Coil Worksheets by qbk17881

VIEWS: 93 PAGES: 19

									Coil Worksheets

The following information is found here, organized by coil:

       - Physical data pertaining to each coil.

        - Least squares approximation of relationship between current through coils and
the voltage on the foil around the coils.

        - Chart showing relationship between current through coils and the voltage on the
foil around the coils.

Separate sets of spreadsheets called coil worksheets and foil worksheets show raw and
processed data and model calculations.




                                             1
79 Micro Henry Coil Worksheet

Coil Dimensions:
Coil length: 10 inches
Number of windings: 230
Coil diameter: .75 inches
Type wire: 18 AWG enameled, nominal diameter .0403 inches (enamel insulation was
discounted in calculations)

Conversion factors:
1 inch = .0254 meters
1 square inch = 6.452*(10^(-4)) square meters

Equations:
rcw = ((coil diameter)+(wire diameter))/2
rw = (length of coil)/(2*(number of windings))
rwa = (wire diameter)/2
Cross-sectional area of wire = A = pi*(rwa^2)
(ro-ri) = A/(2*rw)
ro = rcw+((ro-ri)/2)
ri = rcw-((ro-ri/2)

Calculations:
rcw = (.75 inches + .0403 inches)/2 = .39515 inches = 100.4*(10^(-4)) meters
rw = (10 inches)/(2*230) = .02174 inches = 5.521*(10^(-4)) meters
rwa = .0403/2 inches = .02015 inches = 5.118*(10^(-4)) meters
A = pi*(rwa^2) = 3.1416*((5.118*(10^(-4)))^2) square meters =
  8.229*(10^(-7)) square meters
(ro-ri)/2 = 8.229*(10^(-7))/(4*5.521*(10^(-4)) meters = 3.7*(10^(-4)) meters
ro = 100.4*(10^(-4)) meters + 3.7*(10^(-4)) meters = 1.041*(10^(-2)) meters
ri = 100.4*(10^(-4)) meters – 3.7*(10^(-4)) meters = .967*(10^(-2)) meters

Check:

A = (ro-ri)*2*rw ?

8.225*(10^(-7)) = (1.041-.967)*(10^(-2))*2*5.521*(10^(-4)) ?
               = 8.171*(10^(-7))




                                           2
3
                                               Maximum Foil Potential on 79 UHy Coil
                                                               9 June 2007 Data

                              1,600

                              1,400
Maximum Foil Potential (mV)




                              1,200

                              1,000

                               800

                               600

                               400

                               200

                                 0
                                  0 0. 0. 0. 0. 0. 0. 0. 0. 0. 1 1. 1. 1. 1. 1. 1. 1. 1. 1. 2 2. 2. 2. 2. 2. 2. 2. 2. 2.

                                                                      Coil Current (A)

                                                            Low V          High V        LS High V




                                                                  4
126 Micro Henry Coil Worksheet

Coil Dimensions:
Coil length: 10 inches
Number of windings: 230
Coil diameter: 1 inch
Type wire: 18 AWG enameled, nominal diameter .0403 inches (enamel insulation was
discounted in calculations)

Conversion factors:
1 inch = .0254 meters
1 square inch = 6.451*(10^(-4)) square meters

Equations:
rcw = ((coil diameter)+(wire diameter))/2
rw = (length of coil)/(2*(number of windings))
rwa = (wire diameter)/2
Cross-sectional area of wire = A = pi*(rwa^2)
(ro-ri) = A/(2*rw)
ro = rcw+((ro-ri)/2)
ri = rcw-((ro-ri/2)

Calculations:
rcw = (1 inch + .0403 inches)/2 = .52015 inches = 132.1*(10^(-4)) meters
rw = (10 inches)/(2*230) = .02174 inches = 5.521*(10^(-4)) meters
rwa = .0403/2 inches = .02015 inches = 5.118*(10^(-4)) meters
A = pi*(rwa^2) = 3.1416*((5.118*(10^(-4)))^2) = 8.229*(10^(-7)) square meters
(ro-ri)/2 = 8.225*(10^(-7))/(4*5.521*(10^(-4)) meters = 3.7*(10^(-4)) meters
ro = 132.1*(10^(-4)) meters + 3.7*(10^(-4)) meters = 1.358*(10^(-2)) meters
ri = 132.1*(10^(-4)) meters – 3.7*(10^(-4)) meters = 1.284*(10^(-2)) meters

Check:

pi()*(rwa^2) = 2*(ro-ri)*rw

8.229*(10^(-7)) = 2*(1.358-1.284)*(10^(-2))*5.521*(10^(-4))
               = 8.171*(10^(-7))




                                           5
6
                                              Maximum Foil Potential on 126 UHy Coil
                                                               9 June 2007 Data

                              2,500



                              2,000
Maximum Foil Potential (mV)




                              1,500



                              1,000



                               500



                                 0
                                  0 0. 0. 0. 0. 0. 0. 0. 0. 0. 1 1. 1. 1. 1. 1. 1. 1. 1. 1. 2 2. 2. 2. 2. 2. 2. 2. 2. 2.

