Prices of Jet blue and Travelocity 1. A. We studied the price differences between ordering airline tickets from the actual airline, JetBlue, versus a discount airline ticket website, Travelocity. We searched JetBlue’s website and Travelocity’s website for one-way flights leaving n the 18 th for two adults. After looking up 30 flights from JFK to 30 different locations, we noticed it appeared that Travelocity was more expensive than JetBlue.
2. A.
Collection 1 jet_blue 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 139 368 224 144 89 64 179 64 289 99 144 204 99 144 204 144 189 179 travelocÉ 168 480 261 177 221 126 196 126 341 166 161 221 116 171 221 171 206 196
B.
C.
D.
Collection 1 jet_blue 160.967 64 99 144 189 369 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 media n Q3 max
Collection 1 travelocity 196 96 136 171 221 480 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 median Q3 max
Collection 1 diff 35.0333 -83 17 28 52 132 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 median Q3 max
E. JET BLUEIQR= 90 [Q1-1.5 (IQR), Q3 +1.5(IQR)] 99- 1.5 (90)= -36 189+1.5 (90) = 324 [ -36; 324] Two outliers exist in the distribution for Jet blue. These outliers are found at points: 368, 369. TRAVELOCITYIQR = 85 [Q1-1.5 (IQR), Q3 +1.5(IQR)] 136-1.5(85)= 8.5 221+1.5 (85) = 348.5 [8.5; 348.5] Two Outliers exist in the distribution for Travelocity. These outliers are found at points: 341, 286.
F.
Jet blueMean= 160.97 Standard Dev= 78.55 TravelocityMean= 196 Standard Dev= 82.94
F. The graph of Jet blue has a shape that is skewed right also. The center is found at around point 150. The spread (IQR) of the distribution is 90; as a result, Jet blue has a bigger spread than Travelocity does. Furthermore, the points are more spread out from the center of the graph than they are for Travelocity. Two outliers exist on the graph: 368 and 369. The graph of Travelocity has a shape that is skewed right. The center is found at around point 175. The spread (IQR) of this distribution is 85. Two outliers exist on the graph, at points 341 and 286.
3. A. Ho: =0 (There is no difference in price flights). Ha: > 0 (Travelocity tickets are more expensive than Jet blue).
B. X bar= 35.03 = 36.56 Of X Bar = 36.56/ 30= 6.67 Z= (35.03-0)/ 6.67 – 5.29 C. Z-score=5.29 Percent below= 0 PICTURE:
D. Reject the Ho because the z-score is higher than 1.96 and the probably is greater than .25. The data is significant; our findings tell us that tickets from Travelocity are more expensive than those tickets bought on JetBlue.
Difference of store prices 1. The area of study we chose is finding the difference between an online clothing store and a real clothing store. The two clothing stores we chose are Carollete Russe and Gojane.com; furthermore, these stores are very similar and sell the same types of clothing. The reason for this study is to discover whether the online store (gojane.com) is less expensive than shopping at Charlette Russe. All of our data is collected online because Charlette Russe is accessible online, sampling the same price as in the actual store. Also, Gojane.com is completely found and sold online. 2. A.
Collection 1 char 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 34.99 32.99 32.99 32.99 29.99 26.99 26.99 26.99 26.99 26.99 26.99 24.99 24.99 24.99 24.99 24.99 24.99 gojane 29.99 28.99 25.99 23.99 22.99 22.99 20.99 20.99 20.99 20.99 20.99 18.99 18.88 18.99 18.99 18.99 16.99 diff 5 4 7 9 7 4 6 6 6 6 6 6 6.11 6 6 6 8
B.
C.
D.
Collection 1 char 25.6567 21.99 22.99 24.99 26.99 34.99 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 media n Q3 max
Collection 1 gojane 19.8863 4.99 17.99 19.49 22.99 29.99 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 median Q3 max
E. CharolleteQ3-Q1= 4 Q1-1.5(4)= 16.99
Q3+1.5(4)=32.99 (16.99; 32.99) Two Outliers exist in the distribution, and they lie on the points of 34.99. . Gojane.comIQR= 5 [Q1-1.5 (IQR), Q3 +1.5(IQR)] Q1-1.5(5)= 10.49 Q3+1.5(5)= 30.49 (10.49; 30.49) Two outliers exist for the Gojane.com distribution, on the points of 8.99 and 4.99.
F. Mean for gojane.com= 19.8863 Standard Dev for gojane.com= 5.15 Mean for Char=25.66 Standard Dev for Char=3.74 G. The shape of the graph Char is skewed right. The center of the graph is located at about 25. The spread (IQR) of the distribution is equal to 4. There are two outliers around the points of 33 and 36. The shape of the graph Gojane.com is skewed left. The center of the graph is located at around the point of 20. The spread (IQR) of the graph is 5; as a result, the graph of Gojane.com has a larger spread (IQR) than the spread of Char. Outliers exist at the points of 10 and 5. H.
3. A. Ho: M=0 (There is no difference in price) Ha>0 (Charolette Russe is more expensive than Gojane.com) B. X=5.77 -X = 3.93/ 30 = .72 C. Z = (5.77 – 0)/ .72 Z = 8.01 Z-Score= 8.01 Probability= 0 PICTURE:
D. Reject the Ho because the Z- score is 8.01 which is greater than 1.95. Also, the data is significant. We can conclude that Charolette Russe, a real store, is in fact more expensive than gojane.com, and online only store.
