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Name of STP: STUDENT

Measured Parameters mg/L

BODo= 321

sBODo= 161





CODo= 600.00

sCODo= Si +Ss = 180

rbCODo= Ss = 90.0

bCOD/BODo= 1.6





VSS%= 65.0%

Recirculating rate at average flow 0.75



Chosen M LSS = 3400





Calculated Parameters

bCODo= sbCOD + rbCOD=Ss + Xs + Xp = 514

sCODeff= Si = sCOD - bCOD = -77

biodegradab particul COD bpCOD= Xs + Xp = bCOD/BODo*(BODo-sBOD) 257

particulate COD pCOD= Xs + Xp + Xi = CODo-sCODo 420





VSS= 228.8

nonbiodegradable VSS nbVSS= 88.9

iTSS = TSS-VSS= 123.2

Return sludge concentration, M LSS 7933.3

rbCOD/bCOD= 0.18

Select rbCOD/bCOD= 0.20









Aeration Tank

Aerobic Sludge Age (t-DS) µn = (µm,n x NH 4Neff / (Kn + N) x (DO / Ko+DO) - kd



Kinetic parameters

µm,n , selected 0.75 g VSS/g VSS.d

µm,n,T 0.44 g VSS/g VSS.d

Kn, selected 0.74 g NH4-N/m2

Kn,T 0.49 g NH4-N/m3

kdn, selected 0.08 g VSS/g VSS.d

kdn,T 0.06 g VSS/g VSS.d

kd, selected 0.12 g VSS/g VSS.d

kd,T 0.088 g VSS/g VSS.d







Sludge Production = Biomass Production (Pxbio) = Xb

Px,bio=((Q * Y *(So-S)) / (1 + kd * SRTa)) + ((Q*fd * kd * Y (So-S) *SRTa) / (1 + kd* SRTa)) + (Q * Yn *N

Kinetic parameters

kd, selected 0.12 g VSS/g VSS.d

kd,T 0.088 g VSS/g VSS.d







Sludge Production = Biomass Production (Pxbio) = Xb

Px,bio=((Q * Y *(So-S)) / (1 + kd * SRTa)) + ((Q*fd * kd * Y (So-S) *SRTa) / (1 + kd* SRTa)) + (Q * Yn *N

Kinetic parameters



Y, selected 0.4 g VSS/g bCOD

fd, selected 0.15 -

Yn, selected 0.12 g VSS/g NH4_N Biologic

Ks, selected 20.0 g bCOD/m3









VSS (Assuming bpCOD/pCOD = bpVSS/pVSS)



nbVSS = (1 - (bpCOD / pCOD))*VSS nbVSS =

Px,vss=Px,bio + (nbVSS x Q) / 1000 Px,vss = 4





TSS

Px,tss=Px,bio / VSSperc + (Q*nbVSS ) + Q *(TSSo - VSSo)

Sludge production, Px,tss = 9,0

MLVSS/MLSS = 0



Voxic

Voxic = (Px,tss + PxPO4) x SRTa/ MLSS

Sludge production from Phosphate Precipitation

Pxtotal= Total sludge production 9,0

Va=V-oxic = 15,

Va= Oxic Volume, selected = 15,1



Nitrogen to be , Nitrified =NN = NOx

NN = NOx = TKNo - (NH4Neff +org Neff)- 0.12 x Pxbio / Q

WASN= XorgNWAS= 0.12 x Pxbio / Q=

S-NH4N = NN = NOx=Nitrogen to be nitrified= 48

97



Nitrogen to be Denitrified= NDN = S_NO3,D = DNcapacity

S-NO3,D = NN - NO3Neff = TKNo-TKNeff-WASN +(NO3No-NO3Neff)

