Jeopardy Thermo A

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					 Round 2!

Double Jeopardy
Calorim-            Changes            Thermo
           Energy              Vocab
  etry               in Heat            Fun

  100       100       100      100      100


  200       200       200      200      200


  300       300       300      300      300


  400       400       400      400      400


  500       500       500      500      500
                                              FJ
     Calorimetry for 100

Question: What is the system in
 this example?




                            NaOH
         H 2O

        Check Your Answer
    Calorimetry for 100

Answer: NaOH




                          NaOH
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     Calorimetry for 200

Question: Heat lost by the
 system is equal to what?



       Check Your Answer
     Calorimetry for 200

Answer: Heat gained by the
 surroundings



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      Calorimetry for 300
Question: What is wrong with this
 calorimeter?




         Check Your Answer
     Calorimetry for 300

Answer: no cover – losing
 heat to the environment!



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      Calorimetry for 400
Question: What
 is/are the
 surrounding(s) in
 this example?


        Check Your Answer
     Calorimetry for 400

Answer: Water
 (and everything
 else except the
 metal!)

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      Calorimetry for 500
Question: What law explains the basis
 for calorimetry?




         Check Your Answer
     Calorimetry for 500

Answer: Law of Conservation
 of Energy



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       Energy for 100

Question: What type of
 energy is stored in the
 bonds of a substance?


       Check Your Answer
       Energy for 100

Answer: Chemical potential
 energy



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       Energy for 200

Question:
 Which has the
 most thermal
 energy? (all
 contain H2O)

       Check Your Answer
      Energy for 200

Answer: B, most
mass and highest
temperature


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       Energy for 300
Question: A 30.0 g piece of
 metal gives off 250. J as it
 cools down 35.0  oC. What is

 the specific heat of the
 metal?
       Check Your Answer
         Energy for 300

Answer: 0.238    J/g oC

    q        250 .J
c                       0.238 J / g C
                                      o

   mT 30 .0 g  35 .0 C
                      o




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       Energy for 400

Question: What is the term
 for the measure of the
 average kinetic energy of a
 substance?

       Check Your Answer
       Energy for 400

Answer: Temperature

Kinetic energy =
energy of motion
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      Energy for 500

Question: Convert
 this energy to
 joules.
              440.
             Calories

      Check Your Answer
         Energy for 500

Answer: 1.84 x   106   J


440Cal 1000cal 4.184J
                     1.84 x10 J
                                6

  1     1Cal    1cal

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   Changes in Heat for 100
Question: Is this process
 endothermic or exothermic:
 Water vapor in the air
 condenses on the outside
 of a glass of iced tea.

         Check Your Answer
  Changes in Heat for 100

Answer: Exothermic

                            Heat is
                           released

                           Ice Lab!

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   Changes in Heat for 200

Question: What is the term
 for energy transferred
 between objects because
 of a difference in
 temperature?
        Check Your Answer
  Changes in Heat for 200

Answer: Heat




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   Changes in Heat for 300

Question: Calculate the amount
  of heat required in kilojoules
  to boil 50.0g of water at its
  boiling point.


        Check Your Answer
     Changes in Heat for 300
Answer: 113 kJ


               1molH 2O     40 .7 kJ
50 .0 gH 2O                         113 kJ
              18 .02 gH 2O 1molH 2O


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   Changes in Heat for 400

Question: A 20.0g sample of water
 at 250. K is mixed with 35.0g of
 water at 310. K. Calculate the
 final temperature of the mixture
 assuming no heat loss to the
 surroundings.
        Check Your Answer
   Changes in Heat for 400
Answer: 288K
     q gained   qlost
   20.0(T f  250)  35.0(T f  310)
   20.0T f  5000  35.0T f  10850
            55.0T f  15850
              T f  288K
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   Changes in Heat for 500
Question: How much heat does a
  metal lose when it is heated and
  then submerged in 150. g of cool
  water, and the temperature of the
  water increases by 3.80oC assuming
  no heat loss to the surroundings?

