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Kinematics Motion

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Equations of Uniform

Accelerated Motion

AP Physics C

Mrs. Coyle

Uniform Accelerated Motion







 Motion with constant acceleration

 Straight line



 Same direction

Equations for Uniform Accelerated Motion

 Velocity v= vo+ at



 Position x= xo + vot + ½ at2



 v2 = vo2 + 2a(x-xo)

Remember:

Displacement= Dx = x-xo

More

Equations  vavg = ½ (vo +v)

of Motion

for Uniform

 Dx = ½ (vo+ v)t

Accelerated

Motion

 Assume that ti=0

Example of Position vs Time

(Positive Acceleration)

Position x= xo + vot + ½ at2

(m)

Parabola

o





Time (s)

Slope of Tangent at a given time=

Instantaneous Velocity at that time

Example of Velocity vs Time

(Positive Acceleration)

Velocity v= vo+ at

(m/s)





o



Time (s)



Slope of Line= Acceleration

Area Under Line=Displacement

Example of Acceleration vs Time

(Const. a)

Acceleration

(m/s2)







o





Time (s)





Area under line = Change in Velocity

How do we derive Dx = ½ (vo+ v)t

from the graph?



v

Velocity

(m/s)

vo



o



t Time (s)





Hint: Area Under the Line=Displacement Δx

Example of Position vs Time

(Negative Acceleration)

Position

(m) Parabola





o





Time (s)

Example of Velocity vs Time

(Negative Acceleration)

Velocity

(m/s)





o



Time (s)



Slope of Line= Acceleration

Area Under Line=Displacement

Example of Acceleration vs Time

(Negative a)

Acceleration

(m/s2)



o









Time (s)





Area under line = Change in Velocity

How do we derive x= xo + vot + ½ at2 ?









Hint: Start with Dx = ½ (vo+ v)t



and then substitute for v that v = vo+at.

How do we derive v2 = vo2 + 2a(x-xo)?









 Hint: Start with Dx = ½ (vo+ v)t



then substitute for t = (v – vo) /a

Problem 1



A ball initially stationary, accelerates at

0.25m/s2 down a 2m inclined plane. It then

rolls up another incline, where it comes to

rest after rolling up 1m.

a) What is the speed of the ball at the bottom of

the incline and how much time did this take?

b) What is the acceleration along the second

plane?

Answer: a) 1m/s, 4sec, b) -0.5m/s2

Problem 2

A Mustang travelling with a constant velocity

of 35m/s, passes a stationary police car.

The reaction time of the officer was 2.5sec

and he then accelerates at 5.0 m/s2 to catch

the Mustang. How long does it take for the

police car to catch the Mustang?









Answer: 15.8sec



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