What Will You Learn

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							An-Najah National University
Civil Engineering Department
   Faculty of Engineering
  Engineering Management
           Course
        Nabil Dmaidi



           Nabil Dmaidi        1
Your Expectations of Me
              Be prepared
               Be on time
     Teach for full 50 minute period
          Fair grading system
       Front load the class work
       Do not humiliate students
          Practice golden rule
      Provide real world examples
            Make you think
                 Nabil Dmaidi          2
Topics
   1)  Introduction of construction project planning and scheduling
   2)   Construction scheduling techniques
   3) Preparation and usage of bar charts
   4) Preparation and usage of the Critical Path Method (CPM)
   5) Preparation and usage of Precedence Diagramming Method (PDM)
   6)  Issues relating to determination of activity duration
   7)  Contractual provisions relating to project schedules
   8)  Resource leveling and constraining
   9)  Time cost tradeoff
   10) Schedule monitoring and updating
   11) Management function.
   12) Communicating schedule
   13) Cost Control

   14)   Safety and Quality control



                                   Nabil Dmaidi                        3
Management Functions

   Planning
    –   Where the organization wants to be in the
        future and how to get there.




                         Nabil Dmaidi               4
Management Functions

   Organizing
    –   Follows planning and reflects how the
        organization tries to accomplish the plan.
    –   Involves the assignment of tasks, grouping of
        tasks into departments, and allocation of
        resources.




                         Nabil Dmaidi                   5
Management Functions

   Leading
    –   The use of influence to motivate employees to
        achieve the organization's goals.
    –   Creating a shared culture and values,
        communicating goals to employees throughout
        the organization, and infusing employees to
        perform at a high level.



                        Nabil Dmaidi                    6
Management Functions

   Controlling
    –   Monitoring employees' activities, determining
        if the organization is on target toward its goals,
        and making corrections as necessary.




                           Nabil Dmaidi                      7
Management Skills

 Conceptual Skill—the ability to see the
  organization as a whole and the relationship
  between its parts.
 Human Skill—The ability to work with and
  through people.
 Technical Skill—Mastery of specific
  functions and specialized knowledge.

                    Nabil Dmaidi                 8
Decision Making

 Decision: a choice made from two or more
  alternatives.
 Part of all four managerial functions
 Decisions are made on the basis of:
    –   Rationality
    –   Bounded Rationality
    –   Intuition

                        Nabil Dmaidi         9
Rationality

 Problem is clear and unambiguous.
 Single goal.
 All alternatives are known.
 Clear and constant preferences.
 Maximum payoff.
 The decision is in the best interest of the
  organization—not the manager.
                     Nabil Dmaidi               10
               MANAGEMENT HIERARCHY

        Management Level               Responsibility



        TOP MANAGEMENT              LONG RANGE PLANNING




      MIDDLE MANAGEMENT             SHORT TERM PLANNING




SUPERVISORS                                   EXECUTION




                     Nabil Dmaidi                         11
                  Project Life Cycle
                   Definition           Planning            Execution               Delivery
Level of effort




                  1. Goals              1. Schedules       1. Status reports   1. Train customer
                  2. Specifications     2. Budgets         2. Changes          2. Transfer documents
                  3. Tasks              3. Resources       3. Quality          3. Release resources
                  4. Responsibilities   4. Risks           4. Forecasts        4. Reassign staff
                  5. Teams              5. Staffing                            5. Lessons learned

                                                       Nabil Dmaidi                                    12
Phase One
   Definition Stage
    –   Defining Specifications
    –   Establishing objectives
    –   Determining tasks
    –   Forming teams
    –   Assigning responsibilities
   Low level of effort


                       Nabil Dmaidi   13
Phase Two
   Planning Stage
    –   Estimating time and cost
    –   Scheduling activities and resources
    –   Identifying and determining risks
    –   Assigning teams
   Level of effort increases



                       Nabil Dmaidi           14
Phase Three
   Execution Stage
    –   Producing physical product
    –   Collecting data
    –   Monitoring project performance
    –   Identifying the changes
    –   Forecasting new measures
   Highest level of effort


                      Nabil Dmaidi       15
Phase Four
   Delivery Stage
    –   Training customer
    –   Transferring documents
    –   Releasing resources
    –   Reassigning staff
    –   Documenting lessens learned
   Low level of effort


                     Nabil Dmaidi     16
  Integrated Management of Projects
                                             Customer

Political, social, economic,                                                       Management, facilities
                                     Environmental analysis
and technological                                                                  Financial conditions
                                     External                Internal
                                                Firm
   Signal                                     mission,                                 Signal
   Opportunities                           goals, strategies                           Weaknesses
   and Threats                                                                         and strengths
                                                Priorities


                                                 Projects
                         System                                   Environment
                                                                  and Culture
                                           Scope
                                                         Organization
                               Work Breakdown
                                  Networks                     Leadership
                               Resources                          Teams
                                 Cost                                   Partners

                                       Project Implementation


                                            Nabil Dmaidi                                                17
Definition of a Project
   From the Project Management Institute:


       “A temporary endeavor
     undertaken to create a unique
         product or service”


                    Nabil Dmaidi             18
What is a Project?
 Temporary
 Unique
 There is an end
 Duration is finite
 Characteristics are progressively elaborated




                   Nabil Dmaidi                  19
Examples of projects include:

• Developing a new product or service.
• Effecting a change in structure, staffing, or style of
   an organization.
• Designing a new transportation vehicle.
• Developing or acquiring a new or modified
   information system.
• Constructing a building or facility.
• Running a campaign for political office.
• Implementing a new business procedure or process


                       Nabil Dmaidi                        20
Examples of a Project
   Installing a computer network in a building
   Opening a new store/factory
   Automating an assembly line
   Design a new car model
   Introducing a new car model
   Building a bridge




                       Nabil Dmaidi               21
İn the construction
   Project Management is the sum of all
    activities such as Planning,organising
    ,implementing and controlling a project
    in order to meet the client’s expectation
    from start to finish within the planned
    period, budget and quality.”



                    Nabil Dmaidi                22
The purpose of Project
Management
 The purpose of Project Management is to
  foresee or predict as many of the dangers
  and problems as possible and to
 Plan
 Organize
 Coordinate
 Control


                  Nabil Dmaidi                23
The components of Project Management


   Scope
   Time
   Cost
   Quality
   Human Resource
   Communications
   Risk
   Procurement

                     Nabil Dmaidi      24
Project Constraints
 Time
 Cost
 Quality




              Nabil Dmaidi   25
Control

   The heart of the project management system is
    CONTROLLING the execution of the works.

 The purpose of this control is to determine and
  predict deviations in a project so corrective actions
  can be taken.
 The milestones of the control process are as follows:
To determine the aim
 Determine the control standarts
 To determine the strategic points
 To evaluate the actual results and to compare to the
  planned

                       Nabil Dmaidi                       26
   İt defines the quality of the management




                    Nabil Dmaidi               27
    Skills for Project Management

 Good Planning
 Conflict Resolution
 Creativity
 Flexibility
 Negotiation
 Communication
    –   Client
    –   Subcontractors
    –   Team
                         Nabil Dmaidi   28
    Dimensions of Project Management

 Performance
 Money
 Time


 Plan should consider all of these before
  starting
 Manager needs to track them during project


                    Nabil Dmaidi               29
Project Management
   Project Management is the Science and Art
    of Enhancing the Probability of Success by
    Inspired Leadership using Structured
    Techniques for Planning that Integrate
    Technical Performance, Scheduling and
    Budgeting (1).


    (1)-Fundamentals of Space Systems - Pisacane and Moore



                                Nabil Dmaidi                 30
Project Management
   Guide and Direct the effort
    –   Science and Art
    –   Enhancing the Probability of Success
    –   Leadership (Inspired or not)
    –   Structured Techniques for Planning
          CriticalPath — the path of a network that requires
           the longest period of time to complete
          Integrate Technical Performance, Scheduling and
           Budgeting

                           Nabil Dmaidi                         31
Objectives of a Project
Management Structure

 Deliver a product that meets the
  requirements of the project’s objectives.
  (Systems Engineering)
 Deliver a product that meets the
  requirements of the contract delivery
  schedule
 For commercial companies: meet profit
  objectives
                    Nabil Dmaidi              32
Prerequisites
 Must have adequate resources and facilities
  available to meet the delivery schedule
 Terms of the contract must be realistic and
  adequate to cover the cost to perform under
  the contract




                   Nabil Dmaidi                 33
Project Manager’s Authority
   Technical Decisions
    –   Directing the design approach
    –   Selecting subsystems or components
    –   Identifying type and scope of tests
   Commercial Decisions
    –   Make or Buy
    –   Selecting/recommending subcontractors or
        vendors

                        Nabil Dmaidi               34
Continued
   Administrative Decisions
    –   Selecting and assigning personnel
    –   Scheduling personnel, resources and equipment
   Monetary Decisions
    –   Determining the expenditure of funds




                        Nabil Dmaidi                    35
Project Management Tools
   PERT/GANTT Charts
    –   Program Evaluation Review Technique
                  — element of work
          Activity
          Event— Start or Completion Point
                •   Network — Graphic representation of a program
                    consisting of activities and events which are shown as
                    interconnected paths




                              Nabil Dmaidi                                   36
Planning
   The road to project failure is paved with poor
    plans

PLANNING: Influencing the future by
             making decisions today based on
  missions, needs and objectives.

   It is an art not science.


                         Nabil Dmaidi                37
Categories of planning:


 Time
 Cost
 Resources
 Quality
 Contingency



                Nabil Dmaidi   38
Time Planning


   When to start

   when to finish

   Time plans will be transformed to schedule
    (time scale)

                     Nabil Dmaidi                39
Time planning steps

 1) Divide project into component parts

 2) Sequencing component parts in order of
   accomplishment

 3) Assign durations to each component
   part

                 Nabil Dmaidi                40
Cost Planning
   Allocating direct and indirect costs to the project
    components

   Summation of components costs. Total cost
    should equal the budget.

   ( cost / schedule integration)




                        Nabil Dmaidi                      41
Resources Planning

   Construction Resources includes:

   money
   Material
   Human resources
   Equipments and tools


   Resources should be planned considering the budget.

   Attention to critical resources for project success
                            Nabil Dmaidi                  42
Quality Planning
   what is the minimum accepted quality?

   Should I exceed the required quality?

   How can I achieve this quality?




                     Nabil Dmaidi           43
Contingency (Risk) Planning

   Planning for variability and uncertainty

   “What if” planning to include items subject
    to variability which are significantly impact
    project cost and time




                     Nabil Dmaidi                   44
Integrating Planning

   Integration of time, cost and resource
    planning against the same basic structure
    (WBS)

   Resource budgeting against time

   Cost budgets plotted against time

                     Nabil Dmaidi               45
Thousands of tasks
   The psychologists say our brains can
    normally comprehend around 7-9 items
    simultaneously.

   So, divide and subdivide the project.




                     Nabil Dmaidi           46
The WBS
(Work Breakdown Structure)
   IT is used to break down the project from
    one main and relatively big entity into
    smaller, defined, manageable and
    controllable units, usually called work
    groups or tasks, or, at the finest level of
    detail (which is undesirable) activities



                     Nabil Dmaidi                 47
Take care!!!
 The deeper you go into the lower levels of
  the WBS, the more detailed knowledge
  you’ll need to know.
 A good rule of thumb is the rule of 1-5-5-5,
  which entails that each level be broken
  down into a maximum of five lower levels.



                   Nabil Dmaidi                  48
Who develops the WBS?
 A WBS is developed by the A/E at the end
  of the design phase
 and/or by the bidders during the proposal
  (procurement phase)




                  Nabil Dmaidi                49
The CWBS
(Contract Work breakdown Structure )
    After contract award, the project manager
     expands the WBS into a contract work
     breakdown structure (CWBS).

    as the initial step in the PLANNING
     process.



                     Nabil Dmaidi                50
The CWBS
   The extended CWBS must include the
    levels at which required reporting
    information is summarized for submittal to
    the Owner




                    Nabil Dmaidi                 51
Uses of the WBS
 The WBS is used to report program status
  externally to the Owner.
 The CWBS is used internally to plan the
  program in detail and to collect status
  information on a periodic basis for the
  lowest level of the CWBS, namely the
  schedule activities.
 The basis for technical planning and project
  achievement.
                   Nabil Dmaidi                  52
The CWBS
 it is a major task to undo.
 Why???
 Because cost collections begins at a CWBS
  element,




                  Nabil Dmaidi                53
WBS/CWBS
   The individuals assigned the responsibility
    for WBS/CWBS development should never
    lose sight of the fact that the WBS is used
    for technical planning and status
    achievement.




                    Nabil Dmaidi                  54
                                                               House
 Level 1                                                        1.0




                           Structural                                           fine               Electrical
Level 2                      Work                                              works                Works
                               1.1                                              1.2                   1.3




               Sub-                      Super-                                    Doors &                 Light
                                                                   Finishing       Windows   Conduiting
Level 3      Structure                  Structure                     1.21         frames      1.3.1
                                                                                                          Fittings
               1.1.1                      1.1.2                                      1.2.2                1.3.2




     Earthwork Foundation         Columns Roof slabs        Plaster       Floor tile            Level 4
      1.1.1.1   1.1.1.2            1.1.2.1 1.1.2.2          1.2.1.1        1.2.1.2




Excavation   Backfilling
 1.1.1.1.1   1.1.1.1.2                                                                            Level 5
                                                    Nabil Dmaidi                                                55
Conclusion
 The work breakdown structure defines the
  product elements (work packages).
 And their interrelations to each other and to
  the product.
 The WBS mostly ends with project tasks.
 Using the tasks you can extract project’s
  activities.

                   Nabil Dmaidi                   56
Construction scheduling
   What is the difference between a schedule
    and a Plan?

   The schedule: putting the plan in time scale.




                     Nabil Dmaidi                   57
Most Common Scheduling
methods
   common scheduling methodologies:


 Bar Charts (Gantt Charts)
 Critical Path Method (CPM)
 PERT (Project Evaluation & Review
  Techniques)
 Linear Scheduling Method (LSM)


                    Nabil Dmaidi       58
Construction scheduling
   To be able to build up a successful schedule. You
    need to:
    1) Define activities
    2) Order activities
    3) Establish activities relationships
    4) assign durations to activities
    5) resources and costs allocation
    6) calculate early and late start/finish times
    7) calculate float values and identify the critical
    path

                         Nabil Dmaidi                     59
Bar Chart or Gantt chart
   Bar chart is a collection of activities listed
    vertically, and the horizontal scale
    represents the time.

   First applied by HENRY GANTT




                     Nabil Dmaidi                    60
Typical Bar / Gantt chart




              Nabil Dmaidi   61
Advantages of Bar / Gantt Chart

   Plan, schedule and progress are all depicted
    graphically on a single chart
   Easily read
   Provides simple way to schedule small projects
   Provides summary display of more detailed
    plans and schedules
   Best used for management briefings



                      Nabil Dmaidi                   62
Disadvantages of Bar / Gantt Chart

 Planning and scheduling are considered
  simultaneously
 Activity dependencies cannot adequately be
  shown
 Difficult to determine how activity progress
  delays affect project completion
 Difficult to establish and maintain for large
  projects
                   Nabil Dmaidi                   63
Critical Path Method (CPM)
   Two basic methods of analysis:

1) ADM -- Arrow Diagramming Method
  Activity On Arrow (AOA) or I-J Method
2) PDM -- Precedence Diagramming Method
  Activity On Node (AON) Method



                    Nabil Dmaidi          64
Types of construction Constraints
1)   Physical constraints.
2)   Resource constraints.
3)   Safety constraints.
4)   Financial constraints.
5)   Environmental constraints.
6)   Management constraints.
7)   Contractual constraints.
8)   Regulatory constraints.
                    Nabil Dmaidi    65
Physical constraints.
   Physical constraints exist due to physical
    process of construction.

