# 2009-10-14_133156_Week_8_Math_Problems_solution

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```					Place each of the following sets in ascending order.

16. 3/7 - 6/7, 1/7, - 1/2, 2/7

Solution:

Make the same denominator for all

6/14, -12/14, 2/14, -7/14, 4/14

Now order them in ascending order
-12/14, -7/14, 2/14, 4/14, 6/14

Thus, given numbers in ascending order

-6/7, -1/2, 1/7, 2/7, 3/7

For each set, determine the maximum and minimum values.

Evaluate.

32. |4| + | -3| = 4 + 3 = 7

44. | -9 | - | - 4| = 9 – 4 = 5

40. 7 + (-9) + (-5) + 6

= 7 -9 -5 + 6

= -2 – 5 + 6

=-7+6

= -1

48. 1/3 + (-5/6) + (- ½)

= 1/3 – 5/6 – ½

= 2/6 – 5/6 – 3/6

= (2 -5 – 3)/6

= -6/6 = -1

Evaluate each of the following expressions.

58. |-27+14| = |-13| = 13

Label each of the following statements as true or false.
66. |-8| + |3| = | -8 +3|

|-8| + |3| = 8 + 3 = 11

| -8 +3| = |-5| = 5

Thus, it is FALSE.

72. Business and finance. Jean deposited a check for \$625, wrote two for \$68.74 and \$29.95 and used her
debit card to pay for a purchase of \$57.65. How has her account balance changed?
Solution:

= 625 – (68.74 + 29.95 + 57.65)

= 625 - 156.34

= \$468.66

Now account balance is \$468.66.

Subtract.

44. – ½ - (- 5/8)

= -1/2 + 5/8

= -4/8 + 5/8

= (-4 + 5)/8

= 1/8

48. – 3.4 – (-7.6)

= -3.4 + 7.6

= 4.2

54. Statistics. The lowest temperature ever recorded in the state of Oregon was -54°F (in Seneca, on February
10, 1933). The state’s record high temperature occurred in Pendleton on August 10, 1898, when it reached
119°F. What is the historical temperature range in the state of Oregon?

Solution:

Temperature range = 119 – (-54) = 119 + 54 = 173°F

Multiply

70. (-3)(-6) + (4)(-2)

= 18 – 8 = 10
80. (-3)3 – (- 8)(-2) = -27 – 16 = -43

82. (-6)2 -42 = 36 – 16 = 20

88. -92 – (-6)2 = -81 – 36 = -117

Perform the indicated operations

32. (-9)(5)/ -3 = -45/-3 = 15

Evaluate the following. Remember to use the order of operations.

16  ( 2)  ( 4)
58.                        = (-8*(-4))/(8 + 4) = 32/12 = 8/3
23  4

4  ( 3)  1
60.                 = (4 + 3 + 1)/(2 –(-1) = 8/(2 + 1) = 8/3
2  2  ( 2)

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