TERM 1 COMMON TEST (/75) - Memorandum by 95ON2H

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```									Grade 12 Mathematical Literacy

TERM 1 COMMON TEST (/75) − Memorandum
QUESTION 1:
1.1 72 km + 15% × 72 km √
= 72 km + 10,8 km √
= 82,8 km √                                                                                     (3)

1.2     30 bricks = R240,00
1 brick = R240,00 ÷ 30 √
= R8,00 √                                                                           (2)

1.3    15 : 90
1 : 90 ÷ 15 √
=6√                                                                                      (2)

1.4     Sipho will receive 2/5√ of R100 000
= 2/5 × R100 000 √
= R40 000 √

So, Thembi will receive R100 000 − R40 000 √                                                (4)

1.5     \$1 = R10,52
→ \$1 215,00 = R10,52 × 1 215 √
= R12 781,80 √                                                                              (2)
[13]

QUESTION 2:
2.1
2.1.1 1  = 1 000 m
→ 1,25  = 1 000 m × 1,25 √
= 1 250 m √                                                                    (2)

2.1.2 1 255 kg − 22,5% × 1 255 kg √
= 1 255 kg − 282,38 kg √
= 972,6 kg √                                                                          (3)

2.1.3 R7,542 = \$1,00
R1,00 = \$1,00 ÷ 7,542 √
R15 084 = \$1,00 ÷ 7,542 × 15 084 √
= \$2 000 √                                                                   (3)

2.2
2.2.1 1 lb = 450 g
→ ½ lb = 450 g ÷ 2 √
= 225 g √                                                                            (2)

2.2.2 1 oz = 30 g
9 oz = 30 g × 9 √
= 270 g √                                                                        (2)

This common test was set by the highly intelligent and organized teachers in the Pholela Cluster.
Grade 12 Mathematical Literacy

2.2.3 Sugar needed = ¾ cup √
= ¾ × 250 m √
= 187,5 m √                                                              (3)

2.2.4    Temperature in C = (Temperature in F – 32) × 0,556
= (350√ − 32) × 0,556
= 318√ × 0,556
= 176,808√
≈ 180√ (rounded off to the nearest 10)                          (4)

2.2.5 3 dozen (36) = 4 eggs √
→ 72 tarts = 8 eggs √                                                                 (2)
[21]

QUESTION 3:
3.1
3.1.1 R18,11 √                                                                                  (1)

3.1.2 January 2008 = R40,47     February 2008 = R44,47
→ Price increase = R44,47 − R40,47
= R4,00 √                                                            (1)

3.2     20 loaves = R126,50
1 loaf = R126,50 ÷ 20 √
= R6,33 √     (rounded off to two decimal places)                                     (2)

3.3     Onions : salt
= 1√ : 0,5 √                                                                                (2)

3.4
3.4.1 January 2008 = R162,23
February 2008 = R212,65
Price increase = R212,65 − R162,23 √
= R50,42 √                                                             (2)

R50, 42
3.4.2 % increase =                √√ × 100 √
R162, 23
= 31,1%√        (rounded off to one decimal place)                    (4)

3.5     Soup: January 2008 = R9,64
February 2008 = R9,30
Price decrease = R0,34 √
R0, 34
→ % decrease =          √ × 100 √
R9, 64
= 3,5% √ (rounded off to one decimal place)                            (4)
OR:
Price change = −R0,34 √
R0, 34
→ % change =           √ × 100 √
R9, 64
= −3,5% √ (rounded off to one decimal place)
This common test was set by the highly intelligent and organized teachers in the Pholela Cluster.
Grade 12 Mathematical Literacy

3.6     Whole basket:       January 2008 = R782,02 √
February 2008 = R833,14 √
Price increase = R833,14 − R782,02
= R51,12 √
R51, 12
→ % increase =           √ × 100
R782, 02
≈ 6,5% √ (rounded off to one decimal place)                           (5)

3.7     Price before VAT = R9,30 ÷√ 1,14√
= R8,16√ (rounded off to two decimal places)                               (3)
OR:
Price with VAT = 114%
Price before VAT = 100%
→ 114% = R9,30 √
1% = R9,30 ÷ 114
100% = R9,30 ÷ 114 × 100 √
= R8,16 √ (rounded off to two decimal places)

3.8     Some of the prices increase, while some decrease.√ But the price of the whole
basket increases. √                                                      (2)
[26]

QUESTION 4:
4.1
4.1.1 Bracket 2. √                                                                              (1)

4.1.2 Bracket 4. √                                                                          (1)

4.2     R10 260 √                                                                                   (1)

4.3     R25 200 + 25% of taxable income above R140 000√√                                            (2)

4.4     Yearly taxable income = R230 000 (tax bracket 2) √

Yearly tax = R25 200 + 25% × (R230 000√ − R140 000)
= R25 200 + [25% × R90 000] √
= R25 200 + R22 500 √
= R47 700 √

Tax rebate for someone less than 65 years old = R10 260 √

Actual yearly tax = R47 700 − R10 260 √
= R37 440 √

→ Monthly tax = R37 440 ÷ 12 √
= R3 120 √ (rounded off to two decimal places)
(10)
[15]

This common test was set by the highly intelligent and organized teachers in the Pholela Cluster.

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