   Physical constraints defined by “HOW” the
    project is to be carried out. ( Method of
    construction).

   You need to erect formwork before you can
    cast concrete.
                     Nabil Dmaidi                66
Resource constraints
   These constraints imposed wherever tow activities
    cannot be carried out simultaneously because
    insufficient resources are available.

   E.g. Tow activities require a crane to be performed
    and you have just one crane. So, they should not
    be performed at the same time.

   E.g. The amount of required concrete per day
    exceeds the production capacity of a batch plant.

                       Nabil Dmaidi                     67
       Safety constraints.
   Safety constraints imposed by safety requirements
    through performing the work.
   Sometime imposes that tow activities could not be
    performed at the same time due to non-safe work
    conditions. ( E.g. overhead and ground level work
    at the same area.)
   Imposes specific sequence of the work. (e.g.
    erecting of scaffolding before external paints can
    start)
   Imposes non-working days due to extremely hot
    or cold days.

                       Nabil Dmaidi                      68
Financial constraints
   Financial constraints: high cost activities
    could be delayed due to non-availability of
    cash requirements during construction.

   The amount of cost a company can pay
    within a specific period of time usually
    limited. So, try to avoid overlap between
    high cost activities.

                     Nabil Dmaidi                 69
Environmental constraints.

   Environmental constraints include
    restrictions to the work to avoid
    environmental violations.

   E.g. not working in certain area during
    specific times to avoid affecting
    proliferation of eagles, fish run.


                     Nabil Dmaidi             70
Management constraints.

   Management constraints reflect decisions of
    management that result in a reasonable
    benefit of the company.

 E.g. the management decided to borrow
  from your project resources to be utilized in
  another project.
 E.g. the management decided to extend the
  new year holiday another 2 days.
                    Nabil Dmaidi                  71
Contractual constraints
   The owner may impose constraints on the
    construction process.

   E.g. the owner may require a particular phase of
    the project to be fully completed and occupied
    before start construction of next phase.

   And he may require to minimize the noise and
    dust because that portion is occupied and in
    operation.
                       Nabil Dmaidi                    72
Regulatory constraints.
   These type of constraints related to the
    regulations of the area of construction.
    Imposed by municipality, government, etc.

   E.g. if the construction site in the
    downtown, heavy vehicles like concrete
    mixers prohibited to access the site in a
    specific times of the day. So, you can just
    cast concrete at night.
                     Nabil Dmaidi                 73
Impacts of constraints on the
network
    In the initial definition of the network, it is
     desirable to minimize the number of
     constraints, because excessive constraints
     have the following impact of the project.

1)   Reduce scheduling flexibility.
2)   Lengthen project duration.
3)   Generally increase project costs.
4)   Confuse basic scheduling logic.
                      Nabil Dmaidi                     74
Impacts of constraints on the
network
   The imposition of constraints in the network
    results in linear ordering of activities.
    Which is not desired. (recall: the linear
    order of activities prolong the project
    duration and set most of the activities as
    critical).



                     Nabil Dmaidi              75
Impacts of constraints on the
network
    Only physical constraints should be
     considered in the early preparation of the
     network.
    Other constraints can be deferred until
     actual schedule of activities. Where it can
     be determined that :
1)   the constraints are not met by the
     schedule.
2)   It can be addressed by shifting of activities
     within their available float time.
                     Nabil Dmaidi                76
Resources Allocation & Leveling

   So far, the network analysis has been considered
    using one resource only which is time.

   Construction activities in practice use other
    resources like labor, material, equipment and
    money.

   Moreover, the network analysis considered no
    limitations of the traditional resources (labor,
    material, equipment and money) which is not the
    case in practice.
                       Nabil Dmaidi                    77
Activities Relationships
   Types of relations between activities:

       1) Finish to start – FS
       2) Start to Finish – SF
       3) Finish to Finish – FF
       4) Start to Start - SS


                     Nabil Dmaidi            78
1) Finish to start – FS Relationship

 The traditional relationship between
  activities.
 Implies that the preceding activity must
  finish before the succeeding activities can
  start.
 Example: the plaster must be finished
  before the tile can start.


                   Nabil Dmaidi                 79
   Finish to start with delay relationship


 Pour concrete                Concrete curing                  Deshuttering
    1 day                        28 days                         2 days



Concrete curing an activity which consumes no resources other than time


                                  FS/28
 Pour concrete                                                 Deshuttering
    1 day                                                        2 days



28 days is delay time or LAG means that: deshuttering can start 28 days after
Concrete has been poured
                                  Nabil Dmaidi                                  80
3) Star to Finish – SF relationship

   Appear illogical or irrational.

   Typically used with delay time OR LAG.

   The following examples proofs that its
    logical.


                      Nabil Dmaidi           81
    2) Star to Finish – SF relationship


                                         steel
   Erect formwork                   reinforcement                Pour concrete

                                                                     SF5


                                                                  Order concrete




The concrete supplier stipulates 5 days order before delivery.
                                    Nabil Dmaidi                             82
3) Finish to Finish – FF relationship

 Both activities must finish at the
  same time.
 Can be used where activities can
  overlap to a certain limit.



                Nabil Dmaidi            83
Finish to Finish – FF relationship


    Set flagpole                  Position flagpole
     In the hole                    In the hole




                                                      FF




                                      Backfill
                                       hole


                   Nabil Dmaidi                       84
Finish to Finish with delay relationship


    Erect         Remove
    scaffolding   Old paint

                                  FF/1


                   sanding


                                     FF/2

                                                       Dismantle
                     painting                inspect   scaffolding




                              Nabil Dmaidi                           85
4) Start to Start – SS relationship


 Clean surface            Spread grout




                 SS




                             Set tile    Clean floor area



                      Nabil Dmaidi                    86
The Four Activity Times -
Arrow Diagram Notation
                          Activity
                   i                         j
                            Tij
                               (a)

 ESDij                 EFDij         LSDij                     LFDij


         Activity ij                             Activity ij

             Tij                                    Tij
                            Time
                          Available
                              (b)
                          Nabil Dmaidi                                 87
Forward Pass Rules
Rule 1
  The initial project event is assumed to occur at time zero
Rule 2
  All activities are assumed to start as soon as possible,
  that is , as soon as all the predecessor activities are
  completed.
Rule 3
  The early finish time of an activity is merely the sum of
  its early start date and the estimated activity duration.
  EFDij = ESDij + Tij


                         Nabil Dmaidi                          88
Forward Pass Rules (cont.)

Rule 4
    The late start date LSDij is found by subtracting
    the activity duration Tij from the late finish date
    LFDij
    LSDij = LFDij - Tij




                      Nabil Dmaidi                        89
   Forward Pass Comput at ions - Remodeling Chemical Laborat ory
 i    j Act ivit y Descript ion              T (Days) ESD EFD
 2 4 St rip room                                 3       0      3
       2
 2 1 Obt ain fume hood                          10       0      10
      4
 2 1 Obt ain cabinet                            10       0      10
 2 20 Obt ain chemical sink                     10       0      10
 2 24 Paint er availabilit y                    20       0     20
 2 28 Obt ain vinyl floor covering               5       0      5
 4 6 Rough-in plumbing and elect rical           5       3      8
 4 8 Replace exist ing fume duct                 3       3      6
 6 8 Dummy                                       0       8      8
      0
 6 1 Repair floor                                1       8      9
      0
 8 1 Repair walls and ceiling                    4       8      12
1      2
 0 1 Dummy                                       0       12     12
1     4
 0 1 Dummy                                       0       12     12
 2 6
1 1 Inst all new fume hood                       1       12     13
 4 6
1 1 Dummy                                        0       12     12
 4
1 22 Inst all wall cabinet s                     5       12     17
1     8         /3
 6 1 Inst all 1 base cabinet s                   1       13     14
 8
1 20 Dummy                                       0       14     14
 8
1 22 Inst all 2/3 base cabinet s                 2       14     16
20 22 Inst all chemical sink                     1       14     15
22 24 Finish plumbing and elect rical            2       17     19
24 26 Dummy                                      0      20 20
24 28 Paint cabinet s                            6      20 26
26 28 Paint walls and ceiling                    3      20 23
28 30 Lay vinyl floor                            1      26     27
                          Nabil Dmaidi                               90
                      Forward Pass Comput at ions - Remodeling Chemical Laborat ory
i     j   Act ivit y Descript ion            T (Days)     ESD         EFD         LSD    LFD
 2    4   St rip room                             3          0           3           1     4
 2   12   Obt ain fume hood                      10          0          10           4    14
 2   14   Obt ain cabinet                        10          0          10           3    13
 2   20   Obt ain chemical sink                  10          0          10           7    17
 2   24   Paint er availabilit y                 20          0          20          0     20
 2   28   Obt ain vinyl floor covering            5          0           5          21    26
 4    6   Rough-in plumbing and elect rical       5          3          8            4     9
 4    8   Replace exist ing fume duct             3          3          6           6      9
 6    8   Dummy                                  0           8          8            9     9
 6   10   Repair floor                            1          8           9          12    13
 8   10   Repair walls and ceiling                4          8          12           9    13
10   12   Dummy                                  0           12         12          14    14
10   14   Dummy                                  0           12         12          13    13
12   16   Inst all new fume hood                  1          12         13          14    15
14   16   Dummy                                  0           12         12          15    15
14   22   Inst all wall cabinet s                 5          12         17          13    18
16   18             /3
          Inst all 1 base cabinet s               1          13         14          15    16
18   20   Dummy                                  0           14         14          17    17
18   22   Inst all 2/3 base cabinet s             2          14         16          16    18
20   22   Inst all chemical sink                  1          14         15          17    18
22   24   Finish plumbing and elect rical         2          17         19          18    20
24   26   Dummy                                  0          20          20          23    23
24   28   Paint cabinet s                        6          20          26          20    26
26   28   Paint walls and ceiling                 3         20          23          23    26
28   30   Lay vinyl floor                         1         26          27          26    27

                                          Nabil Dmaidi                                         91
1. Total Float
   Total float may be defined as that time span
    in which the completion of an activity may
    occur and not delay the termination of the
    project.

    TFij   = LFDij - EFDij
       = LSDij - ESDij

                     Nabil Dmaidi                  92
2. Free Float
   Free float may be defined as the time span
    in which the completion of an activity may
    occur and not delay the finish of the project
    nor delay the start of any following activity.

    FFij     = ESDjk - EFDij



                      Nabil Dmaidi                   93
3. Interfering Float
   That part of the total float which remains after free
    float has been deducted is the interfering float.
   It may be defined as: the time span in which the
    completion of an activity may occur and not delay
    the termination of the project but within which
    completion will delay the start of some other
    following activity.

    INTFij    = TFij - FFij



                         Nabil Dmaidi                       94
4. Independent Float
   The fourth float, independent float, is the amount
    of scheduling leeway of an activity that is
    independent of the early starts and late finishes of
    any other activity. It may be formally defined as:
    The time span in which the completion of an
    activity may occur and not delay the termination
    of the project, not delay the start of any following
    activity, and not be delayed by any preceding
    activity.



                         Nabil Dmaidi                      95
                                            Forward Pass Comput at ions - Remodeling Chemical Laborat ory
i     j   Act ivit y Descript ion            T (Days)    ESD          EFD       LSD         LFD           TF   FF   INTF   INDF
 2    4   St rip room                            3         0            3           1          4           1   0      1      -
 2   12   Obt ain fume hood                     10         0           10          4          14           4   2      2      2
 2   14   Obt ain cabinet                       10         0           10          3          13           3   2      1      2
 2   20   Obt ain chemical sink                 10         0           10          7          17           7   4      3      4
 2   24   Paint er availabilit y                20         0           20          0          20          0     -     -      -
 2   28   Obt ain vinyl floor covering           5         0            5          21         26          21   21     0      21
 4    6   Rough-in plumbing and elect rical      5         3           8           4           9           1   0      1      -
 4    8   Replace exist ing fume duct            3         3           6           6           9           3   2      1      1
 6    8   Dummy                                  0         8           8           9           9           1   0      1      -
 6   10   Repair floor                           1         8            9          12         13           4   3      1      2
 8   10   Repair walls and ceiling               4         8           12          9          13           1   0      1      -
10   12   Dummy                                  0         12          12          14         14           2   0      2      -
10   14   Dummy                                  0         12          12          13         13           1   0      1      -
12   16   Inst all new fume hood                 1         12          13          14         15           2   0      2      -
14   16   Dummy                                  0         12          12          15         15           3    1     2      0
14   22   Inst all wall cabinet s                5         12          17          13         18           1   0      1      -
16   18   Inst all 1 base cabinet s
                    /3                           1         13          14          15         16           2   0      2      -
18   20   Dummy                                  0         14          14          17         17           3   0      3      -
18   22   Inst all 2/3 base cabinet s            2         14          16          16         18           2    1     1      0
20   22   Inst all chemical sink                 1         14          15          17         18           3   2      1      0
22   24   Finish plumbing and elect rical        2         17          19          18         20           1    1     0      0
24   26   Dummy                                  0        20           20         23          23           3   0      3      -
24   28   Paint cabinet s                        6        20           26         20          26          0     -     -      -
26   28   Paint walls and ceiling                3        20           23         23          26           3   3      0      3
28   30   Lay vinyl floor                        1        26           27         26          27          0     -     -      -




                                                           Nabil Dmaidi                                                     96
Critical Path Computations on
          the Network




           Nabil Dmaidi         97
The Two Event Approach
   Early Start Event
      In the forward pass, the maximum of the EFD
      values for all activities merging at a node is
      taken as ESD value for all the activities that
      burst from the same node.
      TEj = MaxI (TEi +Tij)




                        Nabil Dmaidi                   98
 For all activities entering node j, TEj
 is taken as the greatest sum of all
 activities merge to the node




                 Nabil Dmaidi               99
 Late   Finish Event
  –   In the backward computations, the
      minimum of LSD valves is taken as the
      latest finish time for all activities that
      enter the node.
      TLj = MinI (TLi +Tij)




                       Nabil Dmaidi                100
      by the last activity, the TL for the
 Start
 next earlier node is taken as the
 minimum value of the late time event
 minus activity duration.




                 Nabil Dmaidi                101
Nabil Dmaidi   102
Float Calculations From Event Times
Total Float
Tfij = TLj - TEi - Tij
Example
TF2-20 =     TL20 - TE2 - T2-20
           = 17 - 0 - 10 = 7



                     Nabil Dmaidi     103
Free Float
FFij = TEj - TEi - Tij
Example
FF2-20 =     TE20 - TE2 - T2-20
           = 14 - 0 - 10 = 4




                     Nabil Dmaidi   104
Scheduling Computations
          for
  Precedence Networks




        Nabil Dmaidi      105
Tabular Format (Precedence Diagram)
   Can be carried out on the tabular form
    without reference to the diagram.
   Advantage: the time required to construct
    the diagram is eliminated.




