Solubility Friday, October 5 Please get your textbooks. DMA: Why do we call water a “universal” solvent? Today: Solubility notes C1-C2 vocabulary well plate testing Water-a Universal Solvent? Everything is “soluble,” or will dissolve in water to some extent given enough time. As a class… What happens when oil is added to water? What happens when food coloring is added to water? What happens when salt or sugar is added to water? Solubility Soluble: one substance dissolves in another Insoluble: one substance does NOT dissolve in another “Like dissolves like” Solubility Data Copy data table into notebook. Write Soluble or Insoluble in each box. Dye#2 is a teacher demonstration. Solubility Vocabulary Solubility: how much of something will dissolve in a substance Solute: (see p.24) Solvent: (see p.24) Solution: _________ mixture of two or more substances Monday, October 8 Please get your textbook. DMA: What does “soluble” mean? Make sure you have the definitions for these words in your notebook: Solubility (p. 39) Solute (p. 24) Solvent (p. 24) Solubility: how much of something will dissolve in a substance Solute: the dissolved substance in a solution; the component present in the smaller amount Solvent: component of a solution present in the largest amount Solution: homogeneous mixture of two or more substances Solution Concentration Concentration is crucial to all life: --red/white blood cell counts in blood --oxygen gas dissolved in air and water Common way of expressing this: g solute / g solution usually 100 or 1,000 g solution Ex. Problem: solution concentration One teaspoon of sucrose (table sugar) , which has a mass of 10g, is dissolved in 240g of water. What is the concentration of the solution, expressed as grams sucrose per 100 g solution? (% sucrose by mass, or pph) What is the concentration in ppt? pph= parts per hundred, ppt = per thousand Example solution concentration 10 g sugar +240 g water = 250 g solution 10 g sugar/250g solution = 0.04 or 4% To get ppt, multiply the % by 10 and divide by 1000 40 /1000 or 40 ppt this is the same ratio as the original solution Solubility Reading Assignment Read C1 and C2 individually (p.39-43) (skip “Your Turn” sections for now) We will go over the bold vocabulary words together and fill in the definitions in 8 min. Solubility Vocabulary #2 Saturated: the solvent has dissolved as much solute as possible at a certain temperature Unsaturated: (book) Supersaturated: (book) Solubility Curve: plotted line of the amount of solute that will dissolve vs. temperature Solution Concentration: (book) Saturated: the solvent has dissolved as much solute as possible at a certain temperature Unsaturated: contains a lower concentration of solute than is possible at a certain temperature Supersaturated: contains a higher concentration of solute than a saturated solution at a temp. Solubility Curve: compares the mass of solute that will dissolve in solute at many temperatures Solution Concentration: quantity of solute dissolved in a specific quantity of solvent C1 and C2 Your Turn problems Your Turn p. 41 Read up to problem 1. Your Turn p. 42: Group works on #1-4. Everyone answers in notebooks. Your Turn p.44: Group works on # 2, 4. Everyone answers in notebooks. Do #1=6 on worksheet. HOMEWORK if not finished in class. Tuesday, October 9 Please get your textbook. DMA: Fill in the blanks: 5 = ______ = _______ 100 1,000 1,000,000 Same numbers go in these blanks: 5% or pph = _____ ppt = ________ ppm Fill in the blanks: 5 = 50 = 50,000 100 1,000 1,000,000 Check for Understanding You need to make a solution of fertilizer and water that has a 5 % concentration. 1. What is the solvent? 2. What is the solute? 3. To make 1,000 mL (1 Liter) of solution, How many grams of fertilizer should you use? How much water? Answers to Your Turn Problems p. 42 1a. 80 grams 1b. 42 grams 2a. 42 g- 25 g = 17 g 2b. 42/100 = 25/x so x = 58.1 g 3a. 7 mg 3b. 9 mg 4. 0.9 mg because it is only100 g water vs. 1000 Answers to Your Turn problems p.44 1a. solute = sugar (the smaller amount) 1b. solvent = water (the larger amount) 2a. 17 g sugar/200 g solution = 0.085 or 8.5% 2b. 34 g sugar/400 g solution =0.085 or 8.5% 4a. the dissolved oxygen (DO) concentration will be less in the warmer water b. because less oxygen dissolves in warmer water Solution concentration problems #7-12 on the worksheet can be solved with algebra using cross-multiplication. 1. Find the saturated line on the graph at that temperature. 2. Write this number divided by 100 3. Set this equal to x and the given amount. For example, #7: 46g KCl/100 g water = 40 g KCl/ x g water x = 86.95 g water Wednesday, October 10 Please get your textbook. DMA: Looking at the 2 graphs on p. 40 and 41, explain how to change the temperature if: a. You want more solid to dissolve in water. b. You want more gas to dissolve in water. DMA To get more solid to dissolve in water, I would raise the temperature. To get more gas to dissolve in water, I would lower the temperature.
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