# Unit 10 Quadratic and Factoring by b7O6Dpvr

VIEWS: 9 PAGES: 5

• pg 1
```									Unit 10 Quiz 2A                                                     Name:_____________________

Factor the expression.

1. (A1.5.C)    d2 + 10d + 9

2. (A1.5.C) k2 + kf – 2f2

3. (A1.5.C)

4. (A1.5.C) 4x2 – 81y2

5. (A1.5.C)

6. (A1.5.C) 16m2 – 24mn + 9n2

Solve the equation using the zero-product property.

7. (A1.5.C)

8. (A1.5.C)

9. (A1.5.C)
10.(A1.5.C)

11.(A1.5.C)

12.(A1.5.C) Tasha is planning an expansion of a square flower garden in a city park. If each side of the original garden is
increased by 7 m, the new total area of the garden will be 144 m2. Find the length of each side of the original
garden.

13.(A1.5.C) The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the
length and width of the playground.

14.(A1.5.C)Explain how to factor the following trinomial.
g2 + 4g – 60
Unit 10 Quiz 2

1. ANS:
(d + 9)(d + 1)

PTS:   1              DIF: L3            REF: 9-5 Factoring Trinomials of the Type x^2 + bx + c
OBJ:   9-5.1 Factoring Trinomials        NAT: NAEP 2005 A3c | ADP J.1.4
STA:   WA 1.5.5       TOP: 9-5 Example 1                     KEY: polynomial | factoring trinomials

2. ANS:
(k + 2f)(k – f)

PTS:   1              DIF: L3            REF: 9-5 Factoring Trinomials of the Type x^2 + bx + c
OBJ:   9-5.1 Factoring Trinomials        NAT: NAEP 2005 A3c | ADP J.1.4
STA:   WA 1.5.5       TOP: 9-5 Example 3                     KEY: polynomial | factoring trinomials

3. ANS:

PTS:   1              DIF: L2               REF: 9-7 Factoring Special Cases
OBJ:   9-7.1 Factoring Perfect-Square Trinomials                  NAT: ADP J.1.4
STA:   WA 1.5.5       TOP: 9-7 Example 1
KEY:   polynomial | factoring trinomials | perfect-square trinomial

4. ANS:
(2x + 9y)(2x – 9y)

PTS:   1              DIF: L3               REF: 9-7 Factoring Special Cases
OBJ:   9-7.2 Factoring the Difference of Squares                 NAT: ADP J.1.4
STA:   WA 1.5.5       TOP: 9-7 Example 4
KEY:   polynomial | factoring trinomials | difference of squares

5. ANS:

PTS:   1              DIF: L3               REF: 9-7 Factoring Special Cases
OBJ:   9-7.1 Factoring Perfect-Square Trinomials                  NAT: ADP J.1.4
STA:   WA 1.5.5       TOP: 9-7 Example 2
KEY:   polynomial | factoring trinomials | perfect-square trinomial

6. ANS:
(4m – 3n)2

PTS:   1              DIF: L3               REF: 9-7 Factoring Special Cases
OBJ:   9-7.1 Factoring Perfect-Square Trinomials                  NAT: ADP J.1.4
STA:   WA 1.5.5       TOP: 9-7 Example 2
KEY:   polynomial | factoring trinomials | perfect-square trinomial

7. ANS:
x = –1 or x = 1

PTS:   1              DIF: L2              REF: 10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:            10-4 Example 1
KEY:   zero-product property | solving quadratic equations

8. ANS:
1
n = 0 or n =
10

PTS:   1              DIF: L2              REF: 10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:            10-4 Example 1
KEY:   zero-product property | solving quadratic equations

9. ANS:
z = –3 or z = 9

PTS:   1               DIF: L2              REF: 10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:             10-4 Example 2
KEY:   factoring | solving quadratic equations

10. ANS:
z = 1 or z = –2

PTS:   1               DIF: L2              REF: 10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:             10-4 Example 2
KEY:   factoring | solving quadratic equations

11. ANS:
c = 0 or c = 4

PTS:   1             DIF:   L2            REF:   10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:             10-4 Example 2
KEY:   factoring | solving quadratic equations

12. ANS:
5m

PTS:   1               DIF: L2              REF: 10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:             10-4 Example 4
KEY:   factoring | solving quadratic equations | word problem | problem solving

13. ANS:
length = 16 yd, width = 21 yd

PTS:   1               DIF: L3              REF: 10-4 Factoring to Solve Quadratic Equations
NAT:   NAEP 2005 A4a | NAEP 2005 A4c | ADP J.3.5 | ADP J.5.3
STA:   WA 1.5.6 | WA 2.2.2bTOP:             10-4 Example 4
KEY:   factoring | solving quadratic equations | word problem | problem solving

ESSAY

14. ANS:
[4]  Since the second sign is negative, one of the factors of 60 will be positive and one will
be negative. Find two factors of 60 that have a difference of 4. 10 – 6 = 4; Since the
first sign is positive, 10 is positive and 6 is negative. The factors of g2 will be g.
(g+ 10)(g – 6)
[3]  correct explanation with one minor factoring error
[2]  correct explanation with one error in the signs of the factors
[1]  correct factors with no explanation

PTS:   1              DIF: L3             REF: 9-5 Factoring Trinomials of the Type x^2 + bx + c
OBJ:   9-5.1 Factoring Trinomials         NAT: NAEP 2005 A3c | ADP J.1.4
STA:   WA 1.5.5       TOP: 9-5 Example 3
KEY:   extended response | rubric-based question | polynomial | factoring trinomials

```
To top