                     Nabil Dmaidi               106
Link Lag
 A link lag is the difference between the
 early start date of an activity and the early
 finish date of the preceding activity

 LAGij = ESDj - EFDi




                   Nabil Dmaidi                  107
Determining log

 Examples:

 LAG 5-10 = ESD 10 - EFD 5 = 4 - 4 = 0

 LAG 15-25 = ESD 25 - EFD 15 = 12 - 7 = 5

 LAG 20-25 = ESD 25 - EFD 20 = 12 - 6 = 6




                    Nabil Dmaidi            108
Determining the Free-Float
 Free Float is the minimum of the log of the
  link that follows an activity.
 Look at the “Pre. column” to find the same
  number value of EF for terminal activity
  “not following act.”

FFi = Minj - LAG ij
FF 35 = LFD 35 - EFD 35 = 20 - 20 = 0
                   Nabil Dmaidi                 109
Determining the Total Float “Backward”
TF i = Min (log ij + TF j )

   Take TF of the terminal activity = 0
    or TF 35 = LFD 35 - EFD 35 = 20 - 20 = 0




                    Nabil Dmaidi               110
Determining the Total Float “Backward” (cont.)


 TF 30 = Min (log 30-35 + TF 35 ) =

 Min ( 7 + 0 ) = 7

 No other link


            {                       } { }
 TF 20 = Min LAG20-25 + TF 25 = Min 6+0 = 6
             LAG20-30 + TF 30         1+7


                     Nabil Dmaidi                111
INTF Float

      INTF     = TF - FF




             Nabil Dmaidi   112
 If   the free float is zero - no INDF
  INDF j = FF j - Max _ I ( TF I - LAGIJ )
  INDF 20 = FF 20 - Max ( TF 5 - LAG5-20 )
           = 1- (0 -0 )=1


                      {
  INDF 30 = FF 30 – Max       TF 15 - LAG15-30
                                TF 20 - LAG20-30   }
              { }
          = 7- 5-0 =2
                6-1


                          Nabil Dmaidi                 113
Float Determination -
Sample Precedence Network




             Nabil Dmaidi   114
Late Date Determination -
Sample Precedence Network




             Nabil Dmaidi   115
Lag Determination -
Sample Precedence Network




             Nabil Dmaidi   116
                                                        Forward Pass Calculations
                                                        Early start / Early Finish
                        8
                                                        EF = ES + D
                             3
                        4                                             15

                                     11            17

                                 6                      7
                                           6                     14

0           4           11
                                                                 18            31             45
    1           2            4                               8             9             10
        4           7                      7                          7             14




                                     8
                                           5
                             4                                        10
                                         Nabil Dmaidi                                     117
                                                Backward Pass Calculations
                                                Late start / Late Finish
                    11                          LS = LF - D

                          3
                    4                                              15

                                  11             17

                              6                       7
                                         6                    14

0       4            11                                       24            31             45

1           2             4                               8             9             10
    4           7                        7                         7             14




                                  24

                                         5
                          4                                        10
                                       Nabil Dmaidi                                    118
                    11                                       The Critical activities
                                                             Total Float= LF – ES – D
                     8
                             3
                    4                                                     15
                                     11             17
                                     11             17

                                 6                       7
                                            6                        14
0       4            11
                                                                     24            31             45
0       4               11
                                                                     18            31             45
1           2                4                                   8             9             10
    4           7                           7                             7             14



                                     24
                                     8
                                            5
                          4                                               10
                                          Nabil Dmaidi                                        119
                    11                                       The critical Path
                     8
                             3
                    4                                                 15
                                     11             17
                                     11             17

                                 6                       7
                                            6                    14
0       4            11
                                                                 24            31             45
0       4               11
                                                                 18            31             45
1           2                4                               8             9             10
    4           7                           7                         7             14



                                     24
                                     8
                                            5
                          4                                           10
                                          Nabil Dmaidi                                    120
    Exercise
   Draw a network for the following activities.

     Activity                  Duration           IPAs
        A                          2                --
        B                          2                A
        C                          4                A
        D                          1                C
        E                          4                B,C
        F                          2                B
        G                          1                D
        H                          4                F,E
        I                          2                F
        J                          4                G,H
        K                          4                I,H
        L                          1                K,J
                                   Nabil Dmaidi           121
The Arrow   Network will be:




    A             B           3           F                          I
1       2                                                    9                10
    2             2                       2                          2
                                                                                   K
            C 4                                                                4
                                              E                  H                          L
                  4                   6               7                  11            12         13
                                              4                  4                          1
                          1                                                    J
                      D                                                            4
                                                  G                      8
                                  5
                                                  1


                                              Nabil Dmaidi                                      122
Forward   Pass calculations (ES, EF)




0       2                     4                                  6                 14
    A             B           3               F                           I
1       2                                                        9                 10
    2             2                           2                           2
                                                                                            K
            C 4       6                                                   14            4       18        19
                                          6               10
                                                  E                  H                               L
                  4                   6                    7                  11                12         13
                                                  4                  4                               1
                          1                                                             J
                      D           7                                                         4
                                                                         14
                                                      G                        8
                                  5
                                                      1


                                                  Nabil Dmaidi                                           123
    backward   Pass calculations (LS, LF)




0         2                     6                                  10                 14
      A             B           3               F                            I
1         2                                                         9                 10
      2             2                           2                            2
                                                                                               K
              C 4       6                                                    14            4       18        19
                                            6               10
                                                    E                   H                               L
                    4                   6                    7                   11                12         13
                                                    4                   4                               1
                            1                                                              J
                        D       13                                                             4
                                                                            14
                                                        G                         8
                                    5
                                                        1


                                                    Nabil Dmaidi                                            124
Specify   the Critical Path



0          2                     6                                  10                 14
0          2                     4                                   6                 14
    A                B           3               F                            I
1          2                                                         9                 10
    2                2                           2                            2
                         6                   6               10               14              K 18            19
               C 4       6                                                    14            4   18            19
                                             6               10
                                                     E                   H                               L
                     4                   6                    7                   11                12         13
                                                     4                   4                               1
                                 13                                          14             J
                             1                                                                  4
                         D        7                                          14
                                                         G                         8
                                     5
                                                         1


                                                     Nabil Dmaidi                                            125
0       2                     6                                  10                 14
0       2                     4                                   6                 14
    A             B           3               F                            I
1       2                                                         9                 10
    2             2                           2                            2
                      6                   6               10               14              K 18            19
            C 4       6                                                    14            4   18            19
                                          6               10
                                                  E                   H                               L
                  4                   6                    7                   11                12         13
                                                  4                   4                               1
                              13                                          14             J
                          1                                                                  4
                      D        7                                          14
                                                      G                         8
                                  5
                                                      1


                                                  Nabil Dmaidi                                            126
Table of activities

EF = ES + D

   Activity   Duration IPAs     ES      EF

       A         2              --             0   2
       B         2              A              2   4
       C         4              A              2   6
       D         1              C              6   7
       E         4              B,C            6   10
       F         2              B              4   6
       G         1              D              7   8
       H         4              F,E           10   14
       I         2              F              6   8
       J         4              G,H           14   18
       K         4              I,H           14   18
       L         1              K,J           18   19
                               Nabil Dmaidi             127
Table of activities

LS = LF - D




     Activity    Duration   IPAs           ES   EF   LS   LF

         A            2       --             0   2    0    2
         B            2       A              2   4    4    6
         C            4       A              2   6    2    6
         D            1       C              6   7    12   13
         E            4       B,C            6   10   6    10
         F            2       B              4   6    8    10
         G            1       D              7   8    13   14
         H            4       F,E           10   14   10   14
         I            2       F              6   8    12   14
         J            4       G,H           14   18   14   18
         K            4       I,H           14   18   14   18
         L            1       K,J           18   19   18   19
                             Nabil Dmaidi                       128
Total Float (TF): The amount of time an activity can be delayed
without delaying the overall project completion.
TF = LF – ES – D
   = LF – EF
   = LS - ES

   Activity   Duration          IPAs         ES   EF   LS    LF    TF

       A          2              --           0    2    0     2     0
       B          2              A            2    4     4     6     2
       C          4              A            2    6    2     6     0
       D          1              C            6    7     12    13    6
       E          4              B,C          6    10   6     10    0
       F          2              B            4    6     8     10    4
       G          1              D            7    8    13    14    6
       H          4              F,E          10   14   10    14    0
       I          2              F            6    8    12    14    6
       J          4              G,H          14   18   14    18    0
       K          4              I,H          14   18   14    18    0
       L          1              K,J          18   19   18    19    0


                               Nabil Dmaidi                              129
Total Float (TF): The amount of time an activity can be delayed
without delaying the overall project completion.
TF = LF – ES – D
   = LF – EF
   = LS - ES

   Activity   Duration          IPAs         ES   EF   LS    LF    TF

       A          2              --           0    2    0     2     0
       B          2              A            2    4     4     6     2
       C          4              A            2    6    2     6     0
       D          1              C            6    7     12    13    6
       E          4              B,C          6    10   6     10    0
       F          2              B            4    6     8     10    4
       G          1              D            7    8    13    14    6
       H          4              F,E          10   14   10    14    0
       I          2              F            6    8    12    14    6
       J          4              G,H          14   18   14    18    0
       K          4              I,H          14   18   14    18    0
       L          1              K,J          18   19   18    19    0


                               Nabil Dmaidi                              130
                   Bar / Gantt chart Early Start / Finish
Activity
                   EF = ES + D
    A
    B
    C
    D

    E
    F
    G
    H

     I
    J

    K
    L
           2   4   6      8       10       12   14      16   18   20
                               Time
                              Nabil Dmaidi                             131
                   Bar / Gantt Chart Late Start / Finish
Activity
                   LS = LF - D
    A
    B
    C
    D
    E

    F
    G
    H

     I

    J
    K
    L
           2   4   6      8       10       12   14     16   18   20
                               Time
                              Nabil Dmaidi                            132
        Bar / Gantt of the previous network

A
B
C
D
E

F
G
H

I
J

K
L
    2   4     6       8       10         12   14   16   18   20
                          Nabil Dmaidi                            133
                   Bar / Gantt chart Early Start / Finish
Activity
                   EF = ES + D
    A
    B
    C
    D

    E
    F
    G
    H

     I
    J

    K
    L
           2   4   6      8       10       12   14      16   18   20
                               Time
                              Nabil Dmaidi                             134
                   Bar / Gantt Chart Late Start / Finish
Activity
                   LS = LF - D
    A
    B
    C
    D
    E

    F
    G
    H

     I

    J
    K
    L
           2   4   6      8       10       12   14     16   18   20
                               Time
                              Nabil Dmaidi                            135
        Bar / Gantt of the previous network

A
B
C
D
E

F
G
H

I

J

K
L
    2   4     6       8       10         12   14   16   18   20
                          Nabil Dmaidi                            136
2) PDM Precedence Diagramming Method
Activity On Node (AON) Method

 PDM is the primary method in use today.
 Used by most of the computer software.


        MS Project
        Primavera




                  Nabil Dmaidi              137
PDM Precedence Diagramming Method

   The PDM depicts activities as NODES in
    the network linked with logic lines.

 The node representing the activity.
 Arrow representing relationship /
  dependency
 PDM should be red left to right


                   Nabil Dmaidi              138
PDM Precedence Diagramming Method

     PDM looks like the following:


       Activity A                     Activity B




• The shape of the node could be any shape

                      Nabil Dmaidi                 139
PDM vs. ADM

        ADM                            PDM

    A       C
1       2       3                  A         C



                        =
    B       D
4       5       6                  B         D




                    Nabil Dmaidi                 140
PDM vs. ADM

        ADM                            PDM
                                             B
                3
            B

    A
1       2
            C
                4       =          A         C


            D
                5                            D




                    Nabil Dmaidi                 141
Exercise
   Draw a PDM for the following activities.

      Activity            Activity
       Label              Description          IPAs

         A                Lay out              --
         B                Excavation           A
         C                place formwork       B
         E                purchase steel       --
         F                bend steel           E
         G                place steel          C,F
         H                order concrete       --
         D                place concrete       G,H


                              Nabil Dmaidi            142
The PDM will be:

                                  H




  A        B            C             D



           E          F           G



                   Nabil Dmaidi           143
Clean surface            Spread grout




                SS




                            Set tile    Clean floor area



                     Nabil Dmaidi                   144
Precedence Network Calculations

   the basic information that should be
    calculated in the precedence network are:

    1) Early activity start (ES)
    2) Early activity finish (EF)
    3) Late activity start (LS)
    4) Late activity finish (LF)
    5) Free Float (FF)
    6) Total Float (TF)
                       Nabil Dmaidi             145
Precedence Network Calculations

   The previously mentioned information can
    be illustrated in the activity nod in the
    network:

                Activity description

         ES         Duration           LS

         EF       FF             TF    LF


                       Nabil Dmaidi             146
Precedence Network Calculations
 ES: the earliest time that an activity can start as
  determined by the latest of the early finish times of all
  immediately preceding activities.
 EF: the earliest time that an activity can finish, determined
  by EF = ES + D
 LS : the latest time that an activity can start without
  delaying the project completion.
 LS = LF – D.
 LF : the latest time that an activity can be finished without
  delaying the project completion, as determined by the
  earliest of the late starts of the immediately succeeding
  activities.

                          Nabil Dmaidi                        147
Precedence Network Calculations

   FF: the amount of time that an activity can be
    delayed before it impacts the start of any
    succeeding activities.
   TF: the amount of time that an activity can be
    delayed before it impacts the project completion.
   Lag: the amount of time that exists between the
    EF of an activity and the ES of a specified
    succeeding activity.

   LAGAB = ESB - EFA

                        Nabil Dmaidi                    148
Precedence Network Calculations



   Reminder: The manual calculations
    assumes that the relationships between
    activities are Finish to Start (FS) Type.




