A Plan for Problem Solving

A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the _____________________. Perimeter is similar to ____________. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around an object Perimeter is the _____________________. a line segment Perimeter is similar to ____________. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around an object Perimeter is the _____________________. a line segment Perimeter is similar to ____________. Area is the _______________________________________________. Area is similar to ______. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around an object Perimeter is the _____________________. a line segment Perimeter is similar to ____________. number of square units needed to cover an object’s surface Area is the _______________________________________________. a plane Area is similar to ______. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around a figure Perimeter is the ____________________. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around a figure Perimeter is the ____________________. The perimeter is the ____ of the lengths of the sides of the figure. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around a figure Perimeter is the ____________________. sum The perimeter is the ____ of the lengths of the sides of the figure. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around a figure Perimeter is the ____________________. sum The perimeter is the ____ of the lengths of the sides of the figure. The perimeter of the room shown here is: A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. distance around a figure Perimeter is the ____________________. sum The perimeter is the ____ of the lengths of the sides of the figure. The perimeter of the room shown here is: 15 ft + 18 ft + 6 ft + 6 ft + 9 ft + 12 ft = 66 ft A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. (A formula is an equation that shows how certain quantities are related.) A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. (A formula is an equation that shows how certain quantities are related.) Perimeter  2l  2w (of a rectangle)  2(l  w) A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. 8 ft 17 ft A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. 8 ft 17 ft Perimeter  2l  2w = 2(17 ft) + 2(8 ft) = 34 ft + 16 ft = 50 ft A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. 8 ft 17 ft Perimeter  2l  2w = 2(17 ft) + 2(8 ft) = 34 ft + 16 ft = 50 ft or  2(l  w) = 2(17 ft + 8 ft) = 2(25 ft) = 50 ft A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. A Plan for Problem Solving Another important measure is area. the number of square units needed to cover its surface The area of a figure is ____________________________________________. A Plan for Problem Solving Another important measure is area. the number of square units needed to cover its surface The area of a figure is ____________________________________________. The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6 A Plan for Problem Solving Another important measure is area. the number of square units needed to cover its surface The area of a figure is ____________________________________________. The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6 A Plan for Problem Solving Another important measure is area. the number of square units needed to cover its surface The area of a figure is ____________________________________________. The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6 The area of a rectangle can also be found by multiplying the length and the width. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. A  lw Find the area of the rectangle w l 10 in. 14 in. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. A  lw Find the area of the rectangle w l A  lw A  (14in)(10in) 2 A  140in 10 in. 14 in. The area of the rectangle is 140 square inches. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. A  lw Find the area of the rectangle w l A  lw A  (14in)(10in) 2 A  140in 10 in. 14 in. The area of the rectangle is 140 square inches. NOTE: units indicate area is being calculated (in)(in)  in 2 Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, rectangle the area of a parallelogram is closely related to the area of a ________. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, rectangle the area of a parallelogram is closely related to the area of a ________. height base The area of a parallelogram is found by multiplying the ____ and the ______. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, rectangle the area of a parallelogram is closely related to the area of a ________. height base height The area of a parallelogram is found by multiplying the ____ and the ______. base Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, rectangle the area of a parallelogram is closely related to the area of a ________. height base height The area of a parallelogram is found by multiplying the ____ and the ______. base Base – the bottom of a geometric figure. Height – measured from top to bottom, perpendicular to the base. A Plan for Problem Solving Find the area of the parallelogram: 4.3 m 4m 5 1 m 10 A Plan for Problem Solving Find the area of the parallelogram: A  bh  51   (4m)  m   10  4.3 m 4m 5 1 m 10 A Plan for Problem Solving Find the area of the parallelogram: A  bh  51   (4m)  m   10   204 2   m   10  2 2  20 m 5 4.3 m 4m 5 1 m 10 §1.6 A Plan for Problem Solving