NMR Spectroscopy Nuclear Magnetic Resonance Spectroscopy

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NMR Spectroscopy Nuclear Magnetic Resonance Spectroscopy Powered By Docstoc
					   Nuclear Magnetic Resonance
          Spectroscopy
                                         O
                                             CH 2 CH 3
                                     CH 2




    7       6      5      4      3      2        1       0
                         PPM
A proton NMR spectrum. Information from peaks:
Signal…
Lines…
Multiplicity…
  How does NMR it work?

Nuclei behave as if they spin…
                       Nuclear spin is quantized and
                       described by the quantum no. I,
                       where I = 0, 1/2, 1, 3/2, 2, ….

               Spin 1/2 nuclei: 1H (proton), 13C, 19F, 31P
               Spin 0 nuclei: 12C, 16O
               Spin 1 nuclei: 14N, 2H
               Spin 5/2: 17O
               Spin 3: 10B
In a given sample of a compound in solution, spins are random
and their fields…

In the presence of an externally applied magnetic field (Ho), a
nucleus will adopt 2I + 1 orientations with differing energies.

For the proton, there are two “spin states”.




                           +1 / 2          -1 / 2
                  Ho
Zeeman splitting
                                                      -1 / 2




                                         ² E = h
             E




                 Ho
                                                      +1 / 2

Important:

The relative number of nuclei in the different spin states
(proton, 60 MHz) is:        N            E
                                                    1,000,000
                                        e        
                                upper        kT

                             N lower                1,000,009
           h            The magnetogyric ratio, , is a physical
 E  h     Ho         constant for each nucleus.
           2               1H     267.53 radians/Tesla*
     
     Ho                   2H     41.1
    2                      13C    67.28
                            19F    251.7
                            31P    108.3
So ∆E depends on…                  * 1 Tesla = 10,000 Gauss.



Resonance occurs when…
For the proton nucleus:      Ho              
                            14.10 kG        60 MHz
                           58.74 kG         250 MHz
                         117,500 kG         500 MHz


 But…
       the actual resonance frequency for a given nucleus
 depends on its…



  i.e. magnetic interactions within the molecule.
These local magnetic effects are due to:

          •  electrons
          • electrons
          • other nuclei - especially protons

   electrons                        In the locale of the proton,
                                     the field lines are opposed
                                     to the applied magnetic
                   H                 field. This has the effect
                                     of “shielding” the proton
                                     from the full Ho.

                   C                             He
 Ho
Chemical shielding has the effect of moving signals to the
right on an NMR spectrum. We refer to this as…




       7       6       5       4       3       2       1     0
                              PPM
                The magnitude of He is proportional to the electron
                density in the s bond.
      He


                Consider…
Ho
                                CH 3                 CH 3

     H3 C   O     CH 3   H3 C   C      CH 3   H3 C   Si     CH 3

                                CH 3                 CH 3

                                              Tetramethylsilane
                                              aka TMS
Because almost all proton resonance frequencies are found
downfield of the TMS signal, TMS is used as an internal
reference. All peak positions are measured as frequencies in Hz
downfield of TMS, with TMS at zero.

 There is a problem however..
                                   is proportional to Ho

 Ho = 60 MHz,  = 162 Hz downfield of TMS
 Ho = 100 MHz,  = 270 Hz downfield of TMS
Solution to this problem…

We define the δ scale:

                   signal downfie ld of TMS
                                              ppm
      spectrometer frequency in MHz
Chemical shift correlates well with electronegativity…

           H3 C            X
      F       O            Cl      Br        I        H      TMS
EN    4.0     3.5          3.1     2.8       2.5      2.1    1.8
ppm 4.26    3.40         3.05    2.68      2.16     0.23   0

 CHCl 3      CH 2 Cl 2         CH 3 Cl
 7 .2 7      5 .3 0            3 .0 5

 CH 2 Br        CH2 CH 2 Br             CH2 CH 2 CH 2 Br     CH2 CH 2 CH 3
 3 .3 0           1 .6 9                    1 .2 5              1 .2 0
     
      Electron Effects - Diamagnetic Anisotropy
     Alkenes…
                                                                              1.96
                                        5.70               4.97
                                            H          H               1.65            5.59



                                                                       1.65            5.59
                 e                     H3 C            H
                                     1.71                  5.03               1.96


      H                      H
                                                1.90
             C       C
                                        1.90               4.60
      H                      H

                                        4.00               6.40
                                                O

                                                                  O
                                                6.05
                                                       H
Ho    Vinyl protons are downfield,                                     OCH 3         3.76

      4.5 - 6 ppm.
                                                5.80
                                                       H          H   6.43
Aldehydes
                                                    O             7.45   7.81
                                                                                O
                                         H3 C   C
       e                                                   7.54
                                  2.20
                                                    H
                                                    9.72                        H
                                                                  7.45   7.81   9.87
R
      C     O
H
                                                    Alkynes
                                                                    H


                                                              e
                                                                    C
                1.80   H3 C   C    C      H 1.82

                                                                    C
                       7.26

               7.26             7.26



               7.26             7.26
       e
                       7.26
H3 C       H



                         2.35



                7.06              7.06



                7.14              7.14

                         7.07
X-ray Structure of
     the 3C
 Naphthodifuran
   Cyclophane
Chemical shift equivalence
          … of atoms or groups.