                      Nabil Dmaidi              149
      Precedence Network Calculations
1) Forward pass calculations                                                               4) Backward pass calculations

                      5) Calculate total Float (TF = LS – ES OR LF – EF)

          A               0
                                       B              0
                                                               D                  0
                                                                                             F          0
                                                                                                                   H
  1       1       1           2        9     2            11       5     11           16     4     16       20        1      20
  2   0       0   2           11   0       0 11           16 0         0 16           20 0       0 20       21 0          0 21

                                                  4                           5                         3
                      0
                                       C                           E                         G
                                                      0                           0
                              2        5     5            7        4     10           11     6     14
                              7    0       3 10           11   0       3 14           17 3       3 20


2) Calculate the Lag ( LAGAB = ESB - EFA
                                                                                                                 ES       Dur.    LS
                                     min. LAG
3) Calculate the Free Float (FF) FF =Nabil Dmaidi                                                                EF FF TF LF
                                                                                                                        150
       Precedence Network Calculations
6) Determine the Critical Path




           A               0
                                        B              0
                                                                    D              0
                                                                                              F          0
                                                                                                                    H
   1       1       1           2        9     2            11       5     11           16     4     16       20        1      20
   2   0       0   2           11   0       0 11           16 0         0 16           20 0       0 20       21 0          0 21

                                                   4                           5                         3
                       0
                                        C                           E                       G
                                                       0                           0
                               2        5     5            7        4     10           11     6     14
                               7    0       3 10           11   0       3 14           17 3       3 20




The critical path passes through the critical activities where TF = 0                                             ES       Dur.    LS
                                                           Nabil Dmaidi                                           EF FF TF LF
                                                                                                                         151
                   Bar / Gantt chart Early Start / Finish
Activity
                   EF = ES + D



    A

    B

    C

    D

    E

    F

    G

    H

           2   4   6      8       10       12   14    16    18   20
                               Time
                              Nabil Dmaidi                            152
                   Bar / Gantt chart Late Start / Finish
Activity
                   LS = LF - D



    A

    B

    C

    D

    E

    F

    G

    H

           2   4   6      8       10       12   14    16   18   20
                               Time
                              Nabil Dmaidi                           153
                       Bar / Gantt chart
Activity




    A

    B

    C

    D

    E

    F

    G

    H

           2   4   6   8       10       12   14   16   18   20
                            Time
                           Nabil Dmaidi                          154
                                                                 Exercise

 1) Forward pass calculations                                                                4) Backward pass calculations

                                                     electrical                                               Water
                                                      conduit                    8                            proofing
                                                 7         2     15                                          25 3 25
                          0
                                                  9 8          8 17                                          28 0   0 28          0
                                                                                                  0



     Block work                        plumbing                        Inspection                 plaster                  Floor tile
                              0                            0                             0
     1        6       1            7        4     7               11      6     11           17       8     17        28      1       28
     7    0       0   7           11    0       0 11              17 0        0 17           25 0         0 25        29 0        0 29




                          0                       sub-frames
                                                                                     9
                                                 7         1     16
                                                 8     9       9 17

ES       Dur. LS
                                  2) Calculate the Lag ( LAGAB = ESB - EFA
EF FF TF LF                                                       Nabil Dmaidi                                                    155
                                  3) Calculate the Free Float (FF) FF = min. LAG
                              6) Determine the Critical Path

                              5) Calculate total Float (TF = LS – ES OR LF – EF)
                                                      electrical                                               Water
                                                       conduit                    8                            proofing
                                                  7         2     15                                          25 3 25
                          0
                                                   9 0          8 17                                          28 0   0 28          0
                                                                                                   0



     Block work                         plumbing                        Inspection                 plaster                  Floor tile
                               0                            0                             0
     1        6       1            7         4     7               11      6     11           17       8     17        28      1       28
     7    0       0   7            11    0       0 11              17 0        0 17           25 0         0 25        29 0        0 29




                          0                        sub-frames
                                                                                      9
                                                  7         1     16
                                                  8     0       9 17

ES       Dur. LS
EF FF TF LF                                                        Nabil Dmaidi                                                    156
Activities Duration
   Activity duration: is the estimated time
    required to complete an activity.

   Activity duration mainly calculated based
    on the quantities take off.

   And labor or machines productivity rates.

                     Nabil Dmaidi               157
Activities Duration
   Durations could be estimated by experience.
    ( previous similar jobs)

   If experience not available, others
    experience could be utilized.

   If not, handbooks of productivity rates are
    available provide the required information.

                     Nabil Dmaidi                 158
Activities Duration
   Activity duration can be calculated as
    follows:

                quantity of the work
                                   = crew hours
                  qty / crew hour
   qty / crew hour is the productivity rate.
   Time unit is hours could be changed to working days.



                                     Nabil Dmaidi          159
Activities Duration
   Example: assume that you have a floor tile area of 600 M2 , and the
    productivity rate of a tile mason and one helper is 1.5 M2 / hour.

   By applying the previous equation:

             600 M2
                           = 400 hours
           1.5 M2 / h

   If the time unit is working day ( 8 hours) :

               400 hours
                              = 50 days
                8 hours


                                    Nabil Dmaidi                          160
Time & Cost Theoretical
Relationship


         Minimum Duration
Cost




             A                  B




                     Duration
                 Nabil Dmaidi       161
Some Factors that affects
Duration
1)   Weather.
2)   Availability, quality, and training of operatives.
3)   Familiarity with the work.
4)   Quality of workmanship specified.
5)   Quality of management/supervision.
6)   Size and completion date of project.
7)   Length and incidence of holidays.
8)   Repetitiveness of the work.
9)   Physical constraints of the site. Such as access,
     size, storage space and etc.

                       Nabil Dmaidi                       162
1) Weather
   Allowance for weather is important for
    activities duration.

   Its particularly critical for excavation and
    earth moving activities.

   Tow approaches to tackle delay due to
    weather conditions:
                      Nabil Dmaidi                 163
1) Weather Cont.
1)   First approach: each activity has an added
     allowance of possible delays due to weather.
     Fixed percentage is added to each activity for
     this purpose.

     But, it produces difficulties for activities with
     long duration, if these activities are not sensitive
     to weather.



                        Nabil Dmaidi                    164
1) Weather Cont.
2) Second approach: adding a single
  allowance at the end of the project.

  This method works best if the work
  activities have more or less the same
  sensitivity to weather. And the weather does
  not vary significantly from period to period.


                   Nabil Dmaidi               165
1) Weather Cont.



   A delay activity could be added separately
    to the network represents the weather delay.




                     Nabil Dmaidi              166
                                 E
                            10   6   16
                            16 6 6 22



                   B             F              I
               6   4   12   11   2   17    13   3   19
               10 0 6 16    13 0 6 19      16   6 6 22



     A             C             G                            K
1    5    1    6   5   6    11   3   11                  22   2     22
6 0 0     6    11 0 0 11    14 0 0 14                    24 0 0 24




                   D                            J
               6   2   12                  14       14
                                                8
               8 0 6 14                    22 0 0 22

                                 H
ES   Dur. LS
                            8     6   16
EF FF TF LF
                                8 Dmaidi
                            14 Nabil8 22                          167
                                     E
                                10   4   16
                                14 6 6 20



                       B             F                I
                   6   4 12     9    2   15    11     3    17
                   10 0 6 16    11 0 6   17    14 6       6 20




         A             C             G                                K
1        5   1     6   3   6    9    3   9                       20   2     20
6 0 0        6     9 0 0   9    12 0 0 12                        22 0 0 22




                       D                              J
                   6   2   10                  12     8     12
                   8 0 4   12                  20 0 0       20

                                     H
    ES   Dur. LS
                                8     7   13
    EF FF TF LF
                                    5 Dmaidi
                                15 Nabil5 20                              168
                      E
                      6




               B      F           I
               4      2           3




     A         C      G               K
1    5         5      3               2




               D                  J
               2                  8



                      H
ES   Dur. LS
                      6
EF FF TF LF
                   Nabil Dmaidi           169
                      E
                      4




               B      F           I
               4      2           3




     A         C      G               K
1    5         3      3               2




               D                  J
               2                  8



                      H
ES   Dur. LS
                      7
EF FF TF LF
                   Nabil Dmaidi           170
Resources Allocation & Leveling
   A time only network assumes that any other
    needed resources are available at any time.

   E.g. if the excavation activity requires three
    large mechanical excavators, A time only
    network assumes that these excavators are
    available on site at the required time. This
    seems to be uneconomic situation.

                      Nabil Dmaidi                   171
       Resources Allocation & Leveling


            A                    B                   D                 F               H
   1        1       1   2        9     2    11       5     11   16     4     16   20     1     20
   2   0        0   2   11   0       0 11   16 0         0 16   20 0       0 20   21 0       0 21
       8H                    9H                  5H                  8H                4H



                                 C                   E               G
                        2        5     5    7        4     10   11     6     14
                        7    0       3 10   11   0       3 14   17 3       3 20
 Activity                        7H                  4H              2H
 desc.
ES Dur. LS
EF FF TF LF
 Resources
                                            Nabil Dmaidi                                       172
Sort




   Sort : the process of arranging activities in
    a      list to certain specific order.




                      Nabil Dmaidi                  173
Priorities & Sorts
 The activities making up the network must
  be listed in order of their priority of
  resources allocation.
 The network shows the logical sequence of
  activities. (predecessor and successor).
 The listing of activities must therefore
  reflects the dependency of some activities .


                   Nabil Dmaidi                  174
   Activities Sort
      Activity       Duration            ES       TF        Resource unit

             A            1                1       0              8H

             B            9                2       0              9H
             C            5                2       3              7H
             D            5                11      0              5H
             E            4                7       3              4H
             F            4                16      0        8H
             G            6                11      3              2H
             H            1                20      0              4H
Activity sort reflects the logic sequence of the network.
                                    Nabil Dmaidi                             175
   Major Sort
      Activity       Duration             ES      TF   Resource unit

             A            1                1       0         8H

             B            9                2       0         9H
             C            5                2       3         7H
             E            4                7       3         4H
             G            6                11      3         2H
             D            5                11      0         5H
             F            4                16      0         8H
             H            1                20      0         4H
Activity sort with ES time as Major sort
                                    Nabil Dmaidi                        176
     Major & Minor Sorts
      Activity       Duration           ES       TF          Resource unit

             A            1               1       0                 8H

             B            9               2       0                 9H
             C            5               2       3                 7H
             E            4               7       3                 4H
             D            5               11      0                 5H
             G            6               11      3                 2H
             F            4               16      0                 8H
             H            1               20      0                 4H
Activity sort with ES time as Major sort & TF as Minor Sort
                                   Nabil Dmaidi                               177
                                         Allocated resources



               8H
           A
                        9H 9H 9H 9H 9H 9H 9H 9H 9H
           B
                    7H 7H 7H 7H 7H
Activity




           C
                                       4H 4H 4H 4H
           E
                                                      5H 5H 5H 5H 5H
           D
                                                      2H 2H 2H 2H 2H 2H
           G
                                                                       8H 8H 8H 8H
           F
                                                                                     4H
           H

                    2       4     6     8       10       12   14   16      18    20
                                             Time
                                            Nabil Dmaidi                              178
                                               Time
                      2       4     6      8     10     12    14    16       18   20
                 8H
             A
                          9H 9H 9H 9H 9H 9H 9H 9H 9H
             B
                      7H 7H 7H 7H 7H
             C
                                         4H 4H 4H 4H
  Activity




             E
                                                       5H 5H 5H 5H 5H
             D
                                                       2H 2H 2H 2H 2H 2H
             G
                                                                        8H 8H 8H 8H
             F
                                                                                      4H
             H

Total Labor      8 16 16 16 16 16 13 13 13 13 7           7   7 7   7 10 8    8 8 4

                                    Early start resources aggregation
                                              Nabil Dmaidi                             179
Resource Aggregation
   Resources aggregation: is a summation of
    the resources that are used to carry out the
    program on a time period basis. For
    example, day to day , or week to week.




                      Nabil Dmaidi                 180
Total Labor     8 16 16 16 16 16 13 13 13 13 7    7   7 7   7 10 8        8 8 4




           16
   Labor




           14
           12
           10
            8
            6
            4
           2

                 2    4     6      8     10      12   14    16       18  20
                                       Nabil Dmaidi                      Time
                                                                            181
                     Early start resources aggregation diagram (Histogram)
    Late start
   Another histogram can be obtained if Late start
    considered. Shows different resources demand.

   And many histograms can be obtained
    considering a different time in the network.

   Each histogram shows different resources
    demand.


                       Nabil Dmaidi                182
     Late start Sorts
      Activity       Duration           LS       TF          Resource unit

             A            1               1       0                 8H

             B            9               2       0                 9H
             C            5               5       3                 7H
             E            4               10      3                 4H
             D            5               11      0                 5H
             G            6               14      3                 2H
             F            4               16      0                 8H
             H            1               20      0                 4H
Activity sort with LS time as Major sort & TF as Minor Sort
                                   Nabil Dmaidi                               183
                                                 Time
                      2       4       6      8     10     12     14        16   18    20
                 8H
             A
                          9H 9H 9H 9H 9H 9H 9H 9H 9H
             B
                                    7H 7H 7H 7H 7H
             C
                                                     4H 4H 4H 4H
  Activity




             E
                                                        5H 5H 5H 5H 5H
             D
                                                                   2H 2H 2H 2H 2H 2H
             G

                                                                            8H 8H 8H 8H
             F
                                                                                          4H
             H

Total Labor      8 9 9            9 16 16 16 16 16 13 9     9   9 7   7 10 10 10 10 4

                                                 resources
                                      Late startNabil Dmaidi aggregation                   184
Total Labor     8 9 9       9 16 16 16 16 16 13 9    9   9 7   7 10 10 10 10 4




           16
   Labor




           14
           12
           10
            8
            6
            4
           2

                 2      4       6     8    10       12   14    16    18     20
                                        Nabil Dmaidi
                     Late start resources aggregation diagram (Histogram)      185
                                                                             Time
Total Labor     8 9 9       9 16 16 16 16 16 13 9     9   9 7     7 10 10 10 10 4




           16
   Labor




           14
           12
           10
            8
            6
            4
           2

                  2     4       6      8     10     12     14     16     18      20
                                                                                   Time
                                                                                     186
                                           Nabil Dmaidi aggregation diagram (Histogram)
                Early start vs Late start resources
Total Labor      8 9 9       9 16 16 16 16 16 13 9    9   9 7   7 10 10 10 10 4




           16
   Labor




           14
           12
           10
            8
            6
            4
           2

                   2     4       6     8    10       12   14    16    18    20
                                            Nabil Dmaidi
                                                                                 Time
                                                                                 187
                Early start vs Late start resources aggregation diagram (Histogram)
                                 E
                            10   6   16
                            16 6 6 22



                   B             F              I
               6   4   12   11   2   17    13   3   19
               10 0 6 16    13 0 6 19      16   6 6 22



     A             C             G                            K
1    5    1    6   5   6    11   3   11                  22   2     22
6 0 0     6    11 0 0 11    14 0 0 14                    24 0 0 24




                   D                            J
               6   2   12                  14       14
                                                8
               8 0 6 14                    22 0 0 22

                                 H
ES   Dur. LS
                            8     6   16
EF FF TF LF
                                8 Dmaidi
                            14 Nabil8 22                          188
   Activities Sort
      Activity       Duration           ES       TF       Resource unit

            A            5               1        0                8H

            C            5               6        0                2H
            D            2               6        6                4H
            B            4               6        6                9H
            H            6               8        8                5H
            E            6               10       6                5H
            G            3               11       0                2H
            F            2               11       6                8H
            I            3               13       6                5H
            J            8               14       0                2H
            K            2               22       0                6H

Activity sort with ES time as Major sort & TF and duration as Minor Sorts
                                   Nabil Dmaidi                             189
                                   Time
          2    4     6        8      10       12        14    16    18    20    22         24

 A      8H 8H 8H 8H 8H

 C                       2H 2H 2H 2H 2H

 D                       4H 4H

 B                        9H 9H    9H
                         9H 9H 9H 9H

 H                               5H 5H 5H   5H 5H 5H

 E                                      5H 5H 5H       5H 5H 5H

 G                                          2H 2H 2H

 F                                          8H 8H

 I                                                     5H 5H 5H
 J                                                        2H 2H 2H 2H 2H 2H 2H 2H

 K                                                                                  6H 6H

Total
Labor
        8 8   8 8   8 15 15 16 16 12 20 20 17 12 12 2 2               2 2 2 2 6        6
                                        Nabil Dmaidi                                 190
                             Early start resources aggregation
Total
Labor
                8 8       8 8       8 15 15 16 16 12 20 20 17 12 12 2 2               2 2 2 2 6              6




   20
  18

  16
Labor




  14
  12
  10
        8
        6
        4
    2

            2         4         6       8    10      12          14   16       18      20       22      24
                                                  Nabil Dmaidi                                          191
                                                  Time                Early start resources aggregation diagram
   Activities Sort
      Activity       Duration           LS       TF        Resource unit

            A            5               1        0                8H

            C            5               6        0                2H
            D            2               12       6                4H
            B            4               12       6                9H
            E            6               16       6                5H
            H            6               16       8                5H
            G            3               11       0                2H
            F            2               17       6                8H
            I            3               19       6                5H
            J            8               14       0                2H
            K            2               22       0                6H

Activity sort with LS time as Major sort & TF and duration as Minor Sorts
                                   Nabil Dmaidi                             192
                                    Time
          2    4        6      8      10      12       14   16    18      20    22         24

 A      8H 8H 8H 8H 8H

 C                       2H 2H 2H 2H 2H

 D                                              4H 4H

 B                                              9H 9H 9H 9H

 E                                                            5H 5H 5H 5H 5H 5H

 H                                                            5H 5H 5H 5H 5H 5H

 G                                          2H 2H 2H

 F                                                               8H 8H

 I                                                                       5H 5H 5H
 J                                                      2H 2H 2H 2H 2H 2H 2H 2H

 K                                                                                  6H 6H
Total
Labor
        8 8   8 8   8       2 2 2   2   2   2 15 15 11 11 12 20 20 17 17 17 6          6
                                        Nabil Dmaidi                                 193
                              Late start resources aggregation
Total
            8 8   8 8   8       2 2 2   2    2    2 15 15 11 11 12 20 20 17 17 17 6 6
Labor




   20
  18

   16
Labor




   14
   12
  10
        8
        6
        4
        2

             2    4         6      8        10     12      14       16       18      20       22      24
                                            Nabil Dmaidi                                          194
                                            Time                Late start resources aggregation diagram
                                               Early start
    20
    18



Labor
    16
    14
    12
    10
     8
     6
     4
     2
         2 4   6   8 10 12 14 16 18 20 22 24
                       Time

    20
    18                                          Late start
Labor




    16
    14
    12
    10
     8
     6
     4
     2
         2 4   6   8 10 12 14 16 18 20 22 24
                      Nabil Dmaidi                           195
                       Time
Total
Labor
             8 8   8 8   8 15 15 16 16 12 20 20 17 12 12 2 2               2 2 2 2 6             6




        20
        18

        16
Labor




        14
        12
        10
         8
         6
         4
        2

              2     4     6     8    10      12       14        16       18      20       22      24
                                       Nabil Dmaidi                                           196
                                          Time             Early/Late start resources aggregation diagra
Smoothing/Leveling
   Let us program activity F to start by its late start
    day which is day 17

   And activity I to start by day 14.

