Solution Of Triangles Part-8 Q-1: The internal bisectors of the angles of the DABC meet the sides BC, CA and AB at P, Q, and R respectively. Show that the area of the DPQR is equal to Solution: Let the bisector of the angles meet at I. then I is the incenter. Let ID^BC, then ID = inradius = r. Q=ÐBIP-ÐBID = Fig (24) Now from DDIP, Q-2: Show that the DABC is equilateral if its circumradius is double of the inradius. Solution: Here R=2r (given) .We know that, So, triangle is equilateral.
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