 Groups or nuclei are shift equivalent if they can be
 exchanged by a bond rotation without changing the structure
 of the molecule.

      H       H              H3 C       CH 3
               H                         CH 3
          C                         C



 These atoms/groups are said to be “homotopic”.
 Homotopic atoms/groups are always shift equivalent.
Shift equivalence can also be determined by symmetry properties
of the molecule.
 A proper axis of rotation…

H3 C       CH 3                           CH 3          CH 3
                                                 CH 3
       C

       C
   H       H                              H             H
                                                 H
Atoms/groups that can be reflected in an internal mirror plane
of symmetry, but not exchanged by bond rotation or a proper
axis of symmetry are “enantiotopic”.

                       O
    O                  C                              H
    C              H       H            H2
           H                                          C
                                        C         H        H
                                 H3 C
           H                                 Cl
                                                      C
                                                  H        H
                   H       H
                                                      Cl
 For our current purposes, enantiotopic protons are always shift
 equivalent.
It is easy to recognize atoms/groups that are constitutionally
different.

    O
                        CH 3
           H                              H       H       H H
    C
                H
                                              C               C
                                     HO               C           H
         CH 2
    C                                             H       H
    H2
    Protons that are not constitutionally different, that cannot
    be exchanged by bond rotation or by molecular
    symmetry are “diastereotopic”.
H                Cl                                           CH 3
         H                                                           H
                                                  H3 C
                                                                  CH 3
H                H         H       H   H H
         H                                               H   Cl
                               C        C
                      Cl                     Cl
                                   H   Cl


    Diastereotopic atoms/groups are NOT shift equivalent,
    except by coincidence (i.e. they happen to have the same
    chemical shift by accident).
                                              O
                                                      CH 2 CH 3
                                           CH 2




       7       6       5          4    3          2        1      0
                                 PPM


Raw integrals: 8.5:3.5:3.4:5.0
 Other nuclei - spin-spin coupling

 Consider the vicinal protons in the molecule:
      HA      HM        In the absence of any influence by HM,
          C   C         HA will resonate at A.
Cl                 Br
     Cl       Br
But proton HM generates its own magnetic field which will affect
A. Is this field aligned with Ho or against Ho i.e. will it shield or
deshield HA?
 Remember that the population of the two spin states are
 nearly equal. In the total of all molecules, half of the HM
 protons will be aligned with Ho and half against.
 So in half the molecules, HM shields HA and in half HM deshields
 HA. We therefore see two peaks for HA, of equal intensity; one
 upfield of A and one downfield of A.               vA


 We call this type of signal a … “doublet”.
 We say that HA is “split” into a doublet by HM.

This effect is referred to as … “spin-spin”
coupling.                                              J AM



The distance between the two peaks in
Hz is J, the coupling constant.
Important aspects of coupling:
  • coupling always goes both ways. If HA is split by HM,
  then HM must also be split by HA and J must be equal in
  both cases.
  • coupling is a through-bond and not a through-space
  effect.
 • coupling between shift-equivalent nuclei is not observed.
A few words about J.
 The magnitude of J can be extremely useful in
 determining structure. It depends on:

 • number of bonds between nuclei
 • type of bonds between nuclei
 • type of nuclei
 • conformation
Because coupling is a through bond effect, the magnitude of
J depends on the number of bonds between coupling nuclei.
One bond couplings are larger than two bond couplings, two
larger than three. In proton-proton couplings, four bond
couplings are not usually observed.


       Geminal                                              J4 = 0 Hz       Long range
                      J2 = 12-14 Hz



                      H   H H         H             H   H H             H

Vicinal
                 Cl                       Cl   Cl                           Cl
    J3 = 7 Hz*
                          H    Cl                       H       Cl

    * In conformationally averaged systems.
 Type of bonds…
-bonds transmit coupling effects more effectively than s bonds.

          H1              H1                  H1

                H2              H2                  H2



                H3              H3                  H3

          H4              H4                  H4



                      H         H


                      H         CH 3
The magnitude of vicinal couplings depends strongly on the
overlap between adjacent C-H bonds.

