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Re Tarski's weird definition of cardinal numbers

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Re Tarski's weird definition of cardinal numbers
Re: Tarski's weird definition of cardinal numbers



Re: Tarski's weird definition of cardinal numbers



Source: http://sci.tech−archive.net/Archive/sci.logic/2005−10/msg00146.html







• From: "Rupert"

• Date: 4 Oct 2005 23:08:15 −0700





andrewspencers@xxxxxxxxx wrote:

> The usual definition I've seen of a cardinal number x is the class of

> all cardinal numbers less than x, with the cardinal number 0 being the

> empty class.



This isn't really satisfactory as it stands, because no definition is

given of "less than". There's a version of this definition that can be

made precise, but it's a definition of ordinal rather than cardinal

numbers.



> Thus all cardinal numbers are finite classes,



Why? What about w={0,1,2,...}?



> and the

> ordering relation is the subset relation. The cardinal number of a

> finite class K is the cardinal number which is equinumerous with K, and

> the cardinal number of a cardinal number x is x itself.

>

> But Tarski says on p. 80 of "Introduction to Logic", "The cardinal

> number of a class K is the class of all classes equinumerous with K."

> Therefore all cardinal numbers are infinite classes, with the exception

> of the cardinal number 0, which is a class containing one element (that

> element being the empty class), i.e. the cardinal number 0 is the class

> {{}}, since the empty class is the only class equinumerous with the

> empty class. The cardinal number 1 is the infinite class containing all

> of the following classes: {{}}, {{{}}}, {{{{}}}}, etc, as well as

> {{{},{}}}, {{{},{},{}}}, {{{},{},{},{}}}, etc, since those classes each

> have exactly one element. The cardinal number of a cardinal number x is

> not x itself, but some other infinite class. Besides all that, the

> ordering relation is nowhere in sight.

>



You could say the cardinal number A is less than the cardinal number B

if there's an injection from a member of A into a member of B, but no

bijection from any member of A to a member of B.



> Who's responsible for perpetrating that latter definition (Tarski





Re: Tarski's weird definition of cardinal numbers 1

Re: Tarski's weird definition of cardinal numbers

> himself?), does anybody still use it today, and what advantage does it

> have over the former definition?



The definition originated with Frege. The main problem with it is that

in most modern theories of sets there's no such thing as the set of all

sets equinumerous with a given set. In some theories of sets there are

sets and classes, where every set is a class but not the converse, and

only sets can be members of a class, and in that case the definition

will work okay if we define a cardinal number to be the class of all

sets equinumerous with a given set. The cardinal number will then not

be a set, it will be a proper class (a class which is not a set). Then

the problem with that is that cardinal numbers can't be members of

sets, and we sometimes want them to be. The way to get around this is

Scott's trick. Ordinal numbers can be defined to be sets which are

transitive and well−ordered by the membership relation. (This is the

precise version of your definition I was alluding to earlier). Then you

can associate an ordinal number to each set called its rank. The empty

set has rank 0, and the rank of any set is the first ordinal greater

than the ranks of all its members. Then you can define a cardinal

number to be the set of all sets equinumerous with a given set that are

of least possible rank among the sets equinumerous with that set. This

will be a set rather than a class. This is the usual definition of

cardinal number when we don't assume the axiom of choice. If we do

assume the axiom of choice, then we can define ordinal numbers in the

way I have mentioned and define cardinal numbers to be ordinals not

equinumerous with any smaller ordinal. (We will then need the axiom of

choice to prove that every set is equinumerous with a unique cardinal).





The advantage that Tarski's definition has over your "definition" is

that it's a definition. You didn't really give a definition. You might

have been thinking of the definition of ordinals as transitive sets

well−ordered by the membership relation and cardinals as ordinals not

equinumerous with any smaller ordinal; that's the usual definition

today. Then Tarski's definition has the advantage over this definition

that you don't need to assume the axiom of choice to prove that any set

has a cardinal, but the disadvantage that you need to work with proper

classes and that your cardinals can't be members of sets. However, this

disadvantage can be remedied with Scott's trick.



.







• Follow−Ups:

♦ Re: Tarski's weird definition of cardinal numbers

◊ From: Ross A. Finlayson

♦ Re: Tarski's weird definition of cardinal numbers

◊ From: andrewspencers



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Re: Tarski's weird definition of cardinal numbers 2

Re: Tarski's weird definition of cardinal numbers

♦ Tarski's weird definition of cardinal numbers

◊ From: andrewspencers



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