Techniques for Automated Deduction
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Decision-Procedure Based Theorem Provers
Tactic-Based Theorem Proving
Inferring Loop Invariants
CS 294-8
Lecture 12
Prof. Necula CS 294-8 Lecture 12 1
Review
Source language
VCGen
FOL Theories
?
Goal-directed Sat. proc Sat. proc
…
proving 1 n
Prof. Necula CS 294-8 Lecture 12 2
Combining Satisfiability Procedures
• Consider a set of literals F
– Containing symbols from two theories T1 and T2
• We split F into two sets of literals
– F1 containing only literals in theory T1
– F2 containing only literals in theory T2
– We name all subexpressions:
p1(f2(E)) is split into f2(E) = n Æ p1(n)
• We have: unsat (F1 Æ F2) iff unsat(F)
– unsat(F1) Ç unsat(F2) ) unsat(F)
– But the converse is not true
• So we cannot compute unsat(F) with a trivial
combination of the sat. procedures for T1 and T2
Prof. Necula CS 294-8 Lecture 12 3
Combining Satisfiability Procedures. Example
• Consider equality and arithmetic
f(f(x) - f(y)) f(z) xy y+zx 0z
yx
x=y
f(x) = f(y)
0=z
f(x) - f(y) = z
false f(f(x) - f(y)) = f(z)
Prof. Necula CS 294-8 Lecture 12 4
Combining Satisfiability Procedures
• Combining satisfiability procedures is non trivial
• And that is to be expected:
– Equality was solved by Ackerman in 1924, arithmetic by
Fourier even before, but E + A only in 1979 !
• Yet in any single verification problem we will have
literals from several theories:
– Equality, arithmetic, lists, …
• When and how can we combine separate satisfiability
procedures?
Prof. Necula CS 294-8 Lecture 12 5
Nelson-Oppen Method (1)
1. Represent all conjuncts in the same DAG
f(f(x) - f(y)) f(z) Æ y ¸ x Æ x ¸ y + z Æ z ¸ 0
f
-
¸ f ¸
f f
¸ +
y x z 0
Prof. Necula CS 294-8 Lecture 12 6
Nelson-Oppen Method (2)
2. Run each sat. procedure
• Require it to report all contradictions (as usual)
• Also require it to report all equalities between nodes
f
-
¸ f ¸
f f
¸ +
y x z 0
Prof. Necula CS 294-8 Lecture 12 7
Nelson-Oppen Method (3)
3. Broadcast all discovered equalities and re-run sat.
procedures
• Until no more equalities are discovered or a contradiction
arises f
x Contradiction
-
¸ f ¸
f f
¸ +
y x z 0
Prof. Necula CS 294-8 Lecture 12 8
What Theories Can be Combined?
• Only theories without common interpreted symbols
– But Ok if one theory takes the symbol uninterpreted
• Only certain theories can be combined
– Consider (Z, +, ·) and Equality
– Consider: 1 · x · 2 Æ a = 1 Æ b = 2 Æ f(x) f(a) Æ f(x) f(b)
– No equalities and no contradictions are discovered
– Yet, unsatisfiable
• A theory is non-convex when a set of literals entails a
disjunction of equalities without entailing any single
equality
Prof. Necula CS 294-8 Lecture 12 9
Handling Non-Convex Theories
• Many theories are non-convex
• Consider the theory of memory and pointers
– It is not-convex:
true ) A = A’ Ç sel(upd(M, A, V), A’) = sel(M, A’)
(neither of the disjuncts is entailed individually)
• For such theories it can be the case that
– No contradiction is discovered
– No single equality is discovered
– But a disjunction of equalities is discovered
• We need to propagate disjunction of equalities …
Prof. Necula CS 294-8 Lecture 12 10
Propagating Disjunction of Equalities
• To propagate disjunctions we perform a case split:
• If a disjunction E1 Ç … Ç En is discovered:
Save the current state of the prover
for i = 1 to n {
broadcast Ei
if no contradiction arises then return “satisfiable”
restore the saved prover state
}
return “unsatisfiable”
Prof. Necula CS 294-8 Lecture 12 11
Handling Non-Convex Theories
• Case splitting is expensive
– Must backtrack (performance --)
– Must implement all satisfiability procedures in incremental
fashion (simplicity --)
• In some cases the splitting can be prohibitive:
– Take pointers for example.