 H                   H                    HH

        C        C
                             H                      H
H                    Cl          Cl                H
    H                             H
    H                H Cl
                                              H
                                  Cl
         C       C
                                                       H
 H                               H
     H                   H                         H
                                          H
     H                   H Cl
                                               H
             C       C            Cl                   H

    H                                 H                H
        H                H
                                               H
 Consider the following molecule:             HA HX
                                    Cl        C   C    HY
                                         Cl       Cl

  The CH2 has one neighbouring proton in equal proportions of
  the up and down spin states. This resonance will therefore
  appear as a …
   And HA…
Possible spin combinations: HX HY
So HA will appear as a three line pattern: a triplet, with peak
intensities in a 1:2:1 ratio where the lines are separated by J Hz.
The central line will occur at the resonance frequency of HA.
NOTE: The SIGNAL INTEGRATION tells you about the
number of protons that give rise to a particular signal.
MULTIPLICITY tells you about the number of …

            NEIGHBOURING NUCLEI.

 The n + 1 rule: for simple aliphatic systems, the number
 of lines in a given signal is n+1 where n is the no. of
 neighbouring protons.
                                 O
                                 C
                  H 3 CH 2 C         Cl
  In this molecule, the CH3 protons will appear as a …
The CH2 protons have three neighbours.
The spin combinations are…

 Giving rise to a quartet with
 peak intensities of 1:3:3:1.
The combination of a 2 proton quartet and a three proton
triplet is characteristic of the presence of an ethyl group.




                     2                     1                   0
                               PPM
The isopropyl group.




                H       Cl
                    C
         H3 C           CH 3




            3                   2    1   0
                               PPM
The n-propyl group.   CH 3 CH 2 CH 2 Cl




             3         2       1          0
                      PPM
The t-butyl group.



                     H2
                     C          CH 3
                Cl        C
                     H3 C       CH 3




           3               2           1   0
                          PPM
Chemical exchange processes - protons attached to O and N.
(Alcohols, phenols, carboxylic acids, amines - but not amides)

Unlike most spectroscopic methods, the acquisition of signal
in NMR spectroscopy takes about three seconds (proton).

In that time, protons attached to O or N can be transferred
from one molecule to another via the autoionization
process…
                                                                    H
          O                   O                  O              O
   H3 C           H    H3 C       H    H3 C              H3 C           H
              H                                                     H
          O                   O               O                 O
  H3 C        H       H3 C        H   H3 C           H   H3 C       H

          O                   O              O                  O
 H3 C                 H3 C        H   H3 C        H      H3 C
                                                               H
       O              O                     O              O
H3 C       H   H3 C       H          H3 C           H3 C        H

If the rate of exchange is slow compared to the time scale of
the NMR experiment (I.e. three seconds) then the spectrum
is that expected of CH3OH. Under these conditions, vicinal
OH:CH coupling is observed. This is rarely the case.
If the rate of exchange is comparable to the NMR time scale,
then one observes the exchanging proton in a range of
environments and at a range of chemical shift postions.
                   HHHHH HH
                  H        H O
                O              CH 3
           H3 C
                            H
 Under these conditions, the OH peak is broad and
 coupling is not observed…
The rate of exchange is catalyzed by acids and bases,
depends on solvent, temperature, concentration, purity, and
lunar phase.
Exchangeable protons…
  • do not couple
  • have variable shift positions
  • are observed as broad peaks
  • exchange with D2O
  OH        Alcohols 1-5 ppm
            Phenols 3.5-6 ppm
            Carboxylic acids 10-12 ppm
            My personal record 13 ppm.
  NH (amines) 0.5 - 5 ppm
3    2    1   0
    PPM
2         1   0
    PPM
Occasionally, carboxylic acid protons resonances are so
broad …

..that the only way to tell that they are there is to integrate
the baseline.


D2O exchange…
    Exchangeable protons on a molecule will exchange
    with exchangeable protons on other molecules…

                    O                                         O
  D2 O                                 HOD             H3 C       D
             H3 C       H

  This can be very useful.
Coupling in non n+1 systems.

Substituted benzenes.


   1,4       These always appear as
             perfectly symmetrical     CN


    X        patterns that look like
             two doublets or a
             quartet.
                                       Br




    Y
Symmetrical 1,2 disubstituted benzenes

   These always appear as a perfectly symmetrical
   pattern with a lot of fine structure …



                                                    Cl
        X

                                                    Cl

        X
1,2,4- trisubstituted systems and the dreaded tree diagrams.

         CN

H6            H2


H5             Cl
        OH

J5,6 = 6 Hz
J2,6 = 2 Hz
J2,5 = 0 Hz
2        6


     5
Coupling in non n+1 systems.

Monosubstituted benzenes.

 X        If the substituent is an alkyl group or halogen,
          then all five protons tend to show up in the same
          place as either a singlet or a somewhat broad
          singlet.
If X is a strong electron-withdrawing group (carbonyl, nitro,
sulfonic acid) then the ortho and para protons will be pulled
downfield.



           X
If X is a strong electron-donating group (OH, OR, NH2)
then the ortho and para protons are pushed upfield.


  OH

				
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