# Answers to Velocity Worksheet 3 1

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Answers to Velocity Worksheet 3 1 document sample

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12/15/2010
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```							                          Position, Velocity, and Acceleration Worksheet Answers

1. (a) v(t) = 3t2 – 6t + 2
a(t) = 6t – 6
v(0) = 2 v(2) = 2
a(0) - -6 a(2) = 6

s (2) − s (0)
(b) average velocity:                 =0
2−0
displacement: s(s) – s(0) = 0

2. (a)
−125 1875
v(t ) =      + 4
t2    t
250 7500
a (t ) = 3 − 5
t    t

v(1) = 1750       v(5) = -2
a(1) = -7250      a(5) = .4

s (5) − s (1)
(b) average velocity:                  = 130
5 −1
displacement: s(5) – s(1) = 520

3. (a) v(t) = 24 – 1.6t
a(t) = -1.6
(b) 15 seconds (when v(t) = 0)
(c) 180 meters (find s(15))
(d) 90 = 24t – 0.8t2
T = 4.3934 seconds
(e) 30 seconds (when s(t) – 0)

Q(10) − Q(0)
4. (a)               = −10, 000 cu gal/min
10 − 0
(b) v(t) = -400(30 – t)
V(10) = - 400 (20) = -8,000 cu gal/min

5. v(t) = 3t2 – 12t + 9
= 3(t2 – 4t + 3)
= 3(t – 1)(t – 3) = 0 when t = 1, 3

a(1) = -6        a(3) = 6

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