upd(upd(…(upd(m, i1, x), …, in-1, x), in, x) =
upd(…(upd(m, j1, x), …, jn-1, x) Æ
sel(m, i1) x Æ … Æ sel(m, in) x
entails Çj k ij ik
(a conjunction of length n entails n2 disjuncts)
Prof. Necula CS 294-8 Lecture 12 12
Forward vs. Backward Theorem Proving
Prof. Necula CS 294-8 Lecture 12 13
Forward vs. Backward Theorem Proving
• The state of a prover can be expressed as:
H1 Æ … Æ Hn )? G
– Given the hypotheses Hi try to derive goal G
• A forward theorem prover derives new hypotheses, in
hope of deriving G
– If H1 Æ … Æ Hn ) H then
move to state H1 Æ … Æ Hn Æ H )? G
– Success state: H1 Æ … Æ G Æ … Hn )? G
• A forward theorem prover uses heuristics to reach G
– Or it can exhaustively derive everything that is derivable !
Prof. Necula CS 294-8 Lecture 12 14
Forward Theorem Proving
• Nelson-Oppen is a forward theorem prover:
– The state is L1 Æ … Æ Ln Æ : L )? false
– If L1 Æ … Æ Ln Æ : L ) E (an equality) then
– New state is L1 Æ … Æ Ln Æ : L Æ E )? false (add the equality)
– Success state is L1 Æ … Æ L Æ … Æ : L Æ … Ln )? false
• Nelson-Oppen provers exhaustively produce all
derivable facts hoping to encounter the goal
• Case splitting can be explained this way too:
– If L1 Æ … Æ Ln Æ : L ) E Ç E’ (a disjunction of equalities) then
– Two new states are produced (both must lead to success)
L1 Æ … Æ Ln Æ : L Æ E )? false
L1 Æ … Æ Ln Æ : L Æ E’ )? false
Prof. Necula CS 294-8 Lecture 12 15
Backward Theorem Proving
• A backward theorem prover derives new subgoals
from the goal
– The current state is H1 Æ … Æ Hn )? G
– If H1 Æ … Æ Hn Æ G1 Æ … Æ Gn ) G (Gi are subgoals)
– Produce “n“ new states (all must lead to success):
H1 Æ … Æ Hn )? Gi
• Similar to case splitting in Nelson-Oppen:
– Consider a non-convex theory:
H1 Æ … Æ Hn ) E Ç E’
is same as H1 Æ … Æ Hn Æ : E Æ : E’ ) false
(thus we have reduced the goal “false” to subgoals : E Æ : E’ )
Prof. Necula CS 294-8 Lecture 12 16
Programming Theorem Provers
• Backward theorem provers most often use heuristics
• If it useful to be able to program the heuristics
• Such programs are called tactics and tactic-based
provers have this capability
– E.g. the Edinburgh LCF was a tactic based prover whose
programming language was called the Meta-Language (ML)
• A tactic examines the state and either:
– Announces that it is not applicable in the current state, or
– Modifies the proving state
Prof. Necula CS 294-8 Lecture 12 17
Programming Theorem Provers. Tactics.
• State = Formula list £ Formula
– A set of hypotheses and a goal
• Tactic = State ! (State ! a) ! (unit ! a) ! a
– Continuation passing style
– Given a state will invoke either the success continuation with
a modified state or the failure continuation
• Example: a congruence-closure based tactic
cc (h, g) c f =
let e1, …, en new equalities in the congruence closure of h
c (h [ {e1, …, en}, g)
– A forward chaining tactic
Prof. Necula CS 294-8 Lecture 12 18
Programming Theorem Provers. Tactics.
• Consider an axiom: 8x. a(x) ) b(x)
– Like the clause b(x) :- a(x) in Prolog
• This could be turned into a tactic
clause (h, g) c f = if unif(g, b) = f then
s (h, f(a))
else
f ()
– A backward chaining tactic
Prof. Necula CS 294-8 Lecture 12 19
Programming Theorem Provers. Tacticals.
• Tactics can be composed using tacticals
Examples:
• THEN : tactic ! tactic ! tactic
THEN t1 t2 = ls.lc.lf.
let newc s’ = t2 s’ c f in t1 s newc f
• REPEAT : tactic ! tactic
REPEAT t = THEN t (REPEAT t)
• ORELSE : tactic ! tactic ! tactic
ORELSE t1 t2 = ls.lc.lf.
