# PHYSICS 242 BLOCK 5 DRILL SET, FALL '09 NAME

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```							PHYSICS 242             BLOCK 5 DRILL SET, FALL ‘09                   NAME _____________________________
Slide this paper under Marteena 308’s door any time before 7:50 AM Friday, September 18, or give it to me in
Marteena 312 by 8:00 AM that day. Use one different equation from the Block 5 objectives for each problem.
For DIRECTION, choose only from these: right (→), left (←), toward the top (↑), toward the bottom (↓), into the
·
paper (⊗), out of the paper (O ), UNDETERMINED (for a zero magnitude vector), or NONE (for a scalar).
1. A straight wire segment is 5.08 cm long and carries a current of 78.9 A into the paper (⊗) through a large
uniform magnetic field of 6.00 T to the right (→). Find the force exerted by the field on the segment.
I find the magnitude using __ = (__)(__)(__)(sin __).
I am using φ = ____˚. (Put symbols in the above blanks)        ________________
(Put a number above for φ .)                                      MAGNITUDE
_________________
DIRECTION
2. A uniform magnetic field makes an angle of 38.2˚ with a flat surface. Thus the magnetic field makes an angle of
90.0˚ – 38.2˚ = 51.8˚ with a normal to the surface. The area of the surface is 2.34 × 10–5 m2. The resulting
magnetic flux through the surface is 5.67 µWb. Calculate the magnitude of the magnetic field.
EQUATION USED (ONE EQUAL SIGN)                           SOLUTION                                  ANSWER

3. An electron is moving toward the top (↑) at 2.99 × 108 m/s through a large magnetic field of 6.00 T to the right
(→). Find the force the magnetic field exerts on the electron.
VECTOR EQUATION USED                                   SOLUTION                              FORCE ANSWER
I find the magnitude using __ = (____)(__)(__)(sin __).
(Put symbols in the above blanks) ________________
→ →                                       MAGNITUDE
I am using φ = ____˚. υ ×  B ’s direction is _________.
(Put a number above for φ .)

________________
DIRECTION
4. We see the edge of a 44 turn flat circular coil of area 0.00555 m2 in magnitude. The eye (not ours) looks along
the coil’s axis, “seeing” a clockwise current of 9.87 A. Find the coil’s magnetic dipole moment (with our
“DIRECTION” answer relative to the paper, not relative to the eye, so our answer is either right (→) or left
(←)).
VECTOR EQUATION USED                              VECTOR SOLUTION                                 ANSWER
eye
________________
coil      MAGNITUDE

________________
DIRECTION
5. A coil has a magnetic dipole moment of 2.41 A·m2 to the right (→). It is in a large external magnetic field of
6.00 T, also to the right (→). Find the torque the field exerts on the coil.
I find the magnitude using __ = (___)(___)(sin __).
I am using φ = ____˚. (Put symbols in the above blanks)   ________________
(Put a number above for φ .)                                 MAGNITUDE
_________________
DIRECTION

```
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