TAP 608- 2: The latent heat of fusion of ice

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TAP 608- 2: The latent heat of fusion of ice Powered By Docstoc
					Name………………..
Group………………
                          The latent heat of fusion of ice
                                                                                                     o
This experiment is designed to measure the amount of heat needed to turn 1 kg of ice at 0 C
                       o
into 1 kg of water at 0 C
                                                                 A




                                                  V
                           ICE


                                    beaker
melted ice




What to do
1        Set up the apparatus as shown in the diagram but without the ice.
2        Weigh your beaker.
3        Crush the ice and put it in the funnel trying to pack it closely round the heater.
4        Start the stopwatch and time 5 minutes. Do not switch on!
5        Remove the beaker and weigh it again. This is the control beaker + melted ice.
6        Empty beaker.
7        Crush the ice and put it in the funnel trying to pack it closely round the heater again.
8        Start the stop watch and turn the current on to about 5 A at the same time.
9        Record the heater voltage and heater current.
10       Leave the heater on for five minutes, adding more ice if needed
11       Switch off, remove the beaker and weigh it.


Observations and calculations
1        Mass of beaker                                       =……………           g
2        Mass of control beaker + melted ice                  =……………           g
3        Mass of control melted ice (2-1)                     =……………           g
4        Mass of beaker + melted ice after heating            =……………           g
5        Mass of melted ice after heating (4-1)               =……………           g
6        Mass of ice melted due the heater alone (5-3)        =……………           g
7        Heater voltage                                       =…………...         V
8        Heater current                                       =…………...         A
9        Heater power (7x8)                                   =……………           W
10       Time                                                 =……………           s
11       Energy input = Power x Time (9x10)                   =……………           J
The energy in 11 is called the Latent Heat Energy and it melted __________ kg of ice.
So ____________J would melt 1 kg of ice.
This is the specific latent heat of fusion of ice since the specific latent heat energy is this is
because the definition is:
The amount of heat needed to change 1 kg of solid to 1 kg of liquid at its melting point
is called the specific latent heat of fusion of the material.

Fusion – Solid to liquid (or vice versa)
Vaporistion – liquid to gas (or vice versa)

				
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posted:6/9/2012
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