let newf x = t2 s c f in t1 s c newf
Prof. Necula CS 294-8 Lecture 12 20
Programming Theorem Provers. Tacticals
• Prolog is just one possible tactic:
– Given tactics for each clause: c1, …, cn
– Prolog : tactic
Prolog = REPEAT (c1 ORLESE c2 ORELSE … ORELSE cn)
• Nelson-Oppen can also be programmed this way
– The result is not as efficient as a special-purpose
implementation
• This is a very powerful mechanism for semi-automatic
theorem proving
– Used in: Isabelle, HOL, and many others
Prof. Necula CS 294-8 Lecture 12 21
Techniques for Inferring Loop Invariants
Prof. Necula CS 294-8 Lecture 12 22
Inferring Loop Invariants
• Traditional program verification has several elements:
– Function specifications and loop invariants
– Verification condition generation
– Theorem proving
• Requiring specifications from the programmer is often
acceptable
• Requiring loop invariants is not acceptable
– Same for specifications of local functions
Prof. Necula CS 294-8 Lecture 12 23
Inferring Loop Invariants
• A set of cutpoints is a set of program points :
– There is at least one cutpoint on each circular path in CFG
– There is a cutpoint at the start of the program
– There is a cutpoint before the return
• Consider that our function uses n variables x:
• We associate with each cutpoint an assertion Ik(x)
• If a is a path from cutpoint k to j then :
– Ra(x) : Zn ! Zn expresses the effect of path a on the values of
x at j as a function of those at k
– Pa(x) : Zn ! B is a path predicate that is true exactly of those
values of x at k that will enable the path a
Prof. Necula CS 294-8 Lecture 12 24
Cutpoints. Example.
0 • p01 = true
L = len(A) r01 = { A Ã A, K Ã 0, L Ã len(A), S Ã 0,
K=0 m à m}
S=0
• p11 = K + 1 < L
1
r11 = { A Ã A, K Ã K + 1, L Ã L,
S = S + A[K]
S à S + sel(m, A + K), m à m}
K ++
K<L
• p12 = K + 1 ¸ L
2 r12 = r11
return S
• Easily obtained through sym. eval.
Prof. Necula CS 294-8 Lecture 12 25
Equational Definition of Invariants
• A set of assertions is a set of invariants if:
– The assertion for the start cutpoint is the precondition
– The assertion for the end cutpoint is the postcondition
– For each path from i to j we have
8x. Ii(x) Æ Pij(x) ) Ij(Rij(x))
• Now we have to solve a system of constraints with the
unknowns I1, …, In-1
– I0 and In are known
• We will consider the simpler case of a single loop
– Otherwise we might want to try solving the inner/last loop
first
Prof. Necula CS 294-8 Lecture 12 26
Invariants. Example.
0 1. I0 ) I1(r0(x))
• The invariant I1 is established initially
L = len(A)
K=0 ro
S=0
2. I1 Æ K+1 < L ) I1(r1(x))
1 • The invariant I1 is preserved in the loop
S = S + A[K]
K ++ r1
K<L 3. I1 Æ K+1 ¸ L ) I2(r1(x))
2 • The invariant I1 is strong enough (i.e.
useful)h
return S
Prof. Necula CS 294-8 Lecture 12 27
The Lattice of Invariants
true • Weak predicates satisfy
the condition 1
– Are satisfied initially
• Strong predicates satisfy
condition 3
– Are useful
• A few predicates satisfy
condition 2
– Are invariant
false
– Form a lattice
Prof. Necula CS 294-8 Lecture 12 28
Finding The Invariant
• Which of the potential invariants should we try to
find ?
• We prefer to work backwards
– Essentially proving only what is needed to satisfy In
– Forward is also possible but sometimes wasteful since we
have to prove everything that holds at any point
Prof. Necula CS 294-8 Lecture 12 29
Finding the Invariant
true • Thus we do not know the
“precondition” of the loop
• The weakest invariant that
is strong enough has most
chances of holding initially
• This is the one that we’ll
try to find
false
– And then check that it is
weak enough
Prof. Necula CS 294-8 Lecture 12 30
Induction Iteration Method
true • Equation 3 gives a
predicate weaker than
any invariant
I1 Æ K+1 ¸ L ) I2(r1(x))
I1 ) ( K+1 ¸ L ) I2(r1(x)))
W0 = K+1 ¸ L ) I2(r1(x))
• Equation 2 suggest an
iterative computation of
the invariant I1
false I1 ) (K+1 < L ) I1(r1(x)))
Prof. Necula CS 294-8 Lecture 12 31
Induction Iteration Method
• Define a family of predicates
W0 = K+1 ¸ L ) I2(r1(x))
Wj = W0 Æ K+1 < L ) Wj-1(r1(x))
• Properties of Wj
– Wj ) Wj-1 ) … ) W0 (they form a strengthening chain)
– I1 ) Wj (they are weaker than any invariant)
– If Wj-1 ) Wj then
• Wj is an invariant (satisfies both equations 2 and 3):
Wj ) K+1 < L ) Wj(r1(x))
• Wj is the weakest invariant
(recall domain theory, predicates form a domain, and we use
the fixed point theorem to obtain least solutions to recursive
equations)
Prof. Necula CS 294-8 Lecture 12 32
Induction Iteration Method
W = K+1 ¸ L ) I2(r1(x)) // This is W0
W’ = true
while (not (W’ ) W)) {
W’ = W
W = (K+1 ¸ L ) I2(r1(x))) Æ (K + 1 < L ) W’(r1(x)))
}
• The only hard part is to check whether W’ ) W
– We use a theorem prover for this purpose
Prof. Necula CS 294-8 Lecture 12 33
Induction Iteration.
