# Chemical Formula Simulation by unm8F6

VIEWS: 0 PAGES: 7

• pg 1
```									In this activity, you will be simulating the writing of chemical formulas by cutting out some
shapes and putting them together to find out how many of each it takes to completely fill up all
of the connectors. This is, in a way, how ions get together to form molecules. Anions (negative
ions that want to get more electrons, which are represented by the consonants) get together with
cations (positive ions that want to get rid of electrons, which are represented by the vowels) to
form molecules. The number of electrons that an ion wants to exchange with its partner is
represented by its oxidation number or charge.

Safety Concerns: Use care in working with scissors and keep them out of reach of children.

Procedure:
1) Rough-cut (don’t waste too much time trying to get it perfect) all of the pieces on the
next page.
3) Combine the given pieces in the combinations below and write the formula.
4) Don’t throw away the pieces, you will need them again.

Some simple rules for combinations:
1) When combined, there should be no unused          or          in the end.

2) You may rotate, flip, and turn the pieces anyway that you want. Do not cut or break them.

3) When you write the formula, the positive one (the vowel) always goes first.

4) The number of each piece in the finished product is written as a subscripted number without
the oxidation number. You don’t need to write “1” if there is only one of a piece. For example,
two A+1 pieces combined with one D-2 piece would have the formula A2D, not A2D1.

Problems:
1)      Write the formula when A and C combine.
2)      Write the formula when A and D combine.
3)      Write the formula when A and F combine.
4)      Write the formula when A and G combine.
5)      Write the formula when I and B combine.
6)      Write the formula when I and D combine.
7)      Write the formula when I and G combine.
8)      Write the formula when U and C combine.
9)      Write the formula when U and F combine.
10)     Write the formula when U and G combine.
11)

A+1          E+1           B-1    C-1

A+1          E+1           B-1    C-1

A+1          E+1           B-1    C-1

I+2          O+2          D-2      F-2

+2           +2
D-2          F-2
I           O

D-2          F-2
I+2         O+2

U+3          G-3

U+3
G-3
Lab 26
In this activity, you will be using the pieces that you cut out in the Chemical Formulas
Simulation to investigate single and double displacement reactions.

Single Displacements Reactions:
A single displacement reaction is one in which an element replaces an ion in a molecule.
Because there is only one switch, this is called a single displacement reaction. Examples of this
type of reaction are Mg + CuCl2 MgCl2 + Cu and NaI + Cl2  NaCl + I2. In the first reaction
Mg replaced Cu and in the second reaction, Cl replaced I. The common mistake that students
make is to just put the ions together on the product side in the same proportions that they were on
the reactant side.
The following is a BAD EXAMPLE Na + MgCl2  Mg + NaCl2. There is no such thing as
NaCl2. We know that the formula for table salt is NaCl and it must be written that way. Your
paper pieces are going to help you avoid this problem if you use them properly. Another
problem that students encounter is trying to replace a positive ion with a negative one. You must
always switch a positive with a positive and a negative with a negative. If you use the paper
pieces correctly, you won’t run into this problem either.

Procedure:
1) Build the molecules represented by the symbols on the reactant side of the equation and
fill in the subscripts (Don’t write “1”s). Don’t cough while you have them laid out. ;-)
2) Switch the appropriate ions and make sure that they are full and correct. Take the
reactants apart to put the products together. You won’t have enough pieces for both.
3) Write the formulas of the products. Don’t forget that the positive ion goes first.

Problems:

Example; IC2 + D  ID + C

A   + I_F_ 

I_C_ + D 

O + U_D_ 

U_B_ + G 

O + U_G_ 
Now try it with some real chemicals:
Remember:
i) Oxidation numbers can be found on the periodic table for most ions
ii) The elements H, O, F, Br, I, N, and Cl are diatomic. This means that if they are