   The resulting resources aggregation histogram will
    be as follows:




                         Nabil Dmaidi                      197
                                   Time
          2    4     6        8      10       12       14   16      18     20   22         24

 A      8H 8H 8H 8H 8H

 C                       2H 2H 2H 2H 2H

 D                       4H 4H

 B                        9H 9H    9H
                         9H 9H 9H 9H

 H                               5H 5H 5H   5H 5H 5H

 E                                      5H 5H 5H 5H 5H 5H

 G                                          2H 2H 2H

 F                                                                 8H 8H

 I                                                      5H 5H 5H
 J                                                      2H 2H 2H 2H 2H 2H 2H 2H

 K                                                                                6H 6H

Total
Labor
        8 8   8 8   8 15 15 16 16 12 12 12 12 12 12 7 10 10 2 2 2 6                    6
                                        Nabil Dmaidi                                 198
                             Early start resources aggregation
Total
Labor           8 8       8 8       8 15 15 16 16 12 12 12 12 12 12 7 10 10 2 2 2 6             6




   20
  18

   16
Labor




   14
   12
  10
        8
        6
        4
        2

            2         4         6       8    10      12          14   16   18   20   22   24
                                                  Nabil Dmaidi                            199
                                                  Time
Smoothing/Leveling
   Let us program activity H to start by its late
    start time.

   So its resources demand starts with its Late
    start date.

   The resulting resource aggregation and
    histogram will be as follows:
                      Nabil Dmaidi                   200
                                   Time
          2    4     6        8      10       12        14    16        18   20   22         24

 A      8H 8H 8H 8H 8H

 C                       2H 2H 2H 2H 2H

 D                       4H 4H

 B                        9H 9H    9H
                         9H 9H 9H 9H

 H                               5H 5H 5H   5H 5H 5H

 E                                                                5H 5H 5H 5H 5H 5H

 G                                          2H 2H 2H

 F                                          8H 8H

 I                                                     5H 5H 5H
 J                                                        2H 2H 2H 2H 2H 2H 2H 2H

 K                                                                                    6H 6H

Total
Labor
        8 8   8 8   8 15 15 16 16 7 15 15 12 7 7                  7 7    7 7 7 7 6       6
                                        Nabil Dmaidi                                   201
                             resources aggregation
Total
Labor
             8 8   8 8   8 15 15 16 16 7 15 15 12 7       7    7 7    7 7 7 7 6       6




        20
        18

        16
Labor




        14
        12
        10
         8
         6
         4
        2

              2     4     6     8    10     12       14       16     18   20   22         24
                                      Nabil Dmaidi                                  202
                                          Time
Smoothing/Leveling
   In case activity D is splitable activity. It could be
    interrupted to be carried out in tow parts.

   Let us program activity B to start by 7th day .

   And activity H to starts by its Late start date.

   And activity E to start by day 14.

   The resulting resource aggregation and histogram will be
    as follows:

                             Nabil Dmaidi                      203
                                   Time
          2    4     6         8     10      12        14      16     18     20    22         24

 A      8H 8H 8H 8H 8H

 C                       2H 2H 2H 2H 2H

 D                       4H                           4H

 B                            9H 9H 9H 9H

 H                                                               5H 5H 5H   5H 5H 5H

 E                                                         5H 5H 5H 5H 5H 5H

 G                                          2H 2H 2H

 F                                          8H 8H

 I                                                    5H 5H 5H
 J                                                         2H 2H 2H 2H 2H 2H 2H 2H

 K                                                                                     6H 6H

Total
Labor
        8 8   8 8   8 6       11 11 11 11 10 10 11 12 12 12 12 12 12 7 7               6   6
                                       Nabil Dmaidi                                     204
                              Early start resources aggregation
Total
Labor            8 8       8 8       8 6   11 11 11 11 10 10 11 12 12 12 12 12 12 7 7      6




        20
        18

        16
Labor




        14
        12
        10
         8
         6
         4
        2

             2         4         6         8   10      12       14   16   18   20   22         24
                                                 Nabil Dmaidi                            205
                                                    Time
Early Start or Early Finish
   There are many solutions between the limits of
    Early Start and Early Finish.

   The optimal solution is zero fluctuation histogram.
    Which is hard to be achieved.

   It is preferred to solve the problem toward the
    Early start resources aggregation diagram.

                        WHY ?!
                        Nabil Dmaidi                  206
Early Start or Early Finish
   Because if there are labor availability
    problems to be overcome, they will occur in
    the early beginning of the project.

   By other words, if the program based on the
    Late Start date, it means that all the
    activities are Critical, and any labor
    problem will affect the project completion.

                    Nabil Dmaidi              207
When Resources are Limited
Resources Allocation
   The previous method of resources aggregation has
    been carried out within a fixed project duration.

   The basic objective was to optimize the use of the
    resources and to know the mount of resources
    needed to carry out the job on time period basis.

   And to maintain the network based duration.


                       Nabil Dmaidi                      208
Allocation within resources
restraints
   Another situation which you may face in practice
    is the restricted resources availability.

   Where you have to carry out the job with the
    available resources only.

   In this case the project duration may be prolonged
    to suit the availability of the restricted resources.



                        Nabil Dmaidi                        209
       Resources Allocation


            A                    B                   D                 F               H
   1        1       1   2        9     2    11       5     11   16     4     16   20     1     20
   2   0        0   2   11   0       0 11   16 0         0 16   20 0       0 20   21 0       0 21
       8H                    9H                  5H                  8H                4H



                                 C                   E               G
                        2        5     5    7        4     10   11     6     14
                        7    0       3 10   11   0       3 14   17 3       3 20
 Activity                        7H                  4H              2H
 desc.
ES Dur. LS
EF FF TF LF
 Resources
                                            Nabil Dmaidi                                       210
     Activity list
      Activity       Duration           LS       TF          Resource unit

             A            1               1       0                 8H

             B            9               2       0                 9H
             C            5               5       3                 7H
             E            4               10      3                 4H
             D            5               11      0                 5H
             G            6               14      3                 2H
             F            4               16      0                 8H
             H            1               20      0                 4H
Activity sort with LS time as Major sort & TF as Minor Sort
                                   Nabil Dmaidi                               211
Solve the schedule
   Assume that the available labors in the
    company restricted to 10 helpers, and the
    company decided to carry out the job
    without resorting to hire more labor.

   The resulting program will exceed the Early
    finish date based on the network.


                     Nabil Dmaidi               212
Total Labor     8 16 16 16 16 16 13 13 13 13 7    7   7 7   7 10 8        8 8 4




           16
   Labor




           14
           12
           10
            8
            6
            4
           2

                 2    4     6      8     10      12   14    16       18  20
                                       Nabil Dmaidi                      Time
                                                                            213
                     Early start resources aggregation diagram (Histogram)
Rules for scheduling activities with
limited resources
1) schedule activities to start as soon as their predecessors
   have been completed.
2) if more than one activity using a specific limited resources
   can be scheduled, priority is given to the activity with early
   Late Start. ( LS as Major Sort)
3) if tow or more activities have the same Late start, give
   priority to the activity with least Total Float. (TF as Minor
   Sort)
4) if the activities have the same Total Float in the minor sort,
   give the priority to the activity with the Largest Number of
   Resources.
5) If the activities are tied in the number of resources, give
   priority to the activity that has already started.
                           Nabil Dmaidi                         214
       Resources Allocation


            A                    B                   D                 F               H
   1        1       1   2        9     2    11       5     11   16     4     16   20     1     20
   2   0        0   2   11   0       0 11   16 0         0 16   20 0       0 20   21 0       0 21
       8H                    9H                  5H                  8H                4H



                                 C                   E               G
                        2        5     5    7        4     10   11     6     14
                        7    0       3 10   11   0       3 14   17 3       3 20
 Activity                        7H                  4H              2H
 desc.
ES Dur. LS
EF FF TF LF
 Resources
                                            Nabil Dmaidi                                       215
                                                   Time
                 2        4    6     8    10 12 14 16 18 20 22                              24 26

           A    8H

           B         9H 9H 9H 9H 9H 9H 9H 9H 9H
                                                  7H 7H 7H 7H
           C
Activity




                                                                4H 4H 4H 4H
           E
                                                                5H 5H 5H 5H 5H
           D
           G                                                                  2H 2H 2H 2H 2H 2H

           F                                                                     8H 8H 8H

           H                                                                                      4H


Total Labor     8 9 9 9 9 9 9 9 9 9 7 7 7 7 9 9 9 9 7 10 10 10 2 2 4

           12
                                                                                                       Labor
           10
                                                                                                       Limit
  Labor




           8
           6

           4
           2
                                              Time Dmaidi
                                               Nabil                                                      216
                                   Resources aggregation diagram
Money and network schedules
   Reminder, cost was one of the elements of
    project constraints triangle ( COST, TIME
    & QUALITY)

   An effective management tries to minimize
    and integrate the above mentioned
    elements.


                    Nabil Dmaidi                217
Money and network schedules
   CPM provides a mean for relating time and
    money.

   The application of resources to a project
    (materials, manpower and machinery)
    related to another resource which is
    MONEY.

   The value of the resources for each activity
    represents a component of project cost.
                     Nabil Dmaidi                218
Hint
Construction costs includes:

     1) Materials costs.
     2) labor costs.
     3) plant and equipment costs
     4) overhead costs and profit.


                   Nabil Dmaidi      219
                                 E
                            10   6   16
                            16 6 6 22



                   B             F              I
               6   4   12   11   2   17    13   3   19
               10 0 6 16    13 0 6 19      16   6 6 22



     A             C             G                            K
1    5    1    6   5   6    11   3   11                  22   2     22
6 0 0     6    11 0 0 11    14 0 0 14                    24 0 0 24




                   D                            J
               6   2   12                  14       14
                                                8
               8 0 6 14                    22 0 0 22

                                 H
ES   Dur. LS
                            8     6   16
EF FF TF LF
                                8 Dmaidi
                            14 Nabil8 22                          220
Activities cost
   Activity   Duration         ES       TF   cost ( $)

         A       5              1        0    650

         C       5              6        0    1300
         D       2              6        6    400
         B       4              6        6    1450
         H       6              8        8    500
         E       6              10       6    1100
         G       3              11       0    600
         F       2              11       6    350
         I       3              13       6    1000
         J       8              14       0    1300
         K       2              22       0    200

                          Nabil Dmaidi                    221
                                                   Time
           2      4          6         8        10     12         14      16       18     20      22          24

  A     200 100 200 100 50

 C                           150 100 200 200 150

 D                               200 200

 B                               100 9H 9H 9H
                                 9H 250 300 100

 H                                         50 100 150 200 50 50

 E                                                200 200 100 150 100 150

 G                                                    200 200 200

 F                                                    150 100

  I                                                              200 100 100
 J                                                                   100 100 150 200 100 100 150 100

 K                                                                                                     100 100

Total
        200 100 200 100 50 350 550 550 400 500 750 450 600 300 350 150 200 100 100 150 100 100 100
cost
                                                  Nabil Dmaidi                                          222
Total
        200 100 200 100 50 350 550 550 400 500 750 450 600 300 350 150 200 100 100 150 100 100 100
cost




800

700

600

500

400

300

200

100


           2      4       6        8      10     12       14      16      18     20     22       24
                                         Time Dmaidi
                                           Nabil                                           223
Cash Flow
   It is quite significant to the contractor to
    know the amount of money that would be
    spent in each stage of the project.(
    Expenditures)

   And compare it to the amount of money that
    would be received. (income)


                      Nabil Dmaidi                 224
Overtrading
   Overtrading: arises when the current
    liabilities of a company exceed the current
    assets, even though the business is solvent.




                     Nabil Dmaidi                  225
                                                   Time
           2      4          6         8        10     12         14      16       18     20      22          24

  A     200 100 200 100 50

 C                           150 100 200 200 150

 D                               200 200

 B                               100 9H 9H 9H
                                 9H 250 300 100

 H                                         50 100 150 200 50 50

 E                                                200 200 100 150 100 150

 G                                                    200 200 200

 F                                                    150 100

  I                                                              200 100 100
 J                                                                   100 100 150 200 100 100 150 100

 K                                                                                                     100 100

Total
        200 100 200 100 50 350 550 550 400 500 750 450 600 300 350 150 200 100 100 150 100 100 100
cost
                                                  Nabil Dmaidi                                          226
Total
          200 100 200 100 50 350 550 550 400 500 750 450 600 300 350 150 200 100 100 150 100 100 100
cost
Com.      200 300 500 600 650 1000 1550 2100 2500 30003750 4200 4800 5100 5450 5600 580059006000 6150 6250 63506450
cost

  $
6400
6000
5600
5200
4800
4400
4000
3600
3200
2800
2400
2000
1600
1200
 800
 400

              2       4        6         8       10     12          14       16       18       20      22       24
 Com. cost = Cumulative Cost                    Time Dmaidi
                                                  Nabil
                                                                                        Cash Flow Diagram
                                                                                                          227
                                        Retainage Release
                  Expenditures


                  Revenues




Cumulative
Expenditure
s
& Revenues
              Amount of
              Negative
              Cash Flow




                                 Time (Months)
                               Nabil Dmaidi
                  Cash Flow Curve for revenue and expenditures   228
Cash Flow Analysis
   Cash flow analysis consists of a detailed
    examination of funds disbursement (expenditures)
    and the receipt of revenue.

   Cash flow shows if surplus fund available during
    project, or if negative cash position will occur
    during construction.

