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Data and Computer Communications Chapter 3 – Data Transmission Transmission Terminology data transmission occurs between a transmitter & receiver via some medium guided medium e.g. twisted pair, coaxial cable, optical fiber unguided / wireless medium e.g. air, water, vacuum Transmission Terminology direct link (guided & unguided) no intermediate devices point-to-point (guided) direct link only 2 devices share link multi-point more than two devices share the link Transmission Terminology simplex one direction • eg. television half duplex either direction, but only one way at a time • eg. police radio full duplex both directions at the same time • eg. telephone Frequency, Spectrum and Bandwidth time domain concepts analog signal • varies in a smooth way over time digital signal (discrete) • maintains a constant level then changes to another constant level periodic signal • pattern repeated over time aperiodic signal • pattern not repeated over time Analogue & Digital Signals Periodic Signals Sine Wave peak amplitude (A) maximum strength of signal volts frequency (f) rate of change of signal Hertz (Hz) or cycles per second period = time for one repetition (T) T = 1/f phase () relative position in time Varying Sine Waves s(t) = A sin(2ft +) Wavelength () isdistance occupied by one cycle between two points of corresponding phase in two consecutive cycles assuming signal velocity v, we have = vT or equivalently f = v especially when v=c c = 3*108 ms-1 (speed of light in free space) Problem # In a multipoint configuration, a central control may be used that enables only one device to transmit. What is the merit and demerit of such control as compared to distributed control? Note According to Fourier analysis, any composite signal is a combination of simple sine waves with different frequencies, amplitudes, and phases. 3.12 Frequency Domain Concepts signalare made up of many frequencies components are sine waves Fourier analysis can show that any signal is made up of component sine waves can plot frequency domain functions Addition of Frequency Components (T=1/f) c is sum of f & 3f (with different amplitudes) Frequency Domain Representations freq domain function of Fig 3.4c freq domain function of single square pulse -ve amplitude? A composite periodic signal 3.16 Decomposition of a composite periodic signal in the time and frequency domains 3.17 Spectrum & Bandwidth spectrum range of frequencies contained in signal absolute bandwidth width of spectrum effective bandwidth often just bandwidth narrow band of frequencies containing most energy DC Component component of zero frequency Data Rate and Bandwidth any transmission system can accommodate a limited band of frequencies this limits the data rate that can be carried Square wave: infinite components and hence bandwidth but most energy in first few components limited bandwidth increases distortion has a direct relationship between data rate & bandwidth Data Rate-Bandwidth Relation Square Wave transmission Case 1: Three frequency components – f, 3f, 5f => Bandwidth = (5-1) f = 4f. Let f = 1 MHz, Bandwidth = 4 MHz, T = 1µs => 1 bit needs 0.5 µs Data rate = 2 MBPS Data Rate-Bandwidth Relation Square Wave transmission Case 2: Three frequency components – f, 3f, 5f => Bandwidth = (5-1) f = 4f. Let f = 2 MHz, Bandwidth = 8 MHz, T = 0.5µs => 1 bit needs 0.25 µs Data rate = 4 MBPS Data Rate-Bandwidth Relation Square Wave transmission Case 3: Two frequency components – f, 3f only => Bandwidth = (3-1) f = 2f. Let f = 2 MHz, Bandwidth = 4 MHz, T = 0.5µs => 1 bit needs 0.25 µs Data rate = 4 MBPS Shape of signal? Analog and Digital Data Transmission data entities that convey meaning / information signals & signaling electric or electromagnetic representations of data, physically propagates along medium Transmission propagation and processing of signals Acoustic Spectrum (Analog) Audio Signals freq range 20Hz-20kHz (speech 100Hz-7kHz) easily converted into electromagnetic signals varying volume converted to varying voltage can limit frequency range for voice channel to 300-3400Hz with acceptable reproduction Video Signals - Bandwidth 525 lines x 30 scans = 15750 lines per sec 63.5s per line 11s for retrace, so 52.5 s per video line max frequency if line alternates black and white 483 lines per frame USA has 525 lines but 42 lost during vertical retrace horizontal resolution is about 450 lines giving 225 cycles of wave in 52.5 s max frequency of 4.2MHz Digital Data asgenerated by computers etc. has two dc components bandwidth depends on data rate Analog Signals Digital Signals Advantages & Disadvantages of Digital Signals cheaper less susceptible to noise but greater attenuation digital now preferred choice Preferred Method Digital, because: - Technology support of VLSI - Security (Encryption) - Integration (data, audio, video) Transmission Impairments received may differ from signal signal transmitted causing: analog - degradation of signal quality digital - bit errors (‘1’ as ‘0’ or vice-versa) most significant impairments are attenuation delay distortion noise Attenuation where signal strength falls off with distance depends on medium received signal strength must be: strong enough to be detected sufficiently higher than noise to receive without error so increase strength using amplifiers/repeaters is also an increasing function of frequency so equalize attenuation across band of frequencies used e.g. using loading coils (voice grade) or amplifiers Problem # A signal has passed through three cascaded amplifiers, each with a 4 dB gain. What is the total gain? How much is the signal amplified? What does a negative dB value signify? Delay Distortion only occurs in guided media propagation velocity varies with frequency hence various frequency components arrive at different times particularly critical for digital data since parts of one bit spill over into others causing inter-symbol interference Noise additionalsignals inserted between transmitter and receiver thermal due to thermal agitation of electrons uniformly distributed across typical bandwidth white noise Inter-modulation signals that are the sum and difference (or multiples) of original frequencies sharing a medium Noise crosstalk a signal from one path / line is picked up by another impulse irregular pulses or spikes • e.g. external electromagnetic interference short duration high amplitude a minor annoyance for analog signals but a major source of error in digital data • a noise spike could corrupt many bits Channel Capacity maximum possible data rate on a communication channel data rate - in bits per second bandwidth - in cycles per second or Hertz noise - on communication link error rate - of corrupted bits due to physical properties limitations want most efficient use of capacity Nyquist Bandwidth consider noise free channels if rate of signal transmission is 2B then it can carry signal with frequencies no greater than B i.e. given bandwidth B, highest signal rate is 2B for binary signals, 2B bps needs bandwidth B Hz can increase rate by using M signal levels Nyquist Formula is: C = 2B log2M so increase rate by increasing signal levels at the cost of receiver complexity limited by noise & other impairments Shannon Capacity Formula consider relation of data rate, noise & error rate faster data rate shortens each bit so bursts of noise affects more bits given noise level, higher rates means higher errors Shannon developed formula relating these to signal to noise ratio (in decibels) SNRdb=10 log10 (signal/noise) Capacity C=B log2(1+SNR) theoretical maximum capacity get lower in practise Summary looked at data transmission issues frequency, spectrum & bandwidth analog vs digital signals transmission impairments Problems Q1. For a video signal, what increase in horizontal resolution is possible if a bandwidth of 5 MHz is used? Q2. For a digitized TV picture matrix of 480×500 pixels, where each pixel can take one of 48 intensity values, assume 30 pictures are sent per second. Find the source rate (bps). Problems Q3.For the above problem, use Shannon’s formula to calculate the channel capacity if BW used is 4.5 MHz and SNR is 35 dB. Q4. A multi level signaling system operates at 9600 bps. A signal element encodes a 4-bit word. Find the minimum BW required of the channel. Problems Q5. A telephone line has 4 KHz BW. When signal is 10V, the noise is 5 mV. Find the maximum data rate supported by this line. Problems Q6. Consider square wave transmission that involves the fundamental frequency and all odd frequencies upto the 9th harmonic. If f = 2MHz, then find the bandwidth required and the data rate achieved. If only the fundamental frequency and the 3rd harmonic are transmitted, find the bandwidth required and the data rate achieved in this case. Comment about the receiver requirements for both the cases.

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Data and Computer Communications, data communications, Computer Communications, Computer networks, William Stallings, Prentice Hall, network security, Packet switching, data networks, final exam

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posted: | 5/15/2010 |

language: | English |

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