# Hyp Test Article Excelformat Nan

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```					Name       Nandita Ghosh
Class time 64Z -Online
Find an article in a newspaper, magazine or on the internet which makes a claim about
ONE population mean or ONE population proportion.
Copy or print out the article and include a copy in your project, along with the source.
The article can be found at
http://www.usatoday.com/news/health/weightloss/2010-02-11-obesekidsdieearlier11_ST_N.htm
Claim : 32% of children and teens are obese or overweight,

State how you will collect your data. (Convenience sampling is not acceptable.)
I will search online for this data. I will use stratified sampling by dividing US into different states or strata
I will collect data containing the percentage of children obese per state in the US

Conduct your survey. You must have more than 50 responses in your sample.
When you hand in your final project, attach the tally sheet or the packet of questionnaires
I got the data for the survery from here
http://en.wikipedia.org/wiki/Obesity_in_the_United_States#Prevalence_by_state

State the statistics that are a result of your data collection: sample size, sample mean, and sample s
sample size : 51
sample mean : 14.29%
sample standard deviation : 0.0321

Make 2 copies of the appropriate solution sheet.
Record the hypothesis test on the solution sheet, based on your experiment. Do a DRAFT
solution first on one of the solution sheets and check it over carefully. Have a classmate
check your solution to see if it is done correctly. Make your decision using a 5% level of
The solution sheet can be accessed :
Solution Sheet

Create a graph that illustrates your data.
This may be a pie or bar chart or may be a histogram or box plot, depending on the nature
of your data. Produce a graph that makes sense for your data and gives useful visual
information about your data. You may need to look at several types of graphs before you
I have created a histogram to display the data . Please find the histogram here :
Histogram

Write your summary (in complete sentences and paragraphs, with proper grammar and correct spel

1. Brief discussion of the article, including the source.
Source of the article :
http://www.usatoday.com/news/health/weightloss/2010-02-11-obesekidsdieearlier11_ST_N.htm
Obsese children are at a higher risk to die early from different diseases such as cardiac, liver and

2. Statement of the claim made in the article (one of the hypotheses).
The claim in the article is that 32% of children and teens in the US are obese

3. Detailed description of how, where, and when you collected the data, including the
sampling technique.
Did you use cluster, stratified, systematic, or simple random sampling (using a random
I used stratified sampling. Since I wanted to calculate data all over the US, I sampled data for all the states in

4. Conclusion about the article claim in light of your hypothesis test.
This is the conclusion of your hypothesis test, stated in words, in the context of the
situation in your project in sentence form, as if you were writing this conclusion for a non-
From the hypothesis test we can conclude that the claim in the article that the percentage of obese
children in US =32% is incorrect.
5. Sentence interpreting your confidence interval in the context of the situation in your project.
We are 95% confident that the true population mean of the average percentage of obese children in US is betw
states or strata

mean, and sample standard deviation, OR sample size and number of successes.

ar and correct spelling) that describes the project. The summary MUST include:

for all the states in the US
hildren in US is between 14.281% and 14.299%
Solution Sheet

a. H o : u = 32% of children in US are obsese
b. H a : u is not = 32%

c. In words, CLEARLY state what your random variable X or P' represents.
X bar represents the % of children who are obese in the US

d. State the distribution to use for the test.
Student-T distribution will be used for this test since we don’t know the population standard
deviation
X bar ~ t df where df = n-1
Hence X bar ~ t50

e. What is the test statistic?
Test statistic is x bar= 14.29%

f. What is the p -value? In 1 – 2 complete sentences, explain what the p -value means for
this problem.
p-value is 0
If the null hypothesis is true there is a 0 probability that the sample mean is 14.29% or less
OR 49.71% or more

g. Use the previous information to sketch a picture of this situation. CLEARLY, label and
scale the horizontal axis and shade the region(s) corresponding to the p -value.

Figure 1

h. Indicate the correct decision (“reject” or “do not reject” the null hypothesis), the reason
for it, and write an appropriate conclusion, using complete sentences.

i. Alpha: 0.05
ii. Decision: Reject the Null Hypothesis
iii. Reason for decision: Since p value < alpha, the decision is to reject the Null hypothesis

iv. Conclusion: at 5% level of significance, the sample data do not show sufficient evidence
that the average percentage of obsese children in the US is 32%

i. Construct a 95% Confidence Interval for the true mean or proportion. Include a sketch of
the graph of the situation. Label the point estimate and the lower and upper bounds of the
Confidence Interval.
Using the T interval to find 95% confidence interval for x bar = 14.29, s=-.032102, n =51,
we get ( 14.281, 14.299)

Figure 2
Bin        Frequency
Histogram
5           0
7           0               16
9           2
11           4               14
13          13
15          14
17           9               12
19           3
21           5               10
23           1
Frequency
25           0
27           0                8
29           0
31           0                6
33           0
35           0
4
More                 0

2

0
5   7   9   11   13       15     17    19     21     23     25     27
Percentage of obese children across different states
Frequency

27         29   31   33   35   More
cross different states
State &
Obesity
District of    Obese Children
Rank
Columbia
Alabama                      16.70%          3
Arizona                      12.20%         40
Arkansas                     16.40%          9
California                   13.20%         41
Connecticut                  12.30%         49
D.C.                         14.80%         43
Delaware                     22.80%         22
Florida                      14.40%         39
Georgia                      16.40%         12 Average     14.29%
Hawaii                       13.30%         50 s         0.032102
Idaho                        10.10%         31
Illinois                     15.80%         26
Indiana                      15.60%         11
Iowa                         12.50%         19
Kansas                       14.00%         23
Kentucky                     20.60%          7
Louisiana                    17.20%          4
Maine                        12.70%         34
Maryland                     13.30%         28
Massachusett
s                            13.60%         48
Michigan                     14.50%         10
Minnesota                    10.10%         30
Mississippi                  17.80%          1
Missouri                     15.60%         13
Montana                      11.10%         45
New
Hampshire                    12.90%         35
New Jersey                   13.70%         42
New Mexico                   16.80%         38
New York                     15.30%         37

North Carolina               19.30%         16
North Dakota                 12.10%         21
Ohio                         14.20%         17
Oklahoma                     15.40%          8
Oregon                       14.10%         29
Pennsylvania                 13.30%         24
Rhode Island                 11.90%         46

South Carolina               18.90%             5
South Dakota    12.10%   20
Tennessee       20.00%    6
Texas           19.10%   15
Utah             8.50%   44
Vermont         11.30%   47
Virginia        13.80%   27
Washington      10.80%   32
West Virginia   20.90%    2
Wisconsin       13.50%   25
Wyoming          8.70%   33

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