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```					Algebra 2 w/ Trig
Lesson # 52
Chemical mixture problems
Type A
Chemical Mixtures
One solution is 10% sugar, and another solution
is 50% sugar. How much of each solution
should be used to make 100 ml of a solution
that is 20% sugar?
w  amount of weak solution
s  amount of strong solution
Solution : w  s  100                   w  100  s
Sugar : 10w  50s  20 100 
10 100  s   50s  20 100 
40s  10 100 
s  25 ml w  75 ml
Toolbox 1
One solution is 10% salt, and another solution is
2% salt. How much of each should be used to
make 1800 ml of a 6% salt solution?
w  amount of weak solution
s  amount of strong solution
Solution : w  s  1800     w  1800  s
Salt :   2w  10s  6 1800 
2 1800  s   10s  6 1800 
8s  4 1800 
s  900 ml w  900 ml
Toolbox 2
One solution is 25% acid, and another solution
is 10% acid. How much of each should be used
to make 2500 ml of a 14% acid solution?
w  amount of weak solution
s  amount of strong solution
Solution : w  s  2500  w  2500  s
Salt :   10w  25s  14  2500 
10  2500  s   25s  14  2500 
15s  4  2500 
s  666.6 ml      w  1833.3 ml
Assignment: Problem Set 52

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