; ideal_gas_equation
Documents
Resources
Learning Center
Upload
Plans & pricing Sign in
Sign Out
Your Federal Quarterly Tax Payments are due April 15th Get Help Now >>

ideal_gas_equation

VIEWS: 13 PAGES: 2

  • pg 1
									Ideal gas equation

Combining the equations PV = constant, P/T = constant and V/T = constant gives:

                                        PV /T = constant



If we use 1 mole of gas the constant is known as the molar gas constant (R).
So for one mole of the ideal gas equation is:

                  Ideal Gas equation (one mole):                   PV = RT



  Example problem
        3                                                      o        o
  0.3 m of an ideal gas are heated at constant pressure from 27 C to 127 C. What is the new volume
  of the gas?
                                             3
   V2 = [V1T2]/T1 = [0.3 x 400]/300 = 0.4 m
  (Notice that the temperatures used are always in Kelvin!)


Now the volume of one mole of an ideal gas at Standard Temperature and Pressure (STP)
         5                            3
(1.014x10 Pa and 273.15 K) is 0.0224m and so

        1.014x105 x 0.0224 = 1 x R x 273.15           and therefore R = 8.314 JK-1mol-1.

For n moles this equation becomes:

                             Ideal Gas equation (n moles): PV = nRT


For a change from P1, V1 and T1 to P2, V2 and T2 the equation can be written:

                                             P1V1 = P2V2
                                              T1     T2



Example problem
                                            5                       3
If 600g of argon have a pressure of 1.5 x 10 Pa and a volume of 0.3m what is the temperature of the
gas?
Molar mass of argon = 40g and so we have 15 moles.
Therefore:
                            5                  o
           T = PV = 1.5 x 10 x 0.3 = 361 K = 88 C
               nR 15 x 8.31

We have of course assumed that argon behaves as an ideal gas.




                                                                                                  1
Example problem
                                                                                                      o
A petrol - air mixture in the piston of a car engine initially has volume of 50cc, a temperature of 27 C
                                5
and is at a pressure of 2 x 10 Pa. When it is ignited by the spark plug the volume increases to 450cc
                                     4
and the pressure drops to 8 x 10 Pa. What is the final temperature of the mixture. (assume that it
behaves as an ideal gas!)
                 5                4
           2 x 10 x 50 = 8 x 10 x 450
              300                T2
                                           4                         o
 Therefore final temperature (T2) = 8 x 10 x 450 x 300 = 1080 K = 807 C
                                               5
                                         2 x 10 x 50


The equation of state for 1 kg of the gas is:

                                       PV = [R/M]T = rT

where M is the molar mass in kg (2 x 10-3 for hydrogen and 32 x 10-3 for oxygen, for
example) and r is a further constant depends on the gas under consideration. Therefore for
m kg of the gas we have:

                                      PV= mRT/M       = mrT


For a fixed mass of gas whose conditions are changed from P1, V1 and T, to P2, V2 and T2
the equation of state can be written:

                                          P1V1/T1 = P2V2/T1

Note that the temperature must always be measured in kelvins.



                             PV (J)

                             20




                             10




                                                          200
                                                         Temperature (K)




                                                                                                      2

								
To top