unattached to anything, they always have a 2 after them. H2, O2, F2, Br2, I2, N2, and
Cl2. THIS IS ONLY WHEN THEY ARE UNATTACHED, NOT WHEN THEY
ARE PART OF A MOLECULE.
iii) All of the rules above still apply (positive one goes first, etc.)

Mg + H_Cl_ 

Na_S_ + I2 

CaO + Br2 

Al_O_ + Ba 

Double Displacement Reactions:
A double displacement reaction is a reaction between two molecules. In this type of reaction, the
molecules switch partners. But just like before, they don’t just switch, they rearrange to make
the correct chemical formulas. An example is: NaI + CuCl2  NaCl + CuI2. Notice that the Cl2
was not simply combined with the Na because we all know that there’s no such thing as NaCl2.
The correct formula for the products must be written and the paper pieces will help you do that.
It doesn’t matter if you switch the positive ion or the negative ion, you will get the correct
answer as long as you write the positive ion first.

Problems:
Example IC2 + EB  OB2 + EC

E_D_ + I_C_ 

A_D_ + I_F_ 

O_C_ + E_D_ 

U_G_ + E_C_ 

O_F_ + I_G_ 
Now try it with some real chemicals and remember:
i)       You can’t do these if you don’t know the oxidation numbers of the ions, so look them
up on the periodic table first.
ii)      Don’t just put them together as-is. Write the correct formulas.
iii)     Positive ions go first.

Problems:

NaCl + CaI2 

KNO3 + LiF 

H2SO4 + Li2O 

Fe2O3 + NaOH 

CuSO4 + HNO3 

General Trend for Oxidation Numbers
+1 +2                                                             0
+3 +/-4 –3 –2 -1

Multiple Oxidation Numbers
Lab 27
In the last simulation, you used papers to represent chemical reactions. But many of the
reactions that you wrote violated the Law of Conservation of matter. That law says that matter
can neither be created nor destroyed. That means that if you have two carbon atoms before a
reaction, you must have two carbon atoms after the reaction. If you look at the example from the
last simulation, this law was violated.

IC2 + EB  IB2 + EC

It’s important to know that the chemicals on the left side of the reaction arrow are called
reactants and the chemicals on the right side of the reaction arrow are called products.
In the products, there were to “C”s. But in the products there was only one. That violates the
Law of Conservation of Matter. To fix this, we have to “balance” the equation.
One way to balance this equation would be to write it:

IC2 + EB2  OB2 + EC2            (NOTE: THIS IS AN EXAMPLE OF WHAT NOT TO DO)

But there is no such thing as EB2 and there is no such thing as EC2. Those formulas are written
incorrectly and you are not allowed to do that.
But you can add more of each compound by putting coefficients in front of it in the equation.

IC2 + 2EB  IB2 + 2EC

Now there is one “I” on the left and one on the right. There are 2 “C”s on the left and 2 on the
right. There are 2 “E”s on the left and 2 on the right. There are 2 “B”s on the left and 2 on the
right. You are allowed to add more chemicals, you just can’t change the formula of the
chemicals.

With your element cutouts, this equation would look like this:

C-1                     E+1      B-1                                      E+1      C-1


B-1

I+2    C-1     +                                    I+2       -1
B
+
E+1      B-1                                      E+1      C-1
Now use your pieces to balance the following equations following these rules:
1) All of the compounds must be correctly built.
2) The number of each element must be equal on both sides of the reaction arrow.
3) The number of each element is written BEFORE the chemical formula in the balanced
equation and is a full-size number, not subscripted.
An extra sheet of elements is included here because you will certainly need them. As you go
along, you might not need to build the chemicals anymore to get the answer, but be sure to

1) I_C_ + D 

2) O + U_D_ 

3) U_B_ + G 

4) A_D_ + I_F_ 

5) O_C_ + E_D_ 

6) U_G_ + E_C_ 

Now try it with real chemicals:
a) assign oxidation numbers to each atom
b) determine what type of reaction it is (single displacement, etc.)
c) finish the equation
d) balance the equation
1) CaCl2 + Na 
2) KF + O2 
3) CuI2 + LiBr 
4) MgO + HCl 
5) H2 + O2 
6) Al + Cl2 

```
To top