true • The sequence of Wj
approaches the weakest
invariant from above
W0
W1 • The predicate Wj can quickly
W2 become very large
W3 – Checking W’ ) W becomes
harder and harder
• This is not guaranteed to
terminate
false
Prof. Necula CS 294-8 Lecture 12 34
Induction Iteration. Example.
0
• Consider that the strength
L = len(A) condition is:
K=0 ro I1 ) K ¸ 0 Æ K < len(A) (array bounds)
S=0
• We compute the W’s:
1 W0 = K ¸ 0 Æ K < len(A)
S = S + A[K] W1 = W0 Æ K+1<L ) K+1¸ 0 Æ K+1<len(A)
K ++ r1 W2 = W0 Æ K+1 < L )
K<L (K + 1 ¸ 0 Æ K + 1 < len(A) Æ
2 K+2< L ) K+2 ¸ 0 Æ
K+2 < len(A)))
return S …
Prof. Necula CS 294-8 Lecture 12 35
Induction Iteration. Strengthening.
• We can try to strengthen the inductive invariant
• Instead of:
Wj = W0 Æ K+1 < L ) Wj-1(r1(x))
we compute:
Wj = strengthen (W0 Æ K+1 < L ) Wj-1(r1(x)))
where strengthen(P) ) P
• We still have Wj ) Wj-1 and we stop when Wj-1 ) Wj
– The result is still an invariant that satisfies 2 and 3
Prof. Necula CS 294-8 Lecture 12 36
Strengthening Heuristics
• One goal of strengthening is simplification:
– Drop disjuncts: P1 Ç P2 ! P1
– Drop implications: P1 ) P2 ! P2
• A good idea is to try to eliminate variables changed in
the loop body:
– If Wj does not depend on variables changed by r1 (e.g. K, S)
– Wj+1 = W0 Æ K+1 < L ) Wj(r1(x))
= W0 Æ K+1 < L ) Wj
– Now Wj ) Wj+1 and we are done !
Prof. Necula CS 294-8 Lecture 12 37
Induction Iteration. Strengthening
true • We are still in the “strong-
enough” area
W0 • We are making bigger steps
W1
W2 • And we might overshoot
W’1
W3 then weakest invariant
• We might also fail to find
W’2
any invariant
• But we do so quickly
false
Prof. Necula CS 294-8 Lecture 12 38
One Strengthening Heuristic for Integers
• Rewrite Wj in conjunctive normal form
W1 = K ¸ 0 Æ K < len(A) Æ (K + 1 < L ) K + 1 ¸ 0 Æ K + 1 < len(A))
= K ¸ 0 Æ K < len(A) Æ (K + 1 ¸ L Ç K + 1 < len(A))
• Take each disjunction containing arithmetic literals
– Negate it and obtain a conjunction of arithmetic literals
K+1 < L Æ K+1 ¸ len(A)
– Weaken the result by eliminating a variable (preferably a
loop-modified variable)
E.g., add the two literals: L > len(A)
– Negate the result and get another disjunction:
L · len(A)
W1 = K ¸ 0 Æ K < len(A) Æ L · len(A) (check that W1 ) W2)
Prof. Necula CS 294-8 Lecture 12 39
Induction Iteration
• We showed a way to compute invariants algoritmically
– Similar to fixed point computation in domains
– Similar to abstract interpretation on the lattice of
predicates
• Then we discussed heuristics that improve the
termination properties
– Similar to widening in abstract interpretation
Prof. Necula CS 294-8 Lecture 12 40
Theorem Proving. Conclusions.
• Theorem proving strengths
– Very expressive
• Theorem proving weaknesses
– Too ambitious
• A great toolbox for software analysis
– Symbolic evaluation
– Decision procedures
• Related to program analysis
– Abstract interpretation on the lattice of predicates
Prof. Necula CS 294-8 Lecture 12 41