NO3Neff=

DN capacity = NO3N to be DN=S-NO3,D = 4

83





Internal Recirculating Rate, IR

IR = NOx / NO3Neff - 1 - R =

Selected IR =

NO3N fed into anoxic tank = Q*(Rr+IR)*NO3Neff/1000 = 83





Anoxic volume

Internal Recirculating Rate, IR

IR = NOx / NO3Neff - 1 - R =

Selected IR =

NO3N fed into anoxic tank = Q*(Rr+IR)*NO3Neff/1000 = 83





Anoxic volume

Selected Retention time =

Anoxic volume, required 3

Anoxic volume, selected 3





F/Mb

Xb = MLVSSbiomass = Q x SRTa / Vaerobic * Y (S0-S) / (1+ kd x SRTa)

MLVSSbiomass =Xb= 1

F/Mb = (Q x S0) / ( Xb * Vd) = F/M b = 1.





Specific Nitrate Removal Rate:



SDNR at 20 o C (read from Fig. 8- 23 ) 0

SDNR at T o C = SDNR20*1.026^(Tmin-20)= 0





Amount of NitrateN that can be reduced = NOr

NOr = SDNR *Xb *Vd Nitrate removed = 83

Capacity Ratio= NO3N that can be removed / No3N fed into Anoxic tank= 1



Aeration Tank Volume

V-aerobic 15,151 m³

V-anoxic 3,862 m³

V-total 19,013.6 m³

V-total 19,013.6 m³

V-anoxic/V-total 0.203 -



F/M ratio 0.101 kgBOD/kgMLSS/

22.449 h

Total sludge age = 7.13 d





Vtotal= 19,014 m³

VD/VT= 0.20

F/M ratio = kgBOD/kgM LSS/d 0.101

tR= 22.4 h

SRTtotal= 7.1 d

Tank quantity 2.000 nos.

3

Tank volume 9,507 m

Water depth 6.000 m

Tank surface, each = 1,584.469

Net tank width 9.300

Diameter of the round parts 9.300

M iddle wall length 33.750

Total tank length 43.050

Tank quantity 2.000 nos.

3

Tank volume 9,507 m

Water depth 6.000 m

Tank surface, each = 1,584.469

Net tank width 9.300

Diameter of the round parts 9.300

M iddle wall length 33.750

Total tank length 43.050

mg/L Selected % Advisable Results

Advisable % values

321

161 50.0% 50% 160.5



600.00 COD/BOD= 1.87

180 30.0% 30% 180

90.0 15.0% 15% 90

1.6





65.0% 85%

0.75 % 0.75

3400 mg/lt









s + Xp = 514 85.6%

-77 -12.8%

ODo-sBOD) 257 42.8% 27%

CODo 420 70.0% 40%





228.8

88.9

123.2

7933.3 mg/lt

0.18

0.20









 A max NH 4 Neff DO

A     1.103(tc 1

n + N) x (DO / Ko+DO) - kdn HSG SFN K n  NH 4 Neff 1  DO

Ko, selected 0.50 mg/L

2.00

Dissolved Oxygen, selected mg/L

C-NH4,OA= NH4Neff=1.00 mg/L

SF = 1.000 TKNpeak/TKNaver= 2.75 SR







Specific growth rate for nitrifying organisms (µ,n) 0.176

Aerobic sludge age, (t-DS) 5.68 kg/kg*d

Aerobic sludge age, selected = SRTa = 5.68 kg/kg*d

A. Biological

ATV SRTa= 6.62



Effluent BOD Concentr

= Xb

(1 + kd* SRTa)) + (Q * Yn *NOx / (1 + Kdn * SRTa))

S = Ks x (1 + kd x SRT) / (SRT x (µm - kd) -1)

Aerobic sludge age, (t-DS) 5.68 kg/kg*d

Aerobic sludge age, selected = SRTa = 5.68 kg/kg*d

A. Biological

ATV SRTa= 6.62



Effluent BOD Concentr

= Xb

(1 + kd* SRTa)) + (Q * Yn *NOx / (1 + Kdn * SRTa))

