2H2(g) + O2(g) ? 2H2O(g)

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					2H2(g) + O2(g)  2H2O(g)
2H2(g) + O2(g)  2H2O(g)




  5[2H2(g) + O2(g)  2H2O(g)]
  10H2(g) + 5O2(g)  10H2O(g)
2H2(g) + O2(g)  2H2O(g)




 5[2H2(g) + O2(g)  2H2O(g)]
 10H2(g) + 5O2(g)  10H2O(g)
  Reaction Stoichiometry

     Limiting Reactant = H2(g)
      Excess Reactant = O2(g)
Theoretical Yield = 10 Molecules H2O

				
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posted:11/4/2012
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