Solution-Of-Triangles-8 by nehalwan

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									                                  Solution Of Triangles
                                         Part-8


Q-1: The internal bisectors of the angles of the DABC meet the sides BC, CA and AB at P, Q,


and R respectively. Show that the area of the DPQR is equal to

Solution:

Let the bisector of the angles meet at I. then I is the incenter. Let ID^BC, then ID = inradius =
r.




Q=ÐBIP-ÐBID =




                                                 Fig (24)



Now from DDIP,
Q-2: Show that the DABC is equilateral if its circumradius is double of the inradius.

Solution:

Here R=2r (given) .We know that,
So, triangle is equilateral.

								
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