S = Ks x (1 + kd x SRT) / (SRT x (µm - kd) -1)

µm , selected = 6.0 g VSS/g VSS.d

VSS/g bCOD µm,T = 3.5 g VSS/g VSS.d

- S= 1.63 mg/l

SS/g NH4_N Biologic Sludge Production=

g bCOD/m3 Xb = Pxbio = 3,090 kg VSS/d

Px ,bio  QYH









nbVSS = 88.9 mg/l 0.252571429

Px,vss = 4,897 kg/d

M &E Yobs

YobsH= (0,75+0,6(SS/BOD)-((1-0,2)*0,17*0,75*SRT*FT)/

(Pxbio/VSSperc)/((Q*BODo-S)/1000) = 0.732

ss = 9,066 kg/d 9,066 kg/d

SS/MLSS = 0.540 (1-bpCOD/pCOD)*VSSperc+(1-VSSperc) = 0.603



Choose VdVt= 0.5

SRTt= 11 d

- kg/d Ft= 0.814

9,066 kg/d ER= 3.6

Va=V-oxic = 15,151 m³ M&E YobsH= 1.396

selected = 15,151 m³ ATV Yobs= 1.05





PxTSS M&E = 9,066

PxT (M&E)= 9,066

x Pxbio / Q= 18.2 mg/l PxT-ATV= 6,824

be nitrified= 48.16 mg/l

978.9 kg/d



pacity

-NO3Neff)

NO3Neff= 7 mg/l

=S-NO3,D = 41.2 mg/l

836.6 kg/d







5.13 %

lected IR = 5.13 %

000 = 836.6 kgNO3/d 0.011x 3 - 0.085x 2 + 0.305x







rbCOD/bCOD SDNR@20C (power fit) 1, OK







15,151 m³

3,862 m³

19,013.6 m³

19,013.6 m³

0.203 -



0.101 kgBOD/kgMLSS/d

22.449 h

7.13 d





19,014 m³

0.20

0.101

22.4 h

7.1 d

2.000 nos.

3

9,507 m

6.000 m

1,584.469

9.300

9.300

33.750

43.050

2.000 nos.

3

9,507 m

6.000 m

1,584.469

9.300

9.300

33.750

43.050

Neff DO

  1.103(tc 15)

4 Neff 1  DO









2.75 SRT %of BOD Load

=20 3.50%

5.68 kg/kg*d

5.68 kg/kg*d

A. Biological Sludge Production (Px,bio)

6.62



Effluent BOD Concentrations, S:



(1  bH ,T SRTa )

S  Ks

SRTa (  H ,T  bH ,T )  1

5.68 kg/kg*d

5.68 kg/kg*d

A. Biological Sludge Production (Px,bio)

6.62



Effluent BOD Concentrations, S:



(1  bH ,T SRTa )

S  Ks

SRTa (  H ,T  bH ,T )  1



bH,T = bH,20(1.04)T-20



 H ,T   H , 20 (1.07) T  20



(S 0  S ) SRTa ( S 0  S ) NO X

Px ,bio  QYH  QYH f d bH ,T  QY A

1  bH ,T SRTa 1  bH ,T SRTa (1  b A,T SRTa )



PX,H PX-particulates PX,A

formed from decay

of heterotrophs





NOX = Oxidized TKN = TKNin - TKNeff – 0.12(Px,bio/Q)





(1-0,2)*0,17*0,75*SRT*FT)/ TKNoxid XorgN,WAS



-S)/1000) = 0.732





c+(1-VSSperc) = 0.603



0.5

11 d

0.814

3.6

1.396 1.389

1.05





9,066

9,066

6,824









x 3 - 0.085x 2 + 0.305x







@20C (power fit)<2 SDNR@20C (ln fit)

x 3 - 0.085x 2 + 0.305x







@20C (power fit)<2 SDNR@20C (ln fit)

0.226

0.256

0.285

0.318 0.328



0.328



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