Math 017 Exam 1 by CF6hC8G

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									Math 121 Review for Exam 2

1. Truncate to 4 significant digits.
(a) 0.0040549          (b) 870723              (c) 70.005              (d) 83066

2. Round to 3 siginificant digits.
(a) 0.0070378          (b) 960645              (c) 0.0999607           (d) 98.747

3. Find the indicated absolute values.
(a)  5                (b) 37                  (c)  5  8             (d)  8  6

4. Rewrite each number without an exponent
(a) 5.8  10 5     (b) 48.2  107       (c)         728.2 E +2        (d) 84  10 2

5. Rewrite each decimal number in decimal normalized exponential form.
(a) 0.000706        (b) 910000           (c) 39.16  10 3    (d) 6.17  104

6. Rewrite each decimal number in scientific notation.
(a) 4090000          (b) 0.0000083          (c) 403 105              (d) 0.032  10 2

7. Rewrite each binary number in binary normalized exponential form.
(a) 0.00001011       (b) 100101000         (c) 0.0101 2 4      (d) 1101 2 3

8. Rewrite each binary number in binary scientific notation..
(a) 0.00011011       (b) 10110100          (c) 0.011 2 4             (d) 1010 2 5

9. Write 73 10
(a) as a 32-bit binary integer.
(b) as a 32-bit binary floating point number using the current IEEE standard.
        Hint: bit 0: sign
                bits 1 to 8: 127 more than the binary scientific notation exponent
                bits 9 to 31: the fractional part of the binary scientific notation mantissa
(c) in ASCII binary code Hint: 7 = 0011_0111 and 3 = 0011_0011 in ASCII.

10.   Compute 23  7 and write the answer as
(a)   an integer quotient and remainder.       (b) a mixed number.
(c)   a repeating decimal.                     (d) a truncated decimal with 3 significant digits.
(e)   a rounded decimal with 3 significant digits.

11. Compute and write the answer in decimal normalized exponential form.
(a) 0.64  10 3  0.62  10 4           (b) 0.76  10 6 0.21  10 4 
(c) 0.73  105  0.87  10 4              (d) 0.31  10 3   0.16  10 8 

12. Compute and write the answer in scientific notation.
(a) 8.3  10 2  4.9  103               (b) 6.8  10 3 3.9  10 8 
(b) 6.2  103  4.7  102                  (d) 7.2  10 2   1.5  10 8 
Math 121 Answers to Review for Exam 2

1.(a) 0.004054            (b) 870700          (c) 70.00               (d)   83060
2.(a) 0.00704             (b) 961000          (c) 0.1000              (d)   98.7
3.(a) 5                   (b) 37              (c) 13                  (d)   2
4.(a) 0.000058            (b) 482000000       (c) 72820               (d)   0.84
                  3                                            1
5.(a) 0.706  10          (b) 0.91 10  6
                                              (c) 0.3916  10         (d)   0.617  105
                                       6                   3
6.(a) 4.09  10 6
                          (b) 8.3  10        (c) 4.03  10           (d)   3.2  10 4
                  4                                        5
7.(a) 0.1011 2           (b) 0.100101 2   9
                                              (c) 0.101 2            (d)   0.1101 2 7
                  4                                     6
8.(a) 1.1011 2           (b) 1.01101 2  7
                                              (c) 1.1 2              (d)   1.01 28
9.(a) 0000_0000_0000_0000_0000_0000_0100_1001
  (b) 0 100_0010_1 001_0010_0000_0000_0000_0000
  (c) 0011_0111_0011_0011
10.(a) 3 R 2 (b) 3 2 7    (c) 3.285714       (d) 3.28         (e) 3.29
11.(a) 0.702  10 3        (b) 0.1596  10 10   (c) 0.643  105     (d) 0.19375 10 4
12.(a) 8.79  10 2         (b) 2.652  106       (c) 5.73  103      (d) 4.8  10 6

								
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