-vertical 25000 100% PERIPHERE _- while the "POLAR-RADIUS" would show a "KIGHT TERlvlINATOR CIRCLE" o:f .44 Million-Foot shorter-arc while the N-S Radius is shorter by 69696 FOOT when compared to the celestial-vertical 100% STANDARDS. A 6250 I'-lile Statute SlJNLIGHT­ AXIS "Prec es s ion-Westerly" about the 1005f EC QUATOR woul d PLANET as the center-one shown below wherein the INATOR CIRCLE which in this view intersects
I

s ho v The

SHADOW-o:f-~IGHT

is now Celestially-Upward with the N-S AXIS being the NIGHT-TERM­
QU~TO,

ECUADOR o:f

South America at the 100% ECQUATOR o:f Celestial-Vertical.

The 1° /

.02112 = "TORRID ZONE" o:f 2 "TROPIC-ZONES" which are 3168

t

Mile Statute parallel distant one :from the other as also then equals 1584 Mile Statute parallel o:f 100% ECQUATOR and 1 "TROPIC-ZONE" as sho"TI above in the Le:ft-hand and Right-hand vieKs o:f the planet.

180

ARK-of-NOAH
=

OUR EARTH SHIP

UP

~

f DOWN

"NIGHT" SHADOW
is UPPER-SIDE.

EARTH-PLANET in 100% ELEKTRON.

DOWN

t

A SINGLE PHENOMENON is depicted in the both above illustrations of Our-Earth Nucleus-Planet enveloped within some of its many-layers of 100% INVISIBLE 100% ELEKTRON( "electron" ) with its ILUJMINATED FACE aimed-downward toward the UP-COMING "SUNLIGHT" VIBRATIONS. The Right-Hand drawing shows EARTH PLANET

=

ATLANTIS in ORBIT

away from your line-of-sight axis-level at QUITO, ECUADOR and the "PICTURE" is when the NUCLEUS of that Earth ELEKTRON is "STOPPED" by your "EXPOSURE" with its radian-line at Sea Level intersecting the Quito site on the ECQVATOR. The Left-Hand illustration is of the "ELECTROMAGNETIC-LAYERS" termed the "AURORA-BOREALIS" or the "NORTHERN-LIGHTS" layers while the Right-Hand illustration is of "VAN ALLEN RADIATION-BELT LAYERS". Consult Page #243 Readers Digest 1972	 MARVELS & MYSTERIES OF THE WORLD AROUND US showing the "Van Allen Belt Layerings". SMITHSONIAN MAGAZINE February 1977 s ho ws the "AURORA BOREALIS" 'electromagnetic-layers'.

181

"REVERSAL OF MAGNETIC-FLUX" of each-layer takes-place during The Roll of our A+T+L+A+N+T+I+S( 96 ) = P+L+A+N+E( 48 ) x T( 2+0

=2

) 360 0

since the "FIELD-LAYERS I' make a transi tion between 100% EXPH.A.l\DING as a relative 'stretch' away from the "polar-regions" to their uppermost position of "expanded-movement" before condensing back to their most-reduced volume state of molecular-order as the FLUX "REVERSAL" effect in moving back to that condensed-norm position. This "FIELD LAYERING" is 'tied-to-the-nucleus' as also exhibits its "ROLL" and "contraction & expansion".
, tv When "SlJNLIGHT-AXIS" is at the Northermost position aligned with

the intersection of the 1 0

/

.04224 "TROPIC-ZONE" we call CA1"JCER h

"

see the Left-Hand drawing of ATLANTIS-PLANET preceding ), or wh on "SLTNLIGHT-AXIS" is at the Southernmost position aligned w i the 1
0 /

t

.04224 "TROPIC-ZONE" we call CAPRICORN ( see the Right­

Hand drawing of ATLANTIS-PLANET preceding) --- the Lo w e r-c d eri s L ty 100% ELEKTRON layers are still upward of the planet-crustal sphere though 'canted' to the Left or the Right for its vertical-axis which axis aims to",ard the HOST SYSTEM "NUCLEUS" about "'hich ",e ORBIT off a mean radian-length of 937.5 Billion MILE STATUTE just as THE LUNAR "Moon" crustal-orb show'S a mean radian elevation of 247.5 Thousand MILE STATUTE off Our-Earth Nucleus-point. Each exhibits relative "NEUTRAL SPECIFIC GRAVITY" as

=

"NEUTRAL SPECIFIC

DENSITY" hence each 100% ELEKTRON and its ~~CLEUS planet-orb holds its MEAN orbit elevation off its HOST-SYSTEM nucleus-point, as it rolls / moves generally about the 100% ECQUATOR celestial of the HOST SYSTEM. In the event you could cause Earth-Planet from H 0 level-do~l",ard 2 of its Sea Level to show a consistent-radius of 3960 Mile Statute 26 its volume would be 261.36 Billion "miles,,3 as 6.6 Billion

=

"cubic-miles" volume, yet 12500

x its 100% DIAMETTRIA of planet

=

its 100% ELEKTRON Celestial-vertical

100% ADIMENCIONAL mean while

its "POLAR-AXIS" of such 100% ELEKTRON is relative very much 'reduced' in comparison to its celestial-magnitude of such radian. See 100% INTELLECT book of this Author concerning such 'Astro­ physics' and 'electromagnetics', etc.

182

```
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