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Number Theory

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Number Theory
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Number Theory

November 13, 2006



Today’s dose of Gaussian Integers…

1. Ordinary integers are also Gaussian integers (by the identification a  a + 0i).

We call them rational integers, and if they are prime (in the ordinary integers) we call

them rational primes. Of course it’s being real that distinguishes them, not being

rational; but these are standard terms.



As we have seen, rational primes may or may not be Gaussian primes. (3 and 7 are, 2

and 5 aren’t.)



2. What are the Gaussian primes?



a. 1 + i is a prime, and so are its associates –1+i, 1 – i, and –1 – i.



a. Any rational prime p that satisfies p  3 (mod 4) is a Gaussian prime, and so

are its associates –p, pi, and –pi. (Proof: N(p) = p2, and any nontrivial factor would

have to have norm p, but no Gaussian integer has norm p because a2 + b2 = p never

occurs.)



b. If a2 + b2 = p, where now p is a rational prime satisfying p  1 (mod 4), then

a + bi is a Gaussian prime. Primes of this form come in eights: There are a + bi and its

associates, and the complex conjugate a – bi and its associates. (Proof: Since

N(a + bi) = p, there is no room for a nontrivial factor.)



Are there any other Gaussian primes? No, but I don’t think it’s obvious. The proof

would be easier after we prove unique factorization, but I propose to skip the proof then,

too.



3. Unique factorization in the Gaussian primes.



We needed ordering to prove unique factorization in Z. Specifically, we needed it for

these steps:

(a) If a | b, and b is positive, then a ≤ b.

(b) Given a and b, if b isn’t 0, we can write a = q b + r, with 0 ≤ r < b.

(In Z, q and r were unique, but we didn’t need that uniqueness to prove unique

factorization.)



We don’t have ordering in the Gaussian integers, but we have the norm, which turns out

to be just as good.

(a) If (a + bi) | (c + di) then N(a + bi) ≤ N(c + di).

(b) Given Gaussian integers x and y, if y isn’t 0, we can write x = q y + r, with

N(r) ≤ N(y).

(For the proof of the last part, see text p. 554. It uses geometry and isn’t hard. The

numbers q and r are not always unique.)



With these adjustments, the proof of unique factorization in the Gaussian integers works

exactly as it does for Z:



(a) Given non-zero Gaussian integers x and y, we can use the Euclidean

algorithm to find their gcd.



- Actually the gcd isn’t unique; if d is a gcd of x and y, then so are –d,

di, and –di. But it’s unique up to associates. We could have had the same problem in Z.

For example, the Euclidean algorithm could have given us +7 or –7 for gcd(14,21), but

we just chose the positive value.



- The gcd is “greatest” in the strong sense: Any common divisor of x and

y is a divisor of their gcd. (Or, of any of their gcds!)



(b) If gcd(x, y) = 1, we can reverse the algorithm to write ax + by = 1 for some

Gaussian integers a and b.



(c) Now if p is a Gaussian prime and p | xy, then p | x or p | y. Proof: If p

doesn’t divide x, then gcd (p, x) = 1, and we can write ap + bx = 1 for some a and b, or

apy + bxy = y. Now p divides both terms on the left, so it divides y.



(d) Any Gaussian integer can be factored into primes. If it isn’t prime then it can

be factored, and if the factors aren’t prime then they can be factored in turn, and the

process can’t go on forever because the factors’ norms keep getting smaller.



(e) If x = p1p2…pk = q1q2…qh, then each one of the pi’s must divide one of the

qj’s, and so on. (It isn’t necessary that pi actually be one of the qj’s; it could be one of the

associates of one of the qj’s. So in the Gaussian integers, factorization is unique only up

to associates. That’s true in the integers, too: 21 = 3  7 = ( -3 )  ( -7 ).)



4. An Application



Theorem: In the ordinary integers, if p is a prime and p  1 (mod 4), then p can be

written in as a sum of two squares, p = a2 + b2, in exactly one way (except for

exchanging a and b, and reversing the signs of a and/or b).



Proof. We showed earlier that p can be written as a sum of two primes. Suppose that

p = a2 + b2 and also p = c2 + d2. Then a  bi and c  di are all primes in the Gaussian

integers (because they all have norm p). Now



p = (a + bi) (a – bi) and p = (c + di) (c – di)

are two different prime factorizations of p in the Gaussian integers, so they must really

be the same, except for the order of the factors and substituting associates of the factors.//



So understanding the Gaussian integers helps us understand ordinary integers. This

keeps happening.



5. Restatement of the Gaussian primes.



Given the theorem, we can restate the list of Gaussian primes:



a. (1 + i) and its associates.



b. Each rational prime that is congruent to 3 (mod 4).



c. For each rational prime that is congruent to 1 (mod 4), exactly two Gaussian

primes: a + bi and a – bi, and their associates, where a and b are chosen so that

a2 + b2 = p.



(end)


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