Loss in a Tank in lbm/hr
Equation What is it units
Wp=(.097+.038)v*(Pw-Pa)*A Loss in a tank lbm/hr
Pw=.0082e^17.27*T/(T+237.3) Saturation vapor pressure of water at actual temp psia
Pa=.0082e^17.27*Tdp/(Tdp+237.3) Saturation vapor pressure of water at dew point psia
Tdp=(b*f(T,H))/(a-f(T,H)) Temp at dew point degrees C
f(T,H)=((a*T)/(b+T))+Ln(H)
H=chart relative humidity
v=chart wind velocity mph
A=chart area of tank ft^2
a=constant 17.27
b=constant 237.7
Average Temperature 22.22 degrees C
Average Dew Point 21.2 degrees C
Average Realative Humidity 84.25 %
Area of Tank(50 ft radius) 7850 ft^2
Wind Velocity 14.316 mph
Loss Equals 2.302956
http://www.bbc.co.uk/weather/world/city_guides/results.shtml?tt=TT001840
http://swera.unep.net/typo3conf/ext/metadata_tool/archive/download/camwindreport_R4_242.pdf
http://www.atlapedia.com/online/countries/elsalvad.htm
http://www.engineeringtoolbox.com/hazen-williams-water-d_797.html
Head loss in Pipes
500 Feet of Pipe
PVC piping (design coefficent of 150)
Flow Rate of 20 gal/min
Inside hydralic diameter=10 inch (2*r*2)
Pipe radius of 2.5 inches
Loss equal .002
http://www.engineeringtoolbox.com/evaporation-water-surface-d_690.html