AOSS 321, Winter 2009 Earth System Dynamics Lecture 5 1/22

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							        AOSS 321, Winter 2009
        Earth System Dynamics

                  Lecture 5
                  1/22/2009

Christiane Jablonowski       Eric Hetland
cjablono@umich.edu       ehetland@umich.edu
    734-763-6238             734-615-3177
                  Class News
• Class web site:
  https://ctools.umich.edu/portal
• HW 1 due today
• Homework #2 posted today, due on Thursday
  (1/29) in class
• Our current grader is Kevin Reed
  (kareed@umich.edu)
• Office Hours
   – Easiest: contact us after the lectures
   – Prof. Jablonowski, 1541B SRB: Tuesday after
     class 12:30-1:30pm, Wednesday 4:30-5:30pm
   – Prof. Hetland, 2534 C.C. Little, TBA
                   Today’s class

•   Definition of the the Total (Material) Derivative
•   Lagrangian and Eulerian viewpoints
•   Advection
•   Fundamental forces in the atmosphere:
    Surface forces:
     – Pressure gradient force
     –…
            Total variations
Consider some parameter, like temperature, T
                      Δx


                  y


                                           Δy
                           x
  If we move a parcel in time Δt

        Using Taylor series expansion


     T      T      T      T         Higher
T     t     x     y     z     Order
     t      x      y      z         Terms

    Assume increments over Δt are small, and
          ignore Higher Order Terms
                   Total derivative
     Total differential/derivative of the temperature T,
                   T depends on t, x, y, z

                T      T      T      T
           T     t     x     y     z
                t      x      y      z


            Assume increments over Δt are small

   Total Derivative
       Divide by Δt

T T T x T y T z
              
t t x t y t z t

   Take limit for small Δt

dT T T dx T dy T dz
              
dt t x dt y dt z dt
                Total Derivative
     Introduction of convention of d( )/dt ≡ D( )/Dt

            DT T T Dx T Dy T Dz
                          
            Dt t x Dt y Dt z Dt

                This is done for clarity.

                     By definition:
                Dx      Dy      Dz
                    u,     v,    w
                Dt      Dt      Dt
             u,v,w: these are the velocities
     Definition of the Total Derivative

             DT T    T    T    T
                  u    v    w
             Dt t    x    y    z

                 The total derivative is also
                 called material derivative.

     D()
         describes a ‘Lagrangian viewpoint’
     Dt
     ()    ()    ()    ()
         u     v     w     describes an ‘Eulerian viewpoint’
     t     x     y     z
             Lagrangian view
             Position vector at different times




Consider fluid parcel moving along some trajectory.
      Lagrangian Point of View
• This parcel-trajectory point of view, which
  follows a parcel, is known as the Lagrangian
  point of view.
   – Useful for developing theory
   – Requires considering a coordinate system
     for each parcel.
   – Very powerful for visualizing fluid motion
          Lagrangian point of view:
         Eruption of Mount Pinatubo
• Trajectories trace the motion of individual fluid
  parcels over a finite time interval
• Volcanic eruption in 1991 injected particles into
  the tropical stratosphere (at 15.13 N, 120.35 E)
• The particles got transported by the atmospheric
   flow, we can follow their trajectories
• Mt. Pinatubo, NASA animation
• Colors in animation reflect the atmospheric height of
   the particles. Red is high, blue closer to the surface.
• This is a Lagrangian view of transport processes.
        Global wind systems
• General Circulation of the Atmosphere
                 Zonally averaged circulation
         • Zonal-mean annual-mean zonal wind u



                                   
Pressure (hPa)
              Eulerian view
Now we are going to really think about fluids.




Could sit in one place and watch parcels go by.
How would we quantify this?
        Eulerian Point of View
• This point of view, where is observer sits at a
  point and watches the fluid go by, is known as
  the Eulerian point of view.
  – Useful for developing theory
  – Looks at the fluid as a field.
  – Requires considering only one coordinate system
    for all parcels
  – Easy to represent interactions of parcels through
    surface forces
  – A value for each point in the field – no gaps or
    bundles of “information.”
An Eulerian Map
       Consider some parameter, like
              temperature, T

                       y



                                 x




DT
    Material derivative, T change following the parcel
Dt
      Consider some parameter, like
             temperature, T

                      y



                                x




T
    Local T change at a fixed point
t
 Consider some parameter, like
        temperature, T

             y



                       x




v T    Advection
     Temperature advection term

                   T    T    T
      v  T  u    v    w
                   x    y    z




        Consider some parameter, like
               temperature, T

    T
 u                   y
    x


   T                        x
v
   y
  Temperature advection term


v  T  0 : warm air advection
v  T  0 : cold air advection
     Advection of cold or warm air
• Temperature advection: v  T
• Imagine the isotherms are oriented in the E-W
  direction         warm

