TERM 1 COMMON TEST (/75) - Memorandum by 95ON2H

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									Grade 12 Mathematical Literacy

               TERM 1 COMMON TEST (/75) − Memorandum
QUESTION 1:
1.1 72 km + 15% × 72 km √
    = 72 km + 10,8 km √
    = 82,8 km √                                                                                     (3)

1.2     30 bricks = R240,00
        1 brick = R240,00 ÷ 30 √
                = R8,00 √                                                                           (2)

1.3    15 : 90
       1 : 90 ÷ 15 √
           =6√                                                                                      (2)

1.4     Sipho will receive 2/5√ of R100 000
        = 2/5 × R100 000 √
        = R40 000 √

        So, Thembi will receive R100 000 − R40 000 √                                                (4)

1.5     $1 = R10,52
        → $1 215,00 = R10,52 × 1 215 √
        = R12 781,80 √                                                                              (2)
                                                                                                          [13]

QUESTION 2:
2.1
    2.1.1 1  = 1 000 m
          → 1,25  = 1 000 m × 1,25 √
                    = 1 250 m √                                                                    (2)

        2.1.2 1 255 kg − 22,5% × 1 255 kg √
              = 1 255 kg − 282,38 kg √
              = 972,6 kg √                                                                          (3)

        2.1.3 R7,542 = $1,00
              R1,00 = $1,00 ÷ 7,542 √
              R15 084 = $1,00 ÷ 7,542 × 15 084 √
                       = $2 000 √                                                                   (3)

2.2
        2.2.1 1 lb = 450 g
        → ½ lb = 450 g ÷ 2 √
               = 225 g √                                                                            (2)

        2.2.2 1 oz = 30 g
              9 oz = 30 g × 9 √
                   = 270 g √                                                                        (2)



This common test was set by the highly intelligent and organized teachers in the Pholela Cluster.
Grade 12 Mathematical Literacy

        2.2.3 Sugar needed = ¾ cup √
                          = ¾ × 250 m √
                          = 187,5 m √                                                              (3)

       2.2.4    Temperature in C = (Temperature in F – 32) × 0,556
                                  = (350√ − 32) × 0,556
                                  = 318√ × 0,556
                                  = 176,808√
                                  ≈ 180√ (rounded off to the nearest 10)                          (4)

        2.2.5 3 dozen (36) = 4 eggs √
              → 72 tarts = 8 eggs √                                                                 (2)
                                                                                                          [21]

QUESTION 3:
3.1
    3.1.1 R18,11 √                                                                                  (1)

        3.1.2 January 2008 = R40,47     February 2008 = R44,47
              → Price increase = R44,47 − R40,47
                               = R4,00 √                                                            (1)

3.2     20 loaves = R126,50
        1 loaf = R126,50 ÷ 20 √
              = R6,33 √     (rounded off to two decimal places)                                     (2)

3.3     Onions : salt
        = 1√ : 0,5 √                                                                                (2)

3.4
        3.4.1 January 2008 = R162,23
              February 2008 = R212,65
              Price increase = R212,65 − R162,23 √
                             = R50,42 √                                                             (2)

                                 R50, 42
        3.4.2 % increase =                √√ × 100 √
                                 R162, 23
                              = 31,1%√        (rounded off to one decimal place)                    (4)

3.5     Soup: January 2008 = R9,64
              February 2008 = R9,30
              Price decrease = R0,34 √
                               R0, 34
              → % decrease =          √ × 100 √
                               R9, 64
                             = 3,5% √ (rounded off to one decimal place)                            (4)
OR:
                Price change = −R0,34 √
                               R0, 34
                → % change =           √ × 100 √
                                R9, 64
                               = −3,5% √ (rounded off to one decimal place)
This common test was set by the highly intelligent and organized teachers in the Pholela Cluster.
Grade 12 Mathematical Literacy

3.6     Whole basket:       January 2008 = R782,02 √
                            February 2008 = R833,14 √
                            Price increase = R833,14 − R782,02
                                            = R51,12 √
                                 R51, 12
                → % increase =           √ × 100
                                R782, 02
                              ≈ 6,5% √ (rounded off to one decimal place)                           (5)

3.7     Price before VAT = R9,30 ÷√ 1,14√
                         = R8,16√ (rounded off to two decimal places)                               (3)
OR:
        Price with VAT = 114%
        Price before VAT = 100%
        → 114% = R9,30 √
        1% = R9,30 ÷ 114
        100% = R9,30 ÷ 114 × 100 √
              = R8,16 √ (rounded off to two decimal places)

3.8     Some of the prices increase, while some decrease.√ But the price of the whole
        basket increases. √                                                      (2)
                                                                                                           [26]


QUESTION 4:
4.1
    4.1.1 Bracket 2. √                                                                              (1)

        4.1.2 Bracket 4. √                                                                          (1)

4.2     R10 260 √                                                                                   (1)

4.3     R25 200 + 25% of taxable income above R140 000√√                                            (2)

4.4     Yearly taxable income = R230 000 (tax bracket 2) √

        Yearly tax = R25 200 + 25% × (R230 000√ − R140 000)
                   = R25 200 + [25% × R90 000] √
                   = R25 200 + R22 500 √
                   = R47 700 √

        Tax rebate for someone less than 65 years old = R10 260 √

        Actual yearly tax = R47 700 − R10 260 √
                          = R37 440 √

        → Monthly tax = R37 440 ÷ 12 √
                      = R3 120 √ (rounded off to two decimal places)
                                                                                                    (10)
                                                                                                           [15]



This common test was set by the highly intelligent and organized teachers in the Pholela Cluster.

								
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