Basketball

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Basketball
Shared by: Pete Roht
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452
posted:
9/12/2008
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Basketball

Jeff Peck & Catherine Lewis



Basketball





There are many aspects and skills involved in the game of basketball:

  



Dribbling Cutting (changing direction) Passing



Dribbling

   



An elastic collision is preferred Deflated ball loses energy to the floor Better inflated ball will lose less energy because not as deformed by floor Greater conservation of energy allows more predictable bounce



Changing Direction





Need traction between floor and shoes

μ must be large Static friction should be considerable











Passing

  



F=ma=m(v/t) Increasing time lessens force When receiving a pass: putting slightly bent arms out allows hands to decelerate ball over greater amount of time, thus decreasing force on chest



Shooting

 







This is perhaps the best-known skill An individual can be sub-par in every other aspect of the game, but if they can shoot well they become a prized asset of any team. In addition, essentially all super stars are known for there scoring ability



The Free-Throw





There are several factors that are integrally involved in the shot

  











Angle of release Initial velocity Acceleration Force (by player and gravity) Mass





We will not take into account the minimal air resistance



How does this happen?





First, we will look at the most basic shot: The free-throw





Though simple, this shot can often be the difference in a game







There is no jumping, driving, or any other extraneous movement to take into account



Statistics on Free Throw Shooting

x=4.57m y=1.32m (above head) Avg. Time=1.065sec Y=V0yt-1/2gt2 X=V0xt V0y=6.46m/s V0x=4.29m/s tanθ=Y/X=6.46/4.29=56.41° V0=(6.46m/s2+4.29m/s2)1/2=7.75m/s VY=V0Y-gt= -3.98m/s At basket: V= (3.98m/s2 + 4.29m/s2)1/2= 5.85m/s Maximum Position: 0=6.46m/s-gt t=.659s Y=V0Yt-1/2gt2=2.13m (above head)



X=V0xt=2.83m



Conservation of Energy: h1=1.77m h2=1.77m + 2.13m=3.91m h3=3.05m V1=7.75m/s V2=4.29m/s V3=5.85m/s

K1 + U1 = K2 + U2 = K3 + U3 1/2mv12 + mgh1 = 1/2mv22 + mgh2 = 1/2mv32 + mgh3 ½(7.75m/s)2 + g(1.77m)= ½ (4.29m/s)2+g(3.91m)= ½ (5.85)2 + g(3.05m) 47.38J = 47.52J = 47.00 J



Spin











 



Players shoot with backspin on the ball Unlike baseball, velocity is too small for spin to affect air resistance When ball hits the rim or backboard, it will bounce off in the opposite direction in a vertical path toward net Backspin gives a greater chance of shot going in if it hits anything Spin helps shooter develop muscle memory so they can reproduce the same shot repeatedly



Jump shot





Now we will explore a more difficult shot: the jump shot



Jump Shot





This shot includes all the variables from the Free Throw in addition to a few new aspects

  



The height off the floor Lateral movement Velocity of body at time of release



Jump Shot

 



This makes the Jump Shot much more difficult In order to eliminate as many variables as possible in their shots, players attempt to jump to the same height, release at the same time, and not drift to either side while shooting





The great players can often make shots with these additional variables. However, a good shooter will try to make the shot as easy as possible to enhance the likelihood of making the shot.



Sources

  



http://www.u.arizona.edu/~clc1/lab3/lab3.ht ml www.geocities.com/thesciencefiles/physics of/basketball.html www.hesston.edu/academics/faculty/nelson k/physicsResearch/basketball/Mainpage.ht m-3k




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