# Percent Yield Worksheet

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```					Name:_______________      Date:______________        Per:____________
Stoichiometry - Percent Yield Worksheet
SHOW ALL WORK!!!!!
Theoretical Yield = answer to your stoich problem.
NOTE:        % Yield =      Actual Yield    x 100            Actual Yield = given in the problem or the
Theoretical Yeild                                 experimental y ield.

1)   Balance the equation for the reaction of iron (III) phosphate with sodium sulfate to make iron
(III) sulfate and sodium phosphate.

FePO4     +     Na2 SO4           Fe 2 (SO4 )3   +       Na3 PO4

a)   If I perform this reaction with 25 grams of iron (III) phosphate and an excess of sodium sulfate,
how many grams of iron (III) sulfate can I make?

b)   If 18.5 grams of iron (III) sulfate are actually made when I do this reaction, what is my percent
yield?

c)   Is the answer from problem #3 reasonable? Explain.

d)   If I do this reaction with 15 grams of sodium sulfate and get a 65.0% yield, how many grams of
sodium phosphate will I make?
Name:_______________       Date:______________        Per:____________

2)   LiOH + KCl               LiCl +      KOH
a) I began this reaction with 20 grams of lithium hydroxide. What is my theoretical yield of
lithium chloride?

b) I actually produced 6 grams of lithium chloride. What is my percent yield?

3)   C3 H8 +     5 O2       3 CO2    +    4 H2 O
a) If I start with 5 grams of C 3 H8 , what is my theoretical yield of water?

b) I got a percent yield of 75% How many grams of water did I make?

4)   Be + 2 HCl  BeCl2 + H2
My theoretical yield of beryllium chloride was 10.7 grams. If my actual yield was 4.5 grams,
what was my percent yield?
Name:_______________ Date:______________              Per:____________
Stoichiometry - Percent Yield Worksheet - Key

1)    Write the equation for the reaction of iron (III) phosphate with sodium sulfate to make iron (III)
sulfate and sodium phosphate.

2 FePO4 + 3 Na2 SO4  1 Fe2 (SO4 )3 + 2 Na3 PO4

a)    If I perform this reaction with 25 grams of iron (III) phosphate and an excess of sodium sulfate,
how many grams of iron (III) sulfate can I make?

25/     =     1/3 =      x          = 17.2 grams iron (III) sulfate

b)    If 18.5 grams of iron (III) sulfate are actually made when I do this reaction, what is my percent
yield?

(18.5 / 17.2) x 100% = 108% yield

c)    Is the answer from problem #3 reasonable? Explain.

No. Any yield over 100% is a violation of the Law of conservation of mass.

d)    If I do this reaction with 15 grams of sodium sulfate and get a 65.0% yield, how many grams of
sodium phosphate will I make?

According to the stoichiometry, the theoretical yield is 11.5 grams. Multiplying this by
0.650, you get 7.48 grams.

2)

3)

4)

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