         Check Your Answer
     Changes in Heat for 500
Answer: 2380 J

           qlost  q gained
q  mC T  150 .g  4.184 J / g C  3.80 C  2380 J
                               o        o




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        Vocab for 100

Question: What
 is the name for
 this piece of
 equipment?


        Check Your Answer
        Vocab for 100

Answer: Calorimeter




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         Vocab for 200
Question: What is the term for the
 amount of heat need to raise the
 temperature of an object by 1oC?




         Check Your Answer
         Vocab for 200
Answer: heat capacity




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        Vocab for 300

Question: What is the term for
 the heat content of a system at
 constant pressure?



        Check Your Answer
         Vocab for 300
Answer: Enthalpy (H)




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         Vocab for 400
Question: What does ΔHf stand
 for?




        Check Your Answer
        Vocab for 400
Answer: Standard heat of
 formation




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         Vocab for 500
Question: What is the term that
 means the energy required to boil
 one mole of a substance at its
 boiling point?


        Check Your Answer
         Vocab for 500
Answer: Molar heat of vaporization,
 ΔHvap




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      Thermo Fun for 100
Question: What are standard
 conditions for a thermochemical
 equation?




        Check Your Answer
     Thermo Fun for 100
Answer: 25oC and standard
 pressure (1 atm)




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      Thermo Fun for 200
Question: Write the complete
 thermochemical equation for the
 formation of carbon monoxide gas.




         Check Your Answer
       Thermo Fun for 200
Answer:

C(s) + ½ O2(g)  CO(g) ΔH = -110.5 kJ/mol




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        Thermo Fun for 300
Question: Find the ΔH for this reaction
 using Hess’s Law:
 H2CO3   (g)      H2O + CO2
                          (g)         (g)   ΔH=?

 H2CO(g) + O2(g)  H2CO3(g)          ΔH =-252.0 kJ
 H2O(g) + CO2(g)  H2CO(g) + O2(g)   ΔH =112.5 kJ
               Check Your Answer
        Thermo Fun for 300
Answer:
 H2CO3(g)        H2CO(g) + O2(g)    ΔH =+252.0 kJ
 H2CO(g) + O2(g)  H2O(g) + CO2(g)   ΔH =-112.5 kJ

H2CO3  (g)    H2O + CO2
                    (g)       (g)    ΔH=139.5kJ

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     Thermo Fun for 400
Question: How much heat is
 absorbed when 15.0 g of NH4NO3
 are dissolved in water?
 NH4NO3(s) → NH4+(aq) + NO3-(aq)
  Hsoln = 25.7 kJ/mol

        Check Your Answer
          Thermo Fun for 400
Answer: 4.82 kJ

                   1molNH 4 NO3       25 .7 kJ
15 .0 gNH 4 NO3                                4.82 kJ
                  80 .06 gNH 4 NO3 1molNH 4 NO3




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      Thermo Fun for 500
Question: It takes 153.9 J to raise
 the temperature of 25.75 g of iron
 from 25.0oC to 38.3oC. Calculate
 the molar heat capacity.



         Check Your Answer
            Thermo Fun for 500
Answer: 25.1 J/moloC

q  mC T
    q       153 .9 J       55 .85 gFe
C                                   25 .1J / mol o C
   mT 25 .75 g  13 .3 C 1molFe
                       o




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     Final Category



Heat in Changes of State
         Final Question
 Question: How
 many kilojoules
  are required to
heat 10.0 grams of
water from 10.0 oC  Cice = 2.03 J/goC
    to 110. oC?    Csteam = 2.02 J/goC

               Answer
                        Final Answer
Answer: 26.6 kJ                                                      C
                                                             B




                                                                     end
                                                 A
                                                     start


A : q  mC T  10 .0 g  4.184 J / g o C  90 o C  3765 .6 J  3.7656 kJ
                     1molH 2O     40 .7 kJ       +
B : q  10 .0 g                           22 .59 kJ
                    18 .02 gH 2O 1molH 2O
                                                                 +
C : q  mC T  10 .0 g  2.02 J / g C  10 C  202 J  0.202 kJ
                                      o      o




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