Cheng Fundamentals of Engineering Electromagnetics---Errata

							    Cheng: Fundamentals of Engineering Electromagnetics—Errata
                                           Jari J. Hänninen
                            TKK Department of Radio Science and Engineering
                                                       7th April 2008


• In Exercise 2.6 on page 33 it is necessary to determine φ to make ar unique: φ = arctan(4/3) ≈ 53.1◦

• P. 271, P.6-15, the third equation should begin
                                                            H2 (R,t) = . . .

• Equation (10-17), p. 432, should read

                                    Pav =     1
                                              2   Re(E × H∗ ) = 1 |Eθ ||Hφ |.
                                                                2                     (10-17)

• P. 441, the first paragraph: The text before equation (10-47) should actually say that while the maximum radiation
  intensity remains the same, the average radiation intensity is halved. Equation (10-47) and the text immediately after it
  should read
                                            Umax       Umax
                                       D=          = 1         = 3.28,          (10-47)
                                                      2 Pr /4π
                                             Uav
                            which is twice the directivity of a half-wave antenna. This antenna . . .


• P. 329, second line:   The Brewster angle θB is 83.6◦ .
• P. 329, in b), the second line should have       θi = 83.6◦
                                                           √
• P. 329, in b), the third line should have       η2 = 377/ εr2 = 42.1 Ω
• P. 329, in b), the reflection and transmission coefficients should read
                                                  42.1 cos 83.6◦ − 377 cos 6.38◦
                                       Γ⊥ =                                      = −0.975,
                                                  42.1 cos 83.6◦ + 377 cos 6.38◦
                                                       2 × 42.1 × cos 83.6◦
                                        τ⊥ =                                     = 0.025.
                                                  42.1 cos 83.6◦ + 377 cos 6.38◦




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