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					Algebra 2 w/ Trig
     Lesson # 52
Chemical mixture problems
         Type A
                Chemical Mixtures
One solution is 10% sugar, and another solution
    is 50% sugar. How much of each solution
   should be used to make 100 ml of a solution
                 that is 20% sugar?
w  amount of weak solution
s  amount of strong solution
Solution : w  s  100                   w  100  s
Sugar : 10w  50s  20 100 
         10 100  s   50s  20 100 
                40s  10 100 
                   s  25 ml w  75 ml
                   Toolbox 1
One solution is 10% salt, and another solution is
 2% salt. How much of each should be used to
     make 1800 ml of a 6% salt solution?
      w  amount of weak solution
      s  amount of strong solution
         Solution : w  s  1800     w  1800  s
       Salt :   2w  10s  6 1800 
        2 1800  s   10s  6 1800 
              8s  4 1800 
        s  900 ml w  900 ml
                   Toolbox 2
 One solution is 25% acid, and another solution
is 10% acid. How much of each should be used
    to make 2500 ml of a 14% acid solution?
     w  amount of weak solution
     s  amount of strong solution
        Solution : w  s  2500  w  2500  s
      Salt :   10w  25s  14  2500 
     10  2500  s   25s  14  2500 
               15s  4  2500 
     s  666.6 ml      w  1833.3 ml
Assignment: Problem Set 52

				
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