   The cash position of contractor during project
    whether positive or negative is important.


                       Nabil Dmaidi                    229
Negative cash position
 Negative cash position means that the
  revenues obtained from a project
  insufficient to meet the financial obligations
  (expenditures) of the project.
 In this case other fund from the company or
  from outside sources must be used.



                    Nabil Dmaidi               230
Positive cash position
   Positive cash position means that the revenues
    obtained from a project exceed the financial
    obligations (expenditures) of the project.

   In this case surplus (extra) fund available with the
    contractor.

   And the contractor may invest this surplus funds
    for short duration.

                        Nabil Dmaidi                       231
Time-Cost Trade-Off




Some amount of knowledge brings more……
                 Nabil Dmaidi            232
Time-Cost Trade-Off
   For the following discussions it is important
    to remember:

   Direct costs: Related to putting the facility
    components in place. They represent the
    resources used by an activity. (material,
    labor and equipment).


                      Nabil Dmaidi                  233
Time-Cost Trade-Off
   Indirect job costs (job overhead): costs that could
    not be attributed to a specific work item. (such as,
    site offices, superintendents, security fence & etc)

   These costs are generally incurred whether or not
    productive work achieved.

   Longer project duration will result in higher
    indirect costs.

                        Nabil Dmaidi                       234
Time-Cost Trade-Off
   Operating Overhead costs (company
    overhead): If the cost cannot be attributed to
    any specific job, they are operating
    overhead costs, costs of running business.
    (head office costs, communications & etc).

   These costs continue as long as the
    company exists even one project is running.

                     Nabil Dmaidi                235
Logic of Time-Cost Trade-Off
   Assumption: increasing or decreasing an
    activity’s duration will lead to increased
    direct costs for that activity.




                     Nabil Dmaidi                236
Direct
Costs



                               Direct costs




                         Project duration
                        Nabil direct
         General relation ofDmaidi costs to project duration   237
Logic of Time-Cost Trade-Off
   Assumption: decreasing a project’s
    duration will lead to lower indirect costs.




                     Nabil Dmaidi                 238
Indirect
 Costs




                                  indirect costs




                            Project duration
                          Nabil indirect costs to project duration
           General relation ofDmaidi                                 239
Logic of Time-Cost Trade-Off
   Assumption: A project’s duration can be
    decreased by decreasing the duration of
    one or more critical activities on the
    critical path.




                    Nabil Dmaidi              240
Logic of Time-Cost Trade-Off
   Assumption: Decreasing a project’s duration may
    increase or decrease the total cost of a project
    depending upon whether the additional direct
    costs required to decrease the activity duration
    are greater or less than indirect costs savings of
    decreasing the project’s duration.

    ‫تقليل المدة لزمنية للمشروع يمكن ان يزيد او يقلل من التكلفة‬    
        ‫الكلية للمشروع , وذلك اعتمادا على ما اذا كانت التكاليف‬
    ‫اإلضافية لتقليل مدة العمل أكبر و أقل من التوفير في التكاليف‬
                                                 .‫الغير مباشرة‬
                           Nabil Dmaidi                           241
                           Total project costs




Project
Costs


                                       Direct costs



          indirect costs




                               Project duration
                             Nabil project costs to project duration
              General relation ofDmaidi                                242
Graph analysis
   A project’s total costs combines direct costs and indirect
    costs. Therefore, the curve of total costs versus duration
    involves adding the cost amounts of direct and indirect
    costs curves.

   Remember, the direct costs curve has a negative slope
    (direct costs increase as duration decrease) and indirect
    costs curve has a positive slope (indirect costs decrease as
    duration decreases).

   So, the slope of the total costs curves at any point depends
    whether the slope of direct costs curve less than that of
    indirect cost curve.

                           Nabil Dmaidi                            243
                                  B                    G                          I
                        2         9     2    11        5     11         16        9     16
                        11   0        0 11   16 0          0 16         25 0          0 25
                            9H, 450 $            5H, 250 $                  8H, 450 $




            A                     D                         F                                       J
   1        1       1   2         9     8          11       8     17                         25     1     25
   2    0       0   2   11   0        6 17         19 0         6 25                         26 0       0 26
       8H, 200 $            9H, 900 $                  5H, 1200 $                             4H, 1500 $


                                  C                    E                     H
                        2         5     10   7         4     15        11     6       19
                        7     0       8 15   11    0       8 19        17 8       8 25
 Activity                   7H, 500 $             4H, 400 $             2H, 900 $
 desc.
ES Dur. LS
EF FF TF LF
 Resources                                        Nabil Dmaidi                                          244
   Activities Sort
      Activity       Duration          LS     TF         Resource
             Cost ($)
                                                             unit
              A            1                1     0          8H
              200
              B            9                2     0           9H
              450
              D            9                8      6          9H
              900
              C            5                10     8          7H
              500
              G            5                11    0           5H
              250
              E            4                15    8           4H
              400
              I            9                16    0           8H
              450
Activity sort with LS time as Major sort & TF and duration as Minor Sorts
              F            8         Nabil Dmaidi
                                            17    6           5H            245
Time-Cost Trade-off
   The previous analysis suggests that in performing
    Time-Cost Trade-off analysis, it is necessary to
    determine the cost of decreasing the critical path
    by one time unit (day, month & etc).
   The cost will vary depending upon which activity
    duration decreased.

   Usually, select the activity with least shortening
    costs. (lowest additional cost per day of
    shortening) to minimize the additional costs of
    shortening.
                        Nabil Dmaidi                     246
    Reducing Project Duration
       As the critical path of the network
        decreased, some non-critical activities lose
        some amount of their total float.

A

B

C

D

F

                         Nabil Dmaidi                  247
    Reducing Project Duration
       Thus, the extent to which an activity can be shortened and
        still has the effect of shortening the project is limited by
        the amount of total float exists in the parallel activities.



A

B

C

D

F

                               Nabil Dmaidi                            248
    Reducing Project Duration
       As the projects duration decreases, the number of
        critical paths through the network increases.



A

B

C

D

F

                           Nabil Dmaidi                     249
    Reducing Project Duration
       If more than one critical path exist, it is necessary to
        reduce all critical paths in the network simultaneously,
        which becomes expensive.



A

B

C

D

F

                               Nabil Dmaidi                        250
Four Different Solutions for Each
Network
    The schedule can be viewed in several different ways in
     order to satisfy the client. A client may with to perform
     the project in the lease cost, or in the least time. Or in
     any manner satisfies him.

1)   All Normal: the original network and activity duration
     result in all normal solution, based on each activity being
     performed in its “NORMAL” least cost manner.

     Remember, it is not necessarily the least cost or least
     time solution to schedule a project.


                          Nabil Dmaidi                            251
Four Different Solutions for Each
Network
2) Least Cost: considering both direct and
    indirect costs, it may be possible to find a
    project duration that minimizes these total
    costs. By paying more to decrease one or
    more critical activity (direct cost) and save
    greater indirect costs. (Means that the
    result will be total cost saving.)


                    Nabil Dmaidi                252
                           Total project costs




Project
Costs


                                       Direct costs



          indirect costs




                               Project duration
                             Nabil project costs to project duration
              General relation ofDmaidi                                253
Four Different Solutions for Each
Network
3) Least Time: A project can be shortened
    beyond its least cost duration. Until a
    point reached where no activities in the
    critical path can be physically shortened
    regardless of how many resources are
    applied. (results in higher costs)



                   Nabil Dmaidi                 254
Four Different Solutions for Each
Network
4) All crash: in this solution, every activity has been
    shortened as much as physically possible. Its
    duration the same as the least time solution, but
    its costs greater. Because the direct cost
    increases without further reductions in the
    indirect costs.

   A fully crashed schedule occurs when all
    activities shortened to their shortest possible
    duration.
                       Nabil Dmaidi                   255
Four Different Solutions for Each
Network

                     All crash
   It is not an efficient approach since some
    non-critical activities will be shortened
    without having any shortening influence
    on the project duration.



                    Nabil Dmaidi                 256
Logically reducing Project
Duration
   The logical approach is to shorten those
    activities that contribute to reduce the
    project duration.

   To begin the time-cost trade-off in a rational
    manner, basic calculations needed.

   First compute the early start and early finish
    times for each activity.
                     Nabil Dmaidi                257
                   Reducing Project Duration to shortest possible duration




                           B                             E                       H
                                         0                        4
                       2   7     2           9       3       13           16       7     16
                       9   0 0   9           12 4 4 16                    23   0       0 23
               0
                                                                                              0
                                     0                            0

     A                     C                         F                           J                         L
                   0                                                  0                           2
1    1     1           2   6     3           9       7       9            16       5     18           23   5     23
                                         1
2    0 0   2           8   1 1 9             16    0 0 16                 21 2         2 23           28 0 0 28

                                                                  0
               0                                                                              4

                           D         0               G                           K
                       2   3     9           5       8       12   3       16       3     20
                       5   0 7 12            13    3 7 20                 19 4 4         23


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                                 258
Logically reducing Project
Duration
   By computing the link lag values between
    activities. (Lag = ESB – EFA). It is logical that
    there is at least one path between the first activity
    and last activity where lag values are 0.

   These activities forming the critical path. (other
    solution can be derived by computing TF).

   In the previous network. Activity A,B,F,H and L
    forming the critical path.

                         Nabil Dmaidi                       259
Logically reducing Project
Duration
   To shorten the project’s duration it is essential to shorten
    on of the critical activities. A or B or F or H or L.

   Without shortening the project will end after 28 days with
    a cost of 5300 $.

   This is the normal duration cost. And any decrease in
    duration will increase the direct cost.

   The following table shows information about activities.


                            Nabil Dmaidi                           260
Duration-Cost Data
   Activity Normal       Crash       Normal       Crash          days to    cost per
                      Duration    Duration      Cost       Cost             Shorten
    day

    A                  1           1           800 800         0                    --
    B                  7           4           1000         1600            3
           200
    C                  6           4           300 500             2
           100
    D                  3           2           400          800             1
           400
    E                  3           1           100 200             2                50
    F                  7           5           500 800             2
           150
    G                  8           4           200 1400            4
           300
    H                  7           6           350          600             1
           250
    J                  5           3Nabil Dmaidi700 850            2                 261
                                                                                    75
Identifying activities for 1st
compression cycle

Activity       A            B                F                H      L


Cost/day       ∞           200$            150$              250$
  350$




     Cannot be shortened                   Least cost activity to shorten
     At any cost

                            Nabil Dmaidi                                    262
Logically reducing Project
Duration
   From the previous table, it can be noticed that
    activity F has the least incremental shortening
    cost.( 150 $ per day).

   E.g. Shortening F for 2 days costs 150 x 2 = 300 $.

   Bear in mind, activities for shortening selected
    based on cost per day. Not on cycle cost basis.


                        Nabil Dmaidi                   263
Logically reducing Project
Duration
   How many days activity F could be
    shortened?

   The answer in computing the Network
    Interaction Limit (NIL).

   So, reducing activity F by 2 days will affect
    the link lag values of the succeeding
    activities and TF of parallel activities.
                     Nabil Dmaidi                   264
                           B                             E                       H
                                         0                        4
                       2   7     2           9       3       13           16       7     16
                       9   0 0   9           12 4 4 16                    23   0       0 23
               0
                                                                                              0
                                     0                            0

     A                     C                         F                           J                         L
                   0                                                  0                           2
1    1     1           2   6     3           9       7       9            16       5     18           23   5     23
                                         1
2    0 0   2           8   1 1 9             16    0 0 16                 21 2         2 23           28 0 0 28

                                                                  0
               0                                                                              4

                           D         0               G                           K
                       2   3     9           5       8       12   3       16       3     20
                       5   0 7 12            13    3 7 20                 19 4 4         23


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                                 265
                           B                             E                       H
                                         0                        2
                       2   7     2           9       3       13           14     7     14
                       9   0 0   9           12 2 4 16                    21 0       0 21
               0
                                                                                            0
                                     0                            0

     A                     C                         F                           J                       L
                   0                                                  0                         2
1    1     1           2   6     3           9       5       9            14     5     16           21   5     21
                                         1
2    0 0   2           8   1 1 9             14    0 0 16                 19 2       2 21           26 0 0 26

                                                                  0
               0                                                                            4

                           D         0               G                           K
                       2   3     7           5       8       10       1   14     3     18
                       5   0 5 10            13    1 5 18                 17 4 4       21


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                               266
Summary of the first compression
cycle

Cycle   Activity    Can be    NIL         Days      Cost     Cost    Total    Project
          to       shortene             shortene   per day    per    cost    duration
 #
        shorten       d                    d                 cycle
 0         --         --      --           --        --       --     5300      28


 1         F          2        3           2       150 $     300 $   5600      26




                                    Nabil Dmaidi                                    267
Identifying activities for 2nd
compression cycle

Activity   A    B              F    H     L


Cost/day   ∞   200$            ∞   250$
  350$




                Nabil Dmaidi                  268
                           B                             E                       H
                                         0                        2
                       2   7     2           9       3       13           14     7     14
                       9   0 0   9           12 2 4 16                    21 0       0 21
               0
                                                                                            0
                                     0                            0

     A                     C                         F                           J                       L
                   0                                                  0                         2
1    1     1           2   6     3           9       5       9            14     5     16           21   5     21
                                         1
2    0 0   2           8   1 1 9             14    0 0 16                 19 2       2 21           26 0 0 26

                                                                  0
               0                                                                            4

                           D         0               G                           K
                       2   3     7           5       8       10       1   14     3     18
                       5   0 5 10            13    1 5 18                 17 4 4       21


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                               269
                           B                             E                       H
                                         0                        2
                       2   6     2           8       3       13           13     7    13
                       8   0 0   9           11 2 4 16                    20 0       0 20
               0
                                                                                            0
                                     0                            0

     A                     C                         F                           J                       L
                   0                                                  0                         2
1    1     1           2   6     2           8       5       8            13     5     15           20   5     20
                                         0
2    0 0   2           8   0 0 8             13    0 0 13                 18 2       2 20           25 0 0 25

                                                                  0
               0                                                                            4

                           D         0               G                           K
                       2   3     6           5       8       9        0   13     3    17
                       5   0 4 9             13    0 4 17                 16 4 4 20


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                               270
Summary of the 2nd compression
cycle

Cycle   Activity    Can be    NIL         Days      Cost     Cost    Total    Project
          to       shortene             shortene   per day    per    cost    duration
  #
        shorten       d                    d                 cycle
 0         --         --      --           --        --       --     5300      28


 1         F          2        3           2       150 $     300 $   5600      26


 2         B          3        1           1        200      200     5800      25




                                    Nabil Dmaidi                                    271
Identifying activities for 3rd
compression cycle

Activity   A     B,C           F    H     L


Cost/day   ∞     300           ∞   250$
  350$




                Nabil Dmaidi                  272
                           B                             E                       H
                                         0                        2
                       2   6     2           8       3       13           13     7    13
                       8   0 0   9           11 2 4 16                    20 0       0 20
               0
                                                                                            0
                                     0                            0

     A                     C                         F                           J                       L
                   0                                                  0                         2
1    1     1           2   6     2           8       5       8            13     5     15           20   5     20
                                         0
2    0 0   2           8   0 0 8             13    0 0 13                 18 2       2 20           25 0 0 25

                                                                  0
               0                                                                            4

                           D         0               G                           K
                       2   3     6           5       8       9        0   13     3    17
                       5   0 4 9             13    0 4 17                 16 4 4 20


