A consistent thermodynamic treatment for quark mass density
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A Consistent Thermodynamic
Treatment for Quark Mass
Density-Dependent Model
Ru-Keng Su
Physics Department
Fudan University
Difficulties
In relativistic energy dispersion relation:
( p) m p m (T , ) p
2 2 * 2 2
Ω becomes an explicit function of m:
Ω Ω(T ,V , {i }, m (T , ))
*
How will the thermodynamic formulae with
the partial derivatives become?
Different treatments with extra terms
from partial derivatives
A.
B
p ,
B.
V V B T ,{ i }
B T
i i
V V B T ,{ } i V T B ,{ i }
i
O. G. Benvenuto and G. Lugones, Phys. Rev. D 51, 1989 (1995)
G. Lugones and O. G. Benvenuto, ibid. 52, 1276 (1995)
C. m m( B )
B T
p , i i ,
V V B T ,{ i }
V i V T B ,{ i }
G. X. Peng, et. al. Phys. Rev. C 59, 3452 (1999)
G. X. Peng, et. al. Phys. Rev. C 62, 025801(2000)
m m( B , T )
~ ~
~ m * i
p V B ,
V i m i B
*
~ ~ ~
~ m * i
i T T ,
i i T ,{ } i m i T
*
B i
X. J. Wen, et. al. Phys. Rev. C 72, 015204 (2005)
Inconsistency of Traditional Thermodynamic
Treatments with Partial Derivative
Differential relation for reversible process
Ω = Ω(T, V, μ).
If m*=m*(T,ρ), Ω = Ω(T, V, μ, m*(T,ρ), ), the
Massieu’s Theorem breaks down.
Quasi-particle approximation
H eff (k , T , )a ak
k
k
( k , T , ) k m (T , )
2 2
G U TS pV F 0; ( 0)
S dS dp
;
V dV dT
U dp(T )
T p(T ).
V dT
Thermodynamic inconsistency
For QMDD Model
ρ=N/V →μ, fixed {T,μ} equals fixed {T,ρ}
Change V, N must change, too.
f f f y
According to x g x y y x x g
, we
write down the invariables explicitly
=0
Inconsistent with
Reversible Process fix t
equilibrium state
Suppose T=T0, ρ=ρ0,
m*(T, ρ)=m*(T0,ρ0)
All formulae in equilibrium state are
applicable
Thermodynamic Consistent Treatment
In equilibrium state
Calculation of U from the definition
Consist with the interaction-free
quasi-particle picture
Calculation of S from the definition
Calculation of S from partial derivative
Our treatment can be expressed by
considering the quasi-particle mass as
independent variable
Ordinary thermodynamic variables depend
on the collection of the subsystem only.
Mass is an intrinsic quantity of a particle, it
does not affect on collective thermodynamic
properties.
Effective mass m*(T, ρ) includes dynamic
interaction, confinement mechanism, etc.
But the macro thermodynamic variables
cannot describe these micro dynamic
interactions. We must choose new
variables to represent these dynamic
interactions or the medium effect.
Introducing m* in quasiparticle physical
picture to represent the medium effect and
taking it as a variable is a twin in
thermodynamics of quasiparticle system.
QMDD model
Old treatment
Our treatment
Our treatment
Old treatment I
Old treatment II
Contribution of Vacuum
Within the statistical frame, the pressure is
positive definite, p=-Ω/V>0
In MIT bag model, B0 is added to energy while
subtracted in pressure as vacuum contribution,
negative pressure can be realized
Constraint on Vacuum
Ω0(ρB) can be obtained by integration
Conclusion
For model Hamiltonian with effective mass
quasiparticles, an intrinsic degree of
freedom m* must be introduced
d SdT pdV N i di Xdm * .
i
All ambiguities are solved
Correct physical picture after the vacuum is
introduced
PRC Referee’s Report
This is an interesting paper which should be published in
PRC. The authors explain the inconsistencies in previous
thermodynamical treatments of quark matter within the
quark mass density-dependent model and show how the
model can be used self-consistently by introducing the
quasiparticle mass as a new independent variable. This
leads to reasonable numerical results resembling those
obtained with the MIT bag model, but more importantly it
leads to an improved understanding of the physics.
In fact as the authors mention in the paper their method
may be more widely applicable to other systems where
medium effects can be described by an effective mass,
and my only suggestion for changes in the manuscript is to
include this statement in the Abstract in order to attract
more readers from other subfields.
Thank you!
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