2
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Description
دروس الرياضيات مع تصحيح
Document Sample


.2
:
. 19 27
. 20 29
. 20 28
.2
: .1.2
an a n n a §
:
an = a × a × … × a
n
a1= a : a §
1
a-n = : n a §
an
a0 = 1. : a :
:
1 1
55=5×5×5×5×5 , 4-2= =
42 16
.2.2
. n m b a
• am × an = a m + n .
• (am)n = am n .
am
• = am – n
an
• (ab)n = an bn .
n
a n a
• = n
b b
1 :
.2
:
52 ×54 = 52+4 =5 6 =15625 ( 62)3 = 62×3=66=46656
42 2-5 -3 1 1
=4 =4 = 3 = (4×5)2 =42×52 = 16 × 25=400
45 4 64
4 42 16
( )2 = 2 =
5 5 25
: .1.2.2
an a-n = a0 =1: n a
n
(-1)n =1 n -
(-1)n =-1 n -
:
(-2)5 = - 25 , (-7)4 =74
19 26
20 31
2 :
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