Weather Differences 1. A We studied the high temperatures for Woodcliff Lake, New Jersey and West Palm Beach, Florida for the month of June. We used weather.com to print out a 30-day calendar with the high and low temperatures of each day. For days (and temperatures) that hadn’t happened yet we used the averages given on the calendar, not the record temperatures for those days. After recording the data, neither of us could guess which place had the higher temperatures, based on looking at both sets of data side by side. 2. A
Collection 1 wcl_high 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 82 82 84 71 74 77 95 95 97 97 92 85 88 88 84 84 83 87 79 79 80 80 81 81 81 81 81 west_pÉ 86 89 88 89 89 88 88 89 88 88 87 86 87 87 88 87 87 87 86 87 89 89 89 89 89 89 89 diff 4 7 4 18 15 11 -7 -6 -9 -9 -5 1 -1 -1 4 3 4 0 7 8 9 9 8 8 8 8 8
B.
C.
D.
Collection 1 wcl_high 83.8 71 81 82 87 97 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 median Q3 max
Collection 1 west_palm_beach_high 88.0333 86 87 88 89 89 S1 = S2 = S3 = S4 = S5 = S6 =
mean min Q1 median Q3 max
Collection 1 diff 4.23333 30 6.6212 1.20886 0 S1 = S2 = S3 = S4 = S5 =
mean count stdDev stdError count missing
E. Woodcliff LakeIQR= 6 [Q1-1.5 (IQR), Q3 +1.5(IQR)] 81 – 1.5 (6)= 72 87+1.5 (6) = 96 [ 72; 96] Two Outliers exist on the graph. These outliers are found on points 71 and 97.
West Palm BeachIQR= 2 [Q1-1.5 (IQR), Q3 +1.5(IQR)] 87-1.5 (2)= 84 89+1.5 (2)= 92 [84; 92] No Outliers exist on the graph of West Palm Beach. F. Woodcliff LakeMean= 83.8 Stand. Dev= 6.23 West Palm BeachMean= 88.0 Stand. Dev= 1.07
G. The graph of Woodcliff Lake almost looks symmetrical; however, the shape is skewed left. The center of the graph lies on point 83. The spread (IQR) of the distribution is equal to 6. Lastly, two outliers are found on the graph at points 71 and 97. The graph of West Palm Beach has a shape that is skewed left also. Also, the center is located at point 88.0 on the graph. The spread of the distribution is equal to 2. Furthermore, the spread of the this graph is smaller, compared to the spread of the Woodcliff Lake graph. The data is more spread around the center in the West Palm Beach graph, unlike the data spread for the Woodcliff Lake graph. H.
3. A. Ho: =0 (There is no difference in price flights). Ha: > 0 (West Palm Beach has higher temperatures than Woodcliff Lake). B. X bar = 4.23 = 6.62 Of X Bar= 6.26/ 30 = 6.26/ 5.477 = 1.14 C. Z-score= 4.23/ 1.14 = 3.71 P= .9998
PICTURE:
-Reject the Ho because the Z-score is greater than 1.96. The data is significant, and the high temperatures between Florida and New Jersey are different. The temperatures in Florida for the month of June have been higher than those
Collection 1 Wii 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 12024608 6220750 3731182 3570776 2653313 2525967 2314095 2231039 1649787 1349828 1096840 1069401 993162 983142 933589 851461 838499 832696 710754 682713 673394 658398 617200 594653 560570 521200 515407 472151 460801 459511 Xbox_360 difference 5756795 4332978 3704444 3342056 2630394 2485636 2470098 2440496 2430426 1786275 1779800 1679095 1512459 1462204 1426260 1405849 1380521 1328973 1284811 1126679 1121767 1107815 1040103 1013020 981517 894730 881681 879842 867468 830352 -6267813 -1887772 -26738 -228720 -22919 -40331 156003 209457 780639 436447 682960 609694 519297 479062 492671 554388 542022 496277 574057 443966 448373 449417 422903 418367 420947 373530 366274 407691 406667 370841
Collection 1 Wii 1.7599e+06 459511 617200 892525 2231039 12024608 2.32471e+06 S1 = S2 = S3 = S4 = S5 = S6 = S7 =
mean min Q1 median Q3 max stdDev
Xbox_360 1.84615e+06 830352 1040103 1.41605e+06 2440496 5756795 1.16232e+06
[Q1 – 1.5 x IQR, Q3 + 1.5 x IQR] = Wii [-1803558.5, 4651797.5] and Xbox 360 [-1060486.5, 4541085.5] Outliers for Wii: 12024608 (#1), 6220750 (#2) Outliers for Xbox 360: 5756795 (#1) Graph Comparison Shape: Both graphs are skewed to the right. The Wii graph is more skewed then the Xbox360 graph Center: The median for the Xbox360 graph is larger then the median for the Wii graph. Spread: The standard deviation for the Wii graph is a little more then twice the standard deviation for the Xbox360 graph Outliers: The Wii graph has two outliers, the values in the #1 and #2 position. The Xbox360 graph has only one outlier, the value in the #1 position.
Hypothesis test: Ho: = 0 (no difference between Wii and Xbox360 sales) Ha: > 0 (Xbox360 sales are greater than Wii sales) “x” bar = 86255.2 x = 235329 z-score = .367 p = .36 conclusion: Fail to reject the null, unable to conclude a difference between Xbox360 sales and Wii sales.