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The spider and the fly

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					The spider and the fly

        An investigation
                                                                 The diagram shows a large
                                                                 room measuring 30 feet long,
                                                                 12 feet broad and 12 feet high.




On one of the
12ft × 12ft walls,
1 foot down from
the ceiling in the
middle of the
wall is a fly.
On the opposite
wall, 1 foot up
from the middle
of the floor
is a spider.




Obviously, since it cannot fly, the spider must stay on the walls,
 the floor or the ceiling at all times.
If the spider wishes to catch the fly, find the shortest route which the spider will take to do so.
                   Solution




SF² = 32² + 24²
    = 1024 + 576
    = 1600
SF = 40
Minimum distance
  = 40 feet

				
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posted:4/8/2010
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