# lec_06

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```					Lecture                 DS & Algorithms:09

Abstract Data Types
Lecture                                         DS & Algorithms:09

Abstract Data Types

Data Type:
A data type is a collection of values and a set of operations on
those values.

The collection and operations form a mathematical construct

An ADT refers to the mathematical concept that defines the
data type

Each ADT operation is defined by its inputs and outputs.

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Lecture                                               DS & Algorithms:09

Abstract Data Types
Def. a collection of related data items
together with
an associated set of operations
e.g. whole numbers (integers) and arithmetic operators for addition,
subtraction, multiplication and division.

e.g. Flight reservation
Basic operations: find empty seat, reserve a seat,
cancel a seat assignment
Why "abstract?"
Data, operations, and relations are studied
independent of implementation.

What not how is the focus.

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Lecture                                                DS & Algorithms:09

Abstract Data Types

Def. Consists of
storage structures (data structures)
to store the data items
and
algorithms for the basic operations.

The storage structures/data structures used in implementations are
provided in a language (primitive or built-in) or are built from the
language constructs (user-defined).

In either case, successful software design uses data abstraction:
Separating the definition of a data type from its implementation.

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Lecture                                         DS & Algorithms:09
Separation of interface and implementation

• Think of ADT as a black box

• ADT is represented by an interface and implementation
is hidden from the user

– This means that the ADT can be implemented in various ways,
as long as it adheres to interface

– For example, a ListADT can be represented using an array
based implementation or a linked list implementation

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Lecture                                             DS & Algorithms:09

Linear list data structure
• Def: An ordered collection of elements
– some examples are an alphabetized list of students, a list of gold
medal winners ordered by year, etc.

• With these examples in mind, we feel the need to perform the
following operations on a linear list

–   Determine whether the list is empty
–   Determine the size of list
–   Find the element with a given index
–   Find the index of a given element
–   Delete an element given its index
–   Insert a new element

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Lecture                                                         DS & Algorithms:09

•   The ADT specification is independent of any representation and programming
language

AbstractDataType linearList
{
elements
ordered finite collection of zero or more elements
operations
empty(): return true if the list is empty
size(): return the list size
get(index): return the indexed element
indexOf(x): return the index of the first occurance of x in
the list, returns -1, if x is not in the list
erase(index): delete the indexth element, element with higher
index have their index reduced by 1
insert(index, x): insert x as the indexth element
output(): output the list elements from left to right

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Lecture                                       DS & Algorithms:09

Array representation
• [5, 2, 4, 8,1]
• Some of the implementations can be

location(i) = i    5   2   4   8   1

location(i) = 9- i                         1    8     4       2   5

location(i) = (7+i)%10    8   1                            5       2   4

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Lecture                         DS & Algorithms:09

Simple Data Types

Also known as built-in data types
Lecture                                          DS & Algorithms:09

Boolean data

Data values: {false, true}

In C/C++: false = 0, true = 1 (or nonzero)
Operations:       and    &&
or     ||
not    !
&& 0              1
||   0    1
0        0        0                                x !x
0    0    1
1        0        1                                0 1
1    1    1
1 0

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Lecture                                              DS & Algorithms:09

Character Data
Store numeric codes (ASCII, EBCDIC, Unicode)
1 byte for ASCII and EBCDIC,
2 bytes for Unicode
ASCII/EBCDIC

Unicode

Basic operation: comparison to determine if Equal, Less than,
Greater than, etc. use their numeric value.
,   11
Lecture                                              DS & Algorithms:09

Integer Data

Non-negative (unsigned) integer:
Store its base-two representation in a fixed number w of bits
(e.g., w = 16 or w = 32)

88 = 00000000010110002

Signed integer:
Store in a fixed number w of bits using one of the following representations:

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Lecture                                                    DS & Algorithms:09

Sign-magnitude representation

Save one bit (usually most significant) for sign
(0 = +, 1 = – )

Use base-two representation in the other bits.

88  _000000001011000
0

sign bit

–88  1
_000000001011000

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Lecture                                               DS & Algorithms:09

Two's complement representation                             Same as
sign mag.

For nonnegative n:
Use ordinary base-two representation with leading (sign) bit 0

For negative n (–n):
(1) Find w-bit base-2 representation of n
(2) Complement each bit.

Example: –88
1. 88 as a 16-bit base-two number     0000000001011000
2. Complement this bit string         1111111110100111

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Lecture               DS & Algorithms:09

Lecture                                          DS & Algorithms:09

Linear Arrays

•   A linear array is a finite number N homogeneous data elements

– Elements are referenced respectively by an index set of N
consecutive numbers

– Elements are stored respectively in successive memory locations

– Fixed number of elements

•   Index always integer

•   Length=UB-LB+1

•   Notation A1 or A(1) or A[1]

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Lecture                                                      DS & Algorithms:09

Declaring arrays in C++

element_type array_name[CAPACITY];
where
element_type           is any type
array_name             is the name of the array — any valid identifier
CAPACITY               (a positive integer constant) is the number of elements
in the array                    Can't input the capacity,
Why?
score[0]
The compiler reserves a block of “consecutive” memory                  score[1]
locations, enough to hold CAPACITY values of type                      score[2]
element_type.                                                          score[3]
.           .
.           .
The elements (or positions) of the array are indexed 0, 1, 2, . .          .           .
., CAPACITY - 1.                                                      score[99]
e.g., double score[100];
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Lecture                                   DS & Algorithms:09