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                               273
                           B                             E                       H
                                         0                        2
                       2   6     2           8       3       10           13     6     13
                       8   0 0   8           11 2 2 13                    19 0       0 19
               0
                                                                                            0
                                     0                            0

     A                     C                         F                           J                       L
                   0                                                  0                         1
1    1     1           2   6     2           8       5       8            13     5    14            19   5     19
                                         0
2    0 0   2           8   0 0 8             13    0 0 13                 18 1       1 19           24 0 0 24

                                                                  0
               0                                                                            3

                           D         0               G                           K
                       2   3     5           5       8       8        0   13     3     16
                       5   0 3 8             13    0 3 16                 16 3 3 19


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                               274
Summary of the 3rd compression
cycle

Cycle   Activity    Can be    NIL         Days      Cost     Cost    Total    Project
          to       shortene             shortene   per day    per    cost    duration
  #
        shorten       d                    d                 cycle
 0         --         --      --           --        --       --     5300      28


 1         F          2        3           2       150 $     300 $   5600      26


 2         B          3        1           1        200      200     5800      25


 3        H           1        2           1        250      250     6050      24




                                    Nabil Dmaidi                                    275
Identifying activities for 4th
compression cycle

Activity   A     B,C           F   H    L


Cost/day   ∞    300            ∞   ∞   350$




                Nabil Dmaidi                  276
                           B                             E                       H
                                         0                        2
                       2   6     2           8       3       10           13     6     13
                       8   0 0   8           11 2 2 13                    19 0       0 19
               0
                                                                                            0
                                     0                            0

     A                     C                         F                           J                       L
                   0                                                  0                         1
1    1     1           2   6     2           8       5       8            13     5    14            19   5     19
                                         0
2    0 0   2           8   0 0 8             13    0 0 13                 18 1       1 19           24 0 0 24

                                                                  0
               0                                                                            3

                           D         0               G                           K
                       2   3     5           5       8       8        0   13     3     16
                       5   0 3 8             13    0 3 16                 16 3 3 19


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                               277
                           B                             E                      H
                                         0                       2
                       2   4     2           6       3       8           11     6     11
                       6   0 0   6           9     2 2 11                17 0       0 17
               0
                                                                                           0
                                     0                           0

     A                     C                         F                          J                       L
                   0                                                 0                         1
1    1     1           2   4     2           6       5       6           11     5    12            17   5     17
                                         0
2    0 0   2           6   0 0 6             11    0 0 11                16 1       1 17           22 0 0 22

                                                                 2
               0                                                                           1

                           D         0               G                          K
                       2   3     3           5       8       6       0   13     3     14
                       5   0 1 6             13    0 1 14                16 1 1 17


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                              278
  Summary of the 4th compression
  cycle

Cycle    Activity     Can be     NIL      Days        Cost per   Cost per   Total    Project
        to shorten   shortened          shortened       day       cycle     cost    duration
 #
 0          --          --       --         --           --         --      5300      28


 1          F           2         3         2          150 $      300 $     5600      26


 2          B           3         1         1           200        200      5800      25


 3         H            1         2         1           250        250      6050      24


 4        B,C           2         3         2           300        600      6650      24

                                       Nabil Dmaidi                                        279
Identifying activities for 5th
compression cycle

Activity   A     B,C           F   H    L


Cost/day   ∞     ∞             ∞   ∞   350$




                Nabil Dmaidi                  280
                           B                             E                      H
                                         0                       2
                       2   4     2           6       3       8           11     6     11
                       6   0 0   6           9     2 2 11                17 0       0 17
               0
                                                                                           0
                                     0                           0

     A                     C                         F                          J                       L
                   0                                                 0                         1
1    1     1           2   4     2           6       5       6           11     5    12            17   5     17
                                         0
2    0 0   2           6   0 0 6             11    0 0 11                16 1       1 17           22 0 0 22

                                                                 2
               0                                                                           1

                           D         0               G                          K
                       2   3     3           5       8       6       0   13     3     14
                       5   0 1 6             13    0 1 14                16 1 1 17


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                              281
                           B                             E                      H
                                         0                       2
                       2   4     2           6       3       8           11     6     11
                       6   0 0   6           9     2 2 11                17 0       0 17
               0
                                                                                           0
                                     0                           0

     A                     C                         F                          J                       L
                   0                                                 0                         1
1    1     1           2   4     2           6       5       6           11     5    12            17   4     17
                                         0
2    0 0   2           6   0 0 6             11    0 0 11                16 1       1 17           21 0 0 21

                                                                 2
               0                                                                           1

                           D         0               G                          K
                       2   3     3           5       8       6       0   13     3     14
                       5   0 1 6             13    0 1 14                16 1 1 17


ES   Dur. LS
EF FF TF LF
                                                  Nabil Dmaidi                                              282
  Summary of the 5th compression
  cycle
Cycle    Activity     Can be     NIL      Days        Cost per   Cost per   Total    Project
        to shorten   shortened          shortened       day       cycle     cost    duration
 #
 0          --          --       --         --           --         --      5300      28


 1          F           2         3         2          150 $      300 $     5600      26


 2          B           3         1         1           200        200      5800      25


 3         H            1         2         1           250        250      6050      24


 4        B,C           2         3         2           300        600      6650      22


 5          L           1
                                 ∞          1           350        350      7000      21

                                       Nabil Dmaidi                                        283
Identifying activities for 6th
compression cycle

Activity   A     B,C           F   H   L


Cost/day   ∞     ∞             ∞   ∞   ∞




                Nabil Dmaidi               284
Exercise
   Reduce the following project to its shortest
    duration.




                     Nabil Dmaidi                  285
               B                   E
               10                  9




     A         C                   F   H
1    5         6                   6   5




               D                   G
               8                   9




ES   Dur. LS
EF FF TF LF
                    Nabil Dmaidi           286
Duration-Cost Data
   Activity   Normal       Crash          Normal   days to      cost per
    Duration   Duration   Duration         Cost        shorten         day

    A          5            5        100                    0              --
    B          10           7        500                    3             20
    C          6            4        300                    2             50
    D          8            6        400                    4            100
    E          9            5        200                    4             30
    F          6            5        100                    1             40
    G          9            7        320                    2             40
    H          5            4        410                    1             90




                                Nabil Dmaidi                                    287
                            B                         E
                                         0
                       6    10               16   9
                       16                    25
               0                                          0
                                     4

     A                      C                     F                H
                   0                 2                    5
1    5                 6    6                14   6           25   5
6                      12                    20               30

                                 0
               0                                          2
                            D            0        G
                       6    8                14   9
                       14                    23


ES   Dur. LS
EF FF TF LF
                                 Nabil Dmaidi                          288
Identifying activities for 1st
compression cycle

Activity   A           B        E    H

Cost/day   ∞           20       30   90




                 Nabil Dmaidi             289
                            B                         E
                                         0
                       6    10               16   9
                       16                    25
               0                                          0
                                     4

     A                      C                     F                H
                   0                 2                    5
1    5                 6    6                14   6           25   5
6                      12                    20               30

                                 0
               0                                          2
                            D            0        G
                       6    8                14   9
                       14                    23


ES   Dur. LS
EF FF TF LF
                                 Nabil Dmaidi                          290
                            B                        E
                                        0
                       6    8               14   9
                       14                   23
               0                                         0
                                    2

     A                      C                    F                H
                   0                2                    3
1    5                 6    6               14   6           23   5
6                      12                   20               28

                                0
               0                                         0
                            D           0        G
                       6    8               14   9
                       14                   23


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                          291
  Summary of the 1st compression
  cycle

Cycle    Activity     Can be     NIL      Days        Cost per   Cost per   Total    Project
        to shorten   shortened          shortened       day       cycle     cost    duration
 #
 0          --          --       --         --           --         --      2330      30


 1          B           3         2         2           20         40       2370      28




                                       Nabil Dmaidi                                        292
Identifying activities for 2nd
compression cycle

Activity   A   B,D              E,G   H

Cost/day   ∞   120              70    90




                 Nabil Dmaidi              293
                            B                        E
                                        0
                       6    8               14   9
                       14                   23
               0                                         0
                                    2

     A                      C                    F                H
                   0                2                    3
1    5                 6    6               14   6           23   5
6                      12                   20               28

                                0
               0                                         0
                            D           0        G
                       6    8               14   9
                       14                   23


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                          294
                            B                        E
                                        0
                       6    8               14   7
                       14                   21
               0                                         0
                                    2

     A                      C                    F                H
                   0                2                    1
1    5                 6    6               14   6           21   5
6                      12                   20               26

                                0
               0                                         0
                            D           0        G
                       6    8               14   7
                       14                   21


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                          295
  Summary of the 2nd compression
  cycle

Cycle    Activity     Can be     NIL      Days        Cost per   Cost per   Total    Project
        to shorten   shortened          shortened       day       cycle     cost    duration
 #
 0          --          --       --         --           --         --      2330      30


 1          B           3         2         2           20         40       2370      28


 2        E,G           2         3         2           70         140      2510      26




                                       Nabil Dmaidi                                        296
                            B                    E
                                        0
                       6    8               14   7
                       14                   21
               0                                     0
                                    2

     A                      C                    F            H
                   0                2                1
1    5                 6    6               14   6       21   5
6                      12                   20           26

                                0
               0                                     0
                            D           0        G
                       6    8               14   7
                       14                   21


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                      297
Identifying activities for 3rd
compression cycle


Activity   A   B,D             E,G   H

Cost/day   ∞   120              ∞    90




                Nabil Dmaidi              298
                            B                    E
                                        0
                       6    8               14   7
                       14                   21
               0                                     0
                                    2

     A                      C                    F            H
                   0                2                1
1    5                 6    6               14   6       21   5
6                      12                   20           26

                                0
               0                                     0
                            D           0        G
                       6    8               14   7
                       14                   21


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                      299
                            B                    E
                                        0
                       6    8               14   7
                       14                   21
               0                                     0
                                    2

     A                      C                    F            H
                   0                2                1
1    5                 6    6               14   6       21   4
6                      12                   20           25

                                0
               0                                     0
                            D           0        G
                       6    8               14   7
                       14                   21


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                      300
  Summary of the 3rd compression
  cycle

Cycle    Activity     Can be     NIL      Days        Cost per   Cost per   Total    Project
        to shorten   shortened          shortened       day       cycle     cost    duration
 #
 0          --          --       --         --           --         --      2330      30


 1          B           3         2         2           20         40       2370      28


 2        E,G           2         2         2           70         140      2510      26


 3         H            1        ∞          1           90         90       2600      25




                                       Nabil Dmaidi                                        301
Identifying activities for 3rd
compression cycle


Activity      A         B,D E,G      H

Cost/day      ∞         120      ∞   ∞




                  Nabil Dmaidi           302
                            B                    E
                                        0
                       6    8               14   7
                       14                   21
               0                                     0
                                    2

     A                      C                    F            H
                   0                2                1
1    5                 6    6               14   6       21   4
6                      12                   20           25

                                0
               0                                     0
                            D           0        G
                       6    8               14   7
                       14                   21


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                      303
                            B                    E
                                        0
                       6    7               13   7
                       13                   20
               0                                     0
                                    1

     A                      C                    F            H
                   0                1                1
1    5                 6    6               13   6       20   4
6                      12                   19           24

                                0
               0                                     0
                            D           0        G
                       6    7               13   7
                       13                   20


ES   Dur. LS
EF FF TF LF
                                Nabil Dmaidi                      304
Summary of the 4th compression
cycle
Cycle   Activity    Can be    NIL         Days      Cost     Cost    Total    Project
          to       shortene             shortene   per day    per    cost    duration
  #
        shorten       d                    d                 cycle
 0         --         --      --           --        --       --     2330      30


 1         B          3        2           2         20       40     2370      28


 2       E,G          2        2           2         70      140     2510      26


 3        H           1       ∞            1         90       90     2600      25


 4       B,D          1        2           1        120      120     2720      24



                                    Nabil Dmaidi                                    305
Nabil Dmaidi   306
Communicating
  the Schedule



     Nabil Dmaidi   307
Communicating the Schedule
     Anticipated User
      –   Top management - No need for great details
      –   Middle Management - looking for detailed breakdown covering
          long time span.
      –   Low-level Management - Superintendents, foreman - detail
          information, cover short period of time.
     Communicating Devices
      –   Verbal and written instructions and reports
      –   Tabular format
      –   Graphical representation
              bar chart
              time scaled

                                 Nabil Dmaidi                           308
Time-Scaled Arrow Diagram
Remodeling Chemical Laboratory




              Nabil Dmaidi       309
Nabil Dmaidi   310
Project Control




    DR. Nabil Dmaidi
Project Control
   Major objectives for a good control plan:
    1. Should accurately represent the work.
    2. Permit deviations to be detected, evaluated and
       forecasted.
    3. Should make provision for periodic corrective
       actions.




                      DR. Nabil Dmaidi
Level of Control
   Small projects - low cost - short duration
    –   Detailed network
    –   Reporting mechanism
   Middle-sized projects (300 activities)
    –   Detailed network
    –   Summary network
    –   Area and craft network


                       DR. Nabil Dmaidi
Target Activities Properties
   The scheduler has to choose between early start
    schedule or target schedule.
Two Major Considerations:
1. The way in which the resources are applied
    to the activity.
2. The manner in which the activity is to be
    measured.
 In all the previous work we assumed that each
   activity has a constant rate of utilization.


                      DR. Nabil Dmaidi
    We will keep this assumption knowing that the
    most probable one is
   If an activity has expended a third of its cost, the
    activity is said to be one-third finished.
   The most important consideration in measuring
    the completion of activities is that the measure
    should be consistent throughout the project.




                       DR. Nabil Dmaidi
Target Activity Durations




             DR. Nabil Dmaidi
Monitoring the Project
1. Feedback from direct contact
  –   Efficient but requires close cooperation
      between the manager and field personnel.




                     DR. Nabil Dmaidi
Monitoring the Project (cont.)

2. Feedback from photography
  –   Record progress and provide permanent
      documentation of the work.
  –   Tell nothing about the time taken to perform the
      work.




                     DR. Nabil Dmaidi
Monitoring the Project (cont.)

3. Feedback from check-off list
  –   Planner prepares a check-off list that is started,
      to be continued, or to be finished in the next
      time interval.
  –   Effective if the reporting periods are short
      “Daily, Weekly” and small number of activities
      involved.
  –   Disadvantage: false reporting


                      DR. Nabil Dmaidi
Monitoring the Project (cont.)

4. Feedback from bar chart
5. Feedback from networks
  Advantage:
   Superintendent has complete information about
   the status of the project.
  Disadvantage:
   Diagram may appear confusing to field
   personnel.

                  DR. Nabil Dmaidi
Setting the Target Schedule
Early Start Schedule: As Target for Control
  –   Problem:
      Required high effort to keep the plan working
Late Start Schedule As Target for Control
  –   Problem:
      Because every activity is timed to start as its latest,
      project overruns are sure to follow.




                         DR. Nabil Dmaidi
Target Schedule
 Activities may be positioned early or late
  start or somewhat in between.
 Non-critical activities allow intermediate
  start.