                                                                        Coil Current (A)

                                                            Low V            High V        LS High V




                                                                    7
199 Micro Henry Coil Worksheet

Coil Dimensions:
Coil length: 10 inches
Number of windings: 370
Coil diameter: .75 inch
Type wire: 22 AWG enameled, nominal diameter .0253 inches (enamel insulation was
discounted in calculations)

Conversion factors:
1 inch = .0254 meters
1 square inch = 6.452*(10^(-4)) square meters

Equations:
rcw = ((coil diameter)+(wire diameter))/2
rw = (length of coil)/(2*(number of windings))
rwa = (wire diameter)/2
Cross-sectional area of wire = A = pi*(rwa^2)
(ro-ri) = A/(2*rw)
ro = rcw+((ro-ri)/2)
ri = rcw-((ro-ri/2)

Calculations:
rcw = (.75 inch + .0253 inches)/2 = .38765 inches = 98.5*(10^(-4)) meters
rw = (10 inches)/(2*370) = .013514 inches = 3.432*(10^(-4)) meters
rwa = .0253/2 inches = .01265 inches = 3.213*(10^(-4)) meters
A = pi*(rwa^2) = 3.1416*((3.213*(10^(-4)))^2) = 3.243*(10^(-7)) square meters
(ro-ri)/2 = 3.243*(10^(-7))/(4*3.432*(10^(-4)) meters = 2.4*(10^(-4)) meters
ro = 98.5*(10^(-4)) meters + 2.4*(10^(-4)) meters = 1.009*(10^(-2)) meters
ri = 98.5*(10^(-4)) meters – 2.4*(10^(-4)) meters = .961*(10^(-2)) meters

Check:

pi()*(rwa^2) = 2*(ro-ri)*rw

3.243*(10^(-7)) = 2*(1.009-.961)*(10^(-2))*3.432*(10^(-4))
               = 3.295*(10^(-7))




                                           8
9
                                             Maximum Foil Potential on 199 UHy Coil
                                                               9 June 2007 Data

                               2,000


                               1,500
Maximum Foil Potential (mV)




                               1,000


                                 500


                                   0
                                    0 0. 0. 0. 0. 0. 0. 0. 0. 0. 1 1. 1. 1. 1. 1. 1. 1. 1. 1. 2 2. 2. 2. 2. 2. 2. 2. 2. 2.

                               (500)


                              (1,000)

                                                                          Coil Current (A)

                                                             Low V            High V         LS High V




                                                                     10
207 Micro Henry Coil Worksheet

Coil Dimensions:
Coil length: 10 inches
Number of windings: 230
Coil diameter: 1.25 inches
Type wire: 18 AWG enameled, nominal diameter .0403 inches (enamel insulation was
discounted in calculations)

Conversion factors:
1 inch = .0254 meters
1 square inch = 6.452*(10^(-4)) square meters

Equations:
rcw = ((coil diameter)+(wire diameter))/2
rw = (length of coil)/(2*(number of windings))
rwa = (wire diameter)/2
Cross-sectional area of wire = A = pi*(rwa^2)
(ro-ri) = A/(2*rw)
ro = rcw+((ro-ri)/2)
ri = rcw-((ro-ri/2)

Calculations:
rcw = (1.25 inch + .0403 inches)/2 = .64515 inches = 163.9*(10^(-4)) meters
rw = (10 inches)/(2*230) = .02174 inches = 5.521*(10^(-4)) meters
rwa = .0403/2 inches = .02015 inches = 5.118*(10^(-4)) meters
A = pi*(rwa^2) = 3.1416*((5.118*(10^(-4)))^2) = 8.229*(10^(-7)) square meters
(ro-ri)/2 = 8.225*(10^(-7))/(4*5.521*(10^(-4)) meters = 3.7*(10^(-4)) meters
ro = 163.9*(10^(-4)) meters + 3.7*(10^(-4)) meters = 1.676*(10^(-2)) meters
ri = 163.9*(10^(-4)) meters – 3.7*(10^(-4)) meters = 1.602*(10^(-2)) meters

Check:

pi()*(rwa^2) = 2*(ro-ri)*rw

8.229*(10^(-7)) = 2*(1.676-1.602)*(10^(-2))*5.521*(10^(-4))
               = 8.171*(10^(-7))




                                          11
12
                                               Maximum Foil Potential on 207 UHy Coil
                                                               9 June 2007 Data

                              3,000


                              2,500
Maximum Foil Potential (mV)




                              2,000


                              1,500


                              1,000


                               500


                                 0
                                  0 0. 0. 0. 0. 0. 0. 0. 0. 0. 1 1. 1. 1. 1. 1. 1. 1. 1. 1. 2 2. 2. 2. 2. 2. 2. 2. 2. 2.

