# Extrinsic by y12b8L8

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```									Problem: Perform a two-tailed hypothesis test on both the intrinsic and extrinsic variables data, using a .05 significance le

5.5                 Data:                       n                    μ                 s
3.6                                             25                   5               1.02
6.7
5.6   (1) Formulate the hypotheses:
5.5
4.4                         H0: that is μ = 5
6.5                         Ha: that is μ ≠ 5
6.9
4.6   (2) Decide the test statistic and the level of significance:
6.8
5.5                   t (Two-tailed), α = 0.05           Lower Critical t- score = -2.0639
3.8
6.8   (3) State the decision Rule:
4.6
6.5                    Reject H0 if |t| > 2.0639
6.1
3.9   (4) Calculate the value of test statistic:
6.2
5.5                           SE = s/n = 0.2040
4.4                   t = (x-bar - μ)/SE = 2.0098
4.7
6.2   (5) Compare with the critical value and make a decision:
4.7
5.5                                  Since 2.0098                    <             2.0639
4.8
Decision: There is no sufficient evidence that the mean extrinsic satisfaction is different from 5.
x-bar =       5.41
s=        1.02 (6) Calculate the p- value for the test and interpret it:

p- value = 0.0558     This is the probability of rejecting a true null hypothesis.
data, using a .05 significance level. Begin by creating a null and alternate statement. Using Microsoft Excel to process your data. Copy a

x-bar
5.41

Upper Crtical t- score = 2.0639

we fail to reject H0

faction is different from 5.

ejecting a true null hypothesis.
to process your data. Copy and paste the results in Microsoft Word. Identify the significance level, the test statistic and the critical valu
test statistic and the critical value. State whether you are rejecting or failing to reject the null hypoothesis statement. In a separate par
esis statement. In a separate paragraph provide some information on when to use a t-test and when to use a z-test and why. Also prov
to use a z-test and why. Also provide some information about why samples are used instead of populations. This will be a T-test. There
tions. This will be a T-test. There are 25 intrinsic variables as follows: 5.5, 4.2, 6.2, 4.3, 3.2, 4.5, 4.7, 5.3, 6.2, 3.4, 5.5, 5.8, 6.2, 4.2, 5
5.3, 6.2, 3.4, 5.5, 5.8, 6.2, 4.2, 5.7, 6.4, 3.7, 6.2, 6.5, 5.1, 4.5, 6.3, 6.3, 5.2, and 6.6 There are 25 extrinsic variables as follows 5.5, 3
xtrinsic variables as follows 5.5, 3.6, 6.7, 5.6, 5.5, 4.4, 6.5, 6.9, 4.6, 6.8, 5.5, 3.8, 6.8, 4.6, 6.5, 6.1, 3.9, 6.2, 5.5, 4.4, 4.7, 6.2, 4,7, 5
3.9, 6.2, 5.5, 4.4, 4.7, 6.2, 4,7, 5.5, and 4.8
Problem: Perform a two-tailed hypothesis test on both the intrinsic and extrinsic variables data, using a .05 significance le

5.5     Data:          n             μ          s         x-bar
4.2                    25            5        1.04        5.27
6.2
4.3   (1) Formulate the hypotheses:
3.2
4.5             H0: that is μ = 5
4.7             Ha: that is μ ≠ 5
5.3
6.2   (2) Decide the test statistic and the level of significance:
3.4
5.5       t (Two-tailed), α = 0.05 Critical t- score = Upper Crtical t- score = 2.0639
Lower                       -2.0639
5.8
6.2   (3) State the decision Rule:
4.2
5.7        Reject H0 if |t| > 2.0639
6.4
3.7   (4) Calculate the value of test statistic:
6.2
6.5               SE = s/n = 0.2080
5.1       t = (x-bar - μ)/SE = 1.2981
4.5
6.3   (5) Compare with the critical value and make a decision:
6.3
5.2        Since 1.2981              <     2.0639      we fail to reject H0
6.6
Decision: There is no sufficient evidence that the mean intrinsic satisfaction is different from 5.
x-bar =       5.27
s=        1.04 (6) Calculate the p- value for the test and interpret it:

p- value = 0.2066        This is the probability of rejecting a true null hypothesis.
s data, using a .05 significance level. Begin by creating a null and alternate statement. Using Microsoft Excel to process your data. Cop

isfaction is different from 5.
t Excel to process your data. Copy and paste the results in Microsoft Word. Identify the significance level, the test statistic and the critic
vel, the test statistic and the critical value. State whether you are rejecting or failing to reject the null hypoothesis statement. In a sepa
hypoothesis statement. In a separate paragraph provide some information on when to use a t-test and when to use a z-test and why. A
d when to use a z-test and why. Also provide some information about why samples are used instead of populations. This will be a T-test
populations. This will be a T-test. There are 25 intrinsic variables as follows: 5.5, 4.2, 6.2, 4.3, 3.2, 4.5, 4.7, 5.3, 6.2, 3.4, 5.5, 5.8, 6.
.5, 4.7, 5.3, 6.2, 3.4, 5.5, 5.8, 6.2, 4.2, 5.7, 6.4, 3.7, 6.2, 6.5, 5.1, 4.5, 6.3, 6.3, 5.2, and 6.6 There are 35 extrinsic variables as follow
re 35 extrinsic variables as follows 5.5, 3.6, 6.7, 5.6, 5.5, 4.4, 6.5, 6.9, 4.6, 6.8, 5.5, 3.8, 6.8, 4.6, 6.5, 6.1, 3.9, 6.2, 5.5, 4.4, 4.7, 6.2
5, 6.1, 3.9, 6.2, 5.5, 4.4, 4.7, 6.2, 4,7, 5.5, and 4.8

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