# Glencoe Algebra

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```					Five-Minute Check (over Chapter 7)
Then/Now
New Vocabulary
Example 1: Monomial in Factored Form
Example 2: GCF of a Set of Monomials
Example 3: Real-World Example: Find a GCF
Over Chapter 7

A.

A.   A
B. 3abc
B.   B
C. 4a2b                              C.   C
0%   0%
D.
0%
D
0%

D. 5a3b
A

B

C

D
Over Chapter 7

Simplify (–2x4y)(–3x2)2.

A. –18x8y

B. –6x8y
A.   A
C. 6x6y                                        B.   B
C.   C
D. 18x8y
0%   0%
D.
0%
D
0%

A

B

C

D
Over Chapter 7

Simplify (3x – 2)2.

A. 9x – 4

B. 9x2 – 4
A.   A
C. 9x2 – 12x + 4                                 B.   B
C.   C
D. 9x2 + 6 – 4
0%   0%
D.
0%
D
0%

A

B

C

D
Over Chapter 7

Simplify (2x – 6)(2x + 6).

A. 4x

B. 4x2 – 36
A.   A
C. 4x2 – x + 6                                  B.   B
C.   C
D. 4x2 – x
0%   0%
D.
0%
D
0%

A

B

C

D
Over Chapter 7

The perimeter of a plot of land
is represented by
36x2 – 54x + 18. If the measures
of three sides are given, what
is the measure of the fourth
side?
A. 20x2 – 40x + 10                             A.   A
B. 18x2 – 9x + 9                               B.   B
C.   C
C. 10x2 – 15x + 5                    0%   0%
D.
0%
D
0%

A

B

C

D
D. 5x2 – 12x + 13
Over Chapter 7

Which value of n makes (c6 – 3)2 = cn – 6c6 + 9 true?

A. 12

B. 8
A.   A
C. 6                                            B.   B
C.   C
D. 4
0%   0%
D.
0%
D
0%

A

B

C

D
You multiplied monomials and divided a
polynomial by a monomial. (Lessons 7–1
and 7–2)

• Factor monomials.
• Find the greatest common factors of
monomials.
• factored form
• greatest common factor (GCF)
Monomial in Factored Form

Factor 18x2y3 completely.
18x2y3 = 2 ● 9 ● x ● x ● y ● y ● y       18 = 2 ● 9,
x2 = x ● x, and
y3 = y ● y ● y
=2●3●3●x●x●y●y●y                  9=3●3

Answer: 18x2y3 in factored form is
2 ● 3 ● 3 ● x ● x ● y ● y ● y.
Factor 15a3b2 completely.

A. 15 ● a ● a ● a ● b ● b

B. 3 ● 5 ● a ● a ● a ● b ● b
A.   A
C. 3 ● 5 ● a3b2
B.   B
D. 3 ● 5 ● a ● a ● a ● b2                C.   C
0%   0%
D.
0%
D
0%

A

B

C

D
GCF of a Set of Monomials

Find the GCF of 27a2b and 15ab2c.

27a2b = 3 ● 3 ● 3 ● a ● a ● b    Factor each number.
15ab2c = 3 ● 5 ● a ● b ● b ● c   Circle the common
prime factors.

Answer: The GCF of 27a2b and 15ab2c is 3 ● a ● b or
3ab.
Find the GCF of 39x2y3 and 26xy4.

A. 2xy

B. 13xy
A.   A
C. 39x2y3
B.   B
D. 13xy3                                      C.   C
0%   0%
D.
0%
D
0%

A

B

C

D
Find a GCF

GEOMETRY The lengths of the sides of a triangle
are 12wz2, 8wz, and 16w2z. Find the GCF of the
three lengths.
12wz2 = 3 ● 22 ● w ● z2
8wz = 23 ● w ● z
16w2z = 24 ● w2 ● z
The common prime factors are 22 ● w ● z.

Answer: So, the GCF is 4wz.
Mary is making bracelets with large and small beads.
the greatest number of bracelets she can make with

A. 3 bracelets

B. 4 bracelets                                 A.   A
B.   B
C. 5 bracelets
C.   C
D. 8 bracelets
0%   0%
D.
0%
D
0%

A

B

C

D

```
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