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Menghitung Load Flow & Losses Tegangan

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Menghitung Load Flow & Losses Tegangan Powered By Docstoc
					                                   DISTRIBUSI TENAGA LISTRIK
Dik :
                               1                                 2
                                           1,84+J3,68


                V1 = 1,05+J0                                         P2 = 400 MW
                                                                                    G
                                                                     V2 = 1,03+J0
                                                                     100 MVA


                           0.92+J2,76                   1,15+J2,3
                                   3
                                                 138,6 MW
                                                 45,2 MVAR
                                                 V3 = 1+J0




Dit:    a. Hitung Iterasi ke 2 pada bus 2 dan 3 dengan percepatan 1,06 !

        b. Hitung aliran daya !

        c. Hitung Loses Tegangan !

Jawab



ADMITANSI SALURAN




ADMITANSI OFF DIAGONAL




ADMITANSI DIAGONAL

Y                    (                 )     (               )

                     (                 )     (               )

                     (                 )     (               )
                        ( )                         ( )                          ( )                           ( )
                (             [                                                                                      ])

           *(               ),(                                ) (                         ) (                                    ) (                     ) (                          ) (         )-+

       *(                   ),(                                        ) (                          ) (                                           ) (                  )
                                  (                                      ) (                         )-+

       *                ,(                                         )         (                                       )       (                                   )-+

       *                ,(                                     )        (                                      )         (                                )- +

       *                (                                 )+

       *                (                                 )+

       (                                  )

       (                              )




                (                     )




ITERASI 1 PADA BUS 2

  ( )                                                                  ( )                          ( )
                    (             ( )
                                                   [                                                      ])


 ( )
                                          [(                           ), (                                          ) (                      )       (                          ) (         )-]


  ( )
                                               [(                                      )       ,(                                         )       (                              )-]

  ( )
                                              ,(                                     )         ,(                                     )       (                            )--
  ( )
                                              ,(                                 )         (                                     )-
  ( )
                                              (                              )
  ( )
                                              (                                   )
  ( )


  ( )
ITERASI 1 BUS 2 DENGAN METODE PERCEPATAN
  ( )       ( )                 ( )              ( )
                      ,                                -
  ( )
        (                 )                 ,(                                      )   (              )-
  ( )
        (                 )                 (                                   )
  ( )
        (                 )                 (                                  )
  ( )
        (                 )
  ( )
        (                 )        (                                   )
  ( )




ITERASI KE 1 PADA BUS 3

  ( )                                                      ( )                              ( )
              (           ( )
                                            [                                                     ])

  ( )
                                        (

                              ,(                                           ) (                     )   (                     ) (              )-)

  ( )                                                                                                            )       (               )-
                                   (                                   )           ,(

  ( )                                                                  )           ,(                       )
                                   [(                                                                                (             )-]
  ( )                              ,(                                  )            (                       )-
  ( )                              (                                   )
  ( )                              (                               )
  ( )


  ( )




ITERASI 1 BUS 3 DENGAN METODE PERCEPATAN
  ( )       ( )                 ( )              ( )
                      ,                                -
  ( )
        (         )                ,(                                  )            (         )-
  ( )
        (         )                ,(                                          )-
  ( )
        (         )                (                                       )
  ( )   (         )       (                                    )
  ( )   (         )       (                                )
  ( )
ITERASI KE 2 PADA BUS 2

  ( )                                                                              ( )                ( )
              (   ( )
                                                         [                                                  ])


 ( )
                             [(                      ), (                                        ) (                     )   (                      ) (   )-]


  ( )
                                  [(                             )           ,(                             )        (                        )-]

  ( )
                                 ,(                                  )        ,(                            )        (                   )--
  ( )
                                 ,(                              )        (                           )-
  ( )
                                 (                       )
  ( )
                                 (                           )
  ( )


  ( )