                  DR. Nabil Dmaidi
Anticipated target S-Curve




             DR. Nabil Dmaidi
The S-Curve field




               DR. Nabil Dmaidi
Sample Project Cost Data

                                  Cos t       T o ta l
                    D u ra tio    R a te      Cos t
     A c tiv ity   n (D a y s ) ($ /D a y )     ($ )
          A            2              500       1,000
          B            17             200       3,400
          C            3              300         900
          D            5              100         500
          E            6            2,000      12,000
          F            2              500       1,000
          G            1            1,000       1,000


                        DR. Nabil Dmaidi
Early Start Tree




              DR. Nabil Dmaidi
Late Start Tree




              DR. Nabil Dmaidi
Target Network




            DR. Nabil Dmaidi
Project S-Curve




              DR. Nabil Dmaidi
Actual Versus Target S-Curves




             DR. Nabil Dmaidi
Earned Value Analysis



        Nabil Dmaidi    331
Earned Value Analysis (EVA)
Foundations of modern cost control
   What’s more important?
    –   Knowing where you are on schedule?
    –   Knowing where you are on budget?
    –   Knowing where you are on work accomplished?
   Earned Value Analysis (EVA) addresses all three:
    –   It compares the PLANNED amount of work with what has
        actually been COMPLETED to determine if COST,
        SCHEDULE, and WORK ACCOMPLISHED are
        progressing as planned.




                          Nabil Dmaidi                         332
                                                               332
              EVA Terminology
   BCWS – Budgeted Cost of Work Scheduled
    –   Planned cost of the total amount of work scheduled to be
        performed by the milestone date. (a.k.a. your original plan)
   BCWP – Budgeted Cost of Work Performed
    –   The planned (not actual) cost to complete the work that has
        been done.
    –   Also known as “Earned Value”
   ACWP – Actual Cost of Work Performed
    –   Cost incurred to accomplish the work that has been done to
        date.



                           Nabil Dmaidi                           333
                                                                  333
      Input data for EVA
 Activity schedule, usually in the form
  of a bar chart.
 Budgeted cost for each activity.
 Percent complete for each activity.
 Cost to date for each activity.




                Nabil Dmaidi               334
                                           334
Information Needed to Compute
   Budgeted Cost of Work Scheduled (BCWS)
         Activity budget at completion (BAC)
         Activity schedule
         Data date
   Budgeted Cost of Work Performed (BCWP)
         Activity budget at completion (BAC)
         Physical activity progress as a percentage of its total work
   Actual Cost of Work Performed (ACWP)
         Each activity’s cost to date from the job costing system




                              Nabil Dmaidi                               335
                                                                         335
 Earned Value Reporting - Costs
                                          Budgeted Cost of Work
                                           Performed (BCWP) =
CV  BCWP  ACWP                           earned value of project
        BCWP                              Actual Cost of Work
  CPI                                     Performed (ACWP)
        ACWP
                                          Cost Variance (CV)
    CPI = 1, on budget                     – Difference between
    CPI < 1, over budget                     earned and actual costs
    CPI > 1, under budget
                                             for the completed work
                                          Cost Performance Index
                                           (CPI or CI)


                            Nabil Dmaidi                          336
                                                                  336
      Earned Value Reporting - Schedule
                                            Budgeted Cost of Work
                                             Performed (BCWP)
SV    BCWP  BCWS  Budgeted Cost of Work
                                             Scheduled (BCWS)
                 BCWP
     SPI                                  Schedule Variance (SV)
                              SV  BCWP  BCWS
                 BCWS SPI  BCWP – Difference between the
                                      BCWS
                                               value of work that was
      SPI = 1, on schedule                     planned for completion and
      SPI < 1, behind schedule
      SPI > 1, ahead of schedule               the value of the work that
                                               was actually completed
                                           Schedule Performance Index
                                             (SPI or SI)

                              Nabil Dmaidi                         337
                                                                   337
Earned Value Reporting

                          (budgeted)




     (earned)




            (actual)
           Nabil Dmaidi            338
           Earned Value Reporting –
             Activity A Example


Week BCWS BCWP ACWP
 1   300   500   500
 2   300   500   500
 3   300   300   300
 4   300   200   200




                          From: SBG
                       Nabil Dmaidi   339
                                      339
            Earned Value Reporting –
               Activity B Example


Week BCWS BCWP ACWP
 1   1000 1000 1000
 2   1000 1000 1000
 3   1000   500   500
 4    0     500   500




                                 From: SBG
                        Nabil Dmaidi         340
                                             340
           Earned Value Reporting –
              Activity C Example


Week BCWS BCWP    ACWP
 1   814    300   814
 2   814    400   686
 3   814    500   1000
 4   814    428   400




                                From: SBG
                         Nabil Dmaidi       341
                                            341
     Earned Value Reporting – Project
       (Activities A, B, C) Example

Week BCWS BCWP ACWP
 1   2114 1800 2314
 2   2114 1900 2186
 3   2114 1300 1800
 4   1114   1128   1100




                              From: SBG
                          Nabil Dmaidi    342
                                          342
        Earned Value Reporting – Project
          (Activities A, B, C) Example




             SI                     CI


From: SBG
                     Nabil Dmaidi          343
                                           343
  Earned Value Reporting – Project
    (Activities A, B, C) Example


Graph shows
trend of cost
                  (CI)

and schedule
   indices


      From: SBG




                         Nabil Dmaidi   (SI)   344
 Schedule and Estimated
          Costs                         Class Exercise: BCWS
                                        Week                                                         Week
          Task              Est. Cost        Week 2 Week 3 Week 4 Week 5 Week 6 Week 7 Week 8 Week 9
                                         1                                                            10
       Mobilization                     100%
                              2,000
        Grubbing                        100%
                              5,000
    Bridge Excavation
                              2,000
                                                100%                                           Data Date
   Install Prefabricated
                                                100%
           Bridge            47,000
     Back Fill Bridge                           100%
                              2,000
     Install Culverts                                  100%
                             10,000
Rough Excavate Roadway                                  25%    25%      25%      25%
                             112,000
  Install Sanitary Sewer                                                         50%    50%
                             57,000
   Install Water Lines                                                                  50%     50%
                             69,000
   Install Storm Drains                                                                         100%
                             15,000
Grade and Roll Sub Grade                                                                        50%     50%
                             12,000
 Place and Compact Road
                                                                                                        100%
           Base              42,000
                                                                      Example:
Place and Compact Asphalt                                             10,000 x 100%                     100%
                             48,000
                                                                      + 112,000 x 25%
    Grade Shoulders
                              3,000                                   = 38,000                                   100%

         Cleanup                                                                                                 100%
                              1,000
       Demobilize                                                                                                100%
                              2,000
 Cost/wk using estimate &
        schedule          429,000       7,000   51,000 Nabil Dmaidi
                                                        38,000                                 55,500   96,000   6,000 345
                                                                                                                       345
                     Class Exercise: BCWP
Actual Percent Performed per
            Week
                                                                                                                                     Week
           Task                 Est. Cost    Week 1     Week 2     Week 3     Week 4   Week 5   Week 6   Week 7    Week 8   Week 9
                                                                                                                                      10
          Mobilization               2,000     90%       10%
           Grubbing                  5,000    100%
      Bridge Excavation              2,000               100%
 Install Prefabricated Bridge       47,000                90%       10%
       Back Fill Bridge              2,000                90%        5%        5%
        Install Culverts            10,000                          80%        20%
  Rough Excavate Roadway           112,000                          10%        25%      30%       5%      30%
    Install Sanitary Sewer          57,000                                                       20%      50%
     Install Water Lines            69,000                                                                50%
     Install Storm Drains           15,000
  Grade and Roll Sub Grade          12,000
Place and Compact Road Base         42,000
 Place and Compact Asphalt          48,000
       Grade Shoulders               3,000
           Cleanup                   1,000
         Demobilize                  2,000
    Cost at Estimated values       429,000      6,800     46,300     24,000
    Budgeted Cost of Work
                                 (BCWP)         6,800     53,100     77,100
         Performed




                                                                                                                   Data Date




                                                             Nabil Dmaidi                                                                   346
                                                                                                                                            346
                        Class Exercise: ACWP
       Actual Costs
                                Actual                                                                          Week
           Task                           Week 1 Week 2 Week 3 Week 4 Week 5 Week 6 Week 7 Week 8      Week 9
                                 Cost                                                                            10
          Mobilization              2,119    1,907    212
           Grubbing                 5,386    5,386
      Bridge Excavation             2,265           2,265
 Install Prefabricated Bridge      40,537          36,483  4,054
       Back Fill Bridge             2,035           1,832    102    102
        Install Culverts            9,828                  7,862  1,966
  Rough Excavate Roadway          108,857                 10,886 27,214 32,657  5,443 32,657
    Install Sanitary Sewer         60,482                                      12,096 30,241
      Install Water Lines          64,066                                             32,033
     Install Storm Drains          14,473
  Grade and Roll Sub Grade         12,439
Place and Compact Road Base        40,298
 Place and Compact Asphalt        48,835
      Grade Shoulders              2,835
         Cleanup                     863
        Demobilize                 1,961
        Actual Totals            417,280   7,293   40,792   22,903
     Actual Cost of Work
                                (ACWP)     7,293   48,085   70,989
         Performed




                                                                                          Data Date




                                                      Nabil Dmaidi                                                     347
                                                                                                                       347
          Class Exercise: SPI and CPI

Performance Indexes
                          Actual   Week
Task                                    Week 2 Week 3 Week 4 Week 5 Week 6 Week 7 Week 8 Week 9 Week 10
                           Cost       1
 Schedule Performance
                          (SPI)    97.14% 91.55% 80.31%
 Index
 Cost Performance Index   (CPI)    93.24% 110.43% 108.61%




                                             Nabil Dmaidi                                         348
                                                                                                  348
Rolling Up EVA Measures




        Nabil Dmaidi      349
                          349
Linear Scheduling Method




          Nabil Dmaidi     350
Linear Scheduling Method

Definition
 A simple diagram to show location and time
 at which a certain crew will be working on a
 given operation.




                  Nabil Dmaidi              351
Characteristics
   Shows repetitive nature of the construction.
   Progression of work can be seen easily.
   Sequence of different work activities can be easily
    understood .
   Have fairly high level of detail.
   Can be developed and prepared in a shorter time
    period than other formats.



                         Nabil Dmaidi                     352
Advantages of LSM

   Provides more information concerning the
    planned method of const. than a bar chart.
   In certain types of projects, LSM offers
    some advantages over the network
    approach.



                     Nabil Dmaidi                353
Line of Balance Technique
   LSM has relationships to the line of balance
    (LOB) technique, developed by US. Navy
    in the early 1950s.
   First applied to industrial manufacturing
    and production control.




                     Nabil Dmaidi               354
Three diagrams are used in LOB:
 1. Production Diagram
     Shows the relationships of the assembly operations
     for a single unit. Similar to AOA, except that it
     shows only one unit of production.
 2. Objective Diagram
     Used to plot the planned or actual number of units
     produced vs. time. LSM diagram resembles this
     diagram.
 3. Progress Diagram
     Shows the number of units for which each of the
     subassembly operations has been completed.
                       Nabil Dmaidi                       355
Difference between Objective
Diagram and LSM :
 O.D. is used to schedule or record the
     cumulative events of unit completion.
 LSM is used to plan or record progress
     on multiple activities that are moving
  continuously in sequence along the
     length of a single project.



                   Nabil Dmaidi               356
Implementation of LSM
   Can be used for continuous activities rather
    than discrete activities.
   Transportation projects; highway const.,
    highway resurfacing and maintenance, airport
    runway const. and resurfacing, tunnels, mass
    transit systems, pipelines, railroads.
   High-rise building construction
   Repetitive building units

                       Nabil Dmaidi                357
Elements of the LSM
 Axis Parameters
 Location
 Measure of progress.
 In high-rises and housing const., measures
  may be stories, floors, subdivisions,
  apartments, housing units
 In Transportation projects, distance (ft. or
  mile can be used, but division by stations
  (100ft.) is common) is general.
                    Nabil Dmaidi                 358
Time
   Hours, days, week, or month - depends on
    the total project time and level of detail
    desired in the schedule.
   Preferable to prepare the schedule based on
    working days and convert to calendar days
    only at the end.



                     Nabil Dmaidi                 359
Activity Production Rates
 Obtained by the usual estimating methods
  as a function of the activity, equip.
  characteristics, labor, and job conditions.
 The initial rate should be associated with
  the min. direct cost of accomplishing the
  single activity.



                   Nabil Dmaidi                 360
Activity Interruption and Restraint
   Prod. rate may vary with locations or time
    periods.
   Progress may be interrupted intentionally
    and restraints may occur between activities
    due to limited equip. or crews.




                     Nabil Dmaidi                 361
Buffers
   When const. activities progress
    continuously in a chain, some spacing
    between activities is required.
   This spacing serves as a buffer and may
    require distance or time interval between
    activities.



                     Nabil Dmaidi               362
Activity Intervals
   Used to describe the period of time between the
    start and finish of an activity at a particular
    location.
   Intervals can be indicated by a broad line, two
    narrow lines, etc.
   Monitoring Progress
   Working calendar can be marked with a moving
    symbol or a line, tape, etc. vertically across the
    diagram.
   Progress on individual activities would be marked
    by location rather than time.
                          Nabil Dmaidi                   363
1. Project Time Optimization
   The total project time may be such that
    indirect costs and liquidated damages
    assessed are more costly than the expense of
    accelerating certain activities.
   Cost-duration analysis can be used to
    minimize the total cost, as follows :



                     Nabil Dmaidi              364
a) Identify all activities that can be accelerated or
  decelerated.
b) Among the above, consider only those that are at a
  buffer limitation at both the start and the finish of the
  activity.
c) Of these, select the one activity with the lowest cost
  slope associated with acceleration (or deceleration).
d) Accelerate (or deceleration) the activity rate of
  production the maximum feasible amount.
e) Repeat the above steps successively until the optimum
  project cost and associated duration are obtained.
                          Nabil Dmaidi                        365
2. Discrete Activities
  Discrete are best scheduled by other methods.
  Once the duration is determined by network
  analysis, it can be scheduled on the LSM
  diagram and coordinated with the linear
  activities.

3. Seasonal Adjustments
  When developing LSM, appropriate
  adjustments can be made for seasonal effect on
  construction progress.


                         Nabil Dmaidi              366
4. Project Progress and Resource Management
   Project progress is often estimated by the S-
    curve with bar chart development.
   In LSM, the determination of activity
    progress is facilitated and made more
    rigorous.




                      Nabil Dmaidi                  367
LSM Schedule


   4
   3
   2
   1

       2   4   6   8    10 12 14 16 1820 22 24




                       Nabil Dmaidi              368
LSM Schedule with Brickwork


   4
   3
   2
   1

       2   4   6   8    10 12 14 16 1820 22 24

                                      Buffer




                       Nabil Dmaidi              369
Four-unit Duplex I-J Fragnet
   2          7            8
   EXC FNDS   F&P FNDS     FRAME
   BLDG 1     & SLAB       BLDG 1
              BLDG 1

                2             7           8
                EXC FNDS      F&P FNDS    FRAME
                BLDG 2        & SLAB      BLDG 2
                              BLDG 2

                              2           7          8
                              EXC FNDS    F&P FNDS   FRAME
                              BLDG 3      & SLAB     BLDG 3
                                          BLDG 3

                                          2          7
                                          EXC FNDS   F&P FNDS
                                          BLDG 4     & SLAB
                                                     BLDG 4




                           Nabil Dmaidi                         370
LSM Schedule

    Duplex Number

                    4

                    3

                    2

                    1


                        2   4    6    8    10   12   14   16   18
                                      Days




                                Nabil Dmaidi                        371
LSM Schedule
   Duplex Number


                   4

                   3

                   2

                   1


                       2   4   6    8   10    12   14   16   18
                                   Days




                               Nabil Dmaidi                       372

						
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