# EMPLOYEE RETENTION AND MOTIVATION STUDY

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```					                  BACKGROUND
Employers must better understand
how to keep employees satisfied in
the newly emerging “not-so-loyal” work force. A
survey instrument was
formulated to meet
this objective.

Study objectives:
1. To identify and understand the correlation factors
2. To maximize or minimize these factors to
a) keep employees satisfied and motivated
b) minimize employee turnover
METHODOLOGY
OF APPROACH
FLOWCHART OF PHASES IN THE STUDY
GENERATIION
DATA
OF                       DISTRIBUTION
ANALYSIS
TOPIC:                          OF
USING
EMPLOYEE      CREATION/         SURVEY                               INTER-
GATHERING    MINITAB
SATISFACTION    EDITING        QUESTIONS                            PRETATION
OF
OF                                                   AND
SURVEY
SURVEY                                              INFERENCE
QUESTIONS
QUESTIONS                                                OF
RESULTS

REFORMULATE

Employee Satisfaction surveyed and analyzed as a tool to adjust
new programs, benefit packages, work environments,
management styles, etc to retain and keep employees satisfied.
Cumulative Distribution Function
Normal with mean = 5.83 and standard deviation = 2.229

Dissatisfied Employees
Normal, Mean=5.83, StDev=2.229
0.20

0.15
Density

0.10

0.05
0.2058

0.00
4.00    5.83
X

20.58% probability that an employee is dissatisfied with
his/her job (Satisfaction Rating less than 4 on scale of 10)
In our sample study we can say within 99% confidence that our
sample salary mean contains the population salary mean of
\$46,326 stated by the Bureau of Labor Statistics for 2005.
S a l a r y N o r ma l D i s tr i buti o n P l o t
M e a n= \$ 4 5 ,8 5 0 , S tDe v= \$ 1 2 ,3 1 0
0 .0 3 5
0 .9 9

0 .0 3 0

0 .0 2 5

0 .0 2 0
Density

0 .0 1 5

0 .0 1 0

0 .0 0 5

0 .0 0 0
\$ 4 1 ,0 3 0                              \$ 4 5 ,8 5 0              \$ 5 0 ,6 7 0
X

Hypothesis Test                               N Mean StDev SE Mean    99% CI        T                     P
47 45.85 12.31 1.79 (41.03, 50.67) -0.26                  0.793
HO: μ = 46,326
Ha: μ ≠ 46, 326
Salary Variance Distribution
Variance within \$10,000
Distribution Plot
Chi-Square, df=46

0.04

0.03
Density

0.02
0.846

0.01

0.00
\$36,326
X

This means our data sample does not contain
extremely variable data or extreme outliers.
Comparison of Two Means: A Female Glass Ceiling still exists

F e ma le V s M a le S a la r y
80

70

60
Salary

50

40

30

20
F e m a le                                     M a le

Female vs Male Salary
Two-sample T for Salary
N Mean StDev SE Mean            Difference = mu (FSalary) - mu (MSalary)
FSalary 23 43.3 11.1         2.3          Estimate for difference: -5.07
MSalary 24 48.3 13.1          2.7         95% CI for difference: (-12.20, 2.06)
T-Test of difference = 0 (vs not =): T-Value = -1.43 P-Value = 0.159 DF = 44
Linear Regression
Satis = 4.31 + 0.418 Friends                                   Satis = - 0.271 + 0.133 Salary

Correlation of Job Satisfaction Vs Friends, Salary, Personal Time, Benefits
Friends                               Salary
10

8

6

4
Overall Satis

2
0.0   1.5        3.0        4.5   6.0     30   40     50       60       70
Personal Time                           Benefits
10

8

6

4

2
0    60        120         180   240 2        4        6           8        10

Satis = 7.89 - 0.0147 Personal Time                               Satis = - 0.068 + 1.00 Benefits
Linear Regression
Satis = 0.326 + 1.64 Sup Satis                            Satis = 9.36 - 0.689 Micromgmt

Correlation of Job Satisfaction Vs Sup Satis, Micromgmt, Empowerment, Bnfts
Sup Satis                           Micromgmt
10

8

6

4
Overall Satis

2
1     2       3         4     5 0.0      2.5     5.0       7.5   10.0
Empwrment                             Benefits
10

8

6

4

2
0.0   2.5      5.0       7.5   10.0 2        4       6         8     10

Satis = 1.47 + 0.761 Empwrment                                 Satis = - 0.068 + 1.00 Benefits

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