                                                                      Coil Current (A)

                                                            Low V          High V        LS High V




                                                                 13
353 Micro Henry Coil Worksheet

Coil Dimensions:
Coil length: 10 inches
Number of windings: 370
Coil diameter: 1 inch
Type wire: 22 AWG enameled, nominal diameter .0253 inches (enamel insulation was
discounted in calculations)

Conversion factors:
1 inch = .0254 meters
1 square inch = 6.452*(10^(-4)) square meters

Equations:
rcw = ((coil diameter)+(wire diameter))/2
rw = (length of coil)/(2*(number of windings))
rwa = (wire diameter)/2
Cross-sectional area of wire = A = pi*(rwa^2)
(ro-ri) = A/(2*rw)
ro = rcw+((ro-ri)/2)
ri = rcw-((ro-ri/2)

Calculations:
rcw = (1 inch + .0253 inches)/2 = .51265 inches = 130.2*(10^(-4)) meters
rw = (10 inches)/(2*370) = .013514 inches = 3.432*(10^(-4)) meters
rwa = .0253/2 inches = .01265 inches = 3.213*(10^(-4)) meters
A = pi*(rwa^2) = 3.1416*((3.213*(10^(-4)))^2) = 3.243*(10^(-7)) square meters
(ro-ri)/2 = 3.243*(10^(-7))/(4*3.432*(10^(-4)) meters = 2.4*(10^(-4)) meters
ro = 130.2*(10^(-4)) meters + 2.4*(10^(-4)) meters = 1.324*(10^(-2)) meters
ri = 130.2*(10^(-4)) meters – 2.4*(10^(-4)) meters = 1.278*(10^(-2)) meters

Check:

pi()*(rwa^2) = 2*(ro-ri)*rw

3.243*(10^(-7)) = 2*(1.324-1.278)*(10^(-2))*3.432*(10^(-4))
               = 3.157*(10^(-7))




                                          14
15
                                              Maximum Foil Potential on 353 UHy Coil
                                                               9 June 2007 Data

                               3,000

                               2,500
Maximum Foil Potential (mV)




                               2,000

                               1,500

                               1,000

                                 500

                                   0
                                    0 0. 0. 0. 0. 0. 0. 0. 0. 0. 1 1. 1. 1. 1. 1. 1. 1. 1. 1. 2 2. 2. 2. 2. 2. 2. 2. 2. 2.
                               (500)

                              (1,000)

                                                                        Coil Current (A)

                                                             Low V          High V         LS High V




                                                                   16
550 Micro Henry Coil Worksheet

Coil Dimensions:
Coil length: 10 inches
Number of windings: 370
Coil diameter: 1.25 inches
Type wire: 22 AWG enameled, nominal diameter .0253 inches (enamel insulation was
discounted in calculations)

Conversion factors:
1 inch = .0254 meters
1 square inch = 6.452*(10^(-4)) square meters

Equations:
rcw = ((coil diameter)+(wire diameter))/2
rw = (length of coil)/(2*(number of windings))
rwa = (wire diameter)/2
Cross-sectional area of wire = A = pi*(rwa^2)
(ro-ri) = A/(2*rw)
ro = rcw+((ro-ri)/2)
ri = rcw-((ro-ri/2)

Calculations:
rcw = (1.25 inch + .0253 inches)/2 = .63765 inches = 162.0*(10^(-4)) meters
rw = (10 inches)/(2*370) = .013514 inches = 3.432*(10^(-4)) meters
rwa = .0253/2 inches = .01265 inches = 3.213*(10^(-4)) meters
A = pi*(rwa^2) = 3.1416*((3.213*(10^(-4)))^2) = 3.243*(10^(-7)) square meters
(ro-ri)/2 = 3.243*(10^(-7))/(4*3.432*(10^(-4)) meters = 2.4*(10^(-4)) meters
ro = 162.0*(10^(-4)) meters + 2.4*(10^(-4)) meters = 1.644*(10^(-2)) meters
ri = 162.0*(10^(-4)) meters – 2.4*(10^(-4)) meters = 1.596*(10^(-2)) meters

Check:

pi()*(rwa^2) = 2*(ro-ri)*rw

3.243*(10^(-7)) = 2*(1.644-1.596)*(10^(-2))*3.432*(10^(-4))
               = 3.294*(10^(-7))




                                          17
18
                                              Maximum Foil Potential on 550 UHy Coil
                                                               9 June 2007 Data

                              3,500

                              3,000
Maximum Foil Potential (mV)




                              2,500

                              2,000

                              1,500

                              1,000

                               500

                                  0
                                   0 0. 0. 0. 0. 0. 0. 0. 0. 0. 1 1. 1. 1. 1. 1. 1. 1. 1. 1. 2 2. 2. 2. 2. 2. 2. 2. 2. 2.
                              (500)

                                                                      Coil Current (A)

                                                            Low V         High V         LS High V




                                                                     19

								
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