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Glencoe Algebra

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					Five-Minute Check (over Chapter 7)
Then/Now
New Vocabulary
Example 1: Monomial in Factored Form
Example 2: GCF of a Set of Monomials
Example 3: Real-World Example: Find a GCF
          Over Chapter 7




A.

                                     A.   A
B. 3abc
                                     B.   B
C. 4a2b                              C.   C
                           0%   0%
                                     D.
                                     0%
                                          D
                                          0%

D. 5a3b
                           A




                                B




                                     C




                                          D
                    Over Chapter 7


Simplify (–2x4y)(–3x2)2.

A. –18x8y


B. –6x8y
                                               A.   A
C. 6x6y                                        B.   B
                                               C.   C
D. 18x8y
                                     0%   0%
                                               D.
                                               0%
                                                    D
                                                    0%




                                     A




                                          B




                                               C




                                                    D
                      Over Chapter 7


Simplify (3x – 2)2.

A. 9x – 4


B. 9x2 – 4
                                                 A.   A
C. 9x2 – 12x + 4                                 B.   B
                                                 C.   C
D. 9x2 + 6 – 4
                                       0%   0%
                                                 D.
                                                 0%
                                                      D
                                                      0%




                                       A




                                            B




                                                 C




                                                      D
                     Over Chapter 7


Simplify (2x – 6)(2x + 6).

A. 4x


B. 4x2 – 36
                                                A.   A
C. 4x2 – x + 6                                  B.   B
                                                C.   C
D. 4x2 – x
                                      0%   0%
                                                D.
                                                0%
                                                     D
                                                     0%




                                      A




                                           B




                                                C




                                                     D
                    Over Chapter 7


The perimeter of a plot of land
is represented by
36x2 – 54x + 18. If the measures
of three sides are given, what
is the measure of the fourth
side?
A. 20x2 – 40x + 10                             A.   A
B. 18x2 – 9x + 9                               B.   B
                                               C.   C
C. 10x2 – 15x + 5                    0%   0%
                                               D.
                                               0%
                                                    D
                                                    0%




                                     A




                                          B




                                               C




                                                    D
D. 5x2 – 12x + 13
                    Over Chapter 7


Which value of n makes (c6 – 3)2 = cn – 6c6 + 9 true?

A. 12


B. 8
                                                A.   A
C. 6                                            B.   B
                                                C.   C
D. 4
                                      0%   0%
                                                D.
                                                0%
                                                     D
                                                     0%




                                      A




                                           B




                                                C




                                                     D
You multiplied monomials and divided a
polynomial by a monomial. (Lessons 7–1
and 7–2)



• Factor monomials.
• Find the greatest common factors of
  monomials.
• factored form
• greatest common factor (GCF)
             Monomial in Factored Form

Factor 18x2y3 completely.
18x2y3 = 2 ● 9 ● x ● x ● y ● y ● y       18 = 2 ● 9,
                                         x2 = x ● x, and
                                         y3 = y ● y ● y
       =2●3●3●x●x●y●y●y                  9=3●3




Answer: 18x2y3 in factored form is
        2 ● 3 ● 3 ● x ● x ● y ● y ● y.
Factor 15a3b2 completely.

A. 15 ● a ● a ● a ● b ● b


B. 3 ● 5 ● a ● a ● a ● b ● b
                                         A.   A
C. 3 ● 5 ● a3b2
                                         B.   B
D. 3 ● 5 ● a ● a ● a ● b2                C.   C
                               0%   0%
                                         D.
                                         0%
                                              D
                                              0%




                               A




                                    B




                                         C




                                              D
            GCF of a Set of Monomials

Find the GCF of 27a2b and 15ab2c.

27a2b = 3 ● 3 ● 3 ● a ● a ● b    Factor each number.
15ab2c = 3 ● 5 ● a ● b ● b ● c   Circle the common
                                 prime factors.




Answer: The GCF of 27a2b and 15ab2c is 3 ● a ● b or
        3ab.
Find the GCF of 39x2y3 and 26xy4.

A. 2xy


B. 13xy
                                              A.   A
C. 39x2y3
                                              B.   B
D. 13xy3                                      C.   C
                                    0%   0%
                                              D.
                                              0%
                                                   D
                                                   0%




                                    A




                                         B




                                              C




                                                   D
                          Find a GCF

GEOMETRY The lengths of the sides of a triangle
are 12wz2, 8wz, and 16w2z. Find the GCF of the
three lengths.
12wz2 = 3 ● 22 ● w ● z2
  8wz = 23 ● w ● z
16w2z = 24 ● w2 ● z
The common prime factors are 22 ● w ● z.

Answer: So, the GCF is 4wz.
Mary is making bracelets with large and small beads.
She has 20 large beads and 96 small beads. What is
the greatest number of bracelets she can make with
having any beads left over?

A. 3 bracelets

B. 4 bracelets                                 A.   A
                                               B.   B
C. 5 bracelets
                                               C.   C
D. 8 bracelets
                                     0%   0%
                                               D.
                                               0%
                                                    D
                                                    0%




                                     A




                                          B




                                               C




                                                    D

				
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