ITERASI 2 BUS 2 DENGAN METODE PERCEPATAN
  ( )       ( )          ( )               ( )
                  ,                              -
  ( )
        (                      )             ,(                               )      (                          )-
  ( )   (                      )             (                           )
  ( )   (                      )             (                                )
  ( )   (                      )       (                                 )
  ( )   (                      )       (                             )
  ( )




ITERASI KE 2 PADA BUS 3

  ( )                                                                              ( )                ( )
              (   ( )
                                                         [                                                  ])


  ( )
                                  (

                        ,(                               ) (                             )   (                               ) (          )-)

  ( )                                                                                                  )         (                       )-
                             (                           )           ,(

  ( )                                                )           ,(                              )
                             [(                                                                        (                           )-]
  ( )                        ,(                      )           (                               )-
  ( )                        (                       )
  ( )                        (                           )
  ( )


  ( )




ITERASI 2 PADA BUS 3 DENGAN METODE PERCEPATAN
  ( )       ( )         ( )           ( )
                   ,                        -
  ( )
        (                     )         ,(                   )       (         )-
  ( )   (                     )         (                    )
  ( )   (                     )         (                        )
  ( )   (                     )   (                      )
  ( )   (                     )   (                  )
  ( )




ALIRAN DAYA

Dari 1 ke 2 →     I12 = Y12 (V1(0) – V2(2))

                        =                       [(1.05 + j 0) – (                   )]

                        =                       (-5,437 - j 0,164)

                        =                       (5,439<1,73)

                        =

                        =

Dari 2 ke 1 →     I21   = Y21 (V2(2) – V1(0))

                        =                       [(                       )–(             )]

                        =                       (5,437 + j 0,164)

                        =                       (5,439<1,73)

                        =

                        =

Dari 2 ke 3 →     I23 = Y23 (V2(2) – V3(2))

                        =                       [(                       )–(                  )]

                        =                       (5,895 - j 0,094)

                        =                       (5,896 < -0,91)

                        =

                        =

Dari 3 ke 2 →     I32   = Y32 (V3(2) – V2(2))

                        =                       [(                       )–(                  )]
                        =                       (-5,895 + j 0,094)

                        =                       (5,896 < -0,91)

                        =

                        =

Dari 1 ke 3 →       I13 = Y13 (V1(0) – V3(2))

                        =                       [(1,05 + j 0) – (                             )]

                        =                       (0,458 -                   )

                        =                       (0,526 < -29,39)

                        =

                        =

Dari 3 ke 1 →   I31     = Y31 (V3(2) – V1(0))

                        =                       [(                             ) – (1,05 + j 0)]

                        =                       (-0,458 +                      )

                        =                       (0,526 < -29,39)

                        =

                        =



S12   = V2 . I21*       = (1,03 < 0) (                         )

                        =(                      )

                        = - 0,646 + j1,199

S21   = V1 . I12*       = (1,05 < 0) (                         )

                        =(                      )

                        = - 0,658 + j1,222

S23   = V2 . I23*       = (1,03 < 0) (                             )

                        =(                          )

                        = - 1,023 + j2,129

S32   = V3 . I32*       = (1,0 < 0) (                          )

                        =(                          )

                        = - 0,993 + j2,067

S13   = V1 . I13*       = (1,05 < 0) (                                 )

                        =(                          )

                        = 0,036 + j0,186

S31   = V3 . I31*       = (1,0 < 0) (                              )

                        =(                              ) = 0,034 + j0,177
POWER LOSES PADA LINE 1 KE 2

SL12   = S12 + S21

       = (- 0,646 + j1,199) + (- 0,658 + j1,222)

       = - 1,304 + j 2,421



POWER LOSES PADA LINE 1 KE 3

SL13   = S13 + S31

       = (0,036 + j0,186) + (0,034 + j0,177)

       = 0,07 + j0,363



POWER LOSES PADA LINE 2 KE 3

SL23   = S23 + S32

       = (- 1,023 + j2,129) + (- 0,993 + j2,067)

       = - 2,016 + j4,196

				
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posted:10/16/2010
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