# 2

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```					                                         A                                                               B
1         For 1-5 determine u and for 6-20 use subsitution to integrate!
2                         Why is six afraid of seven?                                             Answer Key
3   1) ∫(5(x^2) + 1)^2 (10x) dx                                            because: 6(x^1.5) - .4(x^2.5) + c
4   2) ∫(x^2)((x^3) + 1)^.5 dx                                             nine: .25(x^4) - (x^2) + c
5   3) ∫(x)/((x^2) + 1)^.5 dx                                              mean: (1/4)(x^4) - (x^2) + c
6   4) ∫(tanx)^2 (secx)^2 dx                                               different: .4(x^2.5) + 2(x^1.5) +14(x^.333) + c
7   5) ∫(cosx)/((sinx)^2) dx                                               about: (2x)^.5 + c
8   6) ∫((1 + 2x)^24)(2) dx                                                leave: (-1/4)(1 + (x^-1))^4 + c
9   7) ∫((9-(x^2))^.5)(-2x) dx                                             you: -(1 - (x^2))^.5 + c
10   8) ∫ (x^3)((x^4) + 3)^2 dx                                             weak: -3(1 + (x^2))^-1 + c
11   9) ∫(x^2)((x^3) - 1)^4 dx                                              way: (1 - (x^2))^-2 + c
12   10) ∫(x)((x^2) + 2)^.5 dx                                              akward: (15/-8)(1-(x^2))^(4/3) + c
13   11) ∫(x^2)((x^3) - 1)^4 dx                                             ninja: (3/4)((x^2) + 2)^1.5 + c
14   12) ∫(x)((x^2) + 2)^.5 dx                                              pizza: (1/15)((x^3)-1)^5 +c
15   13) ∫(5x)(1 - (x^2))^(1/3) dx                                          come: (1/6)((x^4) + 3)^3 + c
16   14) ∫(x)/(1 - (x^2))^3 dx                                              instead: (2/3)(9 - (x^2))^1.5 +c
17   15) ∫(x^2)/(1 + (x^3))^2 dx                                            guilt: .2(1 + 2x)^5 +c
18   16) ∫(x)/((1 - (x^2))^.5 dx                                            eleven: u = sinx
19   17) ∫(1 + (x^-1))^3 (t^-2) dx                                          ten: u = tanx
20   18) ∫ 1/(2x)^.5 dx                                                     the: u = (x^2) + 1
21   19) ∫(x^3)-2x dx                                                       eight: u = (x^3) + 1
22   20) ∫(9-x)(x^.5) dx                                                    seven: u = 5(x^2) +1
23   ANSWER: 20 - 1 -2 - 19

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 views: 88 posted: 5/24/2010 language: English pages: 1