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# review problem 7.163 by m4N9Vg

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```									                        Problem 7.163

A     B                     (a) draw the shear and bending-
C
moment diagrams, (b) determine
6000 lb
the magnitude and location of the
4 ft   6 ft             maximum absolute value of the
bending moment.
Problem 7.163

1500 lb/ft        Solving Problems on Your Own
C
6000 lb
(a) draw the shear and bending-
moment diagrams, (b) determine
4 ft       6 ft             the magnitude and location of the
maximum absolute value of the
bending moment.
1. Draw a free-body diagram for the entire beam, and use it to
determine the reactions at the beam supports.

2. Draw the shear diagram.

3. Draw the bending-moment diagram by computing the area
under each portion of the shear curve.
3 ft      9 kips                        Problem 7.163 Solution

Draw a free-body diagram for
the entire beam, and use it to
C        determine the reactions at the
A           B                           beam supports.
4 ft           6 ft        6 kips

+ S MA = 0 : (6 kips)(10 ft) - (9 kips)(7 ft) + B (4 ft) = 0

B = 0.75 kips
+ S F = 0 : A + 0.75 kips + 6 kips - 9 kips = 0
y

A = 2.25 kips
Draw the shear diagram.                                             Problem 7.163 Solution
1.5 kips/ft

A                         B                                      C

2.25 kips          0.75 kips                              6 kips
4 ft                           6 ft
V (kips)                              + 3 kip

+ 2.25 kip                                      D
x
A                  B                                          C
VB            3 kips
BD =    =
w           1.5 kips/ft
2 ft                4 ft          - 6 kip
Draw the bending-moment diagram.                                             Problem 7.163 Solution
1.5 kips/ft

A                             B                                               C

2.25 kips                0.75 kips                                     6 kips
4 ft                             6 ft
V (kips)                                  + 3 kip       1
(3 kips)(2 ft) = (+3 kip-ft)
2
+ 2.25 kip       (+9 kip-ft)                        D
x
A                      B                                                   C
(- 12 kip-ft)
VB              3 kips
BD =    =
w             1.5 kips/ft
2 ft                4 ft                   - 6 kip

(+12 kip-ft)                 Mmax = 12 kip-ft
(+9 kip-ft)
M (kip-ft)
6 ft from A

A
x
B               D                                 C

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