How well does C/C++ implement an array ADT?

ordered              indices numbered 0, 1, 2, . . ., CAPACITY - 1
fixed size           CAPACITY specifies the capacity of the array
same type elements   element_type is the type of elements
direct access        subscript operator []

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Lecture                                                     DS & Algorithms:09

Array Initialization
In C++, arrays can be initialized when they are declared. an array literal
Numeric arrays:
element_type num_array[CAPACITY] = {list_of_initial_values};
Example:
double rate[5] = {0.11, 0.13, 0.16, 0.18, 0.21};
0       1       2       3         4
rate     0.11 0.13 0.16 0.18               0.21

Note 1: If fewer values supplied than array's capacity, remaining elements
assigned 0.
double rate[5] = {0.11, 0.13, 0.16};
0       1       2       3         4
rate     0.11 0.13 0.16              0         0

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Lecture                                                 DS & Algorithms:09

Character Arrays
Character arrays may be initialized in the same manner as numeric arrays.
declares vowel to be an array of 5 characters and initializes it as follows:

char vowel[5] = {'A', 'E', 'I', 'O', 'U'};
0   1    2    3    4
vowel   A   E    I    O    U

Note 1: If fewer values are supplied than the declared size of the array,
the zeroes used to fill un-initialized elements are interpreted as
the null character '\0' whose ASCII code is 0.

const int NAME_LENGTH = 10;
char collegeName[NAME_LENGTH]={'C', 'a', 'l', 'v', 'i', 'n'};
0   1   2   3 4    5 6    7 8 9
collegeName     C     a     l   v    i    n \0 \0 \0 \0

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Lecture                                               DS & Algorithms:09

When an array is declared, the address of the first byte (or word) in the block of
memory associated with the array is called the base address of the array.
Each array reference must be translated into an offset from this base address.
For example, if each element of array score will be stored in 8 bytes and the base
address of score is 0x1396. A statement such as
cout << score[3] << endl;
requires that array reference score[3]            score  0x1396               [0]
be translated into a memory address:                                           [1]
[2]
score[3]  0x1396 + 3 * sizeof (double)                         0x13ae             [3]
.        .
= 0x1396 + 3 * 8                                                  .        .
.        .
= 0x13BA
[99]
The contents of the memory word with this address
0x13BA can then be retrieved and displayed.
An address translation like this is carried out each time
What will be the
an array element is accessed.       time complexity
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Lecture                                           DS & Algorithms:09

Character arrays
The value of array_name is actually the base address of array_name
array_name + index is the address of array_name[index].

An array reference    array_name[index]
is equivalent to     *(array_name + index)

* is the dereferencing operator
*ref returns the contents of the memory location with address ref
For example, the following statements of pseudocode are equivalent:

print score[3]
print *(score + 3)

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Lecture                                  DS & Algorithms:09

Operations
•   Traverse
•   Insert
•   Delete
•   Search
– Linear Search
– Binary Search
• Sorting

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Lecture                                DS & Algorithms:09

Traversing Linear Arrays

Repeat for K=LB to UB
Apply PROCESS to Array[K]
[End of Loop]
Exit

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Lecture                                           DS & Algorithms:09

Sorting

BUBBLE(DATA,N)
1. Repeat Steps 2 and 3 for K=1 to N-1
2. Set PTR:=1
3. Repeat while PTR<=N-K
a) if DATA[PTR]>DATA[PTR+1] then:
Swap DATA[PTR] and DATA [PTR+1]
b) Set PTR:=PTR+1
4. Exit

Complexity of Bubble Sort?
n(n-1)/2 + O(n)=?
Can you see any problem?
How to make bubble sort efficient?

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Lecture                                                 DS & Algorithms:09

Bubble Sort Source Code
for(x = 0; x < n; x++)
{
for(y = 0; y < n-1; y++)
{
if(array[y] > array[y+1])
{
temp = array[y+1];
array[y+1] = array[y];
array[y] = temp;
}
}
}

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Lecture                                                 DS & Algorithms:09

•   void bubbleSort(int numbers[], int array_size)
•   {
•    int i, j, temp;
•    for (i = (n - 1); i >= 0; i--)
•    {
•      for (j = 1; j <= i; j++)
•      {
•          if (numbers[j-1] > numbers[j])
•          {
•            temp = numbers[j-1];
•            numbers[j-1] = numbers[j];
•            numbers[j] = temp;
•   }
•   }
•    }
•    }

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Lecture                                      DS & Algorithms:09

Bubble Sort: Example
• Consider the unsorted array to
the right
first location, and move forward:
– if the current and next items are in
order, continue with the next item,
otherwise
– swap the two entries

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Lecture                                DS & Algorithms:09

Bubble Sort: Example
• After one loop, the largest
element is in the last location
• Repeat the procedure

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Lecture                             DS & Algorithms:09

Bubble Sort: Example
• Now the two largest elements
are at the end
• Repeat again

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Lecture                             DS & Algorithms:09

Bubble Sort: Example
• With this loop, 12 is brought to
its appropriate location

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Lecture                            DS & Algorithms:09

Bubble Sort: Example
• Finally, we swap the last two
entries to order them
• At this point, we have a sorted
array

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Lecture                                         DS & Algorithms:09

Problems with arrays

•   Capacity can not be changed during program execution
– Memory wastage
– Out of range errors

33

```
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