# Percent Yield Worksheet_1_

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```					Name:_______________      Date:______________        Per:____________
Stoichiometry - Percent Yield Worksheet
SHOW ALL WORK!!!!!
NOTE:        % Yield =      Actual Yield    x 100           Actual Yield = given in the problem or the
Theoretical Yeild                                experimental yield.

1)   Balance the equation for the reaction of iron (III) phosphate with sodium sulfate to make iron
(III) sulfate and sodium phosphate.

FePO4 +        Na2SO4             Fe2(SO4)3     +       Na3PO4

a)   If I perform this reaction with 25 grams of iron (III) phosphate and an excess of sodium sulfate,
how many grams of iron (III) sulfate can I make?

b)   If 18.5 grams of iron (III) sulfate are actually made when I do this reaction, what is my percent
yield?

c)   Is the answer from problem #3 reasonable? Explain.

d)   If I do this reaction with 15 grams of sodium sulfate and get a 65.0% yield, how many grams of
sodium phosphate will I make?
Name:_______________      Date:______________        Per:____________

2)   LiOH + KCl              LiCl   +    KOH
a) I began this reaction with 20 grams of lithium hydroxide. What is my theoretical yield of
lithium chloride?

b) I actually produced 6 grams of lithium chloride. What is my percent yield?

3)   C3H8 +      5 O2      3 CO2    +    4 H2O
a) If I start with 5 grams of C3H8, what is my theoretical yield of water?

b) I got a percent yield of 75% How many grams of water did I make?

4)   Be + 2 HCl  BeCl2 + H2
My theoretical yield of beryllium chloride was 10.7 grams. If my actual yield was 4.5 grams,
what was my percent yield?
Name:_______________ Date:______________              Per:____________
Stoichiometry - Percent Yield Worksheet - Key

1)    Write the equation for the reaction of iron (III) phosphate with sodium sulfate to make iron (III)
sulfate and sodium phosphate.

2 FePO4 + 3 Na2SO4  1 Fe2(SO4)3 + 2 Na3PO4

a)    If I perform this reaction with 25 grams of iron (III) phosphate and an excess of sodium sulfate,
how many grams of iron (III) sulfate can I make?

25/     =     1/3 =       x          = 17.2 grams iron (III) sulfate

b)    If 18.5 grams of iron (III) sulfate are actually made when I do this reaction, what is my percent
yield?

(18.5 / 17.2) x 100% = 108% yield

c)    Is the answer from problem #3 reasonable? Explain.

No. Any yield over 100% is a violation of the Law of conservation of mass.

d)    If I do this reaction with 15 grams of sodium sulfate and get a 65.0% yield, how many grams of
sodium phosphate will I make?

According to the stoichiometry, the theoretical yield is 11.5 grams. Multiplying this by
0.650, you get 7.48 grams.

2)

3)

4)

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