Electron in a box by 62I0JCj

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```									Electrons in a box

If the electron is confined to move in one dimension within the box then the de Broglie waves
associated with the electron will be standing waves. Since the wave must have zero value (i.e a
node) at the walls of the box only waves that have a wavelength () = 2L/n are allowed. L is the
length of the box and n is a positive integer.

The de Broglie wavelength () of an electron of mass me travelling with velocity v = h/mewhere
h is Planck’s constant.

The kinetic energy of the electron = ½ mev2.

Kinetic energy = ½[mv2] = ½[me(h/me)2] = ½[me(nh/2Lme)2] = ½[n2h2/4meL2] = n2h2/8meL2

The kinetic energy (EK) of the electron = n2h2/8meL2

The potential energy inside the box will be zero and so the expression for the kinetic energy of
the electron is actually the total energy of the electron.

You can see from the equation that the energy of the electron is quantised – the only possible
values are with n = 1, 2, 3 etc. This means that the energy levels can have values h2/8meL2,
4h2/8meL2, 9h2/8meL2, 16h2/8meL2 and so on.

E4 = 16h2/8meL2       n=4

L

E2 = 9h2/8meL2        n=3

E2 = 4h2/8meL2        n=2

E1 = h2/8meL2         n=1

Examples of waves fitting into a box, the energy levels and the probability functions are shown
below for n=1,2,3 and and 4. We have assumed the amplitude of the wave associated with the
electron to be sinusoidal and the probability of the electron being at a particular point to be
proportional to the amplitude of the wave squared. This follows from Schrödinger’s wave
equation.

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