               
        u

                                             y
                                                  X
                     cold
• Draw the horizontal temperature gradient vector!
• pure west wind u > 0, v=0, w=0: Is there
  temperature advection? If yes, is it cold or warm
  air advection?
     Advection of cold or warm air
• Temperature advection: v  T
• Imagine the isotherms are oriented in the E-W
  direction
                      cold

             v   


                                             y
                      warm
                                                  X
• Draw the gradient of the temperature (vector)!
• pure south wind v > 0, u=0, w=0: Is there
  temperature advection? If yes, is it cold or warm
  air advection?
     Advection of cold or warm air
• Temperature advection: v  T
• Imagine the isotherms are oriented as

          cold
                 
                        u
                                    warm
                                             y
• Draw the horizontal temperature gradient!       X
• pure west wind u > 0, v=0, w=0: Is there
  temperature advection? If yes, is it cold or warm
  air advection?
                Summary:
     Local Changes & Material Derivative

            T DT       T      T    T
                    u    v      w
            t    Dt    x      y    z
            T       DT
                          v  T
            t       Dt
Local change                          Advection term
at a fixed location
                    Total change along
                      a trajectory
     Summary: For 2D horizontal flows
            T DT       T      T
                   u      v
            t   Dt     x      y
            T DT
                    vh   hT
            t   Dt
                 u
      with v h    horizontal wind vector and
                 v 
                
                x 
           h     horizontal gradient operator
               
                y 
      Conservation and Steady-State
            DT
         if     0  Conservation of T
            Dt
            T
         if     0  Steady state is reached
            t

   Remember: we talked about the conservation of
   money

   Conservation principle is important for
   tracers in the atmosphere that do not have
   sources and sinks
                Class exercise
• The surface pressure decreases by 3 hPa per
  180 km in the eastward direction.
• A ship steaming eastward at 10 km/h measures
  a pressure fall of 1 hPa per 3 hours.
• What is the pressure change on an island that
  the ship is passing?
                         N
                    NW        NE


  Directions:   W               E


                    SW        SE
                         S
               Food for thought
• Imagine a different situation.
• The surface pressure decreases by 3 hPa per
  180 km in the north-east direction.
• Thus:

                       Low p

                u


      High p
    What are the fundamental forces in
           the Earth’s system?
•   Pressure gradient force
•   Gravitational force
•   Viscous force
•   Apparent forces: Centrifugal and Coriolis
•   Can you think of other classical forces and
    would they be important in the Earth’s system?

• Total Force is the sum of all of these forces.
        A particle of atmosphere
                           r ≡ density = mass
                           per unit volume (V)

                     z    V = xyz

                           m = rxyz
                           ---------------------------------
                y          p ≡ pressure =
                            force per unit area
      x
                            acting on the particle of
                            atmosphere
Check out Unit 6, frames 7-13:
http://www.atmos.washington.edu/2005Q1/101/CD/MAIN3.swf
Pressure gradient force (1)
(x0, y0, z0)            p0 = pressure at (x0, y0, z0)


                    z
                             Pressure at the ‘wall’:
                                        p x
            p .0
                               p  p0 
                                        x 2
                                              

                              higher order terms
                   y
                               Remember the Taylor
       x                      series expansion!
                   
                              x axis
           Pressure at the ‘walls’
         p x                                        p x
p  p0                                     p  p0        
         x 2                                         x 2
higher order terms                           higher order terms

                                        z
                      p . 0   

                                   y
                                                            F
                     x                       remember: p 
                                                            A
                                                x axis
          Pressure gradient force (3)
          (ignore higher order terms)
           p x 
FBx  p0         
                    yz
           x 2                     Area of side A:
                                  A     yz

                            .
                            z
                  B              y
Area of side B:
yz                  x                     p x 
                                 FAx  p0         
                                                      yz
                                             x 2 
     x axis                              Watch out for the + and -
                                         directions!
  Pressure gradient force (4):Total x force
        Fx  FBx  FAx
                  p x             p x 
            p0         
                           yz  p0         
                                                 yz
                  x 2              x 2 
                p
             xyz
                x
 We want force per unit mass
          Fx  p        
               xyz rxyz
              
          m  x         
                  1 p
             
                  r x
Vector pressure gradient force

         1 p p p
F / m   ( i  j  k)
         r x y z
                z k
         1
F / m   p           y j   x i
         r
                 Class exercise
 Compute the pressure gradient force at sea level in x
 and y direction at 60°N          Assume constant
 Isobars with contour              density r = 1.2 kg/m3
 interval p = 5 hPa                  and radius
                                      a = 6371 km


                            L
      1000 hPa                          = 20º = /9
                                       x = a cos 


Low pressure system                  = 20º = /9
at 60°N                             y = a 
                    Class exercise
Compute
                                             990
the pressure            1016
gradient force                                     1000
at the surface                 1008
                        1000

Contour
             1041
interval:
                                                          1008
4 hPa                                 1034



 Density?
                        1012
 NCAR
 forecasts
    Our momentum equation so far

         dv    1
              p  other forces
         dt    r


Here, we use the text’s convention that the velocity is

                   v  u,v,w
         Highs and Lows




Pressure gradient force tries to eliminate
        the pressure differences

						
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