# 6.5 Solving Quadratic Equations by Factoring by pyb17727

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6.5 Solving
by Factoring
equation that can be written in the
form (Standard Form)
2
ax + bx + c = 0
where a, b, and c are real #’s, with
a≠0

Example   x2 + 5x + 6 = 0
Page 418
#4) Solve

( 6K + 5 )( K + 4 ) = 0
#6) Solve

w ( 4w + 1) = 0
Students do #’s 3, 5
Page 420
#22) Solve
2
T        = 2T + 15
#32) Solve
2
18 x         = 12 + 15 x
#38) Solve
2
4w − 9 = 0
Note – In #42, DO NOT begin by
dividing both sides by T to get
T=9. We will not get the other
solution which is 0, if we divide
by a variable.

2
T        = 9T
#42) Solve
2
T       = 9T
Note – In # 46, we can not use
the zero-factor property to solve
the equation r ( r − 5 ) = −6 in its
given form because of the − 6 on
the right. Remember, that the
zero-factor property applies only
to a product that = 0
#46) Solve

r ( r − 5 ) = −6
Students do #’s 21, 31, 37, 41, 45
#52) Solve
2
( 3 m + 4 )( 6 m + m − 2 ) = 0
#56) Solve
3
16 r − 9 r = 0
#66) Solve
2    2                2
(x − 7) + x       = ( x + 1)

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