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Euler-Lagrange Is extremised when Examples: a) Soap bubble- surface tension acts to minimise surface area b) Hamilton's principle in classical mechanics in 1d example we recovered f=ma Generalisations 1) Integrals in more than 1 dimension e.g. Euler-Lagrange equation Summation over repeated index is implied 2) If there are more fields, g, e.g. , we have Euler Lagrange equations for each one. If the fields are We have This is m equations for a=1, .. , m Example: A real particle physics Lagrangian i=0,1,2,3 We will get our equations of motion by extremising i.e. integrate over whole space-time Now just put this into Euler-Lagrange equation: -write it out long hand, or think of So Euler-Lagrange PH-355 Page 1 So Euler-Lagrange (*) This is the Klein-Gordon equation Consider plane-wave solutions Subbing into (*), For this to be a solution we need c.f. The klein-gordon equation describes relativistic scalar particles of mass m. Notes i) Looks (a bit) like KE-PE ii) term gives the mass to the particle Differential Equations 3) Series solutions (Frobenius' method) Consider (**) [linear, 2nd order, homogeneous (no RHS)] Some definitions If as finite regular point If finite is regular singular point If or diverge is irregular singular point Fuch's theorem If is regular or regular singular there exists at least one power series solution to (**) Method Assume a solution of the form Sub into (x) and expand. Then set coefficients to ensure each power of vanishes Example. consider a power series solution to about Set And sub in Write out sum For the whole thing to vanish, we need the coefficients of each power of x to vanish. PH-355 Page 2 i) Indicial equation: Look at the lowest power of x. Remember ii) Next order: We need Options: If If -Corresponds to mixing in an arbitrary amount of the other sol'n In order to separate the two solutions, we consider iii) General power Two solutions 1) 2) Comments In this case, both solutions converge for all x. (*) we have two power law solutions Example 2. This is Bessel's equation- arises whenever you work in cylindrical polars. Recalling the definitions r=0 is a regular singular point we expect one series solution Try Bang the guess into the equation Rearrange in terms of powers of r Again work power by power. Indicial equation: term: in general General term: recurence relation Solutions In the case, the determinator factor in the recurence relation is As n is even in our expansion, this vanishes if is an integer PH-355 Page 3 As n is even in our expansion, this vanishes if is an integer if is an integer the coefficients of the solution blow up bad! For integer, we only have one solution For integer at large n we have convergent for all r. A second solution In situations (such as integer case above) where we have only 1 soution 2nd soluton ’ h v p w xp try a function of the form Subbing in to our equation gives 2 types of term. If the isnt hit by a derivative, we have where our equation is If a derivative hits the h(x) we have powers of x The other class of term is -coefficients are determined by If we are to have solution, both sets of terms must vanish independently If is to vanish. We must set to be the original power series solution The remaining power series terms are then determined order by order as before 2nd solution = ln(x)(first solution)+(different power series) PH-355 Page 4

